Draw a class diagram for the following scenario The following are t.pdf

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Draw a class diagram for the following scenario: The following are the requirements for a Society Membership System: The society has 10,000 members. For purposes of identification, each member has a unique membership number. It is important to know the following about each member : his/her Title, Name, Surname, Gender, Age. Each member of the society may or may not be related to other members, e.g, a Brother, or a sister. It is important to know who is related to whom and the nature of the relationship. The society consists of a number of chapters (each with a chapter number). Each member belongs to only one chapter at a time. The society has several special interest groups (SIGs) which are identified by a group number and have a description. The same group could exist in more than one chapter and a chapter could have many groups in it..

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Critical Thinking 10-7 Dynamic Mobile AccessThere are so many o.pdf

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Crisis Response Instructions In Module 4, you learned that every day, organizations are impacted by incidents and crises; some even threaten the integrity and survivability of their brand. How they respond will determine how consumers respond. Recent examples such as flight cancellations stranding passengers over the holidays and celebrity spokespeople making inflammatory statements or acting improperly come to mind. For this assignment, identify a real-world example of a public relations crisis which required an organization to address and respond. 1. Briefly describe the situation. Include a link to the story (optional). 2. What issues specifically concern the organization, brand, product, or service? 3. What communication/marketing channels did the organization use to advise customers of the situation? 4. How did the organization mitigate the problem and demonstrate customer care? 5. Do you believe they handled the situation effectively? 6. What would you have done differently?.

Crisis Response Instructions In Module 4, you learned that e.pdf

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Create a Schedule D and schedule 1 for this information, and the corresponding line 7 value on the 1040 form. Assuming, Rhonda is filing head of household with an AGI of 72,000 before the capital gain/loss information. 3. Rhonda received $250 in interest from Tulsa City bonds, $120 interest from IBM bonds, and $15 from her savings account at UCU Credit Union. She also received a $460 dividend from Huggies Company and $500 from Bicker Corporation. Both dividends are qualified dividends. 4. Rhonda sold 200 shares of DM stock for $18 a share on June 15, 2023. She purchased the stock on December 12, 2014, for $10 a share. She also sold 50 shares of RSA stock for $15 a share on October 2, 2023. She purchased the stock for $65 a share on February 2, 2023. Stock basis amounts and proceeds have been reported to the IRS with no adjustments required.

Create a Schedule D and schedule 1 for this information, and the cor.pdf

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Fix this code so that it will run with proper answers, please dont use chatgpt and please test your code before submitting: import sys import heapq import copy class PriorityQueue(): def __init__(self): self.thisQueue = [] def push(self, thisNode): heapq.heappush(self.thisQueue, (thisNode.val, -thisNode.id, thisNode)) def pop(self): return heapq.heappop(self.thisQueue)[2] def isEmpty(self): return len(self.thisQueue) == 0 def length(self): return len(self.thisQueue) class Set(): def __init__(self): self.thisSet = set() def add(self, entry): if entry is not None: self.thisSet.add(entry.__hash__()) def length(self): return len(self.thisSet) def isMember(self, query): return query.__hash__() in self.thisSet class Node(): def __init__(self, val, startstate, endstate, depth): global nodeid self.id = nodeid nodeid += 1 self.val = val self.state = startstate self.endstate = endstate self.depth = depth def __str__(self): return 'Node: id=%d val=%d' % (self.id, self.val) def expand(current_node, closedlist, goal_state): closedlist.add(current_node.state) successors = [] up_child = current_node.state.up() down_child = current_node.state.down() right_child = current_node.state.right() left_child = current_node.state.left() children = [left_child, right_child, up_child, down_child] for child in children: if child is not None and not closedlist.isMember(child): s = Node(0, child, None, current_node.depth + 1) s.parent_node = current_node if child == left_child: s.action = "left" elif child == right_child: s.action = "right" elif child == up_child: s.action = "up" elif child == down_child: s.action = "down" successors.append(s) return successors def h0(currenttiles, stiles): misplaced = 0 for i in range(len(stiles)): for j in range(len(currenttiles)): if stiles[i][j] != currenttiles[i][j]: misplaced += 1 return misplaced def manhattan(currenttiles, stiles): total = 0 for i in range(len(stiles)): for j in range(len(currenttiles)): if stiles[i][j] != currenttiles[i][j]: y = stiles[i][j] a = i b = j for k in range(len(stiles)): for l in range(len(stiles)): if currenttiles[k][l] == y: d = k e = l count = (abs(d - a) + abs(e - b)) total += count return total class State(): def __init__(self): self.xpos = 0 self.ypos = 0 self.tiles = [[0, 1, 2], [3, 4, 5], [6, 7, 8]] def left(self): if self.ypos == 0: return None s = self.copy() s.tiles[s.xpos][s.ypos] = s.tiles[s.xpos][s.ypos - 1] s.ypos -= 1 s.tiles[s.xpos][s.ypos] = 0 return s def right(self): if self.ypos == 2: return None s = self.copy() s.tiles[s.xpos][s.ypos] = s.tiles[s.xpos][s.ypos + 1] s.ypos += 1 s.tiles[s.xpos][s.ypos] = 0 return s def up(self): if self.xpos == 0: return None s = self.copy() s.tiles[s.xpos][s.ypos] = s.tiles[s.xpos - 1][s.ypos] s.xpos -= 1 s.tiles[s.xpos][s.ypos] = 0 return s def down(self): if self.xpos == 2: return None s = self.copy() s.tiles[s.xpos][s.ypos] = s.tiles[s.xpos + 1][s.ypos] s.xpos += 1 s.tiles[s.xpos][s.ypos] = 0 return s def __hash__(self): return (tuple(self.tiles[.

