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Microwave Engineering
and Antennas
Power Gain – Part II
Domine Leenaerts, Professor
Department of Electrical Engineering
Center for Wireless Technologies Eindhoven
Note: In these slide we have used the peak power in the
definition of Pav,s and related power definitions.
In the book and quizzes we will use the time-average
(rms) value with an additional factor ½.
Power Gain – Part II
Objective of this lecture
• Introduce the 4 definitions of power gain
• Provide an example to show the differences
Four definitions of Power Gain
• Available (power) Gain 𝐺𝐺𝑎𝑎𝑎𝑎 =
𝑃𝑃𝑎𝑎𝑎𝑎,𝑜𝑜
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
mismatch conditions at input
• Delivered (power) Gain 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖
mismatch conditions at output
• Maximum (power) Gain 𝐺𝐺𝑚𝑚𝑚𝑚𝑚𝑚 =
𝑃𝑃𝑎𝑎𝑎𝑎,𝑜𝑜
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖
optimal power transfer
• Transducer (power) Gain 𝐺𝐺𝑇𝑇 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
mismatch at input and output
Z
V
Z
Z
V
Z
o
s
o
s
i l
V
l
V
i
system S
source load
input impedance
output impedance
Available and Delivered (Power) Gain
Z
V
Z
Z
V
Z
o
s
o
s
i l
V
l
V
i
system S
source load
input impedance
output impedance
𝐺𝐺𝑎𝑎𝑎𝑎 =
𝑃𝑃𝑎𝑎𝑎𝑎,𝑜𝑜
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
=
𝑅𝑅𝑖𝑖
𝑅𝑅𝑖𝑖 + 𝑅𝑅𝑠𝑠
2
𝐴𝐴𝑣𝑣
2
𝑅𝑅𝑠𝑠
𝑅𝑅𝑜𝑜
𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖
= 𝐴𝐴𝑣𝑣
2 𝑅𝑅𝑖𝑖𝑅𝑅𝑙𝑙
𝑅𝑅𝑙𝑙 + 𝑅𝑅𝑜𝑜
2
𝐴𝐴𝑣𝑣 =
𝑉𝑉
𝑜𝑜
𝑉𝑉𝑖𝑖
=
𝑉𝑉𝑙𝑙
𝑉𝑉
𝑠𝑠
Zo=0 Ω; Zi = ∞ Ω:
