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Mechanics of Solids-II (CE-301)
Dr. Aslam Faqeer Mohammad
Academic Calendar 2015
FALL SEMESTER / TERM
Classes Start
27th July, 2015,
Classes End
13th November, 2015
Examinations Start
16th November, 2015
Examinations End 5th December, 2015+
Announcement of Results Latest by 24th December, 2015
Winter Vacations
7th to 27th December, 2015
2
Time Table for Section-A
3
Time Table for Section-B
4
Time Table for Section-C
5
Mechanics of Solids
Mechanics of Solids-I
Mechanics of Solids-II
Advance Mechanics of Solids
6
CE-301-Mechanics of Solids-II
Tentative Course Outlines
1. INTRODUCTION (Basic Concepts and Terminologies)
I. Overview
II. Types of stresses
III. Determinate/Indeterminate Structures
2. ANALYSIS OF STRESSES AND STRAINS DUE TO
I. Axial/Bending/Twisting and Shear Forces
II. Combine effect of axial, bending and twisting forces
3. STRUTS AND COLUMNS
I. Euler, Rankine and other formulae for buckling loads
II. Stability analysis of column under eccentric loading
4. ELEMENTARY THEORY OF ELASTICITY
I. Equilibrium and compatibility equations
II. Biaxial Stresses
III. Stress and deformation relationship
IV. Stress transformation
5. THEORIES OF FAILURES
I. Tresca’s Yield Criterion
II. W.Rankine’s Criterion
III. Von Mises Yield Criterion
6. COMPUTER BASED ANALYSIS 7
Grading
• Homework/class assignments
• E-Tests
• Midterm (9th week)
• Final Exam
8
Text/Ref Books
Course Learning Outcomes (CLO’s)
1. To get an exposure of biaxial bending and its application
2. To understand the problem of stability of column and
design of steel column
3. To get the knowledge of different types of failure
theories and its applications in mechanics of solids
9
Terminologies
10
Stress: Stress is the intensity of the internal force on a specific plane passing through
a point. Mathematically, stress can be expressed as
Types of Stresses
11
12
Types of Strains
Terminologies
13
Normal Stress: The intensity of the force or force per unit area acting normally to
section A is called Normal Stress, σ (sigma), and it is expressed as:
If this stress “pulls” on the area it is referred as Tensile Stress and defined as Positive.
If it “pushes” on the area it is called Compressive Stress and defined as Negative.
Terminologies
14
Shear Stress: The intensity or force per unit area acting tangentially to A is called
Shear Stress, τ (tau), and it is expressed as:
Deformation: Whenever a force is applied to a body, its shape and size will change.
These changes are referred as deformations. These deformations can be thought of
being either positive (elongation) or negative (contraction) in sign as shown in Fig.
Strain: The elongation (+ve) or contraction (−ve) of a body per unit length is termed
Strain.
Terminologies
15
THERMAL STRAIN
When the temperature of a body is changed, its overall size will also change. In
other words, temperature change may cause the dimension or shape change in the
material. More specially, if the temperature increases, generally a material
expands. Whereas if the temperature decreases, the material will contract.
16
Terminologies
Ductile Vs Brittle
17
Notice that for the ductile material, show on the left, larger strains occur before
ultimate failure. In reality this means that (a) the material has a chance to change
its shape in order to redistribute loads, and ( b) if redistributing the loads does not
prevent failure, there is often adequate visual warning (sagging beams, etc.) before
failure occurs. For these reasons, ductile failure is preferable to brittle failure.
Stress-Strain Relationship Hook’s law
18
19
Tensile-Test
FIGURE: (a) Original and final shape of a standard tensile-test specimen. (b) Outline of
a tensile-test sequence showing different stages in the elongation of the specimen.
Types of Analyses
20
There are two types of analyses (Linear/Nonlinear),
• Linear static analysis (without inertial forces)
• Linear dynamic analysis (with inertial forces)
• Nonlinear static analysis (without inertial forces)
• Nonlinear dynamic analysis (with inertial forces)
Types of Loads according to Member Behavior
21
Types of Loads
22
Gravity Loads (Dead/Live Loads)
Lateral Loads
(1) Wind Load
(2) Fluid/Water Load
(3) Earthquake/Seismic Load
23
Types of Loads
24
Types of Loads
25
Types of Loads
Types of Supports
26
Application of different Supports
27
Biaxial Bending
28
Columns are usually subjected to two bending moments about two perpendicular
axes (X and Y) as well as an axial force in the vertical Z direction (see Figure)
State of Stresses
29
(a) plane stress in sheet stretching; there
are no stresses acting on the surfaces of
the sheet (studied in MOS-I).
(b) plane stress in compression; there are
no stresses acting on the sides of the
specimen being compressed.
(c) plane strain in tension; the width of
the sheet remains constant while being
stretched.
(d) plane strain in compression; the width
of the specimen remains constant due to
the restraint by the groove.
(e) Triaxial tensile stresses acting on an
element.
(f) Hydrostatic compression of an
element.
30
Plane Stress-state of stress in which two faces of the cubic element are free of
stress. For the illustrated example, the state of stress is defined by
State of Stresses
Stress Transformation Equations
31
If we vary θ from 0° to 360°, we will get all possible values of σx1 and τx1y1
for a given stress state. It would be useful to represent σx1 and τx1y1 as
functions of θ in graphical form.
Mohr’s Circle for Plane Stress
32
33
Sign Convention
Before the transformation equations are derived, it is necessary for us to review the
sign convention for the normal and shear stress components. As shown in Fig. below,
the sign convention can be remembered by simply noting that positive normal stress
acts outwards from all faces and positive shear stress acts upward on the right-hand
face of the element.
