S&S Game is an Mathematics Game for Junior High School Students in year 8. It created in order to help teachers do an interactive learning, especially in sequences and series topic for grade 8. In this platform, it's only as a file review and uploaded in pdf format, so the macro designed in this game was unabled to show. If you mind to use the game, it's free to ask the creator for the pptm format of the game, so you can use the game perfectly.

1. Loading ...

2. Play
Materials Practice
Quiz
Help
Rate Quit
About
Hi, Welcome to the S&S
Game!

3. Arithmetic
Geometric

4. Arithmetic Sequence
Arithmetic Series

5. Geometric Sequence
Geometric Series

6. Arithmetic
Geometric

7. Let’s Try!
a =
d =
n =
an = Sn =
Arithmetic Sequence & Series
25 39
Check
44
6
4
Check
Start
Random

8. Let’s Try!
a =
r =
n =
an = Sn =
Geometric Sequence & Series
524288
Check
2
4
10
Check
Start
Random

9. Help me
to cross
the river!
Help the duck

10. 28
24 40 Submit Reset

11. 28
24 40 Submit Reset

12. Help the bird
You’ve
to fight
me!
Help
me!!!

13. Answer my
question
correctly!
A week ago, I ate two birds like you. You guys are so delicious,
so I went back to prey on 3 birds on next day and I satisfied
with them. It becomes my new habit to prey 3 birds each day
and strangely I never get bored to prey on you. But
unfortunately today, I only caught a little bird which turned out
to be your friend. I’ll let her go if you can answer my question.
But if you can’t, you’ll die together with her. HAHAHA. How
many birds have I preyed since then?
Help
me!!!

14. A week ago, I ate two birds like you. You guys are so delicious,
so I went back to prey on 3 birds on next day and I satisfied
with them. It becomes my new habit to prey 3 birds each day
and strangely I never get bored to prey on you. But
unfortunately today, I only caught a little bird which turned out
to be your friend. I’ll let her go if you can answer my question.
But if you can’t, you’ll die together with her. HAHAHA. How
many birds have I preyed since then?
Help
me!!!
Answer
Answer

27. Easy
Medium
Hard
Every answer will affect your score.
WARNING!

28. The nth terms formula of the following geometric sequence is...
1,
1
2
,
1
4
,
1
8
,
1
16
, …
A.
1
2𝑛 −1
B.
1
2
𝑛 −
1
2
C.
1
2𝑛
D.
1
2
𝑛

29. The ratio of the sequence
1
6
,
2
15
,
8
75
,
32
375
, … is ...
A. −
2
75
B. −
3
80
C.
2
3
D.
4
5

30. 2 +
1
2
+
1
8
+ ... +
1
512
= ...
A. 2,66
B. 2, 56
C. 2,89
D. 2,99

31. The nth term formula of the sequence 5, –2, –9, –16, … is ...
A. 7n - 12
B. -7n - 2
C. 12 – 7n
D. 12 + 7n

32. ..., 9, ..., ..., ...,
1
9
,
1
27
, …
The correct integers for the first three missing terms are...
A.27, 3, 𝑎𝑛𝑑
1
3
B. 27, 3, 𝑎𝑛𝑑 1
C. 3, 1, 𝑎𝑛𝑑
1
3
D. 3, 27, 𝑎𝑛𝑑 1

33. If the first term of an arithmetic sequence is 4, the second term is
7, and the third term is 10, then we’ll get 49 as ...
A. 13𝑡ℎ
B. 14𝑡ℎ
C. 15𝑡ℎ
D. 16𝑡ℎ

34. In a geometric sequence, a5 = 162 and a2 = -6. The ratio of that sequence is ...
A. -5
B. -4
C. -3
D. -2

35. The total sum of nth term formula of the sequence of positive even number is ...
A. 2𝑛 − 2
B. 2𝑛
C. 𝑛 + 𝑛2
D. n2

36. Score
Home

37. An iron is cut into five parts and forming an arithmetic sequence. If the shortest iron is 1,2
meters and the longest is 2,4 meters, the length of the iron before cutting is...
A. 7,5 m
B. 8,0 m
C. 8,2 m
D. 9,0 m

38. A piece of paper is cut into two parts. Each part is cut again into two parts and so on. The sum
of pieces paper after the fifth cutting is ...
A. 16
B. 32
C. 64
D. 128

39. A small employee recieved Rp3.000.000,00 at the first year he worked. The nominal always raises
Rp500.000,00 each year. The total nominal of his salary for ten years he will recieve is ...
A. Rp7.500.000,00
B. Rp8.000.000,00
C. Rp52.500.000,00
D. Rp55.000.000,00

40. In a performance hall, chairs are arranged which have 14 units in the front row, 16 units in the
second row, 18 units in the third row, and so on. Many arranged seats in the 20th row are ...
A. 54
B. 52
C. 40
D. 38

41. Maura finds a geometric sequence in her mathematic book. There is a little difficult question
that she can’t do yet there. It has 243 as the fifth term and the result of division between the
ninth and the sixth term is 27. Then, the second term of that sequence is...
A. 3
B. 9
C. 27
D. 81

