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The real cost of Inflammation in PRODUCTION–a view across species. Ms Megan Abeyta - Iowa State University
1. Department of Animal Science
Impacts of Leaky Gut and Inflammation on
Production Across Species
Megan Abeyta
PhD Candidate
Iowa State University
maabeyta@iastate.edu
2. Reminder: Intestinal Functions
GIT is a tube running from the mouth to
the anus
Everything inside of the tube is technically
“outside” of the body
Digest and absorb nutrients
GIT lumen is an inhospitable environment
Prevent parasites, pathogens, antigens,
enzymes, acids, toxins etc.. From
infiltrating “self”
Barrier function
8. Heat Stress and Production (Dairy)
Rhoads et al., 2009
10
11
12
13
14
15
16
17
18
19
20
1 2 3 4 5 6 7 8 9
DMI
(kg)
Day
Heat-stressed
Pair-fed
Heat stress feed intake
by ~30%
20
25
30
35
40
45
50
0 1 2 3 4 5 6 7 8 9
Milk
Yield
(kg)
Day
Heat-stressed
Pair-fed
Heat stress yield ~45%
Pair-feeding yield by ~19%
Thus, feed intake only accounts for ~50% of the reduction in milk
yield… other 50% immune system?
9. Heat Stress, Production, and Intestinal Integrity (Pigs)
Thermoneutral Heat Stress Heat Stress and Growth in Swine
Pearce et al., 2013
Mayorga et al., 2019
Heat stress ↑ gut permeability and
↓ growth in pigs
10. Feed Restriction Causes Intestinal Hyperpermeability and
Production Losses in Cattle
2000
2500
3000
3500
4000
4500
5000
P1 2 5
Cr
AUC:
μg/L
×
h
Day of Feed Restriction
AL
FR
Trt: P = 0.01
Day: P = 0.12
Trt × Day: P = 0.09
↑ 17%
P = 0.09
↑ 32%
P = 0.01
Horst et al., 2019
0
2
4
6
8
10
12
Pre-Trt 6 12
Milk
Yield
(kg)
Fasting Time (h)
22%
39%
How often are cows without feed for ≥ 6 hours on farms?
11. 12 h of Feed Restriction Causes Leaky Gut in Pigs
Pearce et al., 2015
0
1
2
3
4
5
6
7
12 TN 12 PF 12 HS 12 HS-Zn
Serum
Endotoxin
(AU)
Pair-fed “Feed Restriction”
12 TN: 12 h of thermal neutral ad libitum fed conditions
12 PF: 12 h of pair-feeding in thermal neutral conditions
12 HS: 12 h of heat stress and ad libitum feed intake
2.3 kg BW loss in 12 h
0.88 kg less feed intake than CON
~1.4 kg BW loss (including lost gain)… part immune response?
~83% less feed intake than TN
Psychological
Stress?
13. Professor Dr. Otto Warburg
First recognized the unique metabolism of cancer cells (1927)
Large glucose consumers
Switch from oxidative phosphorylation aerobic glycolysis
Also observed activated lymphocytes become highly glycolytic (1958)
Mentored Hans Krebs
Drinking buddy with Albert Einstein
Translation: “Metabolism of “Leukocytes
14. Immuno-Metabolism
Immune cells become obligate glucose
utilizers when activated
Called “The Warburg Effect”
Leukocytes are insulin sensitive
Palsson-McDermott and O’Neill, 2013
Advantages of Warburg effect:
Rapid production of ATP
Synthesis of biomolecules (nucleotides,
reducing equivalents, etc.)
Adaptation to hypoxic environment
Inflammatory signaling
GLUCOSE
Insulin
15. GLU GLU
GLU
GLU
Resting Immune Cell Activated Immune Cell
G-6-P
Pyr Pyr
TCA
ETC
ATP
ATP
GLU
G-6-P
Pyr Pyr
TCA
ETC
LPS
Lac
ATP
ATP
Lac
Shouse and Baumgard, 2017
Warburg Effect
Acetate
Amino Acids
NEFA
Insulin
16. How much glucose is the entire body using??
80 years later and we still not know how much glucose the
immune system needs in vivo?