Sign convention of stress components
34
Sign Convention for Mohr’s Circle
Notice that shear stress is plotted as positive downward. The reason for doing
this is that 2θ is then positive counterclockwise, which agrees with the direction
of 2θ used in the derivation of the tranformation equations and the direction of
θ on the stress element.
Notice that although 2θ appears in Mohr’s circle, θ appears on the stress
element.
35
Principal Stresses
36
Maximum Shear Stress
Application of Principle Stresses/Failure Theories/Yield Criterion
37
Maximum-shear-stress criterion:
Distortion-energy criterion:
σmax −σmin = Y
(σ1 −σ2) 2 +(σ2 −σ3) 2 +(σ3 −σ1) 2 = 2Y2
Plane-stress diagrams for maximum -shear-
stress and distortion-energy criteria. Note that
s2 = 0.
3D Stress Transformation
38
3D Stress Transformation
39
3D Stress Transformation
40
3D Stress Transformation
41
42
Example.#.01
43
Example.#.02
44
Example.#.02
45
Example.#.03
46
Example.#.04
47
Example.#.04
48
Example.#.04
49
Example.#.05
50
Example.#.05
51
Example.#.05
52
Example.#.06
53
Example.#.06
54
Principal Stresses by
Stress Tensor Approach
55
Principal stresses and Stress Transformation
3D State of Stress
56
3D State of Stress
57
3D State of Stress
58
3D State of Stress
59
3D State of Stress
60
3D State of Stress
61
How to calculate
principal stresses in 3D
elements
3D State of Stress
62
How to calculate principal
stresses in 3D elements
3D State of Stress
63
How to calculate principal
stresses in 3D elements
3D State of Stress
64
How to calculate principal
stresses in 3D elements
For Direction Cosines
65
For Direction Cosines
66
For Direction Cosines
67
For Direction Cosines
68
For Direction Cosines
69
For Direction Cosines
70
For Principal Stresses
71
72
For Principal Stresses
73
Principal Stresses and DCs
74
Note: In above equation l, m, and n are direction cosines (DCs).
For s1 these l, m and n becomes l1, m1 and n1 and DCs for direction vector N1 which
is normal to the principal plane 1.
Similarly,
l2, m2 and n2 are DCs for direction vector N2 which is normal to the principal plane 2.
l3, m3 and n3 are DCs for direction vector N3 which is normal to the principal plane 3.
Principal Stresses and DCs
75
Relationship b/w DCs and Principal plane angles
= cos a1i + cos b1j + cos g1k = l1i + m1j + n1k
= cos a3i + cos b3j + cos g3k
Here a1 = 71.6 degree
While b1 = 18.4 degree
g1 = 90.0
Here a3 = 18.4 degree
While b3 = 71.6 degree
g3 = 90.0
76
Properties of DCs
Also,
77
How to calculate of DCs
In above equations replace value of s by s1 and l, m, and n by l1, m1 and n1.
78
How to calculate of DCs
79
How to calculate of DCs
80
How to calculate of DCs
For Direction Cosines
81
Alternate way to calculate DCs (lmn)
For Direction Cosines
82
l1=
m1=
n1=
For Direction Cosines
83
For Direction Cosines
84
85
Lecture.#.06
86
Lecture.#.06
87
Octahedral StressLecture.#.06
88
Lecture.#.06 Octahedral Stress
89
Mean and Deviator Stresses
Tm = Mean Stress Tensor
Td = Deviatic Stress Tensor
Lecture.#.06
90
Example-#-02Lecture.#.06
91
Example-#-02Lecture.#.06
92
Example-#-03Lecture.#.06
93
Example-#-03Lecture.#.06
94
Lecture.#.07 Failure Theories
Fig-02
An axially loaded member consider to be safe if
the applied stress is less than the yield strength
(sy) of the material. Fig-01
Yield Criteria for Ductile Material
Since this state is different from the state of
uniaxial stress, it is not possible to predict from
such a test whether or not the structural
element under investigation will fail.
Some criterion regarding the actual mechanism
of failure of the material must be established
that will make it possible to compare the effects
of both states of stress.
To this effect in upcoming slides to present the
two yield criteria most frequently used for
Ductile materials.
95
Lecture.#.07 Failure Theories
96
Lecture.#.07 Failure Theories
97
Lecture.#.07 Failure Theories
98
Lecture.#.07 Failure Theories
99
Lecture.#.07 Failure Theories
100
Lecture.#.07 Failure Theories
101
Lecture.#.07 Failure Theories
102
Lecture.#.07 Failure Theories
103
Lecture.#.07 Failure Theories
104
Lecture.#.07 Failure Theories
105
Lecture.#.07 Failure Theories
106
Lecture.#.07 Failure Theories
107
Lecture.#.07 Failure Theories
108
Lecture.#.07 Failure Theories
109
Lecture.#.07 Failure Theories
110
Lecture.#.07 Failure Theories
111
Lecture.#.07 Failure Theories
112
Lecture.#.07 Failure Theories
113
Lecture.#.07 Failure Theories
114
Lecture.#.07 Failure Theories
115
Lecture.#.07 Failure Theories
Example-#-01
The state of plane stress shown occurs at a critical point of a steel machine component.
As a result of several tensile tests, it has been found that the tensile yield strength is sY
= 250 MPa for the grade of steel used. Determine the factor of safety with respect to
yield, using (a) the maximum-shearing stress criterion, and (b) the maximum-distortion-
energy criterion?.
116
Lecture.#.07 Failure Theories
117
Lecture.#.07 Failure Theories

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