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Please give step by step and explain to get A+ rating Solution int f(x) dx (x from 0 to ) = 1 Thus int k.e-x/2 dx (x from 0 to ) = 1 -2k.e-x/2 (x from 0 to ) = 1 -2ke- - (-2ke0) = 1 0 + 2k = 1 k = 1/2 P(X >= 1) = int f(x) dx (x from 1 to ) = int 1/2 e-x/2 dx (x from 1 to ) = -e-x/2 (x from 1 to ) = -e- - (-e-1/2) = 0 + e-1/2 = e-1/2.
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Please help me to slove above integral. I little bit confused how to.pdf
Please help me to slove above integral. I little bit confused how to make it easy to integrate. Can
you please show me the working fully. tHank you
Solution
put lnx=y =>x=ey & dx=eydy... substitute these values in the integral and u get the answer.
Please help me solve questions below. Please give me crystal cle.pdf
Please help me solve questions below. Please give me crystal clear solutions.
I would like to see how to solve these problems a,b..
Solution
The method of moments estimator of λ = E(x)
E(x) = Σ x e^-λ λ^x / x!, x varies from 0 to infinity
= λ Σ e^-λ λ^(x-1) / (x-1)!, x from 1 to infinity
= λ
The first sample moment is xbar , the sample mean
Equating the sample and population means, the moment estimate of λ is xbar (the sample
mean).
Please help with the following practice questionsQuesti.pdf
Please help with the following practice questions:
Question 1
F can never be negative. a.
True. b.
False.
Question 2
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
Question 3
One drawback of ANOVA is that it allows type 1 error to escalate for every additional group
tested. Answer a.
True. b.
False.
Question 4
The sum of within-groups variance and between-group variance is the total variance. a.
True. b.
False.
Question 5
An ANOVA with one independent variable but four groups is known as a one-way ANOVA.
a.
True. b.
False.
Question 6
In ANOVA, where should you look for the treatment effect? a.
In the within-group variance. b.
In the between-group variance. c.
In the total variance. d.
Within a single individual\'s score.
Question 7
When the null hypothesis is true, the calculated F should be close to a.
0. b.
1. c.
Infinity. d.
There is not enough information to tell.
Question 8
The appropriate statistic to use when testing the hypothesis for a study with three treatment
groups is a a.
One-sample t test. b.
Two-sample t test. c.
ANOVA F test. d.
Either b or c is appropriate.
Question 9
The Tukey HSD is the a.
Smallest amount by which any two means must differ in order to be statistically significant.
b.
Smallest amount by which any two means actually do differ. c.
Largest amount by which any two means actually do differ. d.
Largest amount by which any two means can possibly differ.
Question 10
When and why would you conduct post hoc tests as a follow up to the overall F test? a.
When the overall F test is NOT significant; to determine which of the pairs of groups may be
significant. b.
When the overall F test is NOT significant; to determine why the overall F test is not significant.
c.
When the overall F test is significant; to determine between which pairs of groups the significant
difference lies. d.
When the overall F test IS significant; to determine if the significance is only the result of
chance.
Please help with the following practice questions:
Question 1
F can never be negative. a.
True. b.
False.
F can never be negative. a.
True. b.
False.
F can never be negative. a.
True. b.
False.
F can never be negative.
F can never be negative.
True.
False.
Question 2
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F.
True.
False.
Question 3
One drawback of ANOVA is that it al.
Please help me with my Assignment! Find the general solution of(.pdf
Please help me with my Assignment!
Find the general solution of
(d4y / dx4) + 4(d3y / dx3) + 8(d2y / dx2) + 8(dy/dx) + 4y = 0
Solution
The characteristic equation of the DE is:
r4 + 4r3 + 8r2 + 8r + 4 = 0
(r2 + 2r + 2)2 = 0
So the roots are:
-1-i , -1-i , -1+i , -1+i
Therefore the general solution is:
y = Ae-xcos(x) + Be-xsin(x) + C.xe-xcos(x) + D.xe-xsin(x)
Where A, B, C, and D are constants..
Please Help The content of magnesium in an alloy is a random variabl.pdf
Please Help The content of magnesium in an alloy is a random variable given by the following
probability density function: The profit form this alloy is P = 10 + 4X Find the probability
distribution of P. What is the expected profit E[P].
