This document discusses the concept of work in physics. It defines work as the product of the applied force and the displacement in the direction of the force. It notes that work depends on both the magnitude of the force and the distance of displacement. The document provides examples of work, such as hitting a ball or pulling a bucket of water. It then calculates the work done by lifting a 0.25 kg cup of tea 0.4 meters high as 1 joule by determining the force as weight and multiplying by the displacement.

1. welcome
Sunitha K J
Physical science
Reg no:13360007
CTE Arkannoor

2. WORK
When force is applied on an object
and there is a displacement in the
direction of force,then the work is
considered to be done by the force

3. Factors affecting work
force displacem
ent

4. work = force * displacement
=F*S
Unit = N*m
=Nm Or Joule

5. Examples
Hitting the ball
Pushing the troli
Pulling the bucket of water from the well
Kicking the ball

6. What is the
amount of work
done when a
cup of tea of
mass 0.25 is
lifted to a height
of 40cm?

7. Work, W = F * S
The gravitational force of attraction on the cup of tea or its weight is,
F = mg
=0.25 * 10
=2.5 N
Acceleration due to gravity,g =10 m/s^2
S= 40 cm = 0.4 m
W = F * S
= 2.5 * 0.4
= 1 joule

8. Thank
you