Please help Prove that the following functions are cumulative distribution functions. 1/2+1pi
tan-1(x),x (-infinity, +infinity) 1-e -x, x (0,+infinity).
Solution
(a)when x->inf,,F(x)->1/2 + 1/pi (pi/2)=1/2 +1/2 =1
when x->-inf F(x)->1/2 - 1/2 =0.
Please help me to slove above integral. I little bit confused how to.pdfssusere778e6
Please help me to slove above integral. I little bit confused how to make it easy to integrate. Can
you please show me the working fully. tHank you
Solution
put lnx=y =>x=ey & dx=eydy... substitute these values in the integral and u get the answer.
Please help me solve questions below. Please give me crystal cle.pdfssusere778e6
Please help me solve questions below. Please give me crystal clear solutions.
I would like to see how to solve these problems a,b..
Solution
The method of moments estimator of λ = E(x)
E(x) = Σ x e^-λ λ^x / x!, x varies from 0 to infinity
= λ Σ e^-λ λ^(x-1) / (x-1)!, x from 1 to infinity
= λ
The first sample moment is xbar , the sample mean
Equating the sample and population means, the moment estimate of λ is xbar (the sample
mean).
Please help with the following practice questionsQuesti.pdfssusere778e6
Please help with the following practice questions:
Question 1
F can never be negative. a.
True. b.
False.
Question 2
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
Question 3
One drawback of ANOVA is that it allows type 1 error to escalate for every additional group
tested. Answer a.
True. b.
False.
Question 4
The sum of within-groups variance and between-group variance is the total variance. a.
True. b.
False.
Question 5
An ANOVA with one independent variable but four groups is known as a one-way ANOVA.
a.
True. b.
False.
Question 6
In ANOVA, where should you look for the treatment effect? a.
In the within-group variance. b.
In the between-group variance. c.
In the total variance. d.
Within a single individual\'s score.
Question 7
When the null hypothesis is true, the calculated F should be close to a.
0. b.
1. c.
Infinity. d.
There is not enough information to tell.
Question 8
The appropriate statistic to use when testing the hypothesis for a study with three treatment
groups is a a.
One-sample t test. b.
Two-sample t test. c.
ANOVA F test. d.
Either b or c is appropriate.
Question 9
The Tukey HSD is the a.
Smallest amount by which any two means must differ in order to be statistically significant.
b.
Smallest amount by which any two means actually do differ. c.
Largest amount by which any two means actually do differ. d.
Largest amount by which any two means can possibly differ.
Question 10
When and why would you conduct post hoc tests as a follow up to the overall F test? a.
When the overall F test is NOT significant; to determine which of the pairs of groups may be
significant. b.
When the overall F test is NOT significant; to determine why the overall F test is not significant.
c.
When the overall F test is significant; to determine between which pairs of groups the significant
difference lies. d.
When the overall F test IS significant; to determine if the significance is only the result of
chance.
Please help with the following practice questions:
Question 1
F can never be negative. a.
True. b.
False.
F can never be negative. a.
True. b.
False.
F can never be negative. a.
True. b.
False.
F can never be negative.
F can never be negative.
True.
False.
Question 2
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F.
True.
False.
Question 3
One drawback of ANOVA is that it al.
Please help me with my Assignment! Find the general solution of(.pdfssusere778e6
Please help me with my Assignment!
Find the general solution of
(d4y / dx4) + 4(d3y / dx3) + 8(d2y / dx2) + 8(dy/dx) + 4y = 0
Solution
The characteristic equation of the DE is:
r4 + 4r3 + 8r2 + 8r + 4 = 0
(r2 + 2r + 2)2 = 0
So the roots are:
-1-i , -1-i , -1+i , -1+i
Therefore the general solution is:
y = Ae-xcos(x) + Be-xsin(x) + C.xe-xcos(x) + D.xe-xsin(x)
Where A, B, C, and D are constants..
Please Help The content of magnesium in an alloy is a random variabl.pdfssusere778e6
Please Help The content of magnesium in an alloy is a random variable given by the following
probability density function: The profit form this alloy is P = 10 + 4X Find the probability
distribution of P. What is the expected profit E[P].
Solution
b) E[P]=10+4E[X]
=10+4 int from lim 0-sqrt 20(x* x/10)dx
=10+4[(1/10)*(x^3/3)]lim 0-sqrt 20
=10+4(20sqrt20/30-0/30)
=10+4(2.98)
=10+11.92
=21.92.