Fix this code so that it will run with proper answers, please dont u.pdf

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Five areas that financial ratios concentrate on area) liquidity.pdf

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double Skiplist code below #include #include #include #include #include #include #include "Node.h" #ifndef SKIPLIST_H #define SKIPLIST_H using namespace std; class SkipList{ public: // Maximum number of levels allowed for this skip list int MAXIMUM_ALLOWED_LEVELS; // current maximum level amongst the inserted nodes int level; // the head node's next links are connected to the first node at every level Node *head; SkipList(int maxLevels){ MAXIMUM_ALLOWED_LEVELS = maxLevels; // initially we have the bottom-most level only level = 0; // create the header node, value is irrelevant (as long as it doesn't match an inserted value - NO REPEATS), number of next links is important (this node is connected to the first node at every level) head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS); } int RandomLevel(){ float probablity = (float)rand()/RAND_MAX; // flip a coin int lvl = 0; /*Olog(n) */while (probablity < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS){ lvl++; // landed heads so increase level by 1 probablity = (float)rand()/RAND_MAX; // flip a coin again } return lvl; } Node* CreateNode(int value, int level){ // create a new node with next links for every level that this node will be part of // it will use these links to connect to the next node at each level return new Node(value, level); } void InsertElement(int value)/*Olog(n) becuase all the functions in it are Olog(n) */{ /** * THIS CODE HAS A BUG, * * ***********FIND THE BUG, * *************EXPLAIN THE WHY THE BUG EXIST * AND * **********************SUGGEST A FIX * * */ //w Node *current = head; // start at head node at the toppest level /*Olog(n)*/vector update(MAXIMUM_ALLOWED_LEVELS+1, nullptr); // this will hold the nodes that need updating at every level after the insert takes place /*BIG Olog(n)*/for (int i = level; i >= 0; i--){ //level is the current maximum level // for level i, if value is to be inserted here then find out where (i.e. after which node) /*O(1) constant */ while (current->next[i] != nullptr && current->next[i]->value < value){ //the while loop is saying keep moving right until null or the current.value > value current = current->next[i]; } // found the node after which the value is to be placed at level i update[i] = current; } //if current = current->next[0]; // current moves bcoz we need to check if the value exists if (current == nullptr || current->value != value){ /*Olog(n) */int ranLevel = RandomLevel(); // choose a random level upto where the new node will be placed if (ranLevel > level){ // if random level for current node is higher than the current maximum level for the existing nodes then set updates for each level over current maximum to head (since there are no nodes at these levels yet). /*Olog(n)*/for (int i=level+1;i<=ranLevel;i++){ update[i] = head; } // also change the current maximum level for the existing nodes level = ranLevel; } // create new node with next links for every level from ranLevel to zero /*Olog(n) */Node* n = CreateNode(value, ranLevel); // placi.

double Skiplist code below#include iostream#include vector.pdf

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Discuss the structure of intelligent agents in artificial intelligence systems. Explain the key components and their roles in designing an agent-based system. Consider the following components: perception, knowledge representation, decision-making, and action. Provide a detailed explanation of each component, including how they interact and contribute to the overall functioning of an intelligent agent. Additionally, describe different types of agent architectures, such as simple reflex agents, model- based agents, goal-based agents, and utility-based agents. Compare and contrast these architectures in terms of their strengths, weaknesses, and suitability for different problem domains. Finally, discuss the challenges associated with designing and implementing intelligent agent systems and propose potential solutions or strategies to address these challenges effectively..

