IV is a saturate hydrocarbon (without multiple ca.pdf

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IV is a saturate hydrocarbon (without multiple carbon-carbon bond) V is an unsaturated hydrocarbon (with C=C double bond) Solution IV is a saturate hydrocarbon (without multiple carbon-carbon bond) V is an unsaturated hydrocarbon (with C=C double bond).

IV is a saturate hydrocarbon (without multiple carbon-carbon bond) V is an
unsaturated hydrocarbon (with C=C double bond)
Solution
IV is a saturate hydrocarbon (without multiple carbon-carbon bond) V is an
unsaturated hydrocarbon (with C=C double bond)

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Resonance structures are simply alternate Lewis structures for a given ion or molecule. Thus we can draw all resonance structures by drawing all of the possible Lewis structures. However, it is not always easy to see what all these Lewis structures might be. A set of Lewis structures for a give ion or molecule must have the same number of electrons as the Lewis structures are constructed from the same atoms. The only difference between the Lewis structures is the placement of the electrons. The position of the atoms in space is held constant. We can use this facts to assist us in drawing resonance structures. Because the number of electrons is conserved, electrons taken away from one atom must appear somewhere else in the structure. When drawing resonance structures, it is most convenient to shift these electrons between adjacent atoms. Solution Resonance structures are simply alternate Lewis structures for a given ion or molecule. Thus we can draw all resonance structures by drawing all of the possible Lewis structures. However, it is not always easy to see what all these Lewis structures might be. A set of Lewis structures for a give ion or molecule must have the same number of electrons as the Lewis structures are constructed from the same atoms. The only difference between the Lewis structures is the placement of the electrons. The position of the atoms in space is held constant. We can use this facts to assist us in drawing resonance structures. Because the number of electrons is conserved, electrons taken away from one atom must appear somewhere else in the structure. When drawing resonance structures, it is most convenient to shift these electrons between adjacent atoms..

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//program files //admin.aspx.cs using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; namespace RegistrationUsers { public partial class Admin : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } protected void Button1_Click(object sender, EventArgs e) { Response.Redirect(\"WebForm1.aspx\"); } protected void Button2_Click(object sender, EventArgs e) { Response.Redirect(\"view users.aspx\"); } } } //view users.aspx.cs using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; namespace RegistrationUsers { public partial class view_users : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } } } //webform1.aspx.cs using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.SqlClient; using System.Configuration; namespace RegistrationUsers { public partial class WebForm1 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { /* if (IsPostBack) { String cs = ConfigurationManager.ConnectionStrings[\"Data Source = ADMINIB - 83V87D2; Initial Catalog = employee; Integrated Security = True; Connect Timeout = 15; Encrypt = False; TrustServerCertificate = True; ApplicationIntent = ReadWrite; MultiSubnetFailover = False\"].ConnectionString; SqlConnection connection = new SqlConnection(cs); connection.Open(); string checkuser = \"select count(*) from Users where Username=\" + TextBox1.Text + \"\'\"; SqlCommand com = new SqlCommand(checkuser, connection); int temp = Convert.ToInt32(com.ExecuteScalar().ToString()); if (temp == 1) { Console.WriteLine(\"user already exists\"); } connection.Close(); }*/ } protected void Button2_Click1(object sender, EventArgs e) { try { string cs = ConfigurationManager.ConnectionStrings[\"employeeConnectionString\"].ConnectionString; SqlConnection conn = new SqlConnection(cs); conn.Open(); string insertquery = \"insert into Users(Username,Password,Email,Cell,Location)values(@username,@password,@email,@cell, @location)\"; SqlCommand comm = new SqlCommand(insertquery, conn); comm.Parameters.AddWithValue(\"@username\", TextBox1.Text); comm.Parameters.AddWithValue(\"@password\", TextBox2.Text); comm.Parameters.AddWithValue(\"@email\", TextBox3.Text); comm.Parameters.AddWithValue(\"@cell\", TextBox4.Text); comm.Parameters.AddWithValue(\"@Location\", DropDownList1.SelectedValue); comm.ExecuteNonQuery(); Response.Write(\"Registration Sucessful\"); conn.Close(); } catch (Exception ex) { Console.WriteLine(\"error:\" + ex.ToString()); } } protected void Button1_Click(object sender, EventArgs e) { Response.Redirect(\"Login.aspx\"); } } } //login.aspx.cs using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.

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C is best methode Bromination of alkane is most favourable due to lessbond disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives alkenes Solution C is best methode Bromination of alkane is most favourable due to lessbond disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives alkenes.

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