Maximum and Transducer (Power) Gain
Z
V
Z
Z
V
Z
o
s
o
s
i l
V
l
V
i
system S
source load
input impedance
output impedance
𝐴𝐴𝑣𝑣 =
𝑉𝑉
𝑜𝑜
𝑉𝑉𝑖𝑖
=
𝑉𝑉𝑙𝑙
𝑉𝑉
𝑠𝑠
𝐺𝐺𝑚𝑚𝑚𝑚𝑚𝑚 =
𝑃𝑃𝑎𝑎𝑎𝑎,𝑜𝑜
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖
= 𝐴𝐴𝑣𝑣
2 𝑅𝑅𝑖𝑖
4𝑅𝑅𝑜𝑜
𝐺𝐺𝑇𝑇 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
=
𝑅𝑅𝑖𝑖
𝑅𝑅𝑖𝑖 + 𝑅𝑅𝑠𝑠
2
𝐴𝐴𝑣𝑣
2 4𝑅𝑅𝑙𝑙𝑅𝑅𝑠𝑠
𝑅𝑅𝑙𝑙 + 𝑅𝑅𝑜𝑜
2
𝐺𝐺𝑇𝑇
𝑅𝑅𝑙𝑙=𝑅𝑅𝑜𝑜
𝐺𝐺𝑎𝑎𝑎𝑎
𝐺𝐺𝑇𝑇
𝑅𝑅𝑖𝑖=𝑅𝑅𝑠𝑠
𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑
𝐺𝐺𝑇𝑇
𝑅𝑅𝑙𝑙=𝑅𝑅𝑜𝑜, 𝑅𝑅𝑠𝑠=𝑅𝑅𝑖𝑖
𝐺𝐺𝑚𝑚𝑚𝑚𝑚𝑚
Power Gain and scatter parameters: reflection
𝛤𝛤
𝑖𝑖𝑖𝑖 =
𝑏𝑏1
𝑎𝑎1
= 𝑆𝑆11 +
𝑆𝑆12𝑆𝑆21
1
𝛤𝛤
𝐿𝐿
− 𝑆𝑆22
𝑏𝑏1
𝑏𝑏2
=
𝑠𝑠11 𝑠𝑠12
𝑠𝑠21 𝑠𝑠22
𝑎𝑎1
𝑎𝑎2
𝛤𝛤
𝑜𝑜𝑜𝑜𝑜𝑜 =
𝑏𝑏2
𝑎𝑎2
= 𝑆𝑆22 +
𝑆𝑆12𝑆𝑆21
1
𝛤𝛤
𝑆𝑆
− 𝑆𝑆11
System S
Available, and delivered Power Gain
𝐺𝐺𝑎𝑎𝑎𝑎 𝛤𝛤
𝑆𝑆, 𝑆𝑆 =
𝑃𝑃𝑎𝑎𝑎𝑎,𝑙𝑙
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
=
1 − 𝛤𝛤
𝑆𝑆
2
1 − 𝑆𝑆11𝛤𝛤
𝑆𝑆
2
𝑆𝑆21
2
1
1 − 𝛤𝛤
𝑜𝑜𝑢𝑢𝑢𝑢
2
𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 𝛤𝛤
𝐿𝐿, 𝑆𝑆 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑠𝑠
=
1 − 𝛤𝛤
𝐿𝐿
2
1 − 𝑆𝑆22𝛤𝛤
𝐿𝐿
2
𝑆𝑆21
2
1
1 − 𝛤𝛤
𝑖𝑖𝑖𝑖
2
𝐺𝐺𝑎𝑎𝑎𝑎 𝛤𝛤
𝑆𝑆, 𝑆𝑆 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 𝛤𝛤
𝐿𝐿, 𝑆𝑆
Relation between all power gains
𝑀𝑀𝑆𝑆 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖𝑖𝑖
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
=
1 − Γ𝑖𝑖𝑖𝑖
2
1 − Γ𝑆𝑆
2
1 − Γ𝑖𝑖𝑖𝑖Γ𝑆𝑆
2
𝑀𝑀𝐿𝐿 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑎𝑎𝑎𝑎,𝑙𝑙
=
1 − Γ𝑂𝑂𝑂𝑂𝑂𝑂
2
1 − Γ𝐿𝐿
2
1 − Γ𝑜𝑜𝑢𝑢𝑢𝑢Γ𝐿𝐿
2
𝐺𝐺𝑇𝑇 Γ𝑆𝑆, Γ𝐿𝐿, 𝑆𝑆 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
=
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑠𝑠
