Six stored Hospital Building in Dhaka

1. Welcome to the Presentation
about a Hospital Building
STAMFORD UNIVERSITY BANGLADESH

2. Course Title: Computer Aided Structural Design
Course Code : CEN 416
Department of Civil Engineering
Course Teacher: Soumya Suhreed Das
Senior Lecturer,
Department of Civil Engineering
Stamford University Bangladesh

3. Name Student ID
Kauser Ahmed Himel CEN 062 09 446
Nazmul Hasan Diptu CEN 062 09 450
Hasunat Sayemin CEN 062 09 416
Mohammad Amin Jesan CEN 062 09 482
Md. Tanvir Hasan CEN 062 09 475
Md. Sojib Mostofa CEN 062 09 458
Md. Akramul Haque CEN 062 09 503
Group No: 06

4. Six Storied Hospital Building

5. Material Properties
Yield stress: Fy= 60 ksi,
Concrete compressive strength: F’c= 4 ksi,

6. Grid Data

7. 1. Area = 157 ft x 88 ft
2. Height Above ground level = 66 ft
3. Typical Story Height = 10 ft,
4. Height Below Ground Level = 6 ft,
5. Column Size: C1=16”X16” , C2=12”X16” , C3=12”x12”
6. Column size below ground level: C1= 18”x18”,
C2=14”x18”, C3=14”x14”.
7. Grade Beam Size: GB1=10”X18”
8. Floor Beam: B1=10”X15.5” , B2=10”X15.5”,
B3=10”X15.5”.
9. Wall: 10 inch
10. Floor Slab: 5.5 inch
11. Stair Slab: 7 inch
Section Properties

8. Model

9. Model 3d view

10. Stair case 3D view

11. Lift core (shear wall)
Section- B Section- I

12. Support Assign

13. Slab Section:
Floor slab Stair slab

14. Wall section

15. Grade Beam & Column

16. Column

17. Column

18. Floor Beam

19. Roof Slab

20. Define Load Case

21. Define Mass Source

22. Define Load Case
(For wind load X-Y Direction)

23. Define Load Case
(For Earthquake X-Y direction load)

24. Slab Mashing

26. According to BNBC 2006 Assign Live Load
1. 1st floor = 52 psf
2. 2nd floor= 52 psf
3. 3rf floor = 52 psf
4. 4th floor = 52 psf
5. 5th floor = 40 psf
6. Roof = 40 psf
7. Stair = 100 psf

27. Assign Live load

29. According to BNBC 2006 Assign Floor Finish

32. Assign Frame loads

33. Assign Frame loads

34. Assign Diaphragm

35. Define Load Combination as per
BNBC CODE 2006

36. Define Load Combination as per
BNBC CODE 2006
1. D.L+L.L
2. 1.4 D.L + 1.7 L. L
3. 1.05 D.L + 275 L.L +1.4 EQx
4. 1.05 D.L +1.275 L.L – 1.4 EQx
5. 1.05 D.L +1.275 L.L + 1.4 EQy
6. 1.05 D.L +1.275 L.L - 1.4 EQy
7. 1.05 D.L +1.275 L.L + 1.275 Wx
8. 1.05 D.L +1.275 L.L - 1.275 Wx
9. 1.05 D.L +1.275 L.L + 1.275 Wy
10. 1.05 D.L +1.275 L.L - 1.275 Wy

37. Manual Hand Calculation:
Z= Zone Coefficient = Zone 2= 0.15
I= Importance Coefficient =1
R =Response modification= 8
S= Site coefficient = 1.5
hn = 66 ft
Ct = 0.03ft
T = Cthn3/4 (<0.7) = 0.03*(66')3/4= 0.694671 S
C= 1.25 S/T2/3 (<2.75) = 1.25*1.5/(0.694671^2/3)=
2.390462
Base shear V=ZIC/R
We cannot calculate Volume V
So, V/W =ZIC/R=0.039841029*100
= 3.984102937
Earthquake Load calculation as per BNBC 2006

38. Earthquake Load calculation as per BNBC 2006

39. From Etabs Calculate Base shear
Base Shear: V/W
From Etabs we found, DL=8851.8
FF=2027.05
PW=1217.7
EQx = Eqy = 472.81
W= DL+FF+PW=12096.55
So V/W = 12096.55/472.81 = 0.039086351*100 =3.908635107
Variation = ((3.984102937-3.908635107)/ 3.984102937)*100
= 1.894224% <5% ok
This calculation presents the automatically generated lateral seismic loads for load
pattern EQX & EQY according to UBC 94, as calculated by ETABS.
Earthquake Load calculation as per BNBC 2006

40. Earthquake Load calculation as per BNBC 2006

41. Wind load Base reaction

42. Design Group & Load combination Selection

43. Deform shape

44. Design check

45. Beam & Column Longitudinal Reinforcing
check

46. Beam & Column Longitudinal Reinforcing
check

47. Beam & Column Longitudinal Reinforcing
check

48. Beam & Column Rebar Percentage
check

49. Beam & Column Rebar Percentage
check

50. The Design is ok
Thank You