Please help me because i tried but i can\'t do it right how do i solve for : sin square theta - 2 sin theta - 3 = 0 Solution (2sin ? + 1)(sin ? - 2) = 0, sin ? = -1/2 or 2. Since sine cannot be greater than 1, sin ? = -1/2 ? = 7?/6 + 2k? and ? = 11?/6 + 2k? where k is any integer. Hope you was helped.