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INTRODUCTORY STATISTICS
Chapter 4 Discrete Random Variables
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
CHAPTER 4: DISCRETE RANDOM
VARIABLES
4.1 Probability Distribution Function (PDF) for a Discrete Random
Variable
4.2 Mean or Expected Value and Standard Deviation
4.3 Binomial Distribution
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
CHAPTER OBJECTIVES
By the end of this chapter, the student should be able to:
• Recognize and understand discrete probability distribution
functions, in general.
• Calculate and interpret expected values.
• Recognize the binomial probability distribution and apply it
appropriately.
• Recognize the Poisson probability distribution and apply it
appropriately.
• Recognize the geometric probability distribution and apply it
appropriately.
• Recognize the hypergeometric probability distribution and apply it
appropriately.
• Classify discrete word problems by their distributions.
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
RANDOM VARIABLE NOTATION
A random variable describes the outcomes of a statistical experiment
in words. The values of a random variable can vary with each repetition
of an experiment.
Upper case letters such as X or Y denote a random variable. Lower
case letters like x or y denote the value of a random variable. If X is a
random variable, then X is written in words, and x is given as a
number.
For example, let X = the number of heads you get when you toss three
fair coins. The sample space for the toss of three fair coins is TTT;
THH; HTH; HHT; HTT; THT; TTH; HHH. Then, x = 0, 1, 2, 3. X is in
words and x is a number. Notice that for this example, the x values are
countable outcomes. Because you can count the possible values that
X can take on and the outcomes are random (the x values 0, 1, 2, 3), X
is a discrete random variable.
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
4.1 PROBABILITY DISTRIBUTION
FUNCTION (PDF) FOR A DISCRETE
RANDOM VARIABLE
A discrete probability distribution function has two characteristics:
• 1. Each probability is between zero and one, inclusive.
• 2. The sum of the probabilities is one.
• Example
• A hospital researcher is interested in the number
of times the average post-op patient will ring the
nurse during a 12-hour shift. For a random
sample of 50 patients, the following information
was obtained. Let X = the number of times a
patient rings the nurse during a 12-hour shift.
For this exercise, x = 0, 1, 2, 3, 4, 5. P(x) = the
probability that X takes on value x. Why is this a
discrete probability distribution function (two
reasons)?
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
4.2 MEAN OR EXPECTED VALUE
AND STANDARD DEVIATION
The expected value is often referred to as the "long-term" average or mean. This
means that over the long term of doing an experiment over and over, you would expect
this average.
The Law of Large Numbers states that, as the number of trials in a probability
experiment increases, the difference between the theoretical probability of an event and
the relative frequency approaches zero (the theoretical probability and the relative
frequency get closer and closer together).
When evaluating the long-term results of statistical experiments, we often want to know
the “average” outcome. This “long-term average” is known as the mean or expected
value of the experiment and is denoted by the Greek letter μ. In other words, after
conducting many trials of an experiment, you would expect this average value.
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
EXAMPLE 4.3: EXPECTED VALUE
• A men's soccer team plays soccer zero, one, or two days a week. The
probability that they play zero days is 0.2, the probability that they play one
day is 0.5, and the probability that they play two days is 0.3. Find the long-
term average or expected value, μ, of the number of days per week the
men's soccer team plays soccer.
• To do the problem, first let the random variable X = the number of days the
men's soccer team plays soccer per week. X takes on the values 0, 1, 2.
Construct a PDF table adding a column x*P(x). In this column, you will
multiply each x value by its probability.
• Add the last column x*P(x) to find the long
term average or expected value: (0)(0.2) +
(1)(0.5) + (2)(0.3) = 0 + 0.5 + 0.6 = 1.1.
• The expected value is 1.1. The men's soccer
team would, on the average, expect to play
soccer 1.1 days per week. The number 1.1 is
the long-term average or expected value if the
men's soccer team plays soccer week after
week after week. We say μ = 1.1.
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
STANDARD DEVIATION OF A
PROBABILITY DISTRIBUTION
Like data, probability distributions have standard deviations. To calculate
the standard deviation (σ) of a probability distribution, find each deviation
from its expected value, square it, multiply it by its probability, add the
products, and take the square root. To understand how to do the
calculation, look at the table for the number of days per week a men's
soccer team plays soccer. To find the standard deviation, add the entries in
the column labeled (x – μ)2P(x) and take the square root.
Add the last column in the table. 0.242 + 0.005 + 0.243 = 0.490. The
standard deviation is the square root of 0.49, or σ = sqrt(0.49) = 0.7
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
EXAMPLE
A hospital researcher is interested in the
number of times the average post-op patient
will ring the nurse during a 12-hour shift. For a
random sample of 50 patients, the following
information was obtained.
• What is the expected value?
• What is the standard deviation?
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
4.3 BINOMIAL DISTRIBUTION
There are three characteristics of a binomial experiment.
• 1. There are a fixed number of trials. Think of trials as repetitions of
an experiment. The letter n denotes the number of trials.
• 2. There are only two possible outcomes, called "success" and
"failure," for each trial. The letter p denotes the probability of a
success on one trial, and q denotes the probability of a failure on
one trial. p + q = 1.