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑠𝑠
= 𝑀𝑀𝑆𝑆𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 Γ𝐿𝐿, 𝑆𝑆
𝐺𝐺𝑇𝑇 Γ𝑆𝑆, Γ𝐿𝐿, 𝑆𝑆 ≤ 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 Γ𝐿𝐿, 𝑆𝑆
𝐺𝐺𝑇𝑇 Γ𝑆𝑆, Γ𝐿𝐿, 𝑆𝑆 =
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
=
𝑃𝑃𝑎𝑎𝑎𝑎,𝑙𝑙
𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙
𝑃𝑃𝑎𝑎𝑎𝑎,𝑙𝑙
= 𝐺𝐺𝑎𝑎𝑎𝑎 Γ𝑆𝑆, 𝑆𝑆 𝑀𝑀𝐿𝐿
𝐺𝐺𝑇𝑇 Γ𝑆𝑆, Γ𝐿𝐿, 𝑆𝑆 ≤ 𝐺𝐺𝑎𝑎𝑎𝑎 Γ𝑆𝑆, 𝑆𝑆
𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑
𝐺𝐺𝑎𝑎𝑎𝑎
𝐺𝐺𝑇𝑇
Example: an RF amplifier
𝑠𝑠11 = 0.61, 165𝑜𝑜
𝑠𝑠12 = 0.05, 42𝑜𝑜
𝑠𝑠21 = 3.72, 59𝑜𝑜
𝑠𝑠22 = 0.45, −48𝑜𝑜
𝑍𝑍0 = 50Ω
𝑍𝑍𝑠𝑠 = 40Ω
𝑉𝑉
𝑠𝑠 = 5 ∗ sin(𝜔𝜔𝜔𝜔) 𝑍𝑍𝐿𝐿 = 73Ω
Example: an RF amplifier
Γ =
𝑍𝑍 − 𝑍𝑍0
𝑍𝑍 + 𝑍𝑍0
, 𝑡𝑡𝑡𝑡𝑡𝑡𝑡 Γ𝑠𝑠 = −0.111, Γ𝐿𝐿 = 0.187
𝛤𝛤
𝑖𝑖𝑖𝑖 = 𝑆𝑆11 +
𝑆𝑆12𝑆𝑆21
1
𝛤𝛤
𝐿𝐿
− 𝑆𝑆22
= −0.594 + 𝑗𝑗𝑗.194 𝛤𝛤
𝑜𝑜𝑜𝑜𝑜𝑜 = 𝑆𝑆22 +
𝑆𝑆12𝑆𝑆21
1
𝛤𝛤
𝑠𝑠
− 𝑆𝑆11
= 0.305 − 𝑗𝑗𝑗.356
𝑍𝑍𝑖𝑖𝑖𝑖 = 11 + 𝑗𝑗𝑗.54 [Ω] 𝑍𝑍𝑜𝑜𝑜𝑜𝑜𝑜 = 63 − 𝑗𝑗𝑗𝑗. 4[Ω]
𝛤𝛤
𝑖𝑖𝑖𝑖 𝛤𝛤
𝑜𝑜𝑜𝑜𝑜𝑜
𝑍𝑍𝑠𝑠 = 40Ω
𝑉𝑉
𝑠𝑠 = 5 ∗ sin(𝜔𝜔𝜔𝜔) 𝑍𝑍𝐿𝐿 = 73Ω
Example: an RF amplifier
𝐺𝐺𝑎𝑎𝑎𝑎 𝛤𝛤
𝑆𝑆, 𝑆𝑆 =
1 − 𝛤𝛤
𝑆𝑆
2
1 − 𝑆𝑆11𝛤𝛤
𝑠𝑠
2
𝑆𝑆21
2
1
1 − 𝛤𝛤
𝑜𝑜𝑢𝑢𝑢𝑢
2
= 20.05 𝑜𝑜𝑜𝑜 13.02𝑑𝑑𝑑𝑑
𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 𝛤𝛤
𝐿𝐿, 𝑆𝑆 =
1 − 𝛤𝛤
𝐿𝐿
2
1 − 𝑆𝑆22𝛤𝛤
𝐿𝐿
2
𝑆𝑆21
2
1
1 − 𝛤𝛤
𝑖𝑖𝑖𝑖
2
= 24.49 𝑜𝑜𝑜𝑜 13.89𝑑𝑑𝑑𝑑
𝐺𝐺𝑇𝑇 𝛤𝛤
𝑆𝑆, 𝛤𝛤
𝐿𝐿, 𝑆𝑆 =
1 − 𝛤𝛤
𝐿𝐿
2
1 − 𝑆𝑆22𝛤𝛤
𝐿𝐿
2
𝑆𝑆21
2
1 − 𝛤𝛤
𝑆𝑆
2
1 − 𝛤𝛤
𝑖𝑖𝑖𝑖𝛤𝛤
𝑠𝑠
2
= 16.89 𝑜𝑜𝑜𝑜 12.27𝑑𝑑𝑑𝑑
𝑍𝑍𝑠𝑠 = 40Ω
𝑉𝑉
𝑠𝑠 = 5 ∗ sin(𝜔𝜔𝜔𝜔) 𝑍𝑍𝐿𝐿 = 73Ω
𝐺𝐺𝑚𝑚𝑚𝑚𝑚𝑚 𝑆𝑆 = 41.5 𝑜𝑜𝑜𝑜 16.18𝑑𝑑𝑑𝑑
Example: an RF amplifier
• The available power Pav =
𝑉𝑉𝑠𝑠
2
4𝑅𝑅𝑠𝑠
= 156 mW or Pav = 21.93 dBm.
