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FLUID
DYNAMICS
10 Questions and
Answers EXPLAINED
Water Resources
Engineering series
MCQ, MSQ, NAT types
a) Change in the direction of flow
b) Non-uniform distribution of mass
c) Change in total energy
d) Change in mass rate of flow
Notes:
 Momentum can be written as β. ρ. A. vav
2 | 𝛽 =
1
𝐴𝑉2 𝐴
𝑣2 ⅆ𝐴
 β for uniform flow = 1 | turbulent flow = 1.2 | laminar flow = 1.33
 For velocity distribution
𝑣
𝑣𝑚
= 1 −
𝑟
𝑟0
𝑚
→ 𝛽 =
𝑚+2 2 𝑚+1
4 2𝑚+1
 Kinetic energy correction factor, 𝛼 =
1
𝐴𝑉3 𝐴
𝑣3 ⅆ𝐴
 α for ideal flow profile = 1.0 | turbulent flow = 1.03 to 1.06 | laminar
flow = 2 | parallel plate = 1.543
00
01
02
03
04
05
06
07
08
09
10
a) 6.4 m/s
b) 9.0 m/s
c) 12.8 m/s
d) 25.5 m/s
Calculation:
 v = 2gh | h = x
ρm
ρ0
− 1 ∴ 𝑣 = 12.8 𝑚/𝑠
 When ρm < ρo, then h = x 1 −
ρm
ρ0
 Pitot tube: velocity of flow at particular point is reduced to zero (stagnation point), the
pressure there is increased due to conversion of kinetic energy to pressure energy;
increase in the pressure energy at this point is used to find velocity of flow.
 vactual = Cv 2gh | Cv = 0.98 for Pitot tube; 0.99 for Prandtl tube[curved streamlines]
00
01
02
03
04
05
06
07
08
09
10
a)
k
k−1
p1
w1
+
v1
2
2g
+ z1 =
k
k−1
p2
w2
+
v2
2
2g
+ z2 + hL
b)
k
k−1
p1
w1
+
v1
2
2g
+ z1 =
k
k−1
p2
w2
+
v2
2
2g
+ z2
c)
k
k−1
p1
w1
+
v1
2
2g
+ z1 + Hm =
k
k−1
p2
w2
+
v2
2
2g
+ z2
d)
p1
w1
+
v1
2
2g
+ z1 + Hm =
p2
w2
+
v2
2
2g
+ z2 + hL
Notes:
 p ρk = c  compressible flow in adiabatic process
 Bernoulli’s equation for steady incompressible flow:
p1
ρg
+
v1
2
2g
+ z1 =
p2
ρg
+
v2
2
2g
+ z2 + hL
 For unsteady compressible flow,
ⅆ𝑝
𝜌
+
ⅆ𝑉
ⅆ𝑡
ⅆ𝑠 +
𝑉2
2
+ 𝑔𝑧 = 𝑐
 Assumptions: steady, incompressible, inviscid, stream line, no friction, pr. force & gravity
force, uniform velocity
 Newton’s eqn  Fa + Fp + Fv + Ft + Fc + Fσ | Reynold’s eqn  Fa + Fp + Fv + Ft |
 Navier-Stoke’s eqn  Fa + Fp + Fv | Euler eqn  Fa + Fp
00
01
02
03
04
05
06
07
08
09
10
a) 600 N
b) Zero
c) 320 N
d) 450 N
Calculation:
 When there is no flow, the pressure at both sections is same
 Applying momentum equation, p1A1 – p2A2cosθ – Fx = ρQ(V2cosθ – V1)  Fx =
450N
 In x-direction, p1A1cosθ1 – p2A2cosθ2 – Fx = ρQ(V2cosθ1 – V1cosθ2)
 In y-direction, p1A1sinθ1 + p2A2sinθ2 + Fy – w = ρQ(– V2sinθ1 – V1sinθ2)
00
01
02
03
04
05
06
07
08
09
10
a) 17.5 cm
b) 18.5 cm
c) 19.5 cm
d) 20.5 cm
Calculation:
 @section1 |
𝑝1
𝛾
+ 𝑥 + ℎ =
𝑝2
𝛾
+ 0.8 + 𝑥 + 𝑆ℎ [S – relative density of Hg]
 Q = AV = 0.12 m3/s | A1V1 = A2V2  V1 =1.6977 m/s & V2 = 6.79 m/s
 Bernoulli’s eqn @ 1 & 2,
𝑝1
𝛾
+
𝑣1
2
2𝑔
+ 𝑧1 =
𝑝2
𝛾
+
𝑣2
2
2𝑔
+ 𝑧2
 h = 17.5 cm
00
01
02
03
04
05
06
07
08
09
10
a) 70 cm
b) 80 cm
c) 90 cm
d) 50 cm
Calculation:
 h1 = x1
ρm
ρ0
− 1 | x1 = 0.20 m | h1 = 3.2 m of oil
 Q1 = 0.16 cumecs | Q2 = 0.08 cumecs
 h2 = x2 1 −
ρm
ρ0
[here, manometric fluid is air] = 0.9985 x2 m of oil
 Q =
Cd.A.a. 2gh
A2−a2
→ Q ∝ h ∴ x2 = 80 cm of air
 Others: Orifice meter, nozzle meter
00
01
02
03
04
05
06
07
08
09
10
a) Flow decreases in diverging portion and pressure
increases in d/s direction  adverse pressure gradient, if
it is large
b) Flow separation takes place, if it is large
c) Negative pressure is created at the throat which
obstructs the flow
d) None of these
Notes:
 In convergent cone, flow is accelerating which may be allowed to take place rapidly in
smaller length. While in divergent cone, retardation of flow occurs. If that retardation
takes place in smaller length, then flow separation takes place.
