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Block 3
Parallel + Collinear Vectors
What is to be learned?
• How to identify parallel and collinear
vectors
= 2( )
A
B
3
-2( )AB =

C
AB is parallel to CD
 
D
3
-2( )6
-4
3
-2
A (1,5,7) B(3,9,8) C(0,1,5) D(4,9,7)
Prove AB and CD are parallel
AB = b – a
3
9
8
1
5
7
( ) ( )–
2
4
1
( )=
CD = d – c
4
9
7
0
1
5
( ) ( )–
( )=
4
8
2
2
4
1
( )= 2
= 2ABCD = 2AB therefore parallel
A (0,2,3) B(4,7,1) C(3,6,9) D(15,21,3)
Prove AB and CD are parallel
AB = b – a
4
7
1
0
2
3
( ) ( )–
4
5
-2
( )=
CD = d – c
15
21
3
3
6
9
( ) ( )–
( )=
12
15
-6
4
5
-2
( )= 3
= 3ABCD = 3AB therefore parallel
Collinearity
Must have a
common point
• If AB = kCD, then AB and CD are parallel
• If AB = kBC, then A,B and C are collinear
(common point B)
Parallel + Collinear Vectors
A (2,3,5) B(3,6,7) C(6,15,13)
Prove A,B and C are collinear.
AB = b – a
3
6
7
2
3
5
( ) ( )–
1
3
2
( )=
BC = c – b
6
15
13
3
6
7
( ) ( )–
( )=
3
9
6
1
3
2
( )= 3
= 3AB
BC = 3AB, with common point B,
therefore collinear
A (1,5,8) B(3,9,2) C(3,7,10) D(4,9,7)
Prove AB and CD are parallel
AB = b – a
3
9
2
1
5
8
( ) ( )–
2
4
-6
( )=
CD = d – c
4
9
7
3
7
10
( ) ( )–
( )=
1
2
-3
2
4
-6
( )= ½
= ½ ABCD = ½ AB therefore parallel
Key
Question

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Parallel + collinear vectors

  • 1. Block 3 Parallel + Collinear Vectors
  • 2. What is to be learned? • How to identify parallel and collinear vectors
  • 3. = 2( ) A B 3 -2( )AB =  C AB is parallel to CD   D 3 -2( )6 -4 3 -2
  • 4. A (1,5,7) B(3,9,8) C(0,1,5) D(4,9,7) Prove AB and CD are parallel AB = b – a 3 9 8 1 5 7 ( ) ( )– 2 4 1 ( )= CD = d – c 4 9 7 0 1 5 ( ) ( )– ( )= 4 8 2 2 4 1 ( )= 2 = 2ABCD = 2AB therefore parallel
  • 5. A (0,2,3) B(4,7,1) C(3,6,9) D(15,21,3) Prove AB and CD are parallel AB = b – a 4 7 1 0 2 3 ( ) ( )– 4 5 -2 ( )= CD = d – c 15 21 3 3 6 9 ( ) ( )– ( )= 12 15 -6 4 5 -2 ( )= 3 = 3ABCD = 3AB therefore parallel
  • 7. • If AB = kCD, then AB and CD are parallel • If AB = kBC, then A,B and C are collinear (common point B) Parallel + Collinear Vectors
  • 8. A (2,3,5) B(3,6,7) C(6,15,13) Prove A,B and C are collinear. AB = b – a 3 6 7 2 3 5 ( ) ( )– 1 3 2 ( )= BC = c – b 6 15 13 3 6 7 ( ) ( )– ( )= 3 9 6 1 3 2 ( )= 3 = 3AB
  • 9. BC = 3AB, with common point B, therefore collinear
  • 10. A (1,5,8) B(3,9,2) C(3,7,10) D(4,9,7) Prove AB and CD are parallel AB = b – a 3 9 2 1 5 8 ( ) ( )– 2 4 -6 ( )= CD = d – c 4 9 7 3 7 10 ( ) ( )– ( )= 1 2 -3 2 4 -6 ( )= ½ = ½ ABCD = ½ AB therefore parallel Key Question