mathematics

1. Name of the Teacher : Ashabai. B.S Std : IX
Name of the Subject : Mathematics Str : 40
Name of the Unit : hr¯¯nsâ AfhpIÄ Time : 45 minutes
Name of the Topic : hr¯¯nsâ Npäfhv Date :
CURRICULAR STATEMENTS
hr¯¯nsâ Npäfhv I­p]
nSn¡p¶p.
CONTENT ANALYSIS
Symbols : ss] → π, hr¯¯nsâ Bcw → ‘r’
Facts : ∎ hymkw IqSpt¼mÄ hr¯¯nsâ Npäfhv IqSp¶p.
∎GsXmcp hr¯¯nsâbpw Npäfhns hymkw sIm­v
lcn¨m In«p¶ kwJy Ft¸mgpw Øncambncn¡pw.

2. Concept : hr¯¯nsâ Npäfhv F¶ Bibw
Formula : hr¯¯nsâ Npäfhv = 2 πr ; r → hr¯¯nsâ Bcw
LEARNING OUTCOME
The student will be able to;
1) Recall the information about circles.
2) Describe the peculiarities of a circle
3) Interpret about the perimeter of a circle
4) Explain the concept of perimeter of a circle
5) Use the above concept in another familiar
6) Situation
7) Organise different elements fit within the solution
8) Judge the appropriateness of the above concept in a given problem
9) Accept the beauty of maths.
PRE-REQUISITES
Ip«nIÄ¡v hr¯w, hr¯ tI{μw, Bcw, hymkw F¶nhsb¡pdn¨pff Adnhv.
TEACHING LEARNING RESOURCES
Models and Charts:
1. hr¯¯nsâ amXrI
2. hr¯¯nsâ Npäfhv ImWmpff kq{XhmIyw FgpXnb NmÀ«v
3. {]iv ImÀUpIÄ

3. Class room Interaction Procedure Expected pupils response
Introduction
Hcp IYbneqsS ¢mÊv Bcw`n¡p¶p. A¸phnsâ hoSnv ASp¯v Hcp ¢ºv D­v.
AhnsS HmW¯nv [mcmfw
]cn]mSnIÄ Act§dmdp­v.
HmWw hcmdmbn A¸p ¢ºnse ]cn]mSnIÄ ImWm³ Im¯ncn¡pI bmWv.
A§s HmWw F¯n ¢ºnse ]cn]mSnIÄ XpS§n. ¢ºn DdnbSn, kpμcn¡v s]m«psXmSoÂ,A¯¸q¡f aÕcw,
ItkcIfn, apXemb Hcp]mSv aÕc§Ä D­mbncp
¶p. Ah³ FÃm aÕc§fpw nco£n¨p. ItkcIfn
aÕcambncp¶p ASp¯ Cw . ItkcIÄ tNÀ¯n«v Hcp {]tXyI BIrXnbn aÕcmÀ°nIÄ S¡p¶Xv Ah³
{i²n¨p. AXv GXv BIrXnbn Bbncn¡psa¶v n§Ä¡v ]dbmtam?
hfsc icnbmWv. A¸phnv ho­pw
Hcp kwibw. aÕcmÀ°nIÄ B hr¯w Hcp XhW Id§n hcpt¼mÄ AhÀ
F{X ZqcamWv k©cn¨Xv F¶v F§s Is­
¯pw?
Ah Hcp]mSv BtemNn¨p. ho«n F¯n A¸p Xsâ tN¨ntbmSv CsX¸än tNmZn¨p. At¸mÄ tN¨n ]dª
adp]Sn F´mbncn¡psa¶v n§Ä¡v Duln¡mtam?
hr¯w
hr¯¯nsâ Npäfhv Is­
¯n bm aXn F¶v Ip«nIÄ
]dªp.

4. Class room Interaction Procedure Expected pupils response
Presentation
Ip«nIsf {Kq¸mbn Xncn¨v Hmtcm {Kq¸npw hr¯¯nsâ amXrIbpw, qepw kvsIbnepw ÂIn. F¶n«v
AXnsâ Npäfhv , hymkw F¶nh ImWm³ Bhiys¸Sp¶p. In«nb Npäfhns hymkw sIm­v
lcn¨v Xmsg
X¶ncn¡p¶ ]«nI ]qÀ¯nbm¡m³ Bhiys¸Sp¶p.
Npäfhv hymkw Npäfhv/hymkw
XpSÀ¶pÅ NÀ¨bneqsSbpw hniZoIcW§fneqsSbpw hr¯¯nsâ Npäfhns hymkw sIm­v
lcn¨mÂ
In«p¶Xv Ft¸mgpw Hcp Ønc kwJy Bbncn¡psa¶pw AXns π F¶v kqNn¸n¡p¶psh¶pw
A²ym]nIbpsS klmbt¯msS hnZymÀ°nIÄ Is­
¯p¶p.
AXntmsSm¸w Xs¶ Npäfhv
hymkw
I­p]
nSn¡m³ π F¶ Ønc kwJysb hymkw sIm­v
KpWn¡Ww F¶pw A²ym]nIbpsS klmbt¯msS
hnZymÀ°nIÄ Is­
¯p¶p.
AXmbXv hr¯¯nsâ Npäfhv = 2 πr F¶v A²ym]nI t{ImUoIcn ¡p¶p.
Ip«nIÄ ]«nI ]qÀ¯nbm¡p¶p.
= π, F¶pw hr¯¯nsâ Npäfhv

5. Class room Interaction Procedure Expected pupils response
hr¯¯nsâ Npäfhv ImWp¶Xnsâ kq{XhmIyw FgpXnb NmÀ«v {]ZÀin¸n¡p¶p.
hr¯¯nsâ Npäfhv
‘r’F¶ Bcapff hr¯¯nsâ Npäfhv = 2 πr
Application/review
Hmtcm {Kq¸npw {]iv ImÀUpIÄ ÂIp¶p.
Ip«nIÄ NmÀ«v {i²tbmsS hmbn¡p¶p.
X¶n«pff hneIÄ r = 10 cm
hr¯¯nsâ Npäfhv
= 2 πr
= 2 x 3.14 x 10
= 62.8 cm2
X¶n«pff hneIÄ d = 8 cm
... r = 4 cm
hr¯¯nsâ Npäfhv
= 2 πr
= 2 x 3.14 x 4
= 25.12 cm
hr¯¯nsâ Bcw 10 cm BsW¦n AXnsâ Npäfhv I­p]
nSn¡pI?
( π = 3.14)
8 cm hymkapff Hcp hr¯¯nsâ Npäfhv I­p]
nSn¡pI
( π = 3.14)

6. FOLLOW UP ACTIVITIES
1. 10 cm hymkapff Hcp hr¯w hcbv¡pI. AXnp tijw AXnsâ Npäfhv I­p]
nSn¡pI.
2. Xmsg X¶ncn¡p¶ hr¯¯nsâ Npäfhve Is­
¯pI
4 cm