Solution
b) E[P]=10+4E[X]
=10+4 int from lim 0-sqrt 20(x* x/10)dx
=10+4[(1/10)*(x^3/3)]lim 0-sqrt 20
=10+4(20sqrt20/30-0/30)
=10+4(2.98)
=10+11.92
=21.92.
Please help me with this. I have the answer as you can see. I need t.pdf
Please help me with this. I have the answer as you can see. I need to know how to actually solve
it step by step. I cannot get it. I basically do not know the inbetween steps from the second line
and how it leads to the answer.RS = R0 + (B / S)(R0RB).1305 = R0 + (.30)(R0 .05)R0 =
.1117, or 11.17%
Solution
RS = R0 +(B/S)(R0-RB)
0.1305=R0+(0.30)(R0-0.05)
0.1305=R0+R0(0.30)-(0.30)(0.05)
0.1305=R0+R0(0.30)-0.015
0.1305+0.015=R0+R0(0.30)
0.1455=R0(1+0.30)
0.1455=R0(1.30)
0.1455/1.30=R0
R0=0.111923
R0=11.19%.
Please help Prove that the following functions are cumulative distri.pdf
Please help Prove that the following functions are cumulative distribution functions. 1/2+1pi
tan-1(x),x (-infinity, +infinity) 1-e -x, x (0,+infinity).
Solution
(a)when x->inf,,F(x)->1/2 + 1/pi (pi/2)=1/2 +1/2 =1
when x->-inf F(x)->1/2 - 1/2 =0.
Please help my maths question basically whats happened is that wher.pdf
Please help my maths question: basically whats happened is that where doing enlargements in
yr8! how do i prove that a x-1 enlargement is the same as the original shape using thses words...
bisect, parrallel, congruent (words like that) HELP
Solution
RESIPROCALL.
Recommended
Please help me to slove above integral. I little bit confused how to.pdf
Please help me to slove above integral. I little bit confused how to make it easy to integrate. Can
you please show me the working fully. tHank you
Solution
put lnx=y =>x=ey & dx=eydy... substitute these values in the integral and u get the answer.
Please help me solve questions below. Please give me crystal cle.pdf
Please help me solve questions below. Please give me crystal clear solutions.
I would like to see how to solve these problems a,b..
Solution
The method of moments estimator of λ = E(x)
E(x) = Σ x e^-λ λ^x / x!, x varies from 0 to infinity
= λ Σ e^-λ λ^(x-1) / (x-1)!, x from 1 to infinity
= λ
The first sample moment is xbar , the sample mean
Equating the sample and population means, the moment estimate of λ is xbar (the sample
mean).
Please help with the following practice questionsQuesti.pdf
Please help with the following practice questions:
Question 1
F can never be negative. a.
True. b.
False.
Question 2
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
Question 3
One drawback of ANOVA is that it allows type 1 error to escalate for every additional group
tested. Answer a.
True. b.
False.
Question 4
The sum of within-groups variance and between-group variance is the total variance. a.
True. b.
False.
Question 5
An ANOVA with one independent variable but four groups is known as a one-way ANOVA.
a.
True. b.
False.
Question 6
In ANOVA, where should you look for the treatment effect? a.
In the within-group variance. b.
In the between-group variance. c.
In the total variance. d.
Within a single individual\'s score.
Question 7
When the null hypothesis is true, the calculated F should be close to a.
0. b.
1. c.
Infinity. d.
There is not enough information to tell.
Question 8
The appropriate statistic to use when testing the hypothesis for a study with three treatment
groups is a a.
One-sample t test. b.
Two-sample t test. c.
ANOVA F test. d.
Either b or c is appropriate.
Question 9
The Tukey HSD is the a.
Smallest amount by which any two means must differ in order to be statistically significant.
b.
Smallest amount by which any two means actually do differ. c.
Largest amount by which any two means actually do differ. d.
Largest amount by which any two means can possibly differ.
Question 10
When and why would you conduct post hoc tests as a follow up to the overall F test? a.
When the overall F test is NOT significant; to determine which of the pairs of groups may be
significant. b.
When the overall F test is NOT significant; to determine why the overall F test is not significant.
c.
When the overall F test is significant; to determine between which pairs of groups the significant
difference lies. d.
When the overall F test IS significant; to determine if the significance is only the result of
chance.