• 3. The n trials are independent and are repeated using identical
conditions. Because the n trials are independent, the outcome of
one trial does not help in predicting the outcome of another trial.
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
BINOMIAL DISTRIBUTION
The outcomes of a binomial experiment fit a binomial probability
distribution. The random variable X = the number of successes
obtained in the n independent trials.
The mean, μ, and variance, σ2, for the binomial probability distribution
are
• μ = np and
• σ2 = npq.
• The standard deviation, σ, is then
Any experiment that has characteristics two and three and where n = 1
is called a Bernoulli Trial. A binomial experiment takes place when the
number of successes is counted in one or more Bernoulli Trials.
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
EXAMPLES
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
NOTATION FOR THE BINOMIAL:
B = BINOMIAL PROBABILITY
DISTRIBUTION FUNCTION
X ~ B(n, p)
Read this as "X is a random variable with a binomial distribution." The
parameters are n and p; n = number of trials, p = probability of a success
on each trial.
Example 4.13
• It has been stated that about 41% of adult workers have a high school
diploma but do not pursue any further education. If 20 adult workers
are randomly selected, find the probability that at most 12 of them
have a high school diploma but do not pursue any further education.
How many adult workers do you expect to have a high school diploma
but do not pursue any further education?
• Let X = the number of workers who have a high school diploma but do
not pursue any further education.
• X takes on the values 0, 1, 2, ..., 20 where n = 20, p = 0.41, and q = 1 –
0.41 = 0.59. X ~ B(20, 0.41)
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
EXAMPLE 4.13
SOLUTION
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
NOTATION FOR THE BINOMIAL:
B = BINOMIAL PROBABILITY
DISTRIBUTION FUNCTION
The graph of X ~ B(20, 0.41)
is as follows:
The y-axis contains the probability of x, where X = the number of workers who have only
a high school diploma.
The number of adult workers that you expect to have a high school diploma but not
pursue any further education
is the mean, μ = np = (20)(0.41) = 8.2.
The formula for the variance is σ2 = npq. The standard deviation is
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
EXAMPLE 4.14
In the 2013 Jerry’s Artarama art supplies catalog, there are 560 pages.
Eight of the pages feature signature artists. Suppose we randomly
sample 100 pages. Let X = the number of pages that feature signature
artists.
• a. What values does x take on?
• b. What is the probability distribution? Find the following
probabilities:
• i. the probability that two pages feature signature artists
• ii. the probability that at most six pages feature signature artists
• iii. the probability that more than three pages feature signature
artists.
• c. Using the formulas, calculate the (i) mean and (ii) standard
deviation.
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
EXAMPLE
Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics

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Chapter 4

  • 1. INTRODUCTORY STATISTICS Chapter 4 Discrete Random Variables Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 2. CHAPTER 4: DISCRETE RANDOM VARIABLES 4.1 Probability Distribution Function (PDF) for a Discrete Random Variable 4.2 Mean or Expected Value and Standard Deviation 4.3 Binomial Distribution Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 3. CHAPTER OBJECTIVES By the end of this chapter, the student should be able to: • Recognize and understand discrete probability distribution functions, in general. • Calculate and interpret expected values. • Recognize the binomial probability distribution and apply it appropriately. • Recognize the Poisson probability distribution and apply it appropriately. • Recognize the geometric probability distribution and apply it appropriately. • Recognize the hypergeometric probability distribution and apply it appropriately. • Classify discrete word problems by their distributions. Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 4. RANDOM VARIABLE NOTATION A random variable describes the outcomes of a statistical experiment in words. The values of a random variable can vary with each repetition of an experiment. Upper case letters such as X or Y denote a random variable. Lower case letters like x or y denote the value of a random variable. If X is a random variable, then X is written in words, and x is given as a number. For example, let X = the number of heads you get when you toss three fair coins. The sample space for the toss of three fair coins is TTT; THH; HTH; HHT; HTT; THT; TTH; HHH. Then, x = 0, 1, 2, 3. X is in words and x is a number. Notice that for this example, the x values are countable outcomes. Because you can count the possible values that X can take on and the outcomes are random (the x values 0, 1, 2, 3), X is a discrete random variable. Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 5. 4.1 PROBABILITY DISTRIBUTION FUNCTION (PDF) FOR A DISCRETE RANDOM VARIABLE A discrete probability distribution function has two characteristics: • 1. Each probability is between zero and one, inclusive. • 2. The sum of the probabilities is one. • Example • A hospital researcher is interested in the number of times the average post-op patient will ring the nurse during a 12-hour shift. For a random sample of 50 patients, the following information was obtained. Let X = the number of times a patient rings the nurse during a 12-hour shift. For this exercise, x = 0, 1, 2, 3, 4, 5. P(x) = the probability that X takes on value x. Why is this a discrete probability distribution function (two reasons)? Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 6. 