• The power delivered to the load is the available power multiplied by
the transducer gain. This results in Pdel = PavGT = 2.63W or expressed
in dBm,
𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑 𝑑𝑑𝑑𝑑𝑑𝑑 = 𝐺𝐺𝑇𝑇 𝛤𝛤
𝑆𝑆, 𝛤𝛤
𝐿𝐿, 𝑆𝑆 𝑃𝑃𝑎𝑎𝑎𝑎 𝑑𝑑𝑑𝑑𝑑𝑑 = 21.93 + 12.27 = 34.2𝑑𝑑𝑑𝑑𝑑𝑑
𝑍𝑍𝑠𝑠 = 40Ω
𝑉𝑉
𝑠𝑠 = 5 ∗ sin(𝜔𝜔𝜔𝜔) 𝑍𝑍𝐿𝐿 = 73Ω
Note: The time average Pav = 78 mW or
18.93 dBm. Time average Pdel = 31.2 dBm
Summary
• 4 definitions of power gain, depending on the impedance matching
conditions.
• Matching networks at between source and input (Ms) and output and
load (ML) influences the power transfer from source to load
• Transducer (power) gain is equal to or smaller than the available
(power) gain or delivered (power) gain

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  • 1. Microwave Engineering and Antennas Power Gain – Part II Domine Leenaerts, Professor Department of Electrical Engineering Center for Wireless Technologies Eindhoven Note: In these slide we have used the peak power in the definition of Pav,s and related power definitions. In the book and quizzes we will use the time-average (rms) value with an additional factor ½.
  • 2. Power Gain – Part II Objective of this lecture • Introduce the 4 definitions of power gain • Provide an example to show the differences
