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UNIT .01
- 2. What you’ll learn about
Cartesian Plane
Absolute Value of a Real Number
Distance Formulas
Midpoint Formulas
Equations of Circles
Applications
… and why
These topics provide the foundation for the material that
will be covered in this textbook.
Slide P.2 - 2 Copyright © 2011 Pearson, Inc.
- 3. The Cartesian Coordinate Plane
or Rectangular Coordinate System
Slide P.2 - 3 Copyright © 2011 Pearson, Inc.
- 5. Absolute Value of a Real Number
absolute value of a real num ber a
The is
a a
> ìï
= - < íï
î =
, if 0
a a a
| | if 0.
a
0, if 0
Slide P.2 - 5 Copyright © 2011 Pearson, Inc.
- 6. Example Using the Definition of
Absolute Value
Evaluate:
-7
p - 5
Slide P.2 - 6 Copyright © 2011 Pearson, Inc.
- 7. Solution
Evaluate:
-7 = 7
because - 7 < 0, -4 = -(-7) = 7
p - 5 = -(p - 5) = 5 -p
because p » 3.14, p - 5 < 0
Slide P.2 - 7 Copyright © 2011 Pearson, Inc.
- 8. Properties of Absolute Value
Let a and b be real numbers.
1. | a |³ 0
2. |-a|=|a|
3. |ab |=|a||b |
4. a
b
= |a|
|b |
, b ¹ 0
Slide P.2 - 8 Copyright © 2011 Pearson, Inc.
- 9. Distance Formula (Number Line)
Let a and b be real numbers.
The distance between a and b is a -b .
Note that a-b = b -a .
Slide P.2 - 9 Copyright © 2011 Pearson, Inc.
- 10. Distance Formula (Coordinate Plane)
y2
The distance d between points P ( x, y)
1 1 and Q ( x, 2 ) in the coordinate plane is
( )2 + y1
d = x1- x2
( )2 .
- y2
Slide P.2 - 10 Copyright © 2011 Pearson, Inc.
- 11. The Distance Formula using the
Pythagorean Theorem
Slide P.2 - 11 Copyright © 2011 Pearson, Inc.
- 12. Example Finding the Distance
Between Two Points
Slide P.2 - 12 Copyright © 2011 Pearson, Inc.
- 14. Midpoint Formula (Number Line)
The midpoint of the line segment
with endpoints a and b is
a +b
2
.
Slide P.2 - 14 Copyright © 2011 Pearson, Inc.
- 15. Midpoint Formula (Coordinate Plane)
The midpoint of the line segment
with endpoints (a,b) and (c,d) is
a +c
2
,b +d
2
æè ç öø ÷
.
Slide P.2 - 15 Copyright © 2011 Pearson, Inc.
- 16. Standard Form Equation of a Circle
The standard formequation of a circle
with center (h, k)and radius r is
(x -h)2 + (y- k)2 = r2 .
Slide P.2 - 16 Copyright © 2011 Pearson, Inc.
- 18. Example Finding Standard Form
Equations of Circles
Find the standard form equation of the
circlewith center (2, - 3) and radius 4.
Slide P.2 - 18 Copyright © 2011 Pearson, Inc.
- 19. Example Finding Standard Form
Equations of Circles
Find the standard form equation of the
circlewith center (2, - 3) and radius 4.
(x -h)2 + (y- k)2 = r2 where h = 2, k = -3,and r = 4.
Thus the equation is (x - 2)2 + (y+ 3)2 = 16.
Slide P.2 - 19 Copyright © 2011 Pearson, Inc.
- 20. Quick Review
1. Find the distance between -5 and 3 .
Use a calculator to evaluate the expression. Round answers
to two decimal places.
2. 8 2 +
6
2
3. -12 +
8
2
4. 3 2 +
5
2
5. 2 − 5 + 1 −
3
( ) ( )
2 2
4 2
Slide P.2 - 20 Copyright © 2011 Pearson, Inc.
- 21. Quick Review Solutions
1. Find the distance between -5 and 3 .
2.75
Use a calculator to evaluate the expression. Round answers
to two decimal places.
2. 8 2 +
6
2
3. -12 +
8
2
4. 3 5
5. 2
+
− + −
2 2
10
-2
5.83
( ) ( )
2 2
4 2
5 1 3 3.61
Slide P.2 - 21 Copyright © 2011 Pearson, Inc.