The mission of University is the transformation of the whole person .pdf

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the distirbution of test scores for a class is approx. symmetric with a mean of 72 and a standard deviation of 6. the z-score for a test score of 63 is? the z-score for a test score of 87 is? the percent of test scores between 66 and 78 is? the test score that has a z-score of z = 2.5: is? 95% of the test scores are between what values? Woudl a test score of 54 be considered \"unusual\" why? Solution the z-score for a test score of 63 is? Z = (x - u)/sigma = (63-72)/6 = -1.5 [ANSWER] ********* the z-score for a test score of 87 is? Z = (x - u)/sigma = (87-72)/6 = 2.5 [ANSWER] ****************** the percent of test scores between 66 and 78 is? As there are 1 standard deviation from the mean, around 68% are between 66 and 78. [ANSWER, 68%] ******************* the test score that has a z-score of z = 2.5: is? x =u + z*s = 72 + (-2.5)*6 = 57 [ANSWER] *************** 95% of the test scores are between what values? These are within 2 standard deviations (2*6 = 12) from the mean, so it is 72 - 12 to 72 + 12 or 60 to 84. [ANSWER] ******************** Woudl a test score of 54 be considered \"unusual\" why? z = (X-u)/sigma = (54-72)/6 = -3 As |z| > 2, then YES, IT IS UNUSUAL. [ANSWER].

The mission of University is the transformation of the whole person and our four key values are:
Transformation, Community, Truth and Service. Why do you want to attend NNU and how do
you see yourself contributing to these institutional values?
Solution
Education is enlightment and transformation of person with 4 values namely
Transformation,Community,Truth and service.I want to attend NNU to gain knowledge and
increase market value besides enlightment,transformation,Community,Truth and service.My
joining NNU will add to all above values to society.
Mihir Manek
Cell 91-9892298896 and manek6503@yahoo.com

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visit a local specialty store(e.g., sporting goods, cooking product, electronics) and identify a generic product or commodity that might be de-commoditized and differential through innovation . the name of the book is design of pruduct edition 6th ch3 q1 Solution Decommoditization is the opposite of commidization, where the value of product enriched and differentiated through innovation and enrichment. In electronics one thing is LED bulb. Now most of the elecetronics manufacturer produce LED bulb which save energy and have more life. It can be de-commoditized by innovation and adding value in the LED bulb.Now people are using smartphone and GPS based tracking so through innovation one can control the lighting of home through mobile device in a remote location. Through voice command in wireless device one should switch on and switch off the light..

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Validating Credit Cards Credit card numbers are not randomly chosen. There are rules that determine which credit card numbers are valid. This is a limited attempt to prevent fraud. If you just make up some number, it is unlikely to be valid. You are going to write a program to determine if a number is a valid credit card number. A credit card number must have between 13 and 16 digits. The first digit or two deter mines what type of card it is: Begins with Card Type Visa MasterCard 37 American Express Discover For our purposes, a number that doesn\'t begin with one of these sequences is not a valid credit card number. The algorithm for validating credit cards is credited to Hans Luhn of IBM. To illustrate the algorithm, we will use the sample number 4388576018402626. First, we see that this must be a Visa card, since it starts with 4. To validate it 1. Double every second digit from right to left. If doubling of a digit results in a two- digit number, add up the two digits to get a single-digit number. 2 2 4 2 2 4 2 38 1 2 12 2 3) 5 2 8 2 16 (1 6-7) 4 2 2. Now, add all the single digit numbers from the previous step. 4 4 8 2 3 1 7 8 37 3. Add all the digits in the odd places from right to left in the number. 6 6 0 8 0 7 8 3 38 4. Add these two values together. 37 38 75 Solution #include #include #include int main(void) { double cardnumber; printf(\"Give me a number: \ \"); scanf(\"%lf\", &cardnumber); if(cardnumber < 1000000000000 || cardnumber > 10000000000000000) { printf(\"INVALID\ \"); return 0; } if(cardnumber < 100000000000000 && cardnumber > 9999999999999) { printf(\"INVALID\ \"); return 0; } char creditcard[17]; sprintf(creditcard, \"%f\", cardnumber); char* ptr_cc; ptr_cc = strtok(creditcard,\".\"); int card_size = strlen(ptr_cc); int sum = 0; for(int i = 1; i < card_size; i+=2) { int x = creditcard[card_size-1-i] - \'0\'; int prod = 2 * x; if(prod>=10) { prod = prod%10 + prod/prod%10; } sum += prod; } for(int i = 0; i < card_size; i+=2) { int x = creditcard[card_size-1-i] - \'0\'; sum += x; } if(sum%10 != 0) { printf(\"INVALID\ \"); return 0; } else if(creditcard[0] == \'4\') { printf(\"VISA\ \"); return 0; } else if(creditcard[0] == \'3\' && (creditcard[1] == \'7\' || creditcard[1] ==\'4\')) { printf(\"AMEX\ \"); return 0; } else if(creditcard[0] == \'5\' && (creditcard[1] >=\'1\' && creditcard[1] <=\'5\')) { printf(\"MASTERCARD\ \"); return 0; } else { printf(\"INVALID\ \"); return 0; } }.