Prerequisite for developing mitigation strategies
What’s the Problem?:
Dynamic and ubiquitous distribution of the immune
system throughout tissues
Allows for quasi tissue/organ quantification but….
Complicates whole-body quantification
17. LPS Challenge and Blood Glucose
LPS
Bolus
Glucose
Time
Can we quantify this amount of glucose?
24. Conserved Response Across Species
Species: Immune glucose utilization
Steers: 1.0 g/kg BW0.75/h (Kvidera et al., 2016)
Pigs: 1.1 g/kg BW0.75/h (Kvidera et al., 2015)
Cows: 0.7 g/kg BW0.75/h (Kvidera et al., 2017)
Cows: 1.0 g/kg BW0.75/h (Horst et al, 2020)
25. What does this mean for production?
Dairy Cow
1. ~2,000 g glucose in 24 h
2. 72 g glucose/ 1 liter
milk synthesis
(Kronfield et al., 1982)
~ 28 L of milk
lost in 24 h
120 kg hog
1. ~ 960 g glucose in 24 h
2. 960 g x 0.017 MJ/g = 16.3 MJ
3. Protein synthesis: 0.04 MJ/g
4. 16.3/0.04 = 408 g PTN
5. 408 ÷ ~30% DM = 1,358 g
lean tissue!
~1.4 kg lean tissue
lost in 24 h
1. ~3,200 g glucose in 24 h
2. 3,200 g x 0.017 MJ/g = 54.4 MJ
3. Protein synthesis: 0.04 MJ/g
(Patience, 2012)
4. 54.4 MJ/0.04 MJ = 1,360 g
5. 1,360 g ÷ ~30% DM = 4,533 g
of lean tissue!
680 kg steer
~4.5 kg lean tissue
lost in 24 h
26. Can the feed industry do anything about leaky gut?
Prevent infection (obvious)
Encourage feed intake
Ensure 100% feed availability
Minimize psychological stress
Maximize digestion prior to large intestine
Dietary strategies
Prevent rumen acidosis
Dietary Strategies
Manage intestinal permeability
Dietary strategies
Immunomodulation
Producer’s Responsibility
Nutritionist and Producer’s Responsibility
Nutritionist’s Responsibility
27. Conclusions
Immune activation, regardless of origin, is energetically and nutrient
expensive and compromises production (i.e., milk yield, growth)
28 L milk
1.4 - 4.5 kg lean tissue loss (pigs and steers)
Many different stressors can cause leaky gut, and ergo, inflammation
Heat stress
Feed restriction
Rumen acidosis
Psychological stress
Management and nutrition practices should prioritize the prevention of
immune activation
Here are a couple pictures that hopefully help to illustrate what we did. You can see here there are two jugular lines coming out of this cow. Here we are taking a sample from the cows right catheter while glucose is being infused via a hospital infusion pump through her left jugular catheter. Every 10 minutes, we took a small blood sample from the catheter and measured it using a glucometer. We would record this data and compare it to her baseline in order to adjust the pump rate of infusion, which we also recorded every 10 minutes.
So, using the methods I described earlier, we calculated the total glucose deficit for each cow and we saw a treatment difference with the LPS cows displaying a much higher glucose deficit than the control treatment. There was a tendency for a greater glucose deficit in the euglycemic clamped cows relative to the LPS-only cows. However, it is apparent that reduction in milk glucose output is a major strategy to spare glucose for the immune system. Remember all animals were consuming the same amount of feed, so 483 g of the glucose deficit were due to reduction in feed intake, therefore we estimate that approximately a little over 1 kg of glucose was used by the immune system during this challenge.