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EXPONENTIAL LIKE FUNCTION
FOR RATIONAL INDICES
By Sreeni C, PMP, B.Tech (IITB), MBA29-Aug-2015
Function Definition
By Sreeni C (schopakatla@gmail.com)
Definition: A two variable function f(x,m), where x is a positive real number
and m is a natural number
f(x,m) is an infinite series, wherein N+1th Term of the
Series=
𝑥
𝑁+
1
𝑚
1
𝑚 ∗ 1+1
𝑚 ∗ 2+1
𝑚 ∗⋯∗ 𝑁+1
𝑚
𝑁=∞
𝑁=0
ƒ(x,m)=
𝑥
1
𝑚
1
𝑚
+
𝑥
1+
1
𝑚
1
𝑚 ∗ 1+1
𝑚
+
𝑥
2+
1
𝑚
1
𝑚 ∗ 1+1
𝑚 ∗ 2+1
𝑚
+……..+
𝑥
𝑁+
1
𝑚
1
𝑚 ∗ 1+1
𝑚 ∗ 2+1
𝑚 ∗⋯∗ 𝑁+1
𝑚
… . ∞
Function Continuity Test
By Sreeni C (schopakatla@gmail.com)
ƒ(x,m) can be expressed as a product of the following two functions
ƒ(x,m)=g*h
Where
g(x,m)=
𝑥
1
𝑚
1
𝑚
h x, m = 1 +
x
1+1
𝑚
+
𝑥2
1+1
𝑚 ∗ 2+1
𝑚
+……..+
𝑥 𝑁
1+1
𝑚 ∗ 2+1
𝑚 ∗⋯∗ 𝑁+1
𝑚
… . ∞
For all positive real numbers (x) and natural numbers (m), g is a
continuous function; h is a polynomial function and hence is a continuous
function for all real numbers
Therefore f=g*h is a continuous function for all positive real numbers
(x) and natural numbers (m)
Function Convergence Test
By Sreeni C (schopakatla@gmail.com)
N+2th term of the series (TN+2)=
𝑥
1
𝑚
1
𝑚
*
𝑥 𝑁+1
1+1
𝑚 ∗ 2+1
𝑚 ∗⋯∗ 𝑁+1+1
𝑚
N+1th term of the series(TN+1)=
𝑥
1
𝑚
1
𝑚
*
𝑥 𝑁
1+1
𝑚 ∗ 2+1
𝑚 ∗⋯∗ 𝑁+1
𝑚
TN+2/ TN+1 =
x
(𝑁+1+
1
𝑚
)
lim
𝑁→∞
TN+2/ TN+1 =0 for all finite positive real numbers (x). Hence ƒ(x,m) is a
convergent function for all finite positive real numbers.
Function Upper Bound
By Sreeni C (schopakatla@gmail.com)
Upper Bound
ƒ(x,m) can be expressed as a product of the following two functions
ƒ(x,m)=g*h
Where
g(x,m)=
𝑥
1
𝑚
1
𝑚
h x, m = 1 +
x
1+1
𝑚
+
𝑥2
1+1
𝑚 ∗ 2+1
𝑚
+……..+
𝑥 𝑁
1+1
𝑚 ∗ 2+1
𝑚 ∗⋯∗ 𝑁+1
𝑚
… . ∞
h x, m ≤ 1 +
x
1
+
𝑥2
1∗2
+……..+
𝑥 𝑁
1∗2∗⋯∗𝑁
… . ∞≡ h x, m ≤ 𝑒 𝑥
Hence ƒ(x,m) ≤
𝑥
1
𝑚
1
𝑚
x 𝑒 𝑥≡ ƒ(x,m) ≤ mx1/𝑚 𝑒 𝑥
Function Lower Bound
By Sreeni C (schopakatla@gmail.com)
Lower Bound
h x, m ≥ 1 +
x
2!
+
𝑥2
3!
+……..+
𝑥 𝑁
𝑁+1 !