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using java: An electronics company sells circuit boards at a 40 % profit. If you know the retail price of a circuit board, you can calculate its profit with the following formula: Profit = Retail price x 0.4 Write a program that asks the user for the retail price of a circuit board, calculates the amount of profit earned for that product, and displays the results on the screen. please help. Solution profit.java: import java.util.Scanner; public class profit { public static void main(String[] args) { double retail_price; Scanner scanner = new Scanner(System.in); System.out.println(\"Enter Retail Price: \"); retail_price = scanner.nextFloat(); System.out.println(\"The Amount Of Profit is: \" + (retail_price*0.4 )); } } Sample output: Enter Retail Price: 100 The Amount Of Profit is: 40.0 Enter Retail Price: 200 The Amount Of Profit is: 80.0.

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Use Gauss\'s approach to find the following sum (do not use formulas): 8 + 14 + 20 + 26+ ... + 86. The sum of the sequence is . Solution The sequence given is: 8+14+20+............+86 Now to calculate the sum of this sequence using Gauss approach we use the following steps: Now, 8+86=94;14+80=94;20+74=94 and so on..(basically we are trying to show that the sum of extreme terms.ie.the sum of 1st and last term,2nd and the second last term and so on, are the same in a sequence with common difference) Now,we have to find the number of terms in the sequence. 8=8+0*6 (We are using 6 here as the common difference between the terms of the sequence is 6) 14=8+1*6 20=8+2*6............ 86=8+13*6 Hence,the no of terms(n) is 14......Therefore no of pairs is : n/2=14/2=7....This indicates that we have 7 pairs of numbers whose sum is 94. The sum of the sequence is= 94*7=658.

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Use the definition of the Laplace transform to find L{f(t)} f(t) = {t, 0 ? t ? {2 Solution Definition - Laplace transform of a function f(t) is defined as follows L{f(t)} = integrate[0, inf] f(t)e-st dt So for 0 t 1, the questions says f(t) = t and you just plug it into the definition and get integrate[0, inf]{te-st}dt and evaluate the integral. First step of the intgral is integration by parts, let u=t and dv/dx = e-st , then integration by part formula says uv - integrate v(du/dx), which gives us [- (1/s) te-st] - integrate[0, inf] {-(1/s)e-st}dt. Note that the \"uv\" part [-(1/s) te-st] is equal to zero, and then you just have to integrate by parts the integral part again to get 1/s2 same thing for t 1 . plug in 2-t, and you get L{f(t)}=integrate[0, inf]{(2-t)e-stdt. Notice that the -t term you already did it in part a so you really just have to integrate 2e-st . which gives you 2/s.

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uiz: Chapter 3 Quiz is Question: 10 pts 50110 (4 complete) | Refer to the graphs below. Each graph shows the supply curve for smartphones Figure 1 . Figure 2 S1 Quantty Quantity Figure 1 illustrates_ and Figure 2 illustrates A, a decrease n the price of an nput an increase in the price of a substitute n production O B. an increase in the expected future price of the product a decrease in the number of firms if the markt C, an increase in productivity, a decrease in the price of an input D. an increase in the price of a substitute in production: an increase in the number of firms in the market Click to select youf answer F1 F3 FS F6 F7 F8 F9 Solution The correct answer is B First figure shows an increase in Supply of mobile phones. Expected future price increase induces producers to supply more phones. The second figure shows decline in number of firms, thereby reducing the supply at each price point and shifting the supply curve leftward..

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A farmer has the utility function U=C0.5 and faces a choice between planting a risky high yield variety of maize or planting the traditional variety. The outcomes and probabilities are summarized in the table below: Different from the example in class, the farmer is now endowed with an initial wealth level of 500. So his/her consumption is the amount that they get from the Maize planted +500. (e.g., if a farmer gets 1444 income from maize planting, their consumption is 1444+500=1944). Q1. What is the farmer\'s Expected Utility should they plant the High-Yield Maize?VarietyProbability of Good outcomeIncome in Good outcomeProbability of Bad outcomeIncome in Bad outcomeHigh-Yield Maize0.514440.5100Traditional Maize0.56250.5625 Solution In case of High Yield Maize we have Expected Utility equals to E(U)=Probability of good outcome*U((initial ealth level+Income in good outcome))^0.5+Probability of bad outcome*U((initial ealth level+Income in bd outcome))^0.5 E(U)=0.5(1944)^0.5+0.5(600)^0.5=34.30 Ans wer is 34.30.