Please help me with this. I have the answer as you can see. I need t.pdfssusere778e6
Please help me with this. I have the answer as you can see. I need to know how to actually solve
it step by step. I cannot get it. I basically do not know the inbetween steps from the second line
and how it leads to the answer.RS = R0 + (B / S)(R0RB).1305 = R0 + (.30)(R0 .05)R0 =
.1117, or 11.17%
Solution
RS = R0 +(B/S)(R0-RB)
0.1305=R0+(0.30)(R0-0.05)
0.1305=R0+R0(0.30)-(0.30)(0.05)
0.1305=R0+R0(0.30)-0.015
0.1305+0.015=R0+R0(0.30)
0.1455=R0(1+0.30)
0.1455=R0(1.30)
0.1455/1.30=R0
R0=0.111923
R0=11.19%.
Please help my maths question basically whats happened is that wher.pdfssusere778e6
Please help my maths question: basically whats happened is that where doing enlargements in
yr8! how do i prove that a x-1 enlargement is the same as the original shape using thses words...
bisect, parrallel, congruent (words like that) HELP
Solution
RESIPROCALL.
Please help me and explain 1. If all other agents choose a level of .pdfssusere778e6
Please help me and explain 1. If all other agents choose a level of activity e, the payoff of agent i
can be expressed as V(ei, e). In this case the optimization problem becomes max ei V(ei, e),
Using the optimization problem, show the the conditions for coordination failures. And also
discuss coordination failures with help of the game theoretical structures such as the battle of the
sexes, prisoners\' dilemma and the stag hunt bu giving the real cases in the economy.
Solution
Problem of coordination in a shared production process. Let ej be the effort (input) of
player i in the production of a public good, c. The production
function is c = f(ei,e) with fi > 0 and f2> 0. Agents have identical
utility functions defined over consumption and effort U(c,e), with
U1 > 0, U2 < 0, and U() quasi-concave. These preferences, together
with the production function, generate agent i\'s payoff function:
(1) V(ei,e) = U(f(ej,e),ej.
Note that V12= U1f2> 0, so the model exhibits positive
spillovers.
Differentiating the payoff function with respect to ei and e yields
(2) V12 = U1f12 + U1lflf2 + U12f2.
that preferences between consumption and effort are separable. A
necessary condition for strategic complementarity is then that
inputs be complementary within the production process (/12 > 0).
Increases in e will induce increases in ej if /12 is large enough to offset
the reduction in the marginal utility of consumption brought about
by f2 > 0. If U() is linear, /12 > 0 is sufficient for strategic
complementarities.
Note further that
- V12 UJ1/2 + Ullfl2
V1l -[U11 (fl)2 + U1f/1 + U22]
The necessary condition for multiplicity (p > 1) is
(4) U1(/12 + /11) + U1l[(/l)2 + /1/2] _ -U22.
Multiple Equilbria are thus more likely when the utility function is not very concave with
respect to consumption and effort; when inputs are highly complementary in production; and
when the production function is not very concave with respect to own effort..
Please help me to slove above integral. I little bit confused how to.pdfssusere778e6
Please help me to slove above integral. I little bit confused how to make it easy to integrate. Can
you please show me the working fully. tHank you
Solution
put lnx=y =>x=ey & dx=eydy... substitute these values in the integral and u get the answer.
Please help me solve questions below. Please give me crystal cle.pdfssusere778e6
Please help me solve questions below. Please give me crystal clear solutions.
I would like to see how to solve these problems a,b..
Solution
The method of moments estimator of λ = E(x)
E(x) = Σ x e^-λ λ^x / x!, x varies from 0 to infinity
= λ Σ e^-λ λ^(x-1) / (x-1)!, x from 1 to infinity
= λ
The first sample moment is xbar , the sample mean
Equating the sample and population means, the moment estimate of λ is xbar (the sample
mean).
Please help with the following practice questionsQuesti.pdfssusere778e6
Please help with the following practice questions:
Question 1
F can never be negative. a.
True. b.
False.
Question 2
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
Question 3
One drawback of ANOVA is that it allows type 1 error to escalate for every additional group
tested. Answer a.
True. b.
False.
Question 4
The sum of within-groups variance and between-group variance is the total variance. a.
True. b.
False.
Question 5
An ANOVA with one independent variable but four groups is known as a one-way ANOVA.
a.
True. b.
False.
Question 6
In ANOVA, where should you look for the treatment effect? a.
In the within-group variance. b.
In the between-group variance. c.
In the total variance. d.
Within a single individual\'s score.
