200+ Q Sprint - Beginner.pdf

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Tamanna Chaudhary
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⑦
Chapter : Units and Dimensions
No.
of Questions asked ( IR)
on Average
Most
Important Topics :
1. Dimensions
2. Dimensional Analysis
3.
Propagation of Errors

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I
E- =
12
LIZ
-
②É2E
IT
✓
④ I. q÷.

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↳ HAT
-
÷
II. • ☐
HE
✓

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3
↳
§
Ext
(Mit-
2)CT] -
1.
I 1912-1-2
-
> LIMIT
- •
] .

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Tamanna Chaudhary
"
=p -0
G- IT
-1
a-
Fgn÷ M"m
= M
-
1131--2
.
?⃝
µ ,,
. , .

t ✗ C
"
GY h
2 '
I (1490-1) ✗ [LT
-
1)
"
(M-1131--2]Y
l 1912-1-1]
z
-
{peppy ✗ is-9+4
(ie-13g -1221 .
[1-
-
se
-2g
-
2) .

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4
•
→ →
a-
(F)
y
=
2=21

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5
F-o
-
1- ✗ [Me -1-1]
"
[11--1] Y
[M
- '
131--212
.
c.
Moi -10 ✗ MN
-
Z
inty
-13K
1-
-
se-
y
-
22 .

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5
o
=
✗ =
2=1-2
g- (F)

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°
y je
00T
AT
1-2=411-2.
tg.
✓
g-
-
4T?÷
=
%-✗
1001-2.102-12×100
← ☐g9_% =
Algy.
+2%-1-1.

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7
00
0
✓ H = I
2
R .
t '
Diff
=
2
DIE% +
DL→D÷%
= 213%) + 41. -161 -

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Tamanna Chaudhary
Chapter : kinematics
④
No.
of Questions asked 13-
5)
on Average
Most
Important Topics :
1.
Average /Instantaneous velocity or
speed
2.
Average /Instantaneous Acceleration .
3. Circular Motion -
Equations
4. Oblique Projectile Motion
5. Relative Motion

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9
✓ - -
④dagg.
= 2at -
✓ ⑦ d¥
,
=2bt
'
Vnet =
JÉyÉ

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10
a- IV.dt . a-
-
duty.
= 121-2-2 .
2=1-4-1-20
I

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11
a:É%→Rest .
④ ④ ↳
02. v2 = 21-
az
) (5s
)
v2-02=2as f
f >
1-3--1-2 .
1-a
=
¥
(
t =
_a, 5- vta:&aati
S =
12am (Itf) .

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Tamanna Chaudhary
I 1
=
?÷E+t}=¥¥+a%
I
⑨=
21
£2 .

Another
way of Approaching
:
Graphically
nv ,
&×ti×vm=s
t=2s-①
"
ii÷:vm×↳=ss
:.t3=¥①
0
¥+7
s 2s=vm.t{
tz=2s_①
:÷×=t¥↳)÷=¥

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12
-
10m42
'
ii
d
Area -_
12×11×10
'
Area
✓
55 £
Increase tnv
Vf = Ui + Area .
=
01-55

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13
✓
me
ac =
¥
= air =
4¥)
? R .
:÷
?⃝
÷÷.
¥
,
=
I

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14
✓ -
w=120¥
✓

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15
¥÷É÷:
✓
→
W
IT =
-12 .
Maitre =
MCW2) (e- us.
Mae -
-
ml -
more .
n=
?

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"
== - =
1-= MW? R .
T
awau
÷=(%)
'
wa
=5vpm 1- =
(Wiwa
)
"

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17
0=21-3+0.5
✓
¥ =
61-2
It
-
-2s .

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I8
w
-36
,
wz
-#②.
✓
(f)
2
-
(w)
2
=
2 1-d) . Oi
¥¥-2t2.
F. ¥ .

