Requirements for chapter summaries: 1. Each summary must be typed as a SINGLE paragraph with a 12 pt font and single-spaced with 1” margins on all sides. 2. You must discuss EVERY topic of the chapter for the sections that are listed in the schedule. If you leave out a topic, then you will get no credit no matter the length of your summary. 3. Each summary must be written entirely in your own words (No equations allowed!). Do not copy the wording in the textbook or from any other source. Such acts are plagiarism and constitute academic dishonesty; see http://www.utoledo.edu/policies/academic/undergraduate/pdfs/3364-71-04 Academic dishonesty.pdf. Optical character recognition and plagiarism software is ubiquitous and we use it regularly. You will automatically fail the course if you are guilty of plagiarism to any degree. 4. The very first line will include your name, the chapter number and your recitation section number in the following format: Alex Newton Chapter 47 Summary Recitation 03 5. You will skip the second line and start your summary on the third line of the page. Write the entire summary in a single paragraph. See the example summary at the end of the syllabus. 6. Your summary must contain at least 35 lines of text, covering every section of the entire chapter. Absolutely no bullets or numbered lists are allowed! If your summary is acceptable, a check-mark will be place on your quiz or exam. If not acceptable, then no check-mark will be place on the quiz/exam. 7. Only hard copies of each summary are accepted! You cannot submit them via email! 8. Print each summary at least one day before it is due so you don’t miss the deadline because of a printing problem! You can submit chapter summaries early, if you wish. 9. Each summary must be submitted by 9:25:00 AM (as measured by my timepiece) on the day it is due. Note that 9:25:01 AM is too late! 10. You must submit your chapter summary either on the table in MH 1005 on Friday morning or give it to me directly. You are never allowed to submit your chapter summary in any other way. 11. All summaries must be on a SINGLE sheet of paper. If your summary is longer than one page, you can also use the back of that single sheet of paper. 12. All summaries longer than a single sheet of paper will be thrown away and you will get no credit. 13. Attempting to submit a late chapter summary will result in a penalty (of -2 chapter summaries for each late chapter summary attempted) to your extra credit score. 14. If you will miss class on a Friday because of an excused absence, you must turn in the summary before its due date, except in the case of a documented emergency (such as illness). 15. Submitting acceptable summaries for all 16 chapters will result in your final exam score being increased by 20% of your score. If you submit only some of the summaries, you will receive the appropriate amount of extra credit (e.g., 9/16 of 20% if you submit 9 acceptable summaries). 16. As an example, if you did a ...

1. Requirements for chapter summaries:
1. Each summary must be typed as a SINGLE paragraph with a
12 pt font and single-spaced with 1”
margins on all sides.
2. You must discuss EVERY topic of the chapter for the
sections that are listed in the schedule. If you
leave out a topic, then you will get no credit no matter the
length of your summary.
3. Each summary must be written entirely in your own words
(No equations allowed!). Do not copy the
wording in the textbook or from any other source. Such acts are
plagiarism and constitute academic
dishonesty; see
http://www.utoledo.edu/policies/academic/undergraduate/pdfs/3
364-71-04
Academic dishonesty.pdf. Optical character recognition and
plagiarism software is ubiquitous and we
use it regularly. You will automatically fail the course if you
are guilty of plagiarism to any degree.
4. The very first line will include your name, the chapter
number and your recitation section number in the
following format:
Alex Newton Chapter 47 Summary Recitation 03
5. You will skip the second line and start your summary on the
third line of the page. Write the entire
summary in a single paragraph. See the example summary at the
end of the syllabus.
6. Your summary must contain at least 35 lines of text, covering
every section of the entire chapter.
Absolutely no bullets or numbered lists are allowed! If your
summary is acceptable, a check-mark will
be place on your quiz or exam. If not acceptable, then no check-
mark will be place on the quiz/exam.
7. Only hard copies of each summary are accepted! You cannot

