Suppose that a single gene controls fruit colour in mongo. Yellow fru.pdf

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Suppose that a single gene controls fruit colour in mongo. Yellow fruit (Y-) is dominant to red fruit(yy). Suppose a true breeding yellow mongo plant was crossed with a red-fruited plant and the resulting F_1 was selfed. The F_2 segregation pattern was as expected. If one of the yellow- fruited plant was randomly selected and selfed, what is the probability that the progeny would segregate for fruit colour (i.e. red- and yellow-fruited progeny)? 3/4 2/3 1/4 1/2 none would segregate Solution Answer: b). 2/3 Explanation: Parents are true breeding means that they are homozygous so the F1 gen would be Yy do a punnet and see that a self cross will produce YY, Yy. yY and yy out of the 4 possible there are 3 that are yellow. One in 3 would be true breeding (all yellow offspring) and 2/3 would be heterozygous and produce the typical 3:1 yellow to red offspring. The F2 genotypes are YY (1/4), Yy(1/2) and yy (1/4). Thus, the yellow-fruited plant that was randomly picked could be either YY or Yy. There is a 1/3 chance that it was YY and 2/3 chance that it was Yy. If the YY plant was selected and selfed, the progeny would not segregate for fruit color. If the Yy plant was selected, the progeny would segregate for fruit color..

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5. If an organism were heterozygous for 10 loci, how many different combinations could the organism produce in its gametes? Show all your work to receive full credit. 6. In tomato plants, the production of red fruit color is under the control of an allele R. Yellow. tomatoes are rr. The dominant phenotype for fruit shape is under the control of an allele T. which produces two lobes. Multilobed fruit, the recessive phenotype, have the phenotype tt. Two different crosses are made between parental plants of unknown genotype and phenotype. Use the progeny phenotype ratios to determine the genotypes and phenotypes of each parent. (a) Cross 1 progeny: 3/8 two-lobed, red 3/8 two-lobed, yellow 1/8 multilobed, red 1/8 multilobed, yellow What are the genotypes and phenotypes of the parents in this cross?3. A tropicat fish fancier produced an albino zebra fish. it lacked blue stripes characteristic of the normal zebra fish. When she crossed a normal zebra fish to the albino, all the offspring were narmat. When she crossed two of the normal F1 offspring, y were abbino and % were normal. When an albino was crossed to the normal offspring, half were albino and half were normal. What is the genotype and phenotype of each fish mentioned in this problem? 4. In pea plants, the appearance of flowers along the main stem is a dominant phenotype called "axial" and is controlled by an allele T. The recessive phenotype, produced by an allele t, has flowers only at the end of the stem called "terminal". Pod form displays a dominant phenotype "inflated", controlled by allele F, and a recessive "constricted" form produced by allele f . A pure-breeding axial, constricted plant is crossed to one that is purebreeding terminal, inflated. A. The F1 progeny of this cross are allowed to self-fertilize. What is the expected phenotypic distribution of the F2 progeny? List the genotypes and phenotypes of the f1 generation and the phenotypes of the F2 progeny. B. If an F1 plant from the initial cross described above, is crossed to a plant that is terminal, constricted, what is the expected phenotypic distribution among the resulting progeny?.

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Question 1: Why was it important to start with true-breeding plants? Question 2: What phenotypic ratios did Mendel observe in the F2 generation of a dihybrid cross? Question 4: Would Mendel predict that you would get the same or different results from the cross of white males x scarlet females compared to its reciprocal? Solution Gregor Mendel wanted to know how parental traits are passed to the offspring. To get a clear concluding result without any mixed unexpected outcome or unexplained phenomenon Mendel wisely decided to start with pure breed i.e. known true breeding homozygous (pure dominant/recessive) pea plants (when selfed it produces same trait every time). In 1865 Mendel crossed two equal type of heterozygous pea plants with two characteristics to see outcome of dihybrid cross and discovered law of independent assortment. First he took pea plant of homozygous and dominant round (RR) yellow (YY) seeds and crossed with homozygous and recessive for wrinkled (rr) and green (yy) seeds and produced RrYy genotype heterozygous plants expressing dominant trait i.e. round and yellow seeds (F1 generation). Then he crossed two F1 plants (dihybrid cross: RrYy x RrYy). Phenotypic ratios did Mendel observed in his F2 generation of the dihybrid cross was 9:3:3:1::round & yellow: round & green: wrinkled & yellow: wrinkled & green. This is how he discovered parental trails sorted independently to next generation (linkage was not found). Mendel had not predicted that we would get the different results from the cross of white males x scarlet (Red eyed: Scarlet is a brilliant red colour with a tinge of orange) females compared to its reciprocal. Because the dominant scarlet colour of drosophila is a sex linked inheritance (present in sex chromosome) and the phenotypical output of a cross will arise differently as mended predicted. There is one X and one Y-chromosome in males while females have two X- chromosomes. In female only the dominant gene will produce red eye even if the individual is heterozygous for white allele..

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