Write a parallel program using MPI and not OpeMP to accomp.pdf
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Write a parallel program using MPI (and not OpeMP) to accomplish the same as the following serial program. For the following serial program the user enters a line and the program outputs the number of occurrences of each printable character (but not the space or tab character). For the parallel program if we have p processes we should divide the line into p segments and let each process counts the characters of its segment. #include<stdio.h> #include<stdlib.h> #include <string.h> #define ASCIIs 127 //ASCII characters from 0 to 127 #define atmost 1000 char letters[atmost + 1]; //Extra location for the string terminator '0' int total_count[ASCIIs]; void find(int count[], int start, int end); int main() { int i, processes, n, start, end; int count[ASCIIs], my_rank, segment, p; printf("Enter a line not larger than 1000 characters.n"); fgets(letters, atmost,stdin); printf("How many segments?: "); scanf("%d", &processes); //To make the length of the divisible by processes: while(strlen(letters) % processes != 0) strcat(letters, " "); n = strlen(letters); for(i = 0; i < ASCIIs; i++) total_count[i] = 0; for(p = 0; p < processes; p++) { my_rank = p; segment = n / processes; start = my_rank * segment; end = start + segment; find(count, start, end); for(i = 0; i <= ASCIIs; i++) total_count[i] += count[i]; } for(i = 33; i < ASCIIs; i++) if(total_count[i] != 0) printf("Number of %c is: %dn", i, total_count[i]); return 0; } void find(int count[], int start, int end) { int i; for(i = 0; i < ASCIIs; i++) count[i] = 0; for(i = start; i < end; i++) count[(int)letters[i]]++; }.
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![Write a parallel program using MPI (and not OpeMP) to accomplish the same as the following
serial program. For the following serial program the user enters a line and the program outputs the
number of occurrences of each printable character (but not the space or tab character).
For the parallel program if we have p processes we should divide the line into p segments and let
each process counts the characters of its segment.
#include<stdio.h>
#include<stdlib.h>
#include <string.h>
#define ASCIIs 127 //ASCII characters from 0 to 127
#define atmost 1000
char letters[atmost + 1]; //Extra location for the string terminator '0'
int total_count[ASCIIs];
void find(int count[], int start, int end);
int main()
{
int i, processes, n, start, end;
int count[ASCIIs], my_rank, segment, p;
printf("Enter a line not larger than 1000 characters.n");
fgets(letters, atmost,stdin);
printf("How many segments?: ");
scanf("%d", &processes);
//To make the length of the divisible by processes:
while(strlen(letters) % processes != 0) strcat(letters, " ");
n = strlen(letters);
for(i = 0; i < ASCIIs; i++)
total_count[i] = 0;
for(p = 0; p < processes; p++)
{
my_rank = p;
segment = n / processes;
start = my_rank * segment;
end = start + segment;
find(count, start, end);
for(i = 0; i <= ASCIIs; i++)
total_count[i] += count[i];
}
for(i = 33; i < ASCIIs; i++)
if(total_count[i] != 0)
printf("Number of %c is: %dn", i, total_count[i]);
return 0;
}
void find(int count[], int start, int end)](https://image.slidesharecdn.com/writeaparallelprogramusingmpiandnotopemptoaccomp-230316104945-73e3d97d/85/Write-a-parallel-program-using-MPI-and-not-OpeMP-to-accomp-pdf-1-320.jpg)
![{
int i;
for(i = 0; i < ASCIIs; i++)
count[i] = 0;
for(i = start; i < end; i++)
count[(int)letters[i]]++;
}](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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Here will be the output generated, minus the gap. That\'s just the end of the page.
Solution
int main(int argc, char *argv[]) {
#include
FILE *ptr_file;
char buf[1000];
int digit[10];
int alpha[26];
int other=0;
char alp=65;
int i;
for(i=0;i<=9;i++)
digit[i]=0;
for(i=0;i<=25;i++)
alpha[i]=0;
ptr_file =fopen(\"D:/input.txt\",\"r\");
if (!ptr_file)
return 1;
while (fgets(buf,1000, ptr_file)!=NULL)
printf(\"\ Original File:=>\ \");
printf(\"%s\ \",buf);
fclose(ptr_file);
for(i=0;buf[i]!=NULL;i++)
{
//Digits Count
if(buf[i]==\'0\')
digit[0]=digit[0]+1;
if(buf[i]==\'1\')
digit[1]=digit[1]+1;
if(buf[i]==\'2\')
digit[2]=digit[2]+1;
if(buf[i]==\'3\')
digit[3]=digit[3]+1;
if(buf[i]==\'4\')
digit[4]=digit[4]+1;
if(buf[i]==\'5\')
digit[5]=digit[0]+1;
if(buf[i]==\'6\')
digit[6]=digit[6]+1;
if(buf[i]==\'7\')
digit[7]=digit[7]+1;
if(buf[i]==\'8\')
digit[8]=digit[8]+1;
if(buf[i]==\'9\')
digit[9]=digit[9]+1;
//Alphabatic count
if(buf[i]==\'a\'||buf[i]==\'A\')
alpha[0]=alpha[0]+1;
if(buf[i]==\'b\'||buf[i]==\'B\')
alpha[1]=alpha[1]+1;
if(buf[i]==\'c\'||buf[i]==\'C\')
alpha[2]=alpha[2]+1;
if(buf[i]==\'d\'||buf[i]==\'D\')
alpha[3]=alpha[3]+1;
if(buf[i]==\'e\'||buf[i]==\'E\')
alpha[4]=alpha[4]+1;
if(buf[i]==\'f\'||buf[i]==\'F\')
alpha[5]=alpha[5]+1;
if(buf[i]==\'g\'||buf[i]==\'G\')
alpha[6]=alpha[6]+1;
if(buf[i]==\'h\'||buf[i]==\'H\')
alpha[7]=alpha[7]+1;
if(buf[i]==\'i\'||buf[i]==\'I\')
alpha[8]=alpha[8]+1;
if(buf[i]==\'j\'||buf[i]==\'J\')
alpha[9]=alpha[9]+1;
if(buf[i]==\'k\'||buf[i]==\'K\')
alpha[10]=alpha[10]+1;
if(buf[i]==\'l\'||buf[i]==\'L\')
alpha[11]=alpha[11]+1;
if(buf[i]==\'m\'||buf[i]==\'M\')
alpha[12]=alpha[12]+1;
if(buf[i]==\'n\'||buf[i]==\'N\')
alpha[13]=alpha[13]+1;
if(buf[i]==\'o\'||buf[i]==\'O\')
alpha[14]=alpha[14]+1;
if(bu.