  • 3. Four definitions of Power Gain • Available (power) Gain 𝐺𝐺𝑎𝑎𝑎𝑎 = 𝑃𝑃𝑎𝑎𝑎𝑎,𝑜𝑜 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 mismatch conditions at input • Delivered (power) Gain 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖 mismatch conditions at output • Maximum (power) Gain 𝐺𝐺𝑚𝑚𝑚𝑚𝑚𝑚 = 𝑃𝑃𝑎𝑎𝑎𝑎,𝑜𝑜 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖 optimal power transfer • Transducer (power) Gain 𝐺𝐺𝑇𝑇 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 mismatch at input and output Z V Z Z V Z o s o s i l V l V i system S source load input impedance output impedance
  • 4. Available and Delivered (Power) Gain Z V Z Z V Z o s o s i l V l V i system S source load input impedance output impedance 𝐺𝐺𝑎𝑎𝑎𝑎 = 𝑃𝑃𝑎𝑎𝑎𝑎,𝑜𝑜 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 = 𝑅𝑅𝑖𝑖 𝑅𝑅𝑖𝑖 + 𝑅𝑅𝑠𝑠 2 𝐴𝐴𝑣𝑣 2 𝑅𝑅𝑠𝑠 𝑅𝑅𝑜𝑜 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖 = 𝐴𝐴𝑣𝑣 2 𝑅𝑅𝑖𝑖𝑅𝑅𝑙𝑙 𝑅𝑅𝑙𝑙 + 𝑅𝑅𝑜𝑜 2 𝐴𝐴𝑣𝑣 = 𝑉𝑉 𝑜𝑜 𝑉𝑉𝑖𝑖 = 𝑉𝑉𝑙𝑙 𝑉𝑉 𝑠𝑠 Zo=0 Ω; Zi = ∞ Ω:
  • 5. Maximum and Transducer (Power) Gain Z V Z Z V Z o s o s i l V l V i system S source load input impedance output impedance 𝐴𝐴𝑣𝑣 = 𝑉𝑉 𝑜𝑜 𝑉𝑉𝑖𝑖 = 𝑉𝑉𝑙𝑙 𝑉𝑉 𝑠𝑠 𝐺𝐺𝑚𝑚𝑚𝑚𝑚𝑚 = 𝑃𝑃𝑎𝑎𝑎𝑎,𝑜𝑜 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖 = 𝐴𝐴𝑣𝑣 2 𝑅𝑅𝑖𝑖 4𝑅𝑅𝑜𝑜 𝐺𝐺𝑇𝑇 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 = 𝑅𝑅𝑖𝑖 𝑅𝑅𝑖𝑖 + 𝑅𝑅𝑠𝑠 2 𝐴𝐴𝑣𝑣 2 4𝑅𝑅𝑙𝑙𝑅𝑅𝑠𝑠 𝑅𝑅𝑙𝑙 + 𝑅𝑅𝑜𝑜 2 𝐺𝐺𝑇𝑇 𝑅𝑅𝑙𝑙=𝑅𝑅𝑜𝑜 𝐺𝐺𝑎𝑎𝑎𝑎 𝐺𝐺𝑇𝑇 𝑅𝑅𝑖𝑖=𝑅𝑅𝑠𝑠 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 𝐺𝐺𝑇𝑇 𝑅𝑅𝑙𝑙=𝑅𝑅𝑜𝑜, 𝑅𝑅𝑠𝑠=𝑅𝑅𝑖𝑖 𝐺𝐺𝑚𝑚𝑚𝑚𝑚𝑚
  • 6. Power Gain and scatter parameters: reflection 𝛤𝛤 𝑖𝑖𝑖𝑖 = 𝑏𝑏1 𝑎𝑎1 = 𝑆𝑆11 + 𝑆𝑆12𝑆𝑆21 1 𝛤𝛤 𝐿𝐿 − 𝑆𝑆22 𝑏𝑏1 𝑏𝑏2 = 𝑠𝑠11 𝑠𝑠12 𝑠𝑠21 𝑠𝑠22 𝑎𝑎1 𝑎𝑎2 𝛤𝛤 𝑜𝑜𝑜𝑜𝑜𝑜 = 𝑏𝑏2 𝑎𝑎2 = 𝑆𝑆22 + 𝑆𝑆12𝑆𝑆21 1 𝛤𝛤 𝑆𝑆 − 𝑆𝑆11 System S