 Divergent portion is not used to calculate discharge.
 If c/s area of throat is so much reduced such that pressure falls below vapour pressure,
cavitation occurs.
00
01
02
03
04
05
06
07
08
09
10
a) ½ of the original magnitude when it was full
b) ¼ if the original magnitude when it was full
c) Unchanged
d) zero
Notes:
 Surface will touch the bottom at centre
 Fundamental eqn of vortex flow: ⅆ𝑝 =
𝜌𝑣2
𝑟
ⅆ𝑟 − 𝜌𝑔 ⅆ𝑧
 Free vortex flow: Vr = C | Γ = 2πVr | 𝑧 = 𝑧0 −
1
2
𝑐2
𝑔𝑟2
 Forced cortex flow: V=ωr | 𝑧 − 𝑧0 =
𝜔2𝑟2
2𝑔
|
Vol. of paraboloid = vol. of initial air 
πR2
z
2
= πR2
H
00
01
02
03
04
05
06
07
08
09
10
a)
x
2 yH
b)
2x
yH
c)
x
yH
d)
x
4 yH
Notes:
 Jet distance measurement method
 Coefficient of velocity is defined as the ratio of Actual velocity of jet
at vena-contracta to the theoretical velocity.
 Coefficient of contraction is defined as the ratio of the area of jet at
Vena contracta to the area of orifice (theoretical area)
 Cd = Cv x Cc | function of d/D
00
01
02
03
04
05
06
07
08
09
10
a) 154 lps
b) 145 lps
c) 541 lps
d) 415 lps
Calculation:

p1
ρg
+ z1 −
p2
ρg
+ z2 = ∆h | ∆h = x
Sm
S
− 1 | x = 0.3m
 Q =
Cd.A.a. 2gh
A2−a2
=
Cda2 2g ∆h
1− D2 D1
4
= 154 lps
 ∆z = z2 – z1 = 0.45sin30o = 0.225 m
00
01
02
03
04
05
06
07
08
09
10
Fluid Dynamics

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Fluid Dynamics

  • 1. FLUID DYNAMICS 10 Questions and Answers EXPLAINED Water Resources Engineering series MCQ, MSQ, NAT types
  • 2. a) Change in the direction of flow b) Non-uniform distribution of mass c) Change in total energy d) Change in mass rate of flow Notes:  Momentum can be written as β. ρ. A. vav 2 | 𝛽 = 1 𝐴𝑉2 𝐴 𝑣2 ⅆ𝐴  β for uniform flow = 1 | turbulent flow = 1.2 | laminar flow = 1.33  For velocity distribution 𝑣 𝑣𝑚 = 1 − 𝑟 𝑟0 𝑚 → 𝛽 = 𝑚+2 2 𝑚+1 4 2𝑚+1  Kinetic energy correction factor, 𝛼 = 1 𝐴𝑉3 𝐴 𝑣3 ⅆ𝐴  α for ideal flow profile = 1.0 | turbulent flow = 1.03 to 1.06 | laminar flow = 2 | parallel plate = 1.543 00 01 02 03 04 05 06 07 08 09 10
  • 3. a) 6.4 m/s b) 9.0 m/s c) 12.8 m/s d) 25.5 m/s Calculation:  v = 2gh | h = x ρm ρ0 − 1 ∴ 𝑣 = 12.8 𝑚/𝑠  When ρm < ρo, then h = x 1 − ρm ρ0  Pitot tube: velocity of flow at particular point is reduced to zero (stagnation point), the pressure there is increased due to conversion of kinetic energy to pressure energy; increase in the pressure energy at this point is used to find velocity of flow.  vactual = Cv 2gh | Cv = 0.98 for Pitot tube; 0.99 for Prandtl tube[curved streamlines] 00 01 02 03 04 05 06 07 08 09 10
  • 4. a) k k−1 p1 w1 + v1 2 2g + z1 = k k−1 p2 w2 + v2 2 2g + z2 + hL b) k k−1 p1 w1 + v1 2 2g + z1 = k k−1 p2 w2 + v2 2 2g + z2 c) k k−1 p1 w1 + v1 2 2g + z1 + Hm = k k−1 p2 w2 + v2 2 2g + z2 d) p1 w1 + v1 2 2g + z1 + Hm = p2 w2 + v2 2 2g + z2 + hL Notes:  p ρk = c  compressible flow in adiabatic process  Bernoulli’s equation for steady incompressible flow: p1 ρg + v1 2 2g + z1 = p2 ρg + v2 2 2g + z2 + hL  For unsteady compressible flow, ⅆ𝑝 𝜌 + ⅆ𝑉 ⅆ𝑡 ⅆ𝑠 + 𝑉2 2 + 𝑔𝑧 = 𝑐  Assumptions: steady, incompressible, inviscid, stream line, no friction, pr. force & gravity force, uniform velocity  Newton’s eqn  Fa + Fp + Fv + Ft + Fc + Fσ | Reynold’s eqn  Fa + Fp + Fv + Ft |  Navier-Stoke’s eqn  Fa + Fp + Fv | Euler eqn  Fa + Fp 00 01 02 03 04 05 06 07 08 09 10