Discuss the structure of intelligent agents in artificial intelligen.pdf

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Consider the following game in which Sally can play T or B and John chooses between L or R. Each player makes their choice simultaneously. If Sally chooses T and John chooses L, Sally gets a payoff of 5 and John has a payoff of 4. If Sally plays T and John R, Sallys payoff is 8 and John gets 3. If Sally Chooses B and John L, the payoffs are 3 to Sally and 2 to John. Finally, if Sally chooses B and John R, the payoffs are 7 to Sally and 0 to John. Which statement is true? Group of answer choices a) The Nash equilibrium is (B,R); this is a prisoners dilemma b) The Nash equilibrium is (T,R); this is a prisoners dilemma c) The Nash equilibrium is (T,R); this is not dominant strategy equilibrium d) The Nash equilibrium is (T,L); this is a dominant strategy equilibrium e) None of the above.

Consider the following game in which Sally can play T or B and John .pdf

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***Computer Networks*** Consider the following scenario involving a TCP connection with Host A and Host B. Manu wants to visualize the interactions involved when Host A sends four consecutive TCP packets containing 50 bytes each to Host B. He knows that due to network delays, Host A will finish sending these small packets before any reply can be received from Host B. Complete the diagram below (except on your own paper, of course), showing Manu all of the relevant data for the four packets sent and any relevant replies sent by Host B. Assume no packets are lost, and a reply is sent as soon as a packet is received. Please answer with a diagram with arrows between host A and host B with the SEQ, ACK, and LENS label on each one. Thank you!!.

Computer NetworksConsider the following scenario involving a.pdf

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Character.cpp/hpp given: Character.cpp: #include "Character.hpp" /** Default constructor. Default-initializes all private members. Default character name: "NAMELESS". Booleans are default-initialized to False. Default enum value: NONE. Default Vitality, Max Armor, and Level: 0. */ Character::Character():name_{"NAMELESS"},race_{NONE},vitality_{0},armor_{0},level_{0} ,enemy_{false} { } /** Parameterized constructor. @param : The name of the character (a string in UPPERCASE) @param : The race of the character (a string) @param : The character's vitality (a non-negative integer) , with default value 0 @param : The character's max armor level (a non-negative integer), with default value 0 @param : The character's level (a non-negative integer), with default value 0 @param : A flag indicating whether the character is an enemy, with default value false @post : The private members are set to the values of the corresponding parameters. Hint: Notice the default arguments in the parameterized constructor. If the given parameters are invalid, the default values are used instead. */ Character::Character(const std::string& name, const std::string& race, int vitality, int armor, int level, bool enemy) : Character() { setName(name); // checks valid name setRace(race); // checks valid race (vitality >= 0) ? vitality_ = vitality: vitality_ = 0; (armor >= 0) ? armor_ = armor: armor_ = 0; (level >= 0) ? level_ = level: level_ = 0; enemy_ = enemy; } /** @param : the name of the Character @post : sets the Character's title to the value of the parameter, in UPPERCASE. Only alphabetical characters are allowed. For example, attempting to create a character named "TW3EDLEDUM2" should create a character named "TWEDLEDUM". : If the given parameter does not have any valid alphabetical characters, the character's name should be set to "NAMELESS". */ void Character::setName(const std::string& name) { std::string nameUpper = ""; for(int i = 0; i= 0 : Characters cannot have negative health @post : sets the vitality private member to the value of the parameter */ void Character::setVitality(const int& vitality) { if (vitality >= 0) { vitality_ = vitality; } } /** @return : the value stored in vitality_ */ int Character::getVitality() const { return vitality_; } /** @param : an integer armor level @pre : armor >= 0 : Characters cannot have negative armor @post : sets the armor private member to the value of the parameter */ void Character::setArmor(const int& armor) { if (armor >= 0) { armor_ = armor; } } /** @return : the value stored in armor_ */ int Character::getArmor() const { return armor_; } /** @param : an integer level @pre : level >= 0 : Characters cannot have a negative @post : sets the level private member to the value of the parameter */ void Character::setLevel(const int& level) { if (level >= 0) { level_ = level; } } /** @return : the value stored in level_ */ int Character::getLevel() const { return level_; } /** @post : sets the enemy flag to true */ void Char.

