The document summarizes the transmission system of a drill press. It has 5 gears that allow the user to adjust the speed of the drill by changing belts between different sized pulleys. Charts and calculations are shown to determine the transmission ratio, RPM, belt speed, torque in the pulleys, force in the belt, and distance between pulley centers for each gear. The span angle is also calculated using the pulley diameters and center distance.

1. TRANSMISSION
Technologic Design Engineering
PowerPlus Drill Press
XAVIER HUYGHE

2. TRANSMISSION
The speed of the drill can be
adjusted by moving the belt on
the pulley to a larger or smaller
diameter.
5 gears

3. TRANSMISSION
5 gears
43mm
84mm
56mm
69mm
66mm
59mm
76mm
47mm
88mm
37mm

4. TRANSMISSION RATIO
Transmission
Pulley
Pulley1
1
2
3
4
5
Pulley2
diamters
in
mm
84
69
59
47
37
1
43
1,953488372
2
56
1,232142857
3
66
0,893939394
4
76
0,618421053
5
88
0,420454545
Transmission
ra5o

5. SPEED (RPM)
The speed of the pulley can be found by multiplying the transmission ratio with the
speed of the motor.
RPM motor: 1300
Transmission ration (previous slide)
Example; 1300 x 1,953 = 2540
Speed
On
Machine
it
says;
1
2540
rpm
2620
rpm
2
1602
rpm
3
1162
rpm
4
804
rpm
5
547
rpm
520
rpm

6. BELT SPEED
The speed of the belt can be found using the formula;
v=n*D*Pi
Example; v(gear 1)= (1300/60)rps * 0,084m * Pi = 5,7177m/s
Belt
speed
Pulley1
1
5,71769863
m/s
2
4,696681017
m/s
3
4,016002609
m/s
4
3,199188519
m/s
5
2,518510111
m/s

7. Torque in pulley 1
The torque produced by the motor on pulley1
Torque = Power/(RPS * 2 * Pi)
Koppel
drijver
1
2,570964465
Nm

8. Force in the v-belt
The force in the belt can be found using the formula;
M=F*r => F=M/r
(M=2,57 Nm)
Example; 2,57Nm/(0,084/2) = 61,21N
Force
in
the
belt
1
61,21343965
N
2
74,52070914
N
3
87,15133781
N
4
109,4027432
N
5
138,9710522
N

9. Torque in pulley 2
The torque produced by the pulling force of the belt on pulley 2
Torque = F * r
Example M(1) = 61,21N * (0,043m/2)=1,32Nm
(0,043m is the radius of the pulley on 1st gear)
Torque on pulley 2
1
1,316088952
Nm
2
2,086579856
Nm
3
2,875994148
Nm
4
4,157304242
Nm
5
6,114726296
Nm

10. Distance between the center lines
Calculated distance
Math.
Variable
B
Distance
between
the
center
lines
B=
4*circumference-­‐6,28(D1+D2)
H=(B+Wortel(B^2-­‐32(D2-­‐D1)^2))/16
1
1834,44
228,3849525
mm
2
1847
230,783464
mm
3
1847
230,8484674
mm
4
1859,56
231,9918591
mm
5
1847
229,4580745
mm
Measured
distance
230
mm

11. Distance between the center lines
Span
Angle
omega=
180°-­‐arcsin((D1-­‐D2)/2H)
1
179,9101183
2
179,9718313
3
179,984838
4
179,937457
5
179,8886386
Cf
(graph
in
slides)
0,99