Strain Gauge -
Investigation and Use
26th March 2013
by ZHOU Tianxun (Leo)
Li Shuhan
Liu Jihui
Azat
Introduction
In this lab session, strain gauges are used in the static response of a
cantilever beam when a force is applied to its free end. Strain gauge
is an engineering tool. It is used for measuring force by voltage
change.
Cantilever
Masses
added
(g)
Initial
Beam
(cm)
Final
Beam
(cm)
Beam
Deflection
(cm)
Voltage
Reading
(v)
Change
in
Voltage
(v)
0 8.7 8.7 0.0 -0.05 0.00
100 8.7 8.9 0.20 0.412 0.462
500 8.7 9.5 0.80 2.428 2.478
Hence, the voltage is -0.05 when 0g weight was used.
change in voltage for 100g weight= 0.462 V
beam deflection for 100g weight= 0.20 cm
change in voltage for 500g weight= 2.478 V
beam deflection for 500g weight= 0.80 cm
Linearity
The Voltage of 100g;0.412+0.05=0.462 V
The Voltage of 500g:2.428+0.05=2.478 V
5 * (0.462 V)= 2.31 V which is not same as (2.478 V)
So the voltage reading for 100 g by 5 is not as same as the reading
for 500 g.
Spring constants
According to F=kx
(F is the force applied on the beam (N)
k is spring constant of the beam (Nm^-1)
x is the deflection of the beam (m))
For 100g mass
k=F/x=(100 x 10^-3 x 9.81)/(0.2 x 10^-2)
=490.5(Nm^-1)
For 500g mass
k=F/x=(500 x 10^-3 x 9.81)/(0.8 x 10^-2)
=613.125(Nm^-1)
%difference =(613.125 - 490.5)/((490.5+613.125)/2) x 100
=22.2%
Measurement of
Strain gauge

Strain gauge

  • 1.
    Strain Gauge - Investigationand Use 26th March 2013 by ZHOU Tianxun (Leo) Li Shuhan Liu Jihui Azat
  • 2.
    Introduction In this labsession, strain gauges are used in the static response of a cantilever beam when a force is applied to its free end. Strain gauge is an engineering tool. It is used for measuring force by voltage change. Cantilever Masses added (g) Initial Beam (cm) Final Beam (cm) Beam Deflection (cm) Voltage Reading (v) Change in Voltage (v) 0 8.7 8.7 0.0 -0.05 0.00 100 8.7 8.9 0.20 0.412 0.462 500 8.7 9.5 0.80 2.428 2.478 Hence, the voltage is -0.05 when 0g weight was used. change in voltage for 100g weight= 0.462 V beam deflection for 100g weight= 0.20 cm change in voltage for 500g weight= 2.478 V beam deflection for 500g weight= 0.80 cm Linearity The Voltage of 100g;0.412+0.05=0.462 V
  • 3.
    The Voltage of500g:2.428+0.05=2.478 V 5 * (0.462 V)= 2.31 V which is not same as (2.478 V) So the voltage reading for 100 g by 5 is not as same as the reading for 500 g. Spring constants According to F=kx (F is the force applied on the beam (N) k is spring constant of the beam (Nm^-1) x is the deflection of the beam (m)) For 100g mass k=F/x=(100 x 10^-3 x 9.81)/(0.2 x 10^-2) =490.5(Nm^-1) For 500g mass k=F/x=(500 x 10^-3 x 9.81)/(0.8 x 10^-2) =613.125(Nm^-1) %difference =(613.125 - 490.5)/((490.5+613.125)/2) x 100 =22.2% Measurement of