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In mice, frizzy hair is due to a mutant allele (fr) that is recessive to the wild type allele (Fr). The shaker phenotype in mice is due to a mutant allele (sh) that is recessive to the wild type allele (Sh). The two genes controlling these traits are on the same chromosome. When mice that were heterozygous for both genes was crossed to frizzy-haired, shaker mice the following progeny were obtained: straight-haired, shaker mice 40 straight-haired, non-shaking mice 10 frizzy- haired, shaker mice 5 frizzy-haired, non-shaking mice 45 a. If the Fr gene and the Sh gene were unlinked, how many mice would be expected in each phenotypic category? b. What is the map distance between the two genes? c. Draw a diagram of the chromosomes showing the arrangement of alleles of these two genes in the heterozygous parent. Solution Answer: 3). a. FrfrShsh (heterozygous mice) X frfrshsh (frizzy-haired, shaker mice)-----------Parents frsh FrSh Frfr Shsh (straight-haired, non-shaking mice) 25 Frsh Frfr shsh (straight-haired, shaker mice)25 frSh frfr Shsh (frizzy-haired, non-shaking mice) 25 frsh frfr shsh (frizzy -haired, shaker mice) 25 b). Map distance between the genes = (%) Recombination frequency Recombinantion frequency (RF) = (Total no of recombinants/Total progeny)* 100 RF = (15/100) *100 RF = 15% Map distance = 15 map units c). Fr----------15 mu------------sh fr----------15 mu------------Sh frsh FrSh Frfr Shsh (straight-haired, non-shaking mice) 25 Frsh Frfr shsh (straight-haired, shaker mice)25 frSh frfr Shsh (frizzy-haired, non-shaking mice) 25 frsh frfr shsh (frizzy -haired, shaker mice) 25.

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In aqueous solution, Cd2+will precipitate out of solution in the form of CdS in the presence of hydrogen sulfide (H2S). The Ksp of CdS = 1.0 x 10-28 and Ksp of H2S = 1.0 x 10-26 for the reaction: H2S (aq) = 2 H+(aq) + S2-(aq) a. Write the balanced net ionic equation for the reaction of cadmium ion with hydrogen sulfide to form cadmium sulfide solid. b. Write the equilibrium expression for the equation in part a. c. Calculate Koverall for the reaction in part a. d. Calculate the [Cd2+] in a solution saturated with H2S (0.10 M) at a pH = 2.00 ([H+] = 0.010 M). Solution a) The balanced ionic equation for the formation of cadmium sulfide from cadmium ion and hydrogen sulfide is given as Cd2+ (aq) + H2S (aq) <=======> CdS (s) + 2 H+ (aq) ……..(1) b) The equilibrium constant for the reaction is given as Koverall = [H+]2/[Cd2+][H2S] (ans) Note that the concentration of a solid is not written in the expression for the equilibrium constant. c) Write down the two ionization reactions as below. CdS (s) <=======> Cd2+ (aq) + S2- (aq) ……..(2) Ksp = [Cd2+][S2-] H2S (aq) <=======> 2 H+ (aq) + S2- (aq) …….(3) Ka = [H+]2[S2-]/[H2S] Subtract (2) from (3) and obtain Cd2+ (aq) + H2S (aq) <======> CdS (s) + 2 H+ (aq) Koverall = [H+]2/[Cd2+][H2S] = ([H+]2/[H2S])*(1/[Cd2+]) = ([H+]2[S2-]/[H2S])*1/([Cd2+][S2-] = Ka*1/Ksp = (1.0*10-26)*1/(1.0*10-28) = 100 (ans). d) We have [H2S] = 0.10 M and pH = 2.00. We define pH as pH = -log [H+] ====> 2.00 = -log [H+] ====> [H+] = antilog (-2.00) = 0.01 M Since Ka (H2S) is extremely small, we may assume the equilibrium concentration of H2S to be equal to 0.10 M; hence, we have Koverall = [H+]2/[Cd2+][H2S] ====> 100 = (0.01)2/[Cd2+].(0.10) ====> [Cd2+] = (0.01)2/(100*0.10) = 1.0*10-5 The concentration of Cd2+ at equilibrium is 1.0*10-5 M (ans)..

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