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NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.1 Solve for π‘₯:
1.1.1 π‘₯2 βˆ’ 4π‘₯ + 3 = 0 (3)
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.1 Solve for π‘₯:
1.1.2 5π‘₯2 βˆ’ 5π‘₯ + 1 = 0 (2 decimal places) (3)
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.1 Solve for π‘₯:
1.1.2 5π‘₯2 βˆ’ 5π‘₯ + 1 = 0 (2 decimal places) (3)
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.1 Solve for π‘₯:
1.1.2 5π‘₯2 βˆ’ 5π‘₯ + 1 = 0 (2 decimal places) (3)
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.1 Solve for π‘₯:
1.1.3 π‘₯2 βˆ’ 3π‘₯ βˆ’ 10 > 0 (3)
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.1 Solve for π‘₯:
1.1.3 π‘₯2 βˆ’ 3π‘₯ βˆ’ 10 > 0 (3)
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.1 Solve for π‘₯:
1.1.4 3 π‘₯ = π‘₯ βˆ’ 4 (4)
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.2 Solve for π‘₯ and 𝑦 simultaneously:
3π‘₯ βˆ’ 𝑦 = 2 and 2𝑦 + 9π‘₯2 = βˆ’1 (6)
NSC Mathematics Grade 12
2018 November Paper 1
QUESTION 1
1.3 If 39π‘₯
= 64 and 5 𝑝
= 64, calculate, WITHOUT the use of a
calculator, the value of:
3 π‘₯βˆ’2 3
5
𝑝 (4)

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Nsc mathematics grade 12 2018 nov paper 1 1

  • 1. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1
  • 2. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.1 Solve for π‘₯: 1.1.1 π‘₯2 βˆ’ 4π‘₯ + 3 = 0 (3)
  • 3. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.1 Solve for π‘₯: 1.1.2 5π‘₯2 βˆ’ 5π‘₯ + 1 = 0 (2 decimal places) (3)
  • 4. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.1 Solve for π‘₯: 1.1.2 5π‘₯2 βˆ’ 5π‘₯ + 1 = 0 (2 decimal places) (3)
  • 5. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.1 Solve for π‘₯: 1.1.2 5π‘₯2 βˆ’ 5π‘₯ + 1 = 0 (2 decimal places) (3)
  • 6. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.1 Solve for π‘₯: 1.1.3 π‘₯2 βˆ’ 3π‘₯ βˆ’ 10 > 0 (3)
  • 7. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.1 Solve for π‘₯: 1.1.3 π‘₯2 βˆ’ 3π‘₯ βˆ’ 10 > 0 (3)
  • 8. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.1 Solve for π‘₯: 1.1.4 3 π‘₯ = π‘₯ βˆ’ 4 (4)
  • 9. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.2 Solve for π‘₯ and 𝑦 simultaneously: 3π‘₯ βˆ’ 𝑦 = 2 and 2𝑦 + 9π‘₯2 = βˆ’1 (6)
  • 10. NSC Mathematics Grade 12 2018 November Paper 1 QUESTION 1 1.3 If 39π‘₯ = 64 and 5 𝑝 = 64, calculate, WITHOUT the use of a calculator, the value of: 3 π‘₯βˆ’2 3 5 𝑝 (4)