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19
Dv = 2v.
Sing.
✓ =
2v. sin
@§

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20 •
4=0
Ltl Cg
0
a-
¥•|÷ +5¥.
La
✓ ←
g.
10
sina.bg
b-
shino
U= O
se
t=J÷.
⇐
JÉo=Fgio
a

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21
-
✓
u =
25m15
Use = 25ktSO Yas = 5 =
yyt -
Jay1-2
Uy = 25Sino
k÷
"
I
5 = 1255in ② (2) -12 (g) (2)
2-
t
Sino ✓ =K
O ✓ 30
'

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22
✓
U -
-25m /s (0--60)
Use -_ 256560
.
Uy = 255in 60
'
⑨ Use
=Y=
✗ → 50m
y
-
-8.2m ¥ ¥
y
?⃝
If I
Uytztgt
'
25sinbox
;
-
§At

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23
ft-I.ir??-
✓
y day vy = 8- lot
{1--0
x=6t .
Uy=8☐
vii.
d÷=°ju
?⃝
u¥É.

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24
✓ Rtano =4H .
tan 0=4 .

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25
✗A
=
NB .
1^-1
f
1-
98T
-12Gt
"
= 98 (1--4) -
1-get-45
✓
s
④ time
of meeting .

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26
tap =TÉ -
v☐→
.
✓
TBM =
↳→ - vw→
-
=
(31^+41)-(-31^-45)

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27
←
vniiomlm
°§^
✓
¥¥;r+. .
→ Vriver
Me 5m
/ m vr .
→ downstream
←
1051%0=5
upstream
I
0=30
'

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28
-
☐
Ii I.
'
v
, +
v2 Gmls .
o-F.IM v
,
-
v2 Umts.

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Tamanna Chaudhary
to
chapter : haws of Motion
No.
of Questions asked (2-4)
on Average
Most
Important Topics :
f. Conservation of Momentum
2.
Hanging accelerating / Non -
accelerating systems
3.
Pulley
-
Blocked
4. Friction -
Multiple Blocks and Banking s

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29
•
M
✓ 3
,m% •µj#
1-.
v
.
•
Mly
I
ymls -
F-✗ 5
s÷g=%"

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30
✓
Bullet
→
<Gun_
MG .
VG =
MB -
V13 .
(50) Vq = -
1) ( 100
) .

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31
✓ ↳
DPISDPI.IE?ii:Fouy--oucoso
'
I # bPy=o
.
,,←
'
30
'
Dun =
-
2usino.usin-i.gg?o-
=
?⃝
u Ucoso
DP→z= (0.171-10) .
=-D kgmls -

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32
✓
A
aTm•,
. •
mita.
↳
a•m=MamYYm÷.
mama .
"
%a2-yy.mg#a=m.g-m,g-

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33
F
•F 2kg . Ta-
-2mHz
6 (gta
)
6110+21=372 -
?⃝
|⑧ykg.
Ta-
-2m/s
' '
✓ 1-1--4 (
gta
)
=
4112
) 48N -
ta
aneto -
-
gta da g-a

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34
F§M→Fi
M
£0 Hit =/ Fat
✓
acosi-gsindmaeosa@maFIXmgsina.O
a-
giant
.
Masina.
mgcosod
.

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35
→
Faz =
Mzgsin
mzF_
✓
Mi-1mg -1mg.
F-
-
Cm, -1hPa -13mg)gSino
-
Sino =F
_
lmitmztm3)g-

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36
F
y
-
N
'
-1 It
% 1-
Area
←
Impulse .
← Change inp→
-

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37
0
→
t
✗
Cbeforeoomingtorest
•
gym
,¥Ñ°
"
vid-
uid-2au.su .
y
(05-110)%21-
[gsinotygcoso)) .se .
""
%=gsin3t.
He
set
%¥m/g•, #
496-5370

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38
Vmax =
←
=
5%0×0-

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39
qN=2oN
[
f-
←
→ F ? ? a-4.fm/s2
. Fon
16kg
I
96kg t.fm/s2
'
✗ f- (0.42/190) -
←
•→ F '
Fnet= F- 8.4 = 6 (1-5) -
6kg
→ F- 8.4=9
9=1.5
F=I
'

200+ Q Sprint - Beginner.pdf

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200+ Q Sprint - Beginner.pdf