4.2 MEAN OR EXPECTED VALUE AND STANDARD DEVIATION The expected value is often referred to as the "long-term" average or mean. This means that over the long term of doing an experiment over and over, you would expect this average. The Law of Large Numbers states that, as the number of trials in a probability experiment increases, the difference between the theoretical probability of an event and the relative frequency approaches zero (the theoretical probability and the relative frequency get closer and closer together). When evaluating the long-term results of statistical experiments, we often want to know the “average” outcome. This “long-term average” is known as the mean or expected value of the experiment and is denoted by the Greek letter μ. In other words, after conducting many trials of an experiment, you would expect this average value. Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 7. EXAMPLE 4.3: EXPECTED VALUE • A men's soccer team plays soccer zero, one, or two days a week. The probability that they play zero days is 0.2, the probability that they play one day is 0.5, and the probability that they play two days is 0.3. Find the long- term average or expected value, μ, of the number of days per week the men's soccer team plays soccer. • To do the problem, first let the random variable X = the number of days the men's soccer team plays soccer per week. X takes on the values 0, 1, 2. Construct a PDF table adding a column x*P(x). In this column, you will multiply each x value by its probability. • Add the last column x*P(x) to find the long term average or expected value: (0)(0.2) + (1)(0.5) + (2)(0.3) = 0 + 0.5 + 0.6 = 1.1. • The expected value is 1.1. The men's soccer team would, on the average, expect to play soccer 1.1 days per week. The number 1.1 is the long-term average or expected value if the men's soccer team plays soccer week after week after week. We say μ = 1.1. Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 8. STANDARD DEVIATION OF A PROBABILITY DISTRIBUTION Like data, probability distributions have standard deviations. To calculate the standard deviation (σ) of a probability distribution, find each deviation from its expected value, square it, multiply it by its probability, add the products, and take the square root. To understand how to do the calculation, look at the table for the number of days per week a men's soccer team plays soccer. To find the standard deviation, add the entries in the column labeled (x – μ)2P(x) and take the square root. Add the last column in the table. 0.242 + 0.005 + 0.243 = 0.490. The standard deviation is the square root of 0.49, or σ = sqrt(0.49) = 0.7 Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 9. EXAMPLE A hospital researcher is interested in the number of times the average post-op patient will ring the nurse during a 12-hour shift. For a random sample of 50 patients, the following information was obtained. • What is the expected value? • What is the standard deviation? Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 10. 4.3 BINOMIAL DISTRIBUTION There are three characteristics of a binomial experiment. • 1. There are a fixed number of trials. Think of trials as repetitions of an experiment. The letter n denotes the number of trials. • 2. There are only two possible outcomes, called "success" and "failure," for each trial. The letter p denotes the probability of a success on one trial, and q denotes the probability of a failure on one trial. p + q = 1. • 3. The n trials are independent and are repeated using identical conditions. Because the n trials are independent, the outcome of one trial does not help in predicting the outcome of another trial. Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 11. BINOMIAL DISTRIBUTION The outcomes of a binomial experiment fit a binomial probability distribution. The random variable X = the number of successes obtained in the n independent trials. The mean, μ, and variance, σ2, for the binomial probability distribution are • μ = np and • σ2 = npq. • The standard deviation, σ, is then Any experiment that has characteristics two and three and where n = 1 is called a Bernoulli Trial. A binomial experiment takes place when the number of successes is counted in one or more Bernoulli Trials. Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 12. EXAMPLES Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 13. NOTATION FOR THE BINOMIAL: B = BINOMIAL PROBABILITY DISTRIBUTION FUNCTION X ~ B(n, p) Read this as "X is a random variable with a binomial distribution." The parameters are n and p; n = number of trials, p = probability of a success on each trial. Example 4.13 • It has been stated that about 41% of adult workers have a high school diploma but do not pursue any further education. If 20 adult workers are randomly selected, find the probability that at most 12 of them have a high school diploma but do not pursue any further education. How many adult workers do you expect to have a high school diploma but do not pursue any further education? • Let X = the number of workers who have a high school diploma but do not pursue any further education. • X takes on the values 0, 1, 2, ..., 20 where n = 20, p = 0.41, and q = 1 – 0.41 = 0.59. X ~ B(20, 0.41) Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 14. EXAMPLE 4.13 SOLUTION Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 15. NOTATION FOR THE BINOMIAL: B = BINOMIAL PROBABILITY DISTRIBUTION FUNCTION The graph of X ~ B(20, 0.41) is as follows: The y-axis contains the probability of x, where X = the number of workers who have only a high school diploma. The number of adult workers that you expect to have a high school diploma but not pursue any further education is the mean, μ = np = (20)(0.41) = 8.2. The formula for the variance is σ2 = npq. The standard deviation is Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 16. EXAMPLE 4.14 In the 2013 Jerry’s Artarama art supplies catalog, there are 560 pages. Eight of the pages feature signature artists. Suppose we randomly sample 100 pages. Let X = the number of pages that feature signature artists. • a. What values does x take on? • b. What is the probability distribution? Find the following probabilities: • i. the probability that two pages feature signature artists • ii. the probability that at most six pages feature signature artists • iii. the probability that more than three pages feature signature artists. • c. Using the formulas, calculate the (i) mean and (ii) standard deviation. Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics
  • 17. EXAMPLE Prepared by the College of Coastal Georgia for OpenStax Introductory Statistics