… . ∞≡ h x, m ≥ (𝑒 𝑥−1)/𝑥
Hence ƒ(x,m)≥
𝑥
1
𝑚
1
𝑚
x((𝑒 𝑥
−1)/𝑥)≡ ƒ(x,m)≥mx1/𝑚
((𝑒 𝑥
−1)/𝑥)
Therefore the function is bounded by the following Upper &
Lower Bounds
mx1/𝑚
𝑒 𝑥
≥ ƒ(x,m) ≥ mx1/𝑚
((𝑒 𝑥
−1)/𝑥)
Solution to a Differential Equation
By Sreeni C (schopakatla@gmail.com)
𝜕ƒ(x, m)/∂x=x(
1
𝑚
−1)
+ ƒ(x, m)
The two variable function ƒ(x, m) is the solution for the non-linear
differential of the type
𝛿𝑦
𝛿𝑥
= x(
1
𝑚
−1)
+y, re-expressed as
XY’ −𝑿𝒀 − 𝑿 𝟏/𝒎=0
Where X is positive real number and m is a natural number
Function Behavior (X>1)
By Sreeni C (schopakatla@gmail.com)
The following plot displays the series progression for a sample value of X=5 & m=5
Corollary#1 (To be Proved)
The infinite series peaks at the N=round (X) term and starts sloping down thereafter
0
2
4
6
8
10
12
14
16
18
20
0 5 10 15 20 25 30
Series Nth Term
Series Progression (Series Nth Term Value vs Nth Term)
X=5
m=5

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Exponential Like Function for Rational Indices

  • 1. EXPONENTIAL LIKE FUNCTION FOR RATIONAL INDICES By Sreeni C, PMP, B.Tech (IITB), MBA29-Aug-2015
  • 2. Function Definition By Sreeni C (schopakatla@gmail.com) Definition: A two variable function f(x,m), where x is a positive real number and m is a natural number f(x,m) is an infinite series, wherein N+1th Term of the Series= 𝑥 𝑁+ 1 𝑚 1 𝑚 ∗ 1+1 𝑚 ∗ 2+1 𝑚 ∗⋯∗ 𝑁+1 𝑚 𝑁=∞ 𝑁=0 ƒ(x,m)= 𝑥 1 𝑚 1 𝑚 + 𝑥 1+ 1 𝑚 1 𝑚 ∗ 1+1 𝑚 + 𝑥 2+ 1 𝑚 1 𝑚 ∗ 1+1 𝑚 ∗ 2+1 𝑚 +……..+ 𝑥 𝑁+ 1 𝑚 1 𝑚 ∗ 1+1 𝑚 ∗ 2+1 𝑚 ∗⋯∗ 𝑁+1 𝑚 … . ∞
  • 3. Function Continuity Test By Sreeni C (schopakatla@gmail.com) ƒ(x,m) can be expressed as a product of the following two functions ƒ(x,m)=g*h Where g(x,m)= 𝑥 1 𝑚 1 𝑚 h x, m = 1 + x 1+1 𝑚 + 𝑥2 1+1 𝑚 ∗ 2+1 𝑚 +……..+ 𝑥 𝑁 1+1 𝑚 ∗ 2+1 𝑚 ∗⋯∗ 𝑁+1 𝑚 … . ∞ For all positive real numbers (x) and natural numbers (m), g is a continuous function; h is a polynomial function and hence is a continuous function for all real numbers Therefore f=g*h is a continuous function for all positive real numbers (x) and natural numbers (m)
  • 4. Function Convergence Test By Sreeni C (schopakatla@gmail.com) N+2th term of the series (TN+2)= 𝑥 1 𝑚 1 𝑚 * 𝑥 𝑁+1 1+1 𝑚 ∗ 2+1 𝑚 ∗⋯∗ 𝑁+1+1 𝑚 N+1th term of the series(TN+1)= 𝑥 1 𝑚 1 𝑚 * 𝑥 𝑁 1+1 𝑚 ∗ 2+1 𝑚 ∗⋯∗ 𝑁+1 𝑚 TN+2/ TN+1 = x (𝑁+1+ 1 𝑚 ) lim 𝑁→∞ TN+2/ TN+1 =0 for all finite positive real numbers (x). Hence ƒ(x,m) is a convergent function for all finite positive real numbers.
  • 5. Function Upper Bound By Sreeni C (schopakatla@gmail.com) Upper Bound ƒ(x,m) can be expressed as a product of the following two functions ƒ(x,m)=g*h Where g(x,m)= 𝑥 1 𝑚 1 𝑚 h x, m = 1 + x 1+1 𝑚 + 𝑥2 1+1 𝑚 ∗ 2+1 𝑚 +……..+ 𝑥 𝑁 1+1 𝑚 ∗ 2+1 𝑚 ∗⋯∗ 𝑁+1 𝑚 … . ∞ h x, m ≤ 1 + x 1 + 𝑥2 1∗2 +……..+ 𝑥 𝑁 1∗2∗⋯∗𝑁 … . ∞≡ h x, m ≤ 𝑒 𝑥 Hence ƒ(x,m) ≤ 𝑥 1 𝑚 1 𝑚 x 𝑒 𝑥≡ ƒ(x,m) ≤ mx1/𝑚 𝑒 𝑥
  • 6. Function Lower Bound By Sreeni C (schopakatla@gmail.com) Lower Bound h x, m ≥ 1 + x 2! + 𝑥2 3! +……..+ 𝑥 𝑁 𝑁+1 ! … . ∞≡ h x, m ≥ (𝑒 𝑥−1)/𝑥 Hence ƒ(x,m)≥ 𝑥 1 𝑚 1 𝑚 x((𝑒 𝑥 −1)/𝑥)≡ ƒ(x,m)≥mx1/𝑚 ((𝑒 𝑥 −1)/𝑥) Therefore the function is bounded by the following Upper & Lower Bounds mx1/𝑚 𝑒 𝑥 ≥ ƒ(x,m) ≥ mx1/𝑚 ((𝑒 𝑥 −1)/𝑥)
  • 7. Solution to a Differential Equation By Sreeni C (schopakatla@gmail.com) 𝜕ƒ(x, m)/∂x=x( 1 𝑚 −1) + ƒ(x, m) The two variable function ƒ(x, m) is the solution for the non-linear differential of the type 𝛿𝑦 𝛿𝑥 = x( 1 𝑚 −1) +y, re-expressed as XY’ −𝑿𝒀 − 𝑿 𝟏/𝒎=0 Where X is positive real number and m is a natural number
  • 8. Function Behavior (X>1) By Sreeni C (schopakatla@gmail.com) The following plot displays the series progression for a sample value of X=5 & m=5 Corollary#1 (To be Proved) The infinite series peaks at the N=round (X) term and starts sloping down thereafter 0 2 4 6 8 10 12 14 16 18 20 0 5 10 15 20 25 30 Series Nth Term Series Progression (Series Nth Term Value vs Nth Term) X=5 m=5