2. submit them via email!
8. Print each summary at least one day before it is due so you
don’t miss the deadline because of a printing
problem! You can submit chapter summaries early, if you wish.
9. Each summary must be submitted by 9:25:00 AM (as
measured by my timepiece) on the day it is due.
Note that 9:25:01 AM is too late!
10. You must submit your chapter summary either on the table
in MH 1005 on Friday morning or give it to
me directly. You are never allowed to submit your chapter
summary in any other way.
11. All summaries must be on a SINGLE sheet of paper. If your
summary is longer than one page, you can
also use the back of that single sheet of paper.
12. All summaries longer than a single sheet of paper will be
thrown away and you will get no credit.
13. Attempting to submit a late chapter summary will result in a
penalty (of -2 chapter summaries for each
late chapter summary attempted) to your extra credit score.
14. If you will miss class on a Friday because of an excused
absence, you must turn in the summary before
its due date, except in the case of a documented emergency
(such as illness).
15. Submitting acceptable summaries for all 16 chapters will
result in your final exam score being increased
by 20% of your score. If you submit only some of the
summaries, you will receive the appropriate
amount of extra credit (e.g., 9/16 of 20% if you submit 9
acceptable summaries).
16. As an example, if you did all the extra credit and received
an 88 on the final, then your extra credit would
be 0.20 × 88 = 17.6, making your final exam score = 88 + 17.6
= 105.6.
17. All summaries must be given directly to me or turned in at
the time of the quiz or exam. You can never
give your chapter summary to your TA, put it in my mailbox or

3. slide it under my office door.
18. You can always submit chapter summaries to me early! I
encourage you to do that.
On the next page is an example of the correct format for a
chapter summary
Alex Newton Chapter 47 Summary
Recitation # 3
This chapter discusses the factors which affect the conformation
of the doublehelical
deoxyribonucleic acid (DNA) molecule. The conformation of
the DNA molecule
is obviously of great importance to its biological function, as
described in the
introduction of this chapter. Transcription, the process by which
the genetic code is read
from a gene, involves the unwinding of the double helix into a
flat structure vaguely
similar to a ladder. The two strands are separated and a single
strand of messenger RNA
is created by base-pairing with the template strand. The details
of the unwinding of the
double helix will depend on the initial geometry of the double
helix. Consequently, it is
important to understand the factors which control the
conformation of double-helical
DNA. These factors include the local charges of the DNA
molecule, the nature of the
counterion, the Coulombic interaction, the hydrophobicity of
the bases, the electrolytic
strength and water content of the environment and bonding with
neighboring molecules.
The DNA molecule is composed hydrogen, carbon, nitrogen,
oxygen and phosphorous
atoms. Since these atoms have different electronegativities, they
do not “share” the

4. electrons of their covalent bonds equally. This causes atoms
with a higher
electronegativity to have a net negative charge while atoms with
a lower electronegativity
to have a net positive charge. These locally charged regions
interact via the Coulombic
interactions, affecting the conformation of the molecule.
Coulombic interactions are also
important since each basepair has a net charge of -2e. All of
these Coulombic
interactions are affected by the local water content because of
the very high dielectric
constant of water. This makes water a very effective screener of
the Coulombic
interaction. Consequently, the water content of the sample can
have very significant
affects on the conformation. Similarly, for DNA in solution, the
electrolytic strength of
the solution can greatly alter the conformation. The four bases
of DNA (adenine,
thymine, guanine and cytosine) are hydrophobic in nature.
Consequently they are found
on the inside of the phosphodiester backbones composed of
deoxyribose and phosphate
groups. This geometry minimizes interactions between the bases
and water. Their base
pairing (A-T and G-C) permits for a smooth double helix since
the two basepairs are
almost identical in size. If they were significantly different in
size, the phosphodiester
backbone would not be a smooth helix. Van der Waals
interactions between stacked
bases affect the temperature stability of the double helix.
Hydrogen bonding between the
bases and between the DNA molecule and its local water of
hydration also has significant

5. effects on the conformation of the DNA. Counterions are
necessary for DNA to cancel
the -2e charge of each base pair. The various counterions (Na+
or K+, for instance) can
participate in electrostatic bonding between neighboring DNA
molecules or molecules
(such as proteins) near the DNA molecules. Such bonding
between neighboring DNA
molecules is relevant to our study of chromosomes in which the
DNA is packed in a
highly condensed state. Histones (composed of proteins) are
incorporated in the
chromosomes by having the DNA wrapped around the histones.
These intermolecular
interactions (similar to the intermolecular interactions of solid
DNA) are critical for
chromosome’s stability. Exactly how these interactions are
modified during the
replication of a chromosome is currently a mystery to science.
report
by Report Report
Submission dat e : 30- Jan- 2018 01:22PM (UT C- 0800)
Submission ID: 908903331
File name : NEW.do cx (33.32K)
Word count : 124 7
Charact e r count : 6918

