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The Distance of Point to
             Point

              B




A


                         1
Example
                          Given :
                          cube ABCD.EFGH
                          With the length of
    H      P        G     edge is a cm.
E              F
                   a cm
                          Determine the distance
                          of :
    D               C
                          1. point A to C,
A                  a cm   2. point A to G,
    a cm       B
                          3. point A to the middle
                          of plane EFGH

                                       2
Solution :
                     Look at the triangle
                    ABC that is
                    the right triangle in B,
    H           G
                    then :
E            F        AC =    AB 2  BC 2
                 a cm      = a2  a2
    D            C
                           = 2a 2
               a cm
A     a cm   B             =a 2
      So, side diagonal AC = a 2 cm
                                  3
Distance AG = ?
                         Look at the
             tiangle ACG that is the
   H      right triangle in C, then :
               G
E          F       AG =    AC 2  CG 2
               a cm   =  ( a 2 )2  a 2

   D           C
                      = 2a  a
                             2    2

             a cm
A    a cm  B          = 3a 2 = a 3
  So, space diagonal AG = a 3 cm
                                4
Distance of AP = ?
                           Look at the
         triangle AEP that is the right
   H    P       G triangle in E, then :
E            F
                   AP =    AE 2  EP 2

                       = a  2 a 2 
                                       2
                           2    1

   D            C         a2  2 a2
                                1
A
                       =
     a cm    B
                          3 2
                       = 2  a = 2a 6
                                  1


  So, the distance of A to P = 2 a 6
                                  1


  cm                            5
Projection of Point to Line

          From point P, we can make
P
                      line m line k.
             Line m intersect k in Q,
    m
                           point Q is
          k            the projection
        Q            from P to line k

                              6
Example
    H           G
E                   Given:
            F
                    cube ABCD.EFGH
                    Determine the
                    projection of point A
    D   T       C   to line :
A           B       a. BC b.BD
                    c. ET
                      (T is side diagonal
                      on plane ABCD).

                                 7
Solution :
    H                G to
                         Projection of point A
E                F
                         a. BC is point B
        A’                  (AB  BC)
    D        T       C
A                B       b. BD is point T
                           (AC  BD)

                         c. ET is point A’
                          (AC  ET)

                                        8
Example
    H              G
E              F          Given cube
                   6 cm
                          ABCD.EFGH
    D              C      With the length of
A       6 cm   B
                          edge is 6 cm.
                          The distance of
                          point B to line AG
                          is….

                                    9
E
    H                  G    Solution
                   F

        P                  Distance of B to AG=
    D                  C   Distance of B to P
A       6 cm       B       (BPAG)
               G           BG(side diagonal) =
                           6√2 cm
               6√2         AG(space diagonal)
        P ?
                           = 6√3 cm
    A     6    B
                                       10
G     Look triangle ABG
                  Sin A = AG = AB
                            BG   BP

            6√2
    P
        ?                         6 2           BP
                                  6 3
                                            =    6
A       6   B
                                                   2
                         ( 6 2 )( 6 )       3        6 6
                  BP =                  x       
                            6 3             3         3


           BP = 2√6
So, distance of B to AG = 2√6
cm
                                                11
The other way by using the area of triangle
ABG :
            1            1
               𝐴𝐵. 𝐵𝐺 =     𝐴𝐺. 𝑃𝐵
            2            2
            6 . 6 2 = 6 3 . 𝑃𝐵
           36 2       = 6 3 . 𝑃𝐵
                   36 2
             𝑃𝐵 =       = 2 6 𝑐𝑚
                    6 3
Exercise

          T         Given T.ABCD that
                    the base is square.
                    The length of base
                    edge is 12 cm, and
                    the length of TA is
    D             C 12√2      cm.    The
                    distance of A
        12 cm
A               B   to TC is….

                                13
1.   Given that a regular pyramid T.ABCD has the
     base AB = 4 cm, and TA = 6 cm. Determine
     the distance of :
     a. Point T to line AB
     b. Point T to line AC

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Matematika - Distance Point To Line

  • 1. The Distance of Point to Point B A 1
  • 2. Example Given : cube ABCD.EFGH With the length of H P G edge is a cm. E F a cm Determine the distance of : D C 1. point A to C, A a cm 2. point A to G, a cm B 3. point A to the middle of plane EFGH 2
  • 3. Solution : Look at the triangle ABC that is the right triangle in B, H G then : E F AC = AB 2  BC 2 a cm = a2  a2 D C = 2a 2 a cm A a cm B =a 2 So, side diagonal AC = a 2 cm 3
  • 4. Distance AG = ? Look at the tiangle ACG that is the H right triangle in C, then : G E F AG = AC 2  CG 2 a cm = ( a 2 )2  a 2 D C = 2a  a 2 2 a cm A a cm B = 3a 2 = a 3 So, space diagonal AG = a 3 cm 4
  • 5. Distance of AP = ? Look at the triangle AEP that is the right H P G triangle in E, then : E F AP = AE 2  EP 2 = a  2 a 2  2 2 1 D C a2  2 a2 1 A = a cm B 3 2 = 2 a = 2a 6 1 So, the distance of A to P = 2 a 6 1 cm 5
  • 6. Projection of Point to Line From point P, we can make P line m line k. Line m intersect k in Q, m point Q is k the projection Q from P to line k 6
  • 7. Example H G E Given: F cube ABCD.EFGH Determine the projection of point A D T C to line : A B a. BC b.BD c. ET (T is side diagonal on plane ABCD). 7
  • 8. Solution : H G to Projection of point A E F a. BC is point B A’ (AB  BC) D T C A B b. BD is point T (AC  BD) c. ET is point A’ (AC  ET) 8
  • 9. Example H G E F Given cube 6 cm ABCD.EFGH D C With the length of A 6 cm B edge is 6 cm. The distance of point B to line AG is…. 9
  • 10. E H G Solution F P Distance of B to AG= D C Distance of B to P A 6 cm B (BPAG) G BG(side diagonal) = 6√2 cm 6√2 AG(space diagonal) P ? = 6√3 cm A 6 B 10
  • 11. G Look triangle ABG Sin A = AG = AB BG BP 6√2 P ? 6 2 BP 6 3 = 6 A 6 B 2 ( 6 2 )( 6 ) 3 6 6 BP = x  6 3 3 3 BP = 2√6 So, distance of B to AG = 2√6 cm 11
  • 12. The other way by using the area of triangle ABG : 1 1 𝐴𝐵. 𝐵𝐺 = 𝐴𝐺. 𝑃𝐵 2 2 6 . 6 2 = 6 3 . 𝑃𝐵 36 2 = 6 3 . 𝑃𝐵 36 2 𝑃𝐵 = = 2 6 𝑐𝑚 6 3
  • 13. Exercise T Given T.ABCD that the base is square. The length of base edge is 12 cm, and the length of TA is D C 12√2 cm. The distance of A 12 cm A B to TC is…. 13
  • 14. 1. Given that a regular pyramid T.ABCD has the base AB = 4 cm, and TA = 6 cm. Determine the distance of : a. Point T to line AB b. Point T to line AC