Character.cpphpp givenCharacter.cpp#include Character.hp.pdf

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CNA STB 14 July 2022, STB said visitor arrival to Singapore are expected to increase to between 4 milion and 6 milion this year as global travel pick up pace the projection comes amid the easing of COVID 19 related border restriction globally, and pent up demand for travel." The following show various drawing of Singapore traval Cruise Terminal at Marina Bay South. The inisitutional property has 5 zone which are zone 1: roads leading into external driveway, drop off points, ingress, egress. Zone 2: Terminal buildings; zone 3- Carpark and coach for both 1st and 2nd floor, zone 4 - arrival and departure processing and zone 5: terminal buildings. You are require to do a goal setting and analysis can contribute to strategizing the increase in visitors at the Terminal which include, goals, anaylze current situation's, SWOT anaysis, Sky Key performance Indicator, Segment your audience and develop Strategies..

CNA STB 14 July 2022, STB said � visitor arrival to Singapore are ex.pdf

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Directions: # Caesar Cipher Implementation Your task in this homework is to construct a class to implement Caesar Cipher ## Specification ### __init__() method Define attributes that may be used in the following methods, such as key. ### Encrypt Message The objective of the `encrypt()` method is to encrypt a message using Caesar Cipher. The method should return the encrypted message. Started function: ```python def encrypt(self, plaintext): ''' Task 1: encrypt plaintext using caesar cipher ''' return True ``` ### Decript Message The objective of the `decrypt()` method is to decrypt a encrypted message using Caesar Cipher. The method should return the decrypted message. Started function: ```python def decrypt(self, ciphertext): ''' Task 2: decrypt ciphertext using caesar cipher ''' return True ``` ### Encrypt a File The objective of the `encrypt_file()` method is to encrypt the content in a file using Caesar Cipher and then write the encrypted content in another file. Started function: ```python def encrypt_file(self, input_filename, output_filename): ''' Task 3: encrypt the content in a file (input_filename) using caesar cipher and store the ciphertext in another file (output_filename) ''' pass ``` ### Decrypt a file The objective of the `decrypt_file()` method is to decrypt the content in a file using Caesar Cipher and then write the decrypted content in another file. Starter function: ```python def decrypt_file(self, input_filename, output_filename): ''' Task 4: decrypt the content in a file (input_filename) using caesar cipher and store the decrypted text in another file (output_filename) ''' pass ``` Task: caesar_cipher.py file from pathlib import Path class CaesarCipher: def __init__(self, key=3): pass def encrypt(self, plaintext): ''' Task 1: encrypt plaintext using caesar cipher ''' return True def decrypt(self, ciphertext): ''' Task 2: decrypt ciphertext using caesar cipher ''' return True def encrypt_file(self, input_filename, output_filename): ''' Task 3: encrypt the content in a file (input_filename) using caesar cipher and store the ciphertext in another file (output_filename) ''' pass def decrypt_file(self, input_filename, output_filename): ''' Task 4: decrypt the content in a file (input_filename) using caesar cipher and store the decrypted text in another file (output_filename) ''' pass if __name__ == "__main__": caesar_cipher = CaesarCipher() print(caesar_cipher.encrypt('This is a secret message! My password is XYZ.')) print(caesar_cipher.decrypt('Hello ABC!')) caesar_cipher.encrypt_file('secret_message.txt', 'encrypted_secret_message.txt') caesar_cipher.decrypt_file('encrypted_secret_message.txt', 'decrypted_text.txt') decrypted_text.txt file Hello, this is a secret message! Your password is NDSCsx&s091TSxsa^ encrypted_secret_message.txt Khoor, wklv lv d vhfuhw phvvdjh! Brxu sdvvzrug lv QGVFva&v091WVavd^ test_caesar_cipher.py import pytest from pathlib import Path from caesar_cipher import CaesarCipher def test_caesar_cipher_.

Directions# Caesar Cipher ImplementationYour task in this homew.pdf

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Describe the leadership of Captain Michael Davidson and second mate Danielle Randolph in light of theory. Consider the following questions in your description: Why did the captain ignore warnings about the threat that the hurricane posed to the ship? Identify quotes from the transcripts that reinforce your answers Why did the second mate not speak up more forcefully? Could she have changed the outcomes? What aspects of her past experience prevented her from asserting herself? Why didn't the crew challenge the commanding officer's decisions in spite of their concerns and level of expertise in the matter? What was the impact of the company's policies on the decision-making process? What other factors contributed to the failure of the captain and his subordinates to use their collective expertise to prevent disaster? Have you ever had a work experience where you can identify organizational cultural issues that create conditions and dynamics similar to El Faro's? If so, describe. In conclusion, what can we learn about this case that will make us better organizational managers and leaders?.

Describe the leadership of Captain Michael Davidson and second mate .pdf

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