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Alternate Segment
     Theorem
Alternate Segment
           Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.
Alternate Segment
             Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.



                   A
    B
         O


X            P
Alternate Segment
             Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.
        BPX  PAB                  alternate segment theorem 

                   A
    B
          O


X             P
Alternate Segment
             Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.
        BPX  PAB                  alternate segment theorem 
                            Prove : APY  ABP
                   A
    B
          O


X             P        Y
Alternate Segment
             Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.
        BPX  PAB                  alternate segment theorem 
           Z                Prove : APY  ABP
                   A        Proof: Join PO and produce to meet the
    B                               circumference at Z
          O


X             P        Y
Alternate Segment
             Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.
        BPX  PAB                  alternate segment theorem 
           Z                Prove : APY  ABP
                   A        Proof: Join PO and produce to meet the
    B                               circumference at Z
          O
                                   Join AZ

X             P        Y
Alternate Segment
             Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.
        BPX  PAB                  alternate segment theorem 
           Z                Prove : APY  ABP
                   A        Proof: Join PO and produce to meet the
    B                               circumference at Z
          O
                                   Join AZ
                                 ZPY  90        radius  tangent 
X             P        Y
Alternate Segment
             Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.
        BPX  PAB                  alternate segment theorem 
           Z                Prove : APY  ABP
                   A        Proof: Join PO and produce to meet the
    B                               circumference at Z
          O
                                   Join AZ
                                 ZPY  90        radius  tangent 
X             P        Y         APZ  90 - APY
Alternate Segment
             Theorem
(9) An angle formed by a tangent to a circle with a chord drawn to the
    point of contact is equal to any angle in the alternate segment.
        BPX  PAB                  alternate segment theorem 
           Z                Prove : APY  ABP
                   A        Proof: Join PO and produce to meet the
    B                               circumference at Z
          O
                                   Join AZ
                                 ZPY  90        radius  tangent 
X             P        Y         APZ  90 - APY
                               PAZ  90              in semicircle 
Z
                A
    B
        O


X                   Y
            P
Z
                   A
    B
        O


X                      Y
            P
                PAZ  AZP  APZ  180    sum APZ 
Z
                     A
    B
        O


X                        Y
            P
                 PAZ  AZP  APZ  180        sum APZ 
                90  AZP  90  APY  180
Z
                     A
    B
        O


X                        Y
            P
                 PAZ  AZP  APZ  180        sum APZ 
                90  AZP  90  APY  180
                         AZP  APY
Z
                     A
    B
        O


X                        Y
            P
                  PAZ  AZP  APZ  180              sum APZ 
                90  AZP  90  APY  180
                         AZP  APY
                         AZP  ABP            's in same segment = 
Z
                     A
    B
        O


X                        Y
            P
                  PAZ  AZP  APZ  180              sum APZ 
                90  AZP  90  APY  180
                         AZP  APY
                         AZP  ABP            's in same segment = 
                        APY  ABP
Z
                         A
    B
            O


X                            Y
                P
                      PAZ  AZP  APZ  180              sum APZ 
                    90  AZP  90  APY  180
                             AZP  APY
                             AZP  ABP            's in same segment = 
                            APY  ABP



        Exercise 9F; 2ace etc, 3bd, 4bd, 5b, 7b, 9b, 10b, 12, 14, 15b

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  • 2. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment.
  • 3. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment. A B O X P
  • 4. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment. BPX  PAB  alternate segment theorem  A B O X P
  • 5. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment. BPX  PAB  alternate segment theorem  Prove : APY  ABP A B O X P Y
  • 6. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment. BPX  PAB  alternate segment theorem  Z Prove : APY  ABP A Proof: Join PO and produce to meet the B circumference at Z O X P Y
  • 7. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment. BPX  PAB  alternate segment theorem  Z Prove : APY  ABP A Proof: Join PO and produce to meet the B circumference at Z O Join AZ X P Y
  • 8. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment. BPX  PAB  alternate segment theorem  Z Prove : APY  ABP A Proof: Join PO and produce to meet the B circumference at Z O Join AZ ZPY  90 radius  tangent  X P Y
  • 9. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment. BPX  PAB  alternate segment theorem  Z Prove : APY  ABP A Proof: Join PO and produce to meet the B circumference at Z O Join AZ ZPY  90 radius  tangent  X P Y APZ  90 - APY
  • 10. Alternate Segment Theorem (9) An angle formed by a tangent to a circle with a chord drawn to the point of contact is equal to any angle in the alternate segment. BPX  PAB  alternate segment theorem  Z Prove : APY  ABP A Proof: Join PO and produce to meet the B circumference at Z O Join AZ ZPY  90 radius  tangent  X P Y APZ  90 - APY PAZ  90  in semicircle 
  • 11. Z A B O X Y P
  • 12. Z A B O X Y P PAZ  AZP  APZ  180  sum APZ 
  • 13. Z A B O X Y P PAZ  AZP  APZ  180  sum APZ  90  AZP  90  APY  180
  • 14. Z A B O X Y P PAZ  AZP  APZ  180  sum APZ  90  AZP  90  APY  180 AZP  APY
  • 15. Z A B O X Y P PAZ  AZP  APZ  180  sum APZ  90  AZP  90  APY  180 AZP  APY AZP  ABP  's in same segment = 
  • 16. Z A B O X Y P PAZ  AZP  APZ  180  sum APZ  90  AZP  90  APY  180 AZP  APY AZP  ABP  's in same segment =   APY  ABP
  • 17. Z A B O X Y P PAZ  AZP  APZ  180  sum APZ  90  AZP  90  APY  180 AZP  APY AZP  ABP  's in same segment =   APY  ABP Exercise 9F; 2ace etc, 3bd, 4bd, 5b, 7b, 9b, 10b, 12, 14, 15b