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1 of 13
3 + 2 3 + 2 3 + 2 …
2 2 2 … ???
1 + 2 1 + 3 1 + 4 …
bangdikk.blogspot.com
2
𝑎 + 𝑏 𝑎 + 𝑏 𝑎 + 𝑏 …
Bentuk umum
𝑎 ≥ 0, 𝑏 ≠ 0
dengan
bangdikk.blogspot.com
3
3 + 2 3 + 2 3 + 2 … = ⋯
Contoh
𝑎 = 3, 𝑏 = 2
bangdikk.blogspot.com
4
3 + 2 3 + 2 3 + 2 …
Solusi
Fokus
bangdikk.blogspot.com
5
3 + 2 3 + 2 3 + 2 …
Solusi
Cari
Sehingga
𝑥 ∗ 𝑦 = 3
𝑥, 𝑦
𝑥 − 𝑦 = 2
(x > y)
bangdikk.blogspot.com
6
3 + 2 3 + 2 3 + 2 …
Solusi
Diperoleh
3 ∗ 1 = 3
3 − 1 = 2
Pilih
3
(jika +)
1
(jika -)
=
3
1
[lebih besar]
[lebih kecil]bangdikk.blogspot.com
7
3 + 2 3 + 2 3 + 2 … = 3
Jadi
Done...
bangdikk.blogspot.com
8
2 2 2 … = ⋯
Contoh 2
𝑎 = 0, 𝑏 = 2
bangdikk.blogspot.com
9
0 + 2 0 + 2 0 + 2 …
Solusi
2 ∗ 0 = 0
2 − 0 = 2
= 2 2 2 …
bangdikk.blogspot.com
10
2 2 2 … = 2
Jadi
Done...
bangdikk.blogspot.com
11
𝑏 𝑏 𝑏 … = 𝑏
Secara umum
𝑏 > 0
dengan
bangdikk.blogspot.com
12
1 + 2 1 + 2 1 + 2 … = ⋯
challenge
𝑎 = 1, 𝑏 = 2
bangdikk.blogspot.com
Thanks
bangdikk.blogspot.com
13

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Akar Berulang

  • 1. 3 + 2 3 + 2 3 + 2 … 2 2 2 … ??? 1 + 2 1 + 3 1 + 4 … bangdikk.blogspot.com
  • 2. 2 𝑎 + 𝑏 𝑎 + 𝑏 𝑎 + 𝑏 … Bentuk umum 𝑎 ≥ 0, 𝑏 ≠ 0 dengan bangdikk.blogspot.com
  • 3. 3 3 + 2 3 + 2 3 + 2 … = ⋯ Contoh 𝑎 = 3, 𝑏 = 2 bangdikk.blogspot.com
  • 4. 4 3 + 2 3 + 2 3 + 2 … Solusi Fokus bangdikk.blogspot.com
  • 5. 5 3 + 2 3 + 2 3 + 2 … Solusi Cari Sehingga 𝑥 ∗ 𝑦 = 3 𝑥, 𝑦 𝑥 − 𝑦 = 2 (x > y) bangdikk.blogspot.com
  • 6. 6 3 + 2 3 + 2 3 + 2 … Solusi Diperoleh 3 ∗ 1 = 3 3 − 1 = 2 Pilih 3 (jika +) 1 (jika -) = 3 1 [lebih besar] [lebih kecil]bangdikk.blogspot.com
  • 7. 7 3 + 2 3 + 2 3 + 2 … = 3 Jadi Done... bangdikk.blogspot.com
  • 8. 8 2 2 2 … = ⋯ Contoh 2 𝑎 = 0, 𝑏 = 2 bangdikk.blogspot.com
  • 9. 9 0 + 2 0 + 2 0 + 2 … Solusi 2 ∗ 0 = 0 2 − 0 = 2 = 2 2 2 … bangdikk.blogspot.com
  • 10. 10 2 2 2 … = 2 Jadi Done... bangdikk.blogspot.com
  • 11. 11 𝑏 𝑏 𝑏 … = 𝑏 Secara umum 𝑏 > 0 dengan bangdikk.blogspot.com
  • 12. 12 1 + 2 1 + 2 1 + 2 … = ⋯ challenge 𝑎 = 1, 𝑏 = 2 bangdikk.blogspot.com