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GRE QUANT
PERMUTATIONS AND COMBINATIONS, ALGEBRA,NUMBER
THEORY,CIRCLES, SIMILARITY
Question 1
A manager has the choose 6 persons. From the 11 candidates available, he has already chosen 3.
How many different combinations of the remaining candidates does the manager choose from
Since the manager has already chosen 3 candidates, he now has to choose 3 out of 8.
This can be done in 8𝐢3 =56 ways
Question 2
2 βˆ’ 5π‘₯ ≀
6π‘₯ βˆ’ 5
3
, π‘₯ ∈ 𝑅
Represent on a number line
6 βˆ’ 15π‘₯ ≀ 6π‘₯ βˆ’ 5
11≀ 21π‘₯
11
21
≀ π‘₯
0.5 ≀ π‘₯
0. 0.5. 1
Question 3
S consists of all the positive integers <81 that are not equal to the square of an intager
Quantity A Quantity B
Number of integers in S 72
Squares of integers <81 are 1, 4, 9, 16, 25, 36, 49, 64
These are 8 in number.
Number of integers in S = 80 – 8 = 72
The 2 quantities are equal
Question 4
What arclength is intercepted by an inscribed angle of 210 on a circle with radius = 12
B
21
A B
42
Required to find arclength AB
Angle at the centre = 420
π‘Žπ‘Ÿπ‘π‘™π‘’π‘›π‘”π‘‘β„Ž 𝐴𝐡 = π‘Ÿπœƒ
= 12 Γ— 42 Γ—
πœ‹
180
=17.6
A triangle is inscribed in a circle with shorter sides 3 cm and 4 cm. If the longer side is a diameter,
Find its length
If the longer side is a diameter, we use the
property, angle in a semicircle is a
right angle
3
4
By Pythagoras’ theorem, longer side is the hypotenuse which is 5 cm
QUESTION 5
Triangles PQR and XYZ are similar. If PQ= 6cm, PR = 4 cm, XY = 9 cm, find XZ
QUESTION 6
We draw a rough sketch
R
p
Q R
X
Y Z
6 4
9
x
We use the following property
Corresponding sides of similar triangles are proportional
𝑃𝑄
π‘‹π‘Œ
=
𝑃𝑅
𝑋𝑍
6
9
=
4
π‘₯ x= 6 cm
******************************

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GRE QUANT PERMUTATIONS AND COMBINATIONS, CIRCLES---

  • 1. GRE QUANT PERMUTATIONS AND COMBINATIONS, ALGEBRA,NUMBER THEORY,CIRCLES, SIMILARITY
  • 2. Question 1 A manager has the choose 6 persons. From the 11 candidates available, he has already chosen 3. How many different combinations of the remaining candidates does the manager choose from Since the manager has already chosen 3 candidates, he now has to choose 3 out of 8. This can be done in 8𝐢3 =56 ways
  • 3. Question 2 2 βˆ’ 5π‘₯ ≀ 6π‘₯ βˆ’ 5 3 , π‘₯ ∈ 𝑅 Represent on a number line 6 βˆ’ 15π‘₯ ≀ 6π‘₯ βˆ’ 5 11≀ 21π‘₯ 11 21 ≀ π‘₯ 0.5 ≀ π‘₯ 0. 0.5. 1
  • 4. Question 3 S consists of all the positive integers <81 that are not equal to the square of an intager Quantity A Quantity B Number of integers in S 72 Squares of integers <81 are 1, 4, 9, 16, 25, 36, 49, 64 These are 8 in number. Number of integers in S = 80 – 8 = 72 The 2 quantities are equal
  • 5. Question 4 What arclength is intercepted by an inscribed angle of 210 on a circle with radius = 12 B 21 A B 42 Required to find arclength AB Angle at the centre = 420 π‘Žπ‘Ÿπ‘π‘™π‘’π‘›π‘”π‘‘β„Ž 𝐴𝐡 = π‘Ÿπœƒ = 12 Γ— 42 Γ— πœ‹ 180 =17.6
  • 6. A triangle is inscribed in a circle with shorter sides 3 cm and 4 cm. If the longer side is a diameter, Find its length If the longer side is a diameter, we use the property, angle in a semicircle is a right angle 3 4 By Pythagoras’ theorem, longer side is the hypotenuse which is 5 cm QUESTION 5
  • 7. Triangles PQR and XYZ are similar. If PQ= 6cm, PR = 4 cm, XY = 9 cm, find XZ QUESTION 6 We draw a rough sketch R p Q R X Y Z 6 4 9 x
  • 8. We use the following property Corresponding sides of similar triangles are proportional 𝑃𝑄 π‘‹π‘Œ = 𝑃𝑅 𝑋𝑍 6 9 = 4 π‘₯ x= 6 cm ******************************