Basic of c programming www.eakanchha.com
Understand basic concept of c programming with more than 100 error free programs. use of header file and different symbols in c programs. for better and complete understanding login to www.eakanchha.com
INPUT AND OUTPUT PROCESSINGPlease note that the material o.docx
INPUT AND OUTPUT PROCESSING
Please note that the material on this website is not intended to be exhaustive.
This is intended as a summary and supplementary material to required textbook.
INTRODUCTION
Most computer programs spend very little processing time in obtaining input and producing output.
Most of the work goes into the processing in between. The exception to this generalization is non-
browser-based graphical user interfaces (GUIs). In these programs, often over 50% of the code can be
dedicated to user input and output. In browser-based user interfaces, the browser does a lot of the work
for you.
Input/output (I/O) comes in two flavors: interactive and non-interactive. Interactive I/O involves
prompting the user for the input and displaying the output on the user's monitor. Non-interactive I/O
involves reading and writing files, which for us will be text files.
INTERACTIVE I/O
The majority of interactive I/O is accomplished in C++ using cin and cout. For now all interactive I/O
comes from and goes to the console window. Recall that in order to use cin and cout we have to
#include <iostream>.
The cin input stream views the input the user types as if the data came from a text file. But, cin ignores
as data all whitespace characters: the newline, the tab, and the space. As a result cin does some input
formatting for the program, and only assigns non-whitespace data to the input variables.
If the user is entering several data items on one line (in the console window), cin will wait for the user to
press the newline (Enter or Return) key before it will process the line of input data.
The input stream can consist of any array of characters, representing: integers, decimals, strings, single
characters, .... Each array of characters is delimited by whitespace characters, and cin will interpret any
of the whitespace characters as a delimiter (with some exceptions, of course).
When we invoke cin we always have to specify a variable in which to place the user input; that variable
must have a type. And, cin is very persnickety about types. If cin is expecting an integer, it will not read
an alphabetic character; it will generate an error condition. In the following code snippet cin will expect
to see a single character, an integer, a decimal, and a string, in that order.
char yOrN;
int userID;
double hourlyWage;
string lastName;
...
cin >> yOrN >> userID >> hourlyWage >> lastName;
If the user typed the last name for the userID, cin will flag an error and not continue to read the input
stream until your program deals with that error (see below).
The cout output stream has a lot more variety to it; cout is aware of the types of variables passed to it,
and will format them accordingly, unless your program specifies another format to use. When thinking
about the arrangement of your program's output, consider each string of output characters as a field, and
the contents of each line of output as an array of fields. T.
Similar to Write a parallel program using MPI and not OpeMP to accomp.pdf (20)
Bsc cs i pic u-4 function, storage class and array and strings
Bsc cs i pic u-4 function, storage class and array and strings
Mcai pic u 4 function, storage class and array and strings
Mcai pic u 4 function, storage class and array and strings
Using the Ceasar Cipher encryption algorithm, you take each characte.pdf
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CBSE Class 12 Computer practical Python Programs and MYSQL
CBSE Class 12 Computer practical Python Programs and MYSQL
Fundamental of C Programming Language and Basic Input/Output Function
Fundamental of C Programming Language and Basic Input/Output Function
You are required to open an input file (shown below) then read one c.pdf
You are required to open an input file (shown below) then read one c.pdf
INPUT AND OUTPUT PROCESSINGPlease note that the material o.docx
INPUT AND OUTPUT PROCESSINGPlease note that the material o.docx
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ZZZZ En yi Durum
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olan yllk dnemde, irketin net geliri 200.000 $'n altndan 50 milyon $'lk gelirle 5 milyon $'n zerine kt.
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1987 baharnn sonlarnda, Minkow'un irketteki hisselerinin piyasa deeri 100 milyon dolar aarken,
ZZZZ Best'in toplam piyasa deeri 200 milyon dolar at. lkenin en gen CEO'su, Los Angeles'n sekin
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