Please help with the following practice questions:
Question 1
F can never be negative. a.
True. b.
False.
F can never be negative. a.
True. b.
False.
F can never be negative. a.
True. b.
False.
F can never be negative.
F can never be negative.
True.
False.
Question 2
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F.
True.
False.
Question 3
One drawback of ANOVA is that it al.
Please help me with my Assignment! Find the general solution of(.pdf
Please help me with my Assignment!
Find the general solution of
(d4y / dx4) + 4(d3y / dx3) + 8(d2y / dx2) + 8(dy/dx) + 4y = 0
Solution
The characteristic equation of the DE is:
r4 + 4r3 + 8r2 + 8r + 4 = 0
(r2 + 2r + 2)2 = 0
So the roots are:
-1-i , -1-i , -1+i , -1+i
Therefore the general solution is:
y = Ae-xcos(x) + Be-xsin(x) + C.xe-xcos(x) + D.xe-xsin(x)
Where A, B, C, and D are constants..
Please Help The content of magnesium in an alloy is a random variabl.pdf
Please Help The content of magnesium in an alloy is a random variable given by the following
probability density function: The profit form this alloy is P = 10 + 4X Find the probability
distribution of P. What is the expected profit E[P].
Solution
b) E[P]=10+4E[X]
=10+4 int from lim 0-sqrt 20(x* x/10)dx
=10+4[(1/10)*(x^3/3)]lim 0-sqrt 20
=10+4(20sqrt20/30-0/30)
=10+4(2.98)
=10+11.92
=21.92.
Please help me with this. I have the answer as you can see. I need t.pdf
Please help me with this. I have the answer as you can see. I need to know how to actually solve
it step by step. I cannot get it. I basically do not know the inbetween steps from the second line
and how it leads to the answer.RS = R0 + (B / S)(R0RB).1305 = R0 + (.30)(R0 .05)R0 =
.1117, or 11.17%
Solution
RS = R0 +(B/S)(R0-RB)
0.1305=R0+(0.30)(R0-0.05)
0.1305=R0+R0(0.30)-(0.30)(0.05)
0.1305=R0+R0(0.30)-0.015
0.1305+0.015=R0+R0(0.30)
0.1455=R0(1+0.30)
0.1455=R0(1.30)
0.1455/1.30=R0
R0=0.111923
R0=11.19%.
Please help Prove that the following functions are cumulative distri.pdf
Please help Prove that the following functions are cumulative distribution functions. 1/2+1pi
tan-1(x),x (-infinity, +infinity) 1-e -x, x (0,+infinity).
Solution
(a)when x->inf,,F(x)->1/2 + 1/pi (pi/2)=1/2 +1/2 =1
when x->-inf F(x)->1/2 - 1/2 =0.
Please help my maths question basically whats happened is that wher.pdf
Please help my maths question: basically whats happened is that where doing enlargements in
yr8! how do i prove that a x-1 enlargement is the same as the original shape using thses words...
bisect, parrallel, congruent (words like that) HELP
Solution
RESIPROCALL.
Please help me and explain 1. If all other agents choose a level of .pdf
Please help me and explain 1. If all other agents choose a level of activity e, the payoff of agent i
can be expressed as V(ei, e). In this case the optimization problem becomes max ei V(ei, e),
Using the optimization problem, show the the conditions for coordination failures. And also
discuss coordination failures with help of the game theoretical structures such as the battle of the
sexes, prisoners\' dilemma and the stag hunt bu giving the real cases in the economy.
Solution
Problem of coordination in a shared production process. Let ej be the effort (input) of
player i in the production of a public good, c. The production
function is c = f(ei,e) with fi > 0 and f2> 0. Agents have identical
utility functions defined over consumption and effort U(c,e), with
U1 > 0, U2 < 0, and U() quasi-concave. These preferences, together
with the production function, generate agent i\'s payoff function:
(1) V(ei,e) = U(f(ej,e),ej.
Note that V12= U1f2> 0, so the model exhibits positive
spillovers.
Differentiating the payoff function with respect to ei and e yields
(2) V12 = U1f12 + U1lflf2 + U12f2.
that preferences between consumption and effort are separable. A
necessary condition for strategic complementarity is then that
inputs be complementary within the production process (/12 > 0).