6. 20%
SIMILARIT Y INDEX
10%
INT ERNET SOURCES
1%
PUBLICAT IONS
19%
ST UDENT PAPERS
1 4%
2 4%
3 2%
4 2%
5 1%
6 1%
7 1%
8 1%

7. report
ORIGINALITY REPORT
PRIMARY SOURCES
Submitted to Trident University International
St udent Paper
Submitted to Southern New Hampshire
University - Continuing Education
St udent Paper
Submitted to Laureate Higher Education Group
St udent Paper
Submitted to South Iredell High School
St udent Paper
Submitted to Kolej Mara Banting
St udent Paper
Submitted to University of Witwatersrand
St udent Paper
Submitted to Singapore International School
(Hong Kong)
St udent Paper
Submitted to University College London
St udent Paper
9 1%
10 1%

8. 11 1%
12 1%
Exclude quo tes Of f
Exclude biblio graphy Of f
Exclude matches Of f
www.dtic.mil
Int ernet Source
diva-portal.org
Int ernet Source
brainmass.com
Int ernet Source
Submitted to Li Po Chun United World College
St udent Paper
FINAL GRADE
/0
report
GRADEMARK REPORT
GENERAL COMMENTS
Instructor
PAGE 1

9. PAGE 2
PAGE 3
PAGE 4
PAGE 5
PAGE 6
PAGE 7
PAGE 8
reportby Report ReportreportORIGINALITY
REPORTPRIMARY SOURCESreportGRADEMARK
REPORTFINAL GRADEGENERAL COMMENTSInstructor
Alex Newton Chapter 8 Summary
Recitation # 4
Linear Motion is a product of specific systems mass and its
velocity. Linear momentum is a vector quantity. Linear motion
acts in the same direction as the velocity direction of a body.
Several principles have been made to explain the theory behind
linear motion. This chapter looks at these set principles which
govern bodies in momentum. From Newtons second law of
momentum “The net exterior force is the same as the change in
momentum of a system allover the time over which it changes”.
The relationship between force and momentum exist if and only
if mass is a constant. Impulse is an integral of force over an
interval of time for which it acts. Since force is a vector
quantity, then impulse is a vector quantity acting in the
direction of the force. Impulse has a standard unit of
measurement usually newton second. Any resultant force causes
acceleration resulting to change in the velocity of a body. This
depends on the exposure period and the amount of force

10. exerted. A bigger change in linear motion will result from a
large force exacted. Momentum can be conserved, revisiting the
Newtons law “action and reaction forces are equal and
opposite”. This law can be used to prove that in every single
interaction there is a pair of contradicting force. For the system
of the forces acting against each other to balance, the force
should be equivalent. The law of momentum conservation states
that for colliding bodies the momentum before and after
colliding is equal. This means that the moments lost by the first
body should be equivalent to the moments attained by the
second body. Elastic impact is an encounter amongst bodies
whereby the overall dynamic energy is conserved. Dynamic
energy is the work required to speed-up a body whose mass is
known from its state of rest to a certain velocity. Energy that a
body possess at its state of rest is potential energy. This means
that the dynamic energy within the bodies earlier or at the latter
of a collision do not change. Net conservation of kinetic energy
does not occur because during the collision some energy is
transformed to heat or noise. In the energy conversion a state of
repulse is reached first (potential energy) before transformation
to other forms of energy. An inelastic collision in one-
dimension results to a change in the interior dynamic energy
which is not preserved. After the impact, the objects may twig
together resulting a perfect inelastic collision situation resulting
to a reduction in internal kinetic energy. Collision of bodies
may occur in two dimensions. This assume a case of a body in
motion colliding with a body at rest (velocity=0). After the
collision the velocity of the body in motion decrease meaning
the collision results to loss in kinetic energy. Lastly, rocket
propulsion uses the principle of Newtons third law which
conditions action and rejoinder forces to be equivalent and
contrary. The acceleration of a skyrocket depends on the drain
of blasts velocity which triggers its acceleration. An
explanation of skyrocket at the lift-off stage, the motors of the
skyrocket force hot air out. Proving the law associated, the
burning gases thrust the rocket in the opposite (vertical)

11. direction. This action results to the propulsion of the skyrocket.
If the rocket burns its fuel at a faster rate the its acceleration is
fast too and finally the slighter the skyrocket mass the higher
the rate at which it speeds-up. The thrust increases as the
skyrocket reduces its mass meaning that the change in velocity
will increase with time. This can also be explained by the
reduced pull by the gravitational force.