The document provides information about a 4-session course for high school junior and senior students to learn about processor manufacturing. Session 1 covers general microprocessor terminology and dissecting a processor. Session 2 compares AMD and Intel processors and has students dissect samples. Session 3 has students develop new processor ideas and analyze weaknesses in current designs. Session 4 has students design their own processor on paper. Experiments will be done on provided processors and components. Students should understand low-level C programming. A sample C program for numerical integration is included.

1. Processor Manufacturing By, Michael Rodgers

2. What Level? The Junior/Senior students of high school will understand the necessities and the goals of building a processor. This understanding of the material will help them decide whether or not they want to have a career in this field.

3. Class Times Students will meet for 4 Saturdays in one month. The amount of time spent in the classroom/lab will be 7.5 hours. It is understandable that this may seem like a long time, but the students will have a work like environment.

4. Sessions Session One: General Microprocessors. Learn the terminology of the Microprocessor. Dissect the processor. Session Two: AMD vs. Intel. Understand the differences between the two. Every group will be given one AMD and one Intel processor to dissect and understand how the manufactures accomplished their design/architecture. Session Three: Developing New Ideas. From the previous session, come up with individual ideas on how to produce a faster processor. The students will go deeper in the understanding of how the companies accomplished their processor and then will find the weaknesses and figure out how to improve them. Session Four: Develop a new design. From the previous session, students will apply their developed knowledge of how to create their own processor. The students will come up with a design on paper of a new/faster processor that they believe would work in the real world. Experiments will be made on the processors provided and tested by creating a system with the provided components. The visuals that will be used should be a design/blueprint from AMD and Intel.

5. Additional Information Students will need an understanding of low-level programming, such code will be in the C programming language.

6. A simple C program #include <stdio.h> #include <stdlib.h> #include <math.h> /* * ask integral interval * subdivisions that are multiple of 4 * then display either not divisible by 4 or the integral value */ //h is the incrementation double h; //b is the end or where we are going to double b; //is is where we begin or are coming from double a; //i is going to carry the value in the for loop to be added double i; //answer before multiplying by h/3 double answer; //the final answer that is to be displayed double complete_answer; //the number of increments to be used intn; //starting the for loop...pretty much a counter int start; //f() is the function that holds what is to be evaluated by the integral double f(doublex); double f(doublex) { return exp(-x*x); } int main(){ //the menu to ask for the a, b and n value. printf("integrate from: "); scanf("%lf", &a); printf("integrate to: "); scanf("%lf", &b); printf("how many subdivisions? (must be a multiple of 4) "); scanf("%d", &n); //checking to make sure the n is divisible by 4. if(n%4!=0){ printf("%d is not divisible by 4",n); exit(1); } //h is going to be how the integral is to be incremented h=(b-a)/n; //loop to keep the summation of the evauluatedf() running until //it has reached the b or its number of increments needed for(start=0; start<=n;start++){ //for the first or x sub 0 value starts us off and begins //the i value to be summed in the end. if(start==0){ answer=f(a); i=a+h; } //if the "start" value is even, this will use a coefficient of 2 else if((start%2)==0 && start!=n){ answer=answer+(2*f(i)); i=i+h; //even } //if the "start" value is odd, this will give a coefficient of 4 else if((start%2)!=0 && start!=n){ answer=answer+(4*f(i)); i=i+h; //odd } //when we have reached where start=n, the program will finish with //adding the final f() to the answer and will complete the for loop. else if(start==n){ answer=answer+f(i); } } //multiplying h/3 to the answer to give the final answer complete_answer=(h/3)*(answer); //displaying the final answer. printf("%.10f",complete_answer); return 1; }