Increases in e will induce increases in ej if /12 is large enough to offset
the reduction in the marginal utility of consumption brought about
by f2 > 0. If U() is linear, /12 > 0 is sufficient for strategic
complementarities.
Note further that
- V12 UJ1/2 + Ullfl2
V1l -[U11 (fl)2 + U1f/1 + U22]
The necessary condition for multiplicity (p > 1) is
(4) U1(/12 + /11) + U1l[(/l)2 + /1/2] _ -U22.
Multiple Equilbria are thus more likely when the utility function is not very concave with
respect to consumption and effort; when inputs are highly complementary in production; and
when the production function is not very concave with respect to own effort..
Please help verify the identity showing the steps.1(sec-tan) = .pdf
Please help verify the identity showing the steps.
1/(sec?-tan?) = sec? + tan?
Thank you!
Solution
LHS: 1/(sect -tant)
Multiply sect +tant in both denominator and numerator.
= (sect +tant)/[(sect +tant)(sect -tant)]
= (sect +tant)/(sec^2t -tan^2t)
= (sect +tant)/1
= sect + tant ---> RHS.
Please help me aswer this...I will rate you life saving!!! Solu.pdf
Please help me aswer this...I will rate you life saving!!!
Solution
Oral cavity Pharynx Esophagus Stomach Duodenum Jejunum Ileum Cecum Ascending Colon
Transverse Colon DescendingColon Sigmoid Colon Rectum Anus Feces Human waste
Duodenum to the Ileum that isfrom the small intestine
Cecum to Rectum is from thelarge intestine
Duodenum to the Ileum that isfrom the small intestine
Cecum to Rectum is from thelarge intestine.
please help and be as detail as you can 1. Variation is a key .pdf
please help and be as detail as you can
1. Variation is a key statistic used in the most analytical studies. what are the implications of the
high level of variations vs. low level of variation in a sample data
2. what are the implications
Solution
1. In statistics, analysis of variance (ANOVA) is a collection of statistical models,
and their associated procedures, in which the observed variance in a particular variable is
partitioned into components attributable to different sources of variation. In its simplest form,
ANOVA provides a statistical test of whether or not the means of several groups are all equal,
and therefore generalizes t-test to more than two groups. Doing multiple two-sample t-tests
would result in an increased chance of committing a type I error. For this reason, ANOVAs are
useful in comparing two, three, or more means. 2. the act of implicating or the state of being
implicated.
Please help Lot, Xn and Yn have the distributions shown above. Fi.pdf
Please help
Lot, Xn and Yn have the distributions shown above. Find the expected value and variance of
Xn and Yn. What does the Chebyshev inequality\'- tell us about the convergence of Xn and Yn?
Is Yn convergent in probability? If so, to what value?
Solution
1. E(X) = 0*1/n + 1*1/n = 1/n ; V(X) = E(X^2) - (E(X))^2 = (0*1/n + 1*1/n) - (1/n)^2 = 1/n -
1/n^2 = (n-1)/(n^2)
E(Y) = 0*1/n + n*1/n = 1 ; V(Y) = E(Y^2) - (E(Y))^2 = (0*1/n + n^2/n) - (1) = n-1
2.Pr(|X-1/n|>k*sqrt(V(X))) <= 1/(k^2) for k>=1
Pr(|Y-1|>k*sqrt(V(Y))) <= 1/(k^2) for k>=1
3. No its not convergent as Sum of P(X) not converging to 1.
Please help me and explainGraphically show and verbally argue that.pdf
Please help me and explain
Graphically show and verbally argue that a Walrasian equiblirium in an economy is Pareto
efficient as long as preferences are locally non-satiated. How about convexity? ?s it important for
this theorem to hold ?
Solution
Walras Equil.
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Please help me and explain 1. If all other agents choose a level of .pdf
Please help me and explain 1. If all other agents choose a level of activity e, the payoff of agent i
can be expressed as V(ei, e). In this case the optimization problem becomes max ei V(ei, e),
Using the optimization problem, show the the conditions for coordination failures. And also
discuss coordination failures with help of the game theoretical structures such as the battle of the
sexes, prisoners\' dilemma and the stag hunt bu giving the real cases in the economy.