Question 7
When the null hypothesis is true, the calculated F should be close to a.
0. b.
1. c.
Infinity. d.
There is not enough information to tell.
Question 8
The appropriate statistic to use when testing the hypothesis for a study with three treatment
groups is a a.
One-sample t test. b.
Two-sample t test. c.
ANOVA F test. d.
Either b or c is appropriate.
Question 9
The Tukey HSD is the a.
Smallest amount by which any two means must differ in order to be statistically significant.
b.
Smallest amount by which any two means actually do differ. c.
Largest amount by which any two means actually do differ. d.
Largest amount by which any two means can possibly differ.
Question 10
When and why would you conduct post hoc tests as a follow up to the overall F test? a.
When the overall F test is NOT significant; to determine which of the pairs of groups may be
significant. b.
When the overall F test is NOT significant; to determine why the overall F test is not significant.
c.
When the overall F test is significant; to determine between which pairs of groups the significant
difference lies. d.
When the overall F test IS significant; to determine if the significance is only the result of
chance.
Please help with the following practice questions:
Question 1
F can never be negative. a.
True. b.
False.
F can never be negative. a.
True. b.
False.
F can never be negative. a.
True. b.
False.
F can never be negative.
F can never be negative.
True.
False.
Question 2
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F. a.
True. b.
False.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F.
If the HSD is 22, a paired mean difference of 23 would indicate that that pair contributed toward
the significant F.
True.
False.
Question 3
One drawback of ANOVA is that it al.
Please help me with my Assignment! Find the general solution of(.pdfssusere778e6
Please help me with my Assignment!
Find the general solution of
(d4y / dx4) + 4(d3y / dx3) + 8(d2y / dx2) + 8(dy/dx) + 4y = 0
Solution
The characteristic equation of the DE is:
r4 + 4r3 + 8r2 + 8r + 4 = 0
(r2 + 2r + 2)2 = 0
So the roots are:
-1-i , -1-i , -1+i , -1+i
Therefore the general solution is:
y = Ae-xcos(x) + Be-xsin(x) + C.xe-xcos(x) + D.xe-xsin(x)
Where A, B, C, and D are constants..
Please Help The content of magnesium in an alloy is a random variabl.pdfssusere778e6
Please Help The content of magnesium in an alloy is a random variable given by the following
probability density function: The profit form this alloy is P = 10 + 4X Find the probability
distribution of P. What is the expected profit E[P].
Solution
b) E[P]=10+4E[X]
=10+4 int from lim 0-sqrt 20(x* x/10)dx
=10+4[(1/10)*(x^3/3)]lim 0-sqrt 20
=10+4(20sqrt20/30-0/30)
=10+4(2.98)
=10+11.92
=21.92.
Please help me with this. I have the answer as you can see. I need t.pdfssusere778e6
Please help me with this. I have the answer as you can see. I need to know how to actually solve
it step by step. I cannot get it. I basically do not know the inbetween steps from the second line
and how it leads to the answer.RS = R0 + (B / S)(R0RB).1305 = R0 + (.30)(R0 .05)R0 =
.1117, or 11.17%
Solution
RS = R0 +(B/S)(R0-RB)
0.1305=R0+(0.30)(R0-0.05)
0.1305=R0+R0(0.30)-(0.30)(0.05)
0.1305=R0+R0(0.30)-0.015
0.1305+0.015=R0+R0(0.30)
0.1455=R0(1+0.30)
0.1455=R0(1.30)
0.1455/1.30=R0
R0=0.111923
R0=11.19%.
Please help my maths question basically whats happened is that wher.pdfssusere778e6
Please help my maths question: basically whats happened is that where doing enlargements in
yr8! how do i prove that a x-1 enlargement is the same as the original shape using thses words...
bisect, parrallel, congruent (words like that) HELP
Solution
RESIPROCALL.
Please help me and explain 1. If all other agents choose a level of .pdfssusere778e6
Please help me and explain 1. If all other agents choose a level of activity e, the payoff of agent i
can be expressed as V(ei, e). In this case the optimization problem becomes max ei V(ei, e),
Using the optimization problem, show the the conditions for coordination failures. And also
discuss coordination failures with help of the game theoretical structures such as the battle of the
sexes, prisoners\' dilemma and the stag hunt bu giving the real cases in the economy.
