This document contains the slides from a presentation on various C programming concepts and examples including: - A program to calculate shear force and bending moment in a cantilever beam at different distances from the fixed end. - Programs to calculate total head of flow through a pipe, add two matrices, and print a multiplication table. - Examples of using decision making (if/else statements) to determine if a number is even or odd, and using operators to convert days to months. The presentation provides explanations and step-by-step workings for each programming problem and example.

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CE 2202
NUMERICAL METHODS AND
COMPUTER PROGRAMMING
SESSIONAL
5TH FEBRUARY 2019
A PRESENTATION ON

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FAISAL FARUQUE RAFAT
ROLL NO. 1600079
RAJSHAHI UNIVERSITY OF ENGINEERING AND TECHNOLOGY
DEPT. OF CIVIL ENGINEERING
PRESENTED BY
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W
L
P
A cantilever beam is shown in the upper figure.
Write a C program to compute shear and moment
of the beam at every L/N distance from the free
end.
Here,
Length of the beam, L = 79+10= 89 feet
Concentrated Load, P = 79+13= 82 lbs
Uniformly Distributed Load, W = 13 lbs/feet
N = 100+79= 179
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Shear = Sum of all transverse load
Moment = Load x Distance
For this problem,
Shear = p+i*w
Moment = -p*i-i*w*(i/2)
Here,
i = Sectional distance from right side of the beam

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0
200
400
600
800
1000
1200
1400
0 10 20 30 40 50 60 70 80 90 100
SFD
SHEAR FORCE DIAGRAM

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BENDING MOMENT DIAGRAM
-70000
-60000
-50000
-40000
-30000
-20000
-10000
0
0 10 20 30 40 50 60 70 80 90 100
BMD

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W
L
A cantilever beam is shown in the upper figure.
Write a C program to compute shear and moment
of the beam at every L/N distance from the free
end.
Here,
Length of the beam, L = 79+10= 89 feet
Uniformly Distributed Load, W = 13 lbs/feet
N = 100+79= 179

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Shear = Sum of all transverse load
Moment = Load x Distance
For this problem,
Shear = r-i*w
Moment = r*i-i*w*(i/2)
Reaction from right side, R = (w*l)/2
Here,
i = Sectional distance from right side of the beam

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SHEAR FORCE DIAGRAM
-800
-600
-400
-200
0
200
400
600
800
0 10 20 30 40 50 60 70 80 90 100
SFD

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BENDING MOMENT DIAGRAM
0
2000
4000
6000
8000
10000
12000
14000
0 10 20 30 40 50 60 70 80 90 100
BMD

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Write a C program to find the total
head of a flow through pipe.
Here,
Value of pressure, p = 40
Value of velocity, v = 3
Value of datum head, z = 6

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The equation use for this
problem in program is:
Total head,
H = (p/a)+((v*v)/(2*g))+z

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Following matrices are used for the
program.
Write a C program to read to two
matrices A and B and print A+B.
1 2 3
4 5 6
7 8 9
9 8 7
6 5 4
3 2 1
10 10 10
10 10 10
10 10 10
A = B =
A+B=C =

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i loop j loop Elements a[i][j]
i = 0 j = 0 a[0][0]
i = 0 j = 1 a[0][1]
i = 0 j = 2 a[0][2]
i = 1 j = 0 a[1][0]
i = 1 j = 1 a[1][1]
i = 1 j = 2 a[1][2]
i = 2 j = 0 a[2][0]
i = 2 j = 1 a[2][1]
i = 2 j = 2 a[2][2]
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C matrix
00+00 01+01 02+02
10+10 11+11 12+12
20+20 21+21 22+22
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A matrix B matrix
00 01 02 00 01 02
10 11 12 10 11 12
20 21 22 20 21 22
For the addition of that matrices we need the
concept of two-dimensional array in C program.

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DECISION MAKING AND LOOPING:
Write a C program to print the
following multiplication table.
2 x 1 2
2 x 2 4
2 x 3 6
2 x 4 8
2 x 5 10
2 x 6 12
2 x 7 14
2 x 8 16
2 x 9 18
2 x 10 20

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• To print this multiplication table, a single
for loop would be adequate.
• Initially value of the variable n should be
taken 2, as we are printing the
multiplication table of 2.
• The statement for loop will be like this,
for(i=0;i<=10;i++)
• Initially the value of i will be taken 1 and
It will execute the loop as long as the
value becomes equal to 10.

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DECISION MAKING AND BRANCING:
Write a C program to determine
whether the following number is even
or odd.
23
We can take the following number as
an example:

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The number is even, If and only
if we can divide the given
number by 2 keeping the
reamainder 0. Otherwise, the
number is definitely odd.

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if-else statement will be used for
executing this program.
If the input is assigned to variable n, the
statements will be like this,
If(n%2==0)
{
printf(“Even”);
}
else
{
printf(“Odd”);
}

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OPERATORS AND EXPRESSIONS:
Write a C program to convert days
into months.
1 Month = 30 Days
on average

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So, if we divide the desired value by
30, the integer part will be the
number of months. Again, the
remainder will be the remaining days
which don’t make up a total month.
455/30=15 (Integer)
455%30=5
15 Months 5 Days

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T H A N K S
F O R Y O U R P A T I E N C E