Solution
Problem of coordination in a shared production process. Let ej be the effort (input) of
player i in the production of a public good, c. The production
function is c = f(ei,e) with fi > 0 and f2> 0. Agents have identical
utility functions defined over consumption and effort U(c,e), with
U1 > 0, U2 < 0, and U() quasi-concave. These preferences, together
with the production function, generate agent i\'s payoff function:
(1) V(ei,e) = U(f(ej,e),ej.
Note that V12= U1f2> 0, so the model exhibits positive
spillovers.
Differentiating the payoff function with respect to ei and e yields
(2) V12 = U1f12 + U1lflf2 + U12f2.
that preferences between consumption and effort are separable. A
necessary condition for strategic complementarity is then that
inputs be complementary within the production process (/12 > 0).
Increases in e will induce increases in ej if /12 is large enough to offset
the reduction in the marginal utility of consumption brought about
by f2 > 0. If U() is linear, /12 > 0 is sufficient for strategic
complementarities.
Note further that
- V12 UJ1/2 + Ullfl2
V1l -[U11 (fl)2 + U1f/1 + U22]
The necessary condition for multiplicity (p > 1) is
(4) U1(/12 + /11) + U1l[(/l)2 + /1/2] _ -U22.
Multiple Equilbria are thus more likely when the utility function is not very concave with
respect to consumption and effort; when inputs are highly complementary in production; and
when the production function is not very concave with respect to own effort..
Please help verify the identity showing the steps.1(sec-tan) = .pdf
Please help verify the identity showing the steps.
1/(sec?-tan?) = sec? + tan?
Thank you!
Solution
LHS: 1/(sect -tant)
Multiply sect +tant in both denominator and numerator.
= (sect +tant)/[(sect +tant)(sect -tant)]
= (sect +tant)/(sec^2t -tan^2t)
= (sect +tant)/1
= sect + tant ---> RHS.
Please help me aswer this...I will rate you life saving!!! Solu.pdf
Please help me aswer this...I will rate you life saving!!!
Solution
Oral cavity Pharynx Esophagus Stomach Duodenum Jejunum Ileum Cecum Ascending Colon
Transverse Colon DescendingColon Sigmoid Colon Rectum Anus Feces Human waste
Duodenum to the Ileum that isfrom the small intestine
Cecum to Rectum is from thelarge intestine
Duodenum to the Ileum that isfrom the small intestine
Cecum to Rectum is from thelarge intestine.
please help and be as detail as you can 1. Variation is a key .pdf
please help and be as detail as you can
1. Variation is a key statistic used in the most analytical studies. what are the implications of the
high level of variations vs. low level of variation in a sample data
2. what are the implications
Solution
1. In statistics, analysis of variance (ANOVA) is a collection of statistical models,
and their associated procedures, in which the observed variance in a particular variable is
partitioned into components attributable to different sources of variation. In its simplest form,
ANOVA provides a statistical test of whether or not the means of several groups are all equal,
and therefore generalizes t-test to more than two groups. Doing multiple two-sample t-tests
would result in an increased chance of committing a type I error. For this reason, ANOVAs are
useful in comparing two, three, or more means. 2. the act of implicating or the state of being
implicated.
Please help Lot, Xn and Yn have the distributions shown above. Fi.pdf
Please help
Lot, Xn and Yn have the distributions shown above. Find the expected value and variance of
Xn and Yn. What does the Chebyshev inequality\'- tell us about the convergence of Xn and Yn?
Is Yn convergent in probability? If so, to what value?
Solution
1. E(X) = 0*1/n + 1*1/n = 1/n ; V(X) = E(X^2) - (E(X))^2 = (0*1/n + 1*1/n) - (1/n)^2 = 1/n -
1/n^2 = (n-1)/(n^2)
E(Y) = 0*1/n + n*1/n = 1 ; V(Y) = E(Y^2) - (E(Y))^2 = (0*1/n + n^2/n) - (1) = n-1
2.Pr(|X-1/n|>k*sqrt(V(X))) <= 1/(k^2) for k>=1
Pr(|Y-1|>k*sqrt(V(Y))) <= 1/(k^2) for k>=1
3. No its not convergent as Sum of P(X) not converging to 1.
Please help me and explainGraphically show and verbally argue that.pdf
Please help me and explain
Graphically show and verbally argue that a Walrasian equiblirium in an economy is Pareto
efficient as long as preferences are locally non-satiated. How about convexity? ?s it important for
this theorem to hold ?
Solution
Walras Equil.
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