Solution
Problem of coordination in a shared production process. Let ej be the effort (input) of
player i in the production of a public good, c. The production
function is c = f(ei,e) with fi > 0 and f2> 0. Agents have identical
utility functions defined over consumption and effort U(c,e), with
U1 > 0, U2 < 0, and U() quasi-concave. These preferences, together
with the production function, generate agent i\'s payoff function:
(1) V(ei,e) = U(f(ej,e),ej.
Note that V12= U1f2> 0, so the model exhibits positive
spillovers.
Differentiating the payoff function with respect to ei and e yields
(2) V12 = U1f12 + U1lflf2 + U12f2.
that preferences between consumption and effort are separable. A
necessary condition for strategic complementarity is then that
inputs be complementary within the production process (/12 > 0).
Increases in e will induce increases in ej if /12 is large enough to offset
the reduction in the marginal utility of consumption brought about
by f2 > 0. If U() is linear, /12 > 0 is sufficient for strategic
complementarities.
Note further that
- V12 UJ1/2 + Ullfl2
V1l -[U11 (fl)2 + U1f/1 + U22]
The necessary condition for multiplicity (p > 1) is
(4) U1(/12 + /11) + U1l[(/l)2 + /1/2] _ -U22.
Multiple Equilbria are thus more likely when the utility function is not very concave with
respect to consumption and effort; when inputs are highly complementary in production; and
when the production function is not very concave with respect to own effort..
Please help me aswer this...I will rate you life saving!!! Solu.pdfssusere778e6
Please help me aswer this...I will rate you life saving!!!
Solution
Oral cavity Pharynx Esophagus Stomach Duodenum Jejunum Ileum Cecum Ascending Colon
Transverse Colon DescendingColon Sigmoid Colon Rectum Anus Feces Human waste
Duodenum to the Ileum that isfrom the small intestine
Cecum to Rectum is from thelarge intestine
Duodenum to the Ileum that isfrom the small intestine
Cecum to Rectum is from thelarge intestine.
please help and be as detail as you can 1. Variation is a key .pdfssusere778e6
please help and be as detail as you can
1. Variation is a key statistic used in the most analytical studies. what are the implications of the
high level of variations vs. low level of variation in a sample data
2. what are the implications
Solution
1. In statistics, analysis of variance (ANOVA) is a collection of statistical models,
and their associated procedures, in which the observed variance in a particular variable is
partitioned into components attributable to different sources of variation. In its simplest form,
ANOVA provides a statistical test of whether or not the means of several groups are all equal,
and therefore generalizes t-test to more than two groups. Doing multiple two-sample t-tests
would result in an increased chance of committing a type I error. For this reason, ANOVAs are
useful in comparing two, three, or more means. 2. the act of implicating or the state of being
implicated.
Please give step by step and explain to get A+ ratingSolutioni.pdfssusere778e6
Please give step by step and explain to get A+ rating
Solution
int f(x) dx (x from 0 to ) = 1
Thus
int k.e-x/2 dx (x from 0 to ) = 1
-2k.e-x/2 (x from 0 to ) = 1
-2ke- - (-2ke0) = 1
0 + 2k = 1
k = 1/2
P(X >= 1) = int f(x) dx (x from 1 to ) =
int 1/2 e-x/2 dx (x from 1 to ) =
-e-x/2 (x from 1 to ) =
-e- - (-e-1/2) = 0 + e-1/2 = e-1/2.
Please help Lot, Xn and Yn have the distributions shown above. Fi.pdfssusere778e6
Please help
Lot, Xn and Yn have the distributions shown above. Find the expected value and variance of
Xn and Yn. What does the Chebyshev inequality\'- tell us about the convergence of Xn and Yn?
Is Yn convergent in probability? If so, to what value?
Solution
1. E(X) = 0*1/n + 1*1/n = 1/n ; V(X) = E(X^2) - (E(X))^2 = (0*1/n + 1*1/n) - (1/n)^2 = 1/n -
1/n^2 = (n-1)/(n^2)
E(Y) = 0*1/n + n*1/n = 1 ; V(Y) = E(Y^2) - (E(Y))^2 = (0*1/n + n^2/n) - (1) = n-1
2.Pr(|X-1/n|>k*sqrt(V(X))) <= 1/(k^2) for k>=1
Pr(|Y-1|>k*sqrt(V(Y))) <= 1/(k^2) for k>=1
3. No its not convergent as Sum of P(X) not converging to 1.
Please help me and explainGraphically show and verbally argue that.pdfssusere778e6
Please help me and explain
Graphically show and verbally argue that a Walrasian equiblirium in an economy is Pareto
efficient as long as preferences are locally non-satiated. How about convexity? ?s it important for
this theorem to hold ?