  • 7. Available, and delivered Power Gain 𝐺𝐺𝑎𝑎𝑎𝑎 𝛤𝛤 𝑆𝑆, 𝑆𝑆 = 𝑃𝑃𝑎𝑎𝑎𝑎,𝑙𝑙 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 = 1 − 𝛤𝛤 𝑆𝑆 2 1 − 𝑆𝑆11𝛤𝛤 𝑆𝑆 2 𝑆𝑆21 2 1 1 − 𝛤𝛤 𝑜𝑜𝑢𝑢𝑢𝑢 2 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 𝛤𝛤 𝐿𝐿, 𝑆𝑆 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑠𝑠 = 1 − 𝛤𝛤 𝐿𝐿 2 1 − 𝑆𝑆22𝛤𝛤 𝐿𝐿 2 𝑆𝑆21 2 1 1 − 𝛤𝛤 𝑖𝑖𝑖𝑖 2 𝐺𝐺𝑎𝑎𝑎𝑎 𝛤𝛤 𝑆𝑆, 𝑆𝑆 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 𝛤𝛤 𝐿𝐿, 𝑆𝑆
  • 8. Relation between all power gains 𝑀𝑀𝑆𝑆 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑖𝑖𝑖𝑖 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 = 1 − Γ𝑖𝑖𝑖𝑖 2 1 − Γ𝑆𝑆 2 1 − Γ𝑖𝑖𝑖𝑖Γ𝑆𝑆 2 𝑀𝑀𝐿𝐿 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑎𝑎𝑎𝑎,𝑙𝑙 = 1 − Γ𝑂𝑂𝑂𝑂𝑂𝑂 2 1 − Γ𝐿𝐿 2 1 − Γ𝑜𝑜𝑢𝑢𝑢𝑢Γ𝐿𝐿 2 𝐺𝐺𝑇𝑇 Γ𝑆𝑆, Γ𝐿𝐿, 𝑆𝑆 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑠𝑠 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑠𝑠 = 𝑀𝑀𝑆𝑆𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 Γ𝐿𝐿, 𝑆𝑆 𝐺𝐺𝑇𝑇 Γ𝑆𝑆, Γ𝐿𝐿, 𝑆𝑆 ≤ 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 Γ𝐿𝐿, 𝑆𝑆 𝐺𝐺𝑇𝑇 Γ𝑆𝑆, Γ𝐿𝐿, 𝑆𝑆 = 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 = 𝑃𝑃𝑎𝑎𝑎𝑎,𝑙𝑙 𝑃𝑃𝑎𝑎𝑎𝑎,𝑠𝑠 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑,𝑙𝑙 𝑃𝑃𝑎𝑎𝑎𝑎,𝑙𝑙 = 𝐺𝐺𝑎𝑎𝑎𝑎 Γ𝑆𝑆, 𝑆𝑆 𝑀𝑀𝐿𝐿 𝐺𝐺𝑇𝑇 Γ𝑆𝑆, Γ𝐿𝐿, 𝑆𝑆 ≤ 𝐺𝐺𝑎𝑎𝑎𝑎 Γ𝑆𝑆, 𝑆𝑆 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 𝐺𝐺𝑎𝑎𝑎𝑎 𝐺𝐺𝑇𝑇
  • 9. Example: an RF amplifier 𝑠𝑠11 = 0.61, 165𝑜𝑜 𝑠𝑠12 = 0.05, 42𝑜𝑜 𝑠𝑠21 = 3.72, 59𝑜𝑜 𝑠𝑠22 = 0.45, −48𝑜𝑜 𝑍𝑍0 = 50Ω 𝑍𝑍𝑠𝑠 = 40Ω 𝑉𝑉 𝑠𝑠 = 5 ∗ sin(𝜔𝜔𝜔𝜔) 𝑍𝑍𝐿𝐿 = 73Ω
