16. Paulingandslaterresolveddiscrepancybyintroducingtheconceptof orbitalhybridizationwhich involvesmixingof
differentorbitalsof anatomtoformnewhybridorbitals,beforeoverlapping andbondformation.
These hybrid orbitals are identical in directional character and have the same shape and energy. The total
number of hybridorbitals formed after mixing, isalwaysequal to the number ofatomic orbitals mixed.
“Theprocessof mixingof orbitalsof anatomof nearlyequalenergygivingrisetoentirelynew orbitalsequalto
thenumbertothenumberof mixingorbitalsandhavingidenticalshapeand sameenergycontentiscalled
hybridization.”
Hybridization
20. 2)Acetylene(C2H2)
The ground state electronic configuration of 'C' is 1
s
2
2s2
2px
1
2py
1
.There are only two
unpairedelectrons in thegroundstate.However, the valencyof carbon is four i.e.,it
forms 4bonds. In order to form four bonds, there must be four unpaired electrons.
Hence carbon promotes one of its 2s electron into the empty 2pz orbital in the
excitedstate.
Thusintheexcitedstate,theelectronic configurationof carbon is
1
s
2
2s1
2px
1
2py
1
2pz
1
.
Eachcarbonatomundergoes'sp'hybridizationbyusinga2sandone 2porbitals in
theexcitedstatetogivetwo halffilled'sp'orbitals, which arearrangedlinearly.
Thetwo carbonatomsformaσsp-spbondwith eachotherbyusingsp- orbitals.
TypesofHybridization
21. Howevertherearealsotwo unhybridizedp orbitalsi.e.,2pyand 2pzon
eachcarbonatomwhich areperpendiculartothesp hybridorbitals.These
orbitalsformtwo πp-p bondsbetweenthe two carbonatoms.
Thusatriplebond(includingoneσsp-sp bond&two πp-p bonds)is formed
betweencarbonatoms.
Eachcarbonalsoformsaσsp-s bondwith thehydrogenatom. Thus
acetylenemoleculeislinearwith 180o
of bondangle.
TypesofHybridization
22. ii)sp2
hybridization
Intermixing of one 's' and two 'p' orbitals of almost equal energytogivethreeidenticaland
degeneratehybridorbitalsisknownassp2hybridization.
Thethreesp2
hybridorbitalsareorientedintrigonalplanarsymmetryatanglesof 120o
toeach other.
Thesp2
hybridorbitalshave33.3%'s'characterand 66.6%'p'character.
TypesofHybridization
30. iv)sp3
dhybridization
In sp3
d hybridization,one's',three'p'andone'd'orbitalsof almost equalenergy
intermix to give five identical and degenerate hybrid orbitals, which are
arrangedintrigonalbipyramidal symmetry.
Amongthem,threearearrangedintrigonalplaneandthe remainingtwo orbitals
arepresentaboveandbelow thetrigonal planeatrightangles.
The sp3
d hybrid orbitals have 20% 's', 60% 'p' and 20% 'd'
characters.
TypesofHybridization
32. TypesofHybridization
By using these half filled sp3
d orbitals, phosphorous forms
five σsp3d-p bonds with chlorine atoms. Each chlorine atom
makesuseof halffilled3pzorbital for thebond formation.
The shape of PCl5molecule is trigonal bipyramidal with 120o
and90o
of ∠Cl- P- Cl bondangles.
33. v)sp3
d2
hybridization
Intermixing of one 's', three 'p' and two 'd' orbitals of almost same energy by
givingsixidenticalanddegeneratehybridorbitalsis calledsp3
d2
hybridization.
These six sp3
d2
orbitals are arranged in octahedral symmetry by making 90o
angles to each other. This arrangement can be visualized as four orbitals
arranged in a square plane and the remaining two are oriented above and
below thisplane perpendicularly.
TypesofHybridization
35. In thesecond excited state,sulfur under goes sp3
d2
hybridization by
mixing a3s,three3pandtwo 3d orbitals. Thusformed six half filled
sp3
d2
hybridorbitals arearrangedinoctahedral symmetry.
Sulfur atom forms six σsp3d2-p bonds with 6 fluorine atomsby using
thesesp3
d2
orbitals. Eachfluorine atom usesis half-filled 2pzorbitals
for the bond formation. SF6is octahedral in shape with bond angles
equalto90o
.
TypesofHybridization
36. Vi)sp3
d3
hybridization
In sp3
d3
hybridization, one 's', three 'p' and three 'd' orbitals of almost same
energy intermix to give seven sp3
d3
hybrid orbitals, which are oriented in
pentagonalbipyramidal symmetry.
Five amongthe sp3
d3
orbitals are arranged in apentagonal plane by making72o
of angles. The remaining are arranged perpendicularly above and below this
pentagonalplane.
TypesofHybridization
38. In the third excited state, iodine atom undergoes sp3
d3
hybridization to give 7 half filled sp3
d3
hybrid orbitals in
pentagonal bipyramidal symmetry. These will form 7σsp3d3-p
bondswith fluorine atoms.
Thus the shapeof IF7is pentagonal bipyramidal. The∠F-I-F
bond angles in the pentagonal plane are equal to 72o
,
whereas two fluorine are present perpendicularly to the
pentagonalplaneaboveand below.
TypesofHybridization