Solution
Walras Equil.
THE SACRIFICE HOW PRO-PALESTINE PROTESTS STUDENTS ARE SACRIFICING TO CHANGE T...indexPub
The recent surge in pro-Palestine student activism has prompted significant responses from universities, ranging from negotiations and divestment commitments to increased transparency about investments in companies supporting the war on Gaza. This activism has led to the cessation of student encampments but also highlighted the substantial sacrifices made by students, including academic disruptions and personal risks. The primary drivers of these protests are poor university administration, lack of transparency, and inadequate communication between officials and students. This study examines the profound emotional, psychological, and professional impacts on students engaged in pro-Palestine protests, focusing on Generation Z's (Gen-Z) activism dynamics. This paper explores the significant sacrifices made by these students and even the professors supporting the pro-Palestine movement, with a focus on recent global movements. Through an in-depth analysis of printed and electronic media, the study examines the impacts of these sacrifices on the academic and personal lives of those involved. The paper highlights examples from various universities, demonstrating student activism's long-term and short-term effects, including disciplinary actions, social backlash, and career implications. The researchers also explore the broader implications of student sacrifices. The findings reveal that these sacrifices are driven by a profound commitment to justice and human rights, and are influenced by the increasing availability of information, peer interactions, and personal convictions. The study also discusses the broader implications of this activism, comparing it to historical precedents and assessing its potential to influence policy and public opinion. The emotional and psychological toll on student activists is significant, but their sense of purpose and community support mitigates some of these challenges. However, the researchers call for acknowledging the broader Impact of these sacrifices on the future global movement of FreePalestine.
Elevate Your Nonprofit's Online Presence_ A Guide to Effective SEO Strategies...TechSoup
Whether you're new to SEO or looking to refine your existing strategies, this webinar will provide you with actionable insights and practical tips to elevate your nonprofit's online presence.
CapTechTalks Webinar Slides June 2024 Donovan Wright.pptxCapitolTechU
Slides from a Capitol Technology University webinar held June 20, 2024. The webinar featured Dr. Donovan Wright, presenting on the Department of Defense Digital Transformation.
Philippine Edukasyong Pantahanan at Pangkabuhayan (EPP) CurriculumMJDuyan
(𝐓𝐋𝐄 𝟏𝟎𝟎) (𝐋𝐞𝐬𝐬𝐨𝐧 𝟏)-𝐏𝐫𝐞𝐥𝐢𝐦𝐬
𝐃𝐢𝐬𝐜𝐮𝐬𝐬 𝐭𝐡𝐞 𝐄𝐏𝐏 𝐂𝐮𝐫𝐫𝐢𝐜𝐮𝐥𝐮𝐦 𝐢𝐧 𝐭𝐡𝐞 𝐏𝐡𝐢𝐥𝐢𝐩𝐩𝐢𝐧𝐞𝐬:
- Understand the goals and objectives of the Edukasyong Pantahanan at Pangkabuhayan (EPP) curriculum, recognizing its importance in fostering practical life skills and values among students. Students will also be able to identify the key components and subjects covered, such as agriculture, home economics, industrial arts, and information and communication technology.
𝐄𝐱𝐩𝐥𝐚𝐢𝐧 𝐭𝐡𝐞 𝐍𝐚𝐭𝐮𝐫𝐞 𝐚𝐧𝐝 𝐒𝐜𝐨𝐩𝐞 𝐨𝐟 𝐚𝐧 𝐄𝐧𝐭𝐫𝐞𝐩𝐫𝐞𝐧𝐞𝐮𝐫:
-Define entrepreneurship, distinguishing it from general business activities by emphasizing its focus on innovation, risk-taking, and value creation. Students will describe the characteristics and traits of successful entrepreneurs, including their roles and responsibilities, and discuss the broader economic and social impacts of entrepreneurial activities on both local and global scales.
Temple of Asclepius in Thrace. Excavation resultsKrassimira Luka
The temple and the sanctuary around were dedicated to Asklepios Zmidrenus. This name has been known since 1875 when an inscription dedicated to him was discovered in Rome. The inscription is dated in 227 AD and was left by soldiers originating from the city of Philippopolis (modern Plovdiv).
How to Download & Install Module From the Odoo App Store in Odoo 17Celine George
Custom modules offer the flexibility to extend Odoo's capabilities, address unique requirements, and optimize workflows to align seamlessly with your organization's processes. By leveraging custom modules, businesses can unlock greater efficiency, productivity, and innovation, empowering them to stay competitive in today's dynamic market landscape. In this tutorial, we'll guide you step by step on how to easily download and install modules from the Odoo App Store.