  • 10. Example: an RF amplifier Γ = 𝑍𝑍 − 𝑍𝑍0 𝑍𝑍 + 𝑍𝑍0 , 𝑡𝑡𝑡𝑡𝑡𝑡𝑡 Γ𝑠𝑠 = −0.111, Γ𝐿𝐿 = 0.187 𝛤𝛤 𝑖𝑖𝑖𝑖 = 𝑆𝑆11 + 𝑆𝑆12𝑆𝑆21 1 𝛤𝛤 𝐿𝐿 − 𝑆𝑆22 = −0.594 + 𝑗𝑗𝑗.194 𝛤𝛤 𝑜𝑜𝑜𝑜𝑜𝑜 = 𝑆𝑆22 + 𝑆𝑆12𝑆𝑆21 1 𝛤𝛤 𝑠𝑠 − 𝑆𝑆11 = 0.305 − 𝑗𝑗𝑗.356 𝑍𝑍𝑖𝑖𝑖𝑖 = 11 + 𝑗𝑗𝑗.54 [Ω] 𝑍𝑍𝑜𝑜𝑜𝑜𝑜𝑜 = 63 − 𝑗𝑗𝑗𝑗. 4[Ω] 𝛤𝛤 𝑖𝑖𝑖𝑖 𝛤𝛤 𝑜𝑜𝑜𝑜𝑜𝑜 𝑍𝑍𝑠𝑠 = 40Ω 𝑉𝑉 𝑠𝑠 = 5 ∗ sin(𝜔𝜔𝜔𝜔) 𝑍𝑍𝐿𝐿 = 73Ω
  • 11. Example: an RF amplifier 𝐺𝐺𝑎𝑎𝑎𝑎 𝛤𝛤 𝑆𝑆, 𝑆𝑆 = 1 − 𝛤𝛤 𝑆𝑆 2 1 − 𝑆𝑆11𝛤𝛤 𝑠𝑠 2 𝑆𝑆21 2 1 1 − 𝛤𝛤 𝑜𝑜𝑢𝑢𝑢𝑢 2 = 20.05 𝑜𝑜𝑜𝑜 13.02𝑑𝑑𝑑𝑑 𝐺𝐺𝑑𝑑𝑑𝑑𝑑𝑑 𝛤𝛤 𝐿𝐿, 𝑆𝑆 = 1 − 𝛤𝛤 𝐿𝐿 2 1 − 𝑆𝑆22𝛤𝛤 𝐿𝐿 2 𝑆𝑆21 2 1 1 − 𝛤𝛤 𝑖𝑖𝑖𝑖 2 = 24.49 𝑜𝑜𝑜𝑜 13.89𝑑𝑑𝑑𝑑 𝐺𝐺𝑇𝑇 𝛤𝛤 𝑆𝑆, 𝛤𝛤 𝐿𝐿, 𝑆𝑆 = 1 − 𝛤𝛤 𝐿𝐿 2 1 − 𝑆𝑆22𝛤𝛤 𝐿𝐿 2 𝑆𝑆21 2 1 − 𝛤𝛤 𝑆𝑆 2 1 − 𝛤𝛤 𝑖𝑖𝑖𝑖𝛤𝛤 𝑠𝑠 2 = 16.89 𝑜𝑜𝑜𝑜 12.27𝑑𝑑𝑑𝑑 𝑍𝑍𝑠𝑠 = 40Ω 𝑉𝑉 𝑠𝑠 = 5 ∗ sin(𝜔𝜔𝜔𝜔) 𝑍𝑍𝐿𝐿 = 73Ω 𝐺𝐺𝑚𝑚𝑚𝑚𝑚𝑚 𝑆𝑆 = 41.5 𝑜𝑜𝑜𝑜 16.18𝑑𝑑𝑑𝑑
  • 12. Example: an RF amplifier • The available power Pav = 𝑉𝑉𝑠𝑠 2 4𝑅𝑅𝑠𝑠 = 156 mW or Pav = 21.93 dBm. • The power delivered to the load is the available power multiplied by the transducer gain. This results in Pdel = PavGT = 2.63W or expressed in dBm, 𝑃𝑃𝑑𝑑𝑑𝑑𝑑𝑑 𝑑𝑑𝑑𝑑𝑑𝑑 = 𝐺𝐺𝑇𝑇 𝛤𝛤 𝑆𝑆, 𝛤𝛤 𝐿𝐿, 𝑆𝑆 𝑃𝑃𝑎𝑎𝑎𝑎 𝑑𝑑𝑑𝑑𝑑𝑑 = 21.93 + 12.27 = 34.2𝑑𝑑𝑑𝑑𝑑𝑑 𝑍𝑍𝑠𝑠 = 40Ω 𝑉𝑉 𝑠𝑠 = 5 ∗ sin(𝜔𝜔𝜔𝜔) 𝑍𝑍𝐿𝐿 = 73Ω Note: The time average Pav = 78 mW or 18.93 dBm. Time average Pdel = 31.2 dBm
  • 13. Summary • 4 definitions of power gain, depending on the impedance matching conditions. • Matching networks at between source and input (Ms) and output and load (ML) influences the power transfer from source to load • Transducer (power) gain is equal to or smaller than the available (power) gain or delivered (power) gain