  • 5. a) 600 N b) Zero c) 320 N d) 450 N Calculation:  When there is no flow, the pressure at both sections is same  Applying momentum equation, p1A1 – p2A2cosθ – Fx = ρQ(V2cosθ – V1)  Fx = 450N  In x-direction, p1A1cosθ1 – p2A2cosθ2 – Fx = ρQ(V2cosθ1 – V1cosθ2)  In y-direction, p1A1sinθ1 + p2A2sinθ2 + Fy – w = ρQ(– V2sinθ1 – V1sinθ2) 00 01 02 03 04 05 06 07 08 09 10
  • 6. a) 17.5 cm b) 18.5 cm c) 19.5 cm d) 20.5 cm Calculation:  @section1 | 𝑝1 𝛾 + 𝑥 + ℎ = 𝑝2 𝛾 + 0.8 + 𝑥 + 𝑆ℎ [S – relative density of Hg]  Q = AV = 0.12 m3/s | A1V1 = A2V2  V1 =1.6977 m/s & V2 = 6.79 m/s  Bernoulli’s eqn @ 1 & 2, 𝑝1 𝛾 + 𝑣1 2 2𝑔 + 𝑧1 = 𝑝2 𝛾 + 𝑣2 2 2𝑔 + 𝑧2  h = 17.5 cm 00 01 02 03 04 05 06 07 08 09 10
  • 7. a) 70 cm b) 80 cm c) 90 cm d) 50 cm Calculation:  h1 = x1 ρm ρ0 − 1 | x1 = 0.20 m | h1 = 3.2 m of oil  Q1 = 0.16 cumecs | Q2 = 0.08 cumecs  h2 = x2 1 − ρm ρ0 [here, manometric fluid is air] = 0.9985 x2 m of oil  Q = Cd.A.a. 2gh A2−a2 → Q ∝ h ∴ x2 = 80 cm of air  Others: Orifice meter, nozzle meter 00 01 02 03 04 05 06 07 08 09 10
  • 8. a) Flow decreases in diverging portion and pressure increases in d/s direction  adverse pressure gradient, if it is large b) Flow separation takes place, if it is large c) Negative pressure is created at the throat which obstructs the flow d) None of these Notes:  In convergent cone, flow is accelerating which may be allowed to take place rapidly in smaller length. While in divergent cone, retardation of flow occurs. If that retardation takes place in smaller length, then flow separation takes place.  Divergent portion is not used to calculate discharge.  If c/s area of throat is so much reduced such that pressure falls below vapour pressure, cavitation occurs. 00 01 02 03 04 05 06 07 08 09 10
  • 9. a) ½ of the original magnitude when it was full b) ¼ if the original magnitude when it was full c) Unchanged d) zero Notes:  Surface will touch the bottom at centre  Fundamental eqn of vortex flow: ⅆ𝑝 = 𝜌𝑣2 𝑟 ⅆ𝑟 − 𝜌𝑔 ⅆ𝑧  Free vortex flow: Vr = C | Γ = 2πVr | 𝑧 = 𝑧0 − 1 2 𝑐2 𝑔𝑟2  Forced cortex flow: V=ωr | 𝑧 − 𝑧0 = 𝜔2𝑟2 2𝑔 | Vol. of paraboloid = vol. of initial air  πR2 z 2 = πR2 H 00 01 02 03 04 05 06 07 08 09 10
  • 10. a) x 2 yH b) 2x yH c) x yH d) x 4 yH Notes:  Jet distance measurement method  Coefficient of velocity is defined as the ratio of Actual velocity of jet at vena-contracta to the theoretical velocity.  Coefficient of contraction is defined as the ratio of the area of jet at Vena contracta to the area of orifice (theoretical area)  Cd = Cv x Cc | function of d/D 00 01 02 03 04 05 06 07 08 09 10
  • 11. a) 154 lps b) 145 lps c) 541 lps d) 415 lps Calculation:  p1 ρg + z1 − p2 ρg + z2 = ∆h | ∆h = x Sm S − 1 | x = 0.3m  Q = Cd.A.a. 2gh A2−a2 = Cda2 2g ∆h 1− D2 D1 4 = 154 lps  ∆z = z2 – z1 = 0.45sin30o = 0.225 m 00 01 02 03 04 05 06 07 08 09 10