Please help me aswer this...I will rate you life saving!!! Solu.pdfssusere778e6
Please help me aswer this...I will rate you life saving!!!
Solution
Oral cavity Pharynx Esophagus Stomach Duodenum Jejunum Ileum Cecum Ascending Colon
Transverse Colon DescendingColon Sigmoid Colon Rectum Anus Feces Human waste
Duodenum to the Ileum that isfrom the small intestine
Cecum to Rectum is from thelarge intestine
Duodenum to the Ileum that isfrom the small intestine
Cecum to Rectum is from thelarge intestine.
please help and be as detail as you can 1. Variation is a key .pdfssusere778e6
please help and be as detail as you can
1. Variation is a key statistic used in the most analytical studies. what are the implications of the
high level of variations vs. low level of variation in a sample data
2. what are the implications
Solution
1. In statistics, analysis of variance (ANOVA) is a collection of statistical models,
and their associated procedures, in which the observed variance in a particular variable is
partitioned into components attributable to different sources of variation. In its simplest form,
ANOVA provides a statistical test of whether or not the means of several groups are all equal,
and therefore generalizes t-test to more than two groups. Doing multiple two-sample t-tests
would result in an increased chance of committing a type I error. For this reason, ANOVAs are
useful in comparing two, three, or more means. 2. the act of implicating or the state of being
implicated.
Please give step by step and explain to get A+ ratingSolutioni.pdfssusere778e6
Please give step by step and explain to get A+ rating
Solution
int f(x) dx (x from 0 to ) = 1
Thus
int k.e-x/2 dx (x from 0 to ) = 1
-2k.e-x/2 (x from 0 to ) = 1
-2ke- - (-2ke0) = 1
0 + 2k = 1
k = 1/2
P(X >= 1) = int f(x) dx (x from 1 to ) =
int 1/2 e-x/2 dx (x from 1 to ) =
-e-x/2 (x from 1 to ) =
-e- - (-e-1/2) = 0 + e-1/2 = e-1/2.
Please help Lot, Xn and Yn have the distributions shown above. Fi.pdfssusere778e6
Please help
Lot, Xn and Yn have the distributions shown above. Find the expected value and variance of
Xn and Yn. What does the Chebyshev inequality\'- tell us about the convergence of Xn and Yn?
Is Yn convergent in probability? If so, to what value?
Solution
1. E(X) = 0*1/n + 1*1/n = 1/n ; V(X) = E(X^2) - (E(X))^2 = (0*1/n + 1*1/n) - (1/n)^2 = 1/n -
1/n^2 = (n-1)/(n^2)
E(Y) = 0*1/n + n*1/n = 1 ; V(Y) = E(Y^2) - (E(Y))^2 = (0*1/n + n^2/n) - (1) = n-1
2.Pr(|X-1/n|>k*sqrt(V(X))) <= 1/(k^2) for k>=1
Pr(|Y-1|>k*sqrt(V(Y))) <= 1/(k^2) for k>=1
3. No its not convergent as Sum of P(X) not converging to 1.
Please help me and explainGraphically show and verbally argue that.pdfssusere778e6
Please help me and explain
Graphically show and verbally argue that a Walrasian equiblirium in an economy is Pareto
efficient as long as preferences are locally non-satiated. How about convexity? ?s it important for
this theorem to hold ?
Solution
Walras Equil.
THE SACRIFICE HOW PRO-PALESTINE PROTESTS STUDENTS ARE SACRIFICING TO CHANGE T...indexPub
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𝐄𝐱𝐩𝐥𝐚𝐢𝐧 𝐭𝐡𝐞 𝐍𝐚𝐭𝐮𝐫𝐞 𝐚𝐧𝐝 𝐒𝐜𝐨𝐩𝐞 𝐨𝐟 𝐚𝐧 𝐄𝐧𝐭𝐫𝐞𝐩𝐫𝐞𝐧𝐞𝐮𝐫:
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Please help Prove that the following functions are cumulative distri.pdf
1. Please help Prove that the following functions are cumulative distribution functions. 1/2+1pi
tan-1(x),x (-infinity, +infinity) 1-e -x, x (0,+infinity).
Solution
(a)when x->inf,,F(x)->1/2 + 1/pi (pi/2)=1/2 +1/2 =1
when x->-inf F(x)->1/2 - 1/2 =0