42. In the courtroom, there are 15 rows of seats which have 23 seats in the front row. It always
has 2 more seats in the next row. The total number of seats in the courtroom is...
A. 385
B. 555
C. 1.110
D. 1.140

43. In a geometric sequence, it has known that the first term is 3 and the ninth term is 768. Then, the
seventh term of this sequence is...
A. 168
B. 192
C. 256
D. 384

44. Tina is a young little girl who always save her money. She always sets aside Rp5.000,00 from her
allowance to save every day. If now the total money she has saved are Rp60.000, she wil have
... after 2 weeks saving.
A. Rp70.000,00
B. Rp120.000,00
C. Rp125.000,00
D. Rp130.000,00

45. Score
Home

46. If a1,a2 , a3, ... are a geometric sequence while a3 – a6 = x and a2 – a4 = y, and r is ratio of this sequence,
then
𝑥
𝑦
is ...
A.
𝑟3
− 𝑟2
−𝑟
𝑟 −1
B.
𝑟3
− 𝑟2
+ 𝑟
𝑟 −1
C.
𝑟3
+ 𝑟2
+ 𝑟
𝑟 + 1
D.
𝑟3
+ 𝑟2
−𝑟
𝑟 −1

47. Between the following nth formula of the sequence, .... is the only one that forms a geometric
sequence.
A. 4n - 5
B. 2n . n-2
C. 𝑛3 . 2-n
D. 2n+1 . 3-n

48. If (2x – 5), (x – 4), (-3x + 10) are first three terms of a geometric sequence, then the value of x is
... (x is integer)
A. 1
B. 2
C. 3
D. 4

49. There are three integers, they are a, b, and c. They make an arithmetic sequence, a is the
smallest and c is the biggest. Three of them are triple pythagoras. If a is known as 69, the sum
of that three number is...
A. 646
B. 598
C. 340
D. 276

50. In January 2019, the cow population of city A and city B was 1600 and 500. It increased every
month which are 25 cows in city A and 10 cows in city B. When the cow population of city A is
three times of the cow population in city B, the cow population of city A reachs ...
A. 2100 cows
B. 2250 cows
C. 2350 cows
D. 2500 cows

51. A circular pizza with diameter 20 cm is cut into ten slices and each slice forms a sector. Their
center angle forms an arithmetic sequence. If the center angle of the smallest pizza is 1/5 of
the biggest pizza’s center angle, then the area of the biggest sliced pizza is ...
A. 48
2
3
𝑐𝑚2
B. 52
1
3
𝑐𝑚2
C. 55
1
3
𝑐𝑚2
D. 58
2
3
𝑐𝑚2

52. The nth term of geometric sequence is a6. If a2 . a8 =
1
3
and
a6
a8
= 3, then the value of a10 is ...
A.
1
27
B.
1
9
C.
3
27
D.
3
9

53. Three numbers form an geometric sequence. The sum of them is 26 and the result of their
multiplication is 216. The sum of the first and the third number of this sequence is...
A. 16
B. 20
C. 36
D. 48

54. Score
Home

55. What is arithmetic sequence ?
A sequence is called as arithmetic when the common differences between two consecutive terms are
same or constant.
Example:
Here we have,
3, 7, 11, 15, 19, ...
a1 a2 a3 a4 a5 ... an
We can define them as
+ 4 + 4 + 4 + 4
d d d d
From that, we know that common differences between two consecutive terms of the sequence are
always same or constant, then that sequence is an arithmetic.
d(common difference) = a2 – a1 = a3 – a2 = a4 – a3 = ... =
Remember this!
Next...
Note:
a1 = first term
an = nth term
d = common difference
an – an-1

56. How to determine the nth term of arithmetic sequence ?
Example:
Here we have,
a1 a2 a3 a4 a5 ... an
We can define them as
+ 4 + 4 + 4 + 4
d d d d
3, 7, 11, 15, 19, ...
a1 = 3
a2 = 3 + 4
a3 = 3 + 4 + 4
a4 = 3 + 4 + 4 + 4
 a1 = 3
 a2 = 3 + 1(4)
 a3 = 3 + 2(4)
 a4 = 3 + 3(4)
...  an = a1 + (n - 1)(d)
So, we can determine the nth term of
arithmetic sequence by using the
following formula:
an = a1 + (n - 1)(d)

57. How to determine the Sum of nth terms of arithmetic sequence?
Example:
We have an arithmetic sequence
a1 a2 a3 a4 a5 ... an
We can define them as
+ 1 + 1 + 1 + 1
d d d d
1, 2, 3, 4, 5, ...
And what we want to think about is ...
What is the sum of this sequence going to
be? And we can call the sum of the
sequence as a series. Because it is an
arithmetic sequence, so we call this series
as arithmetic series. We can write a
series as Sn.
Then, we can write the series as
Sn = 1 + 2 + 3 + ... + n
Sn = n + (n – 1) + (n – 2) + ... + 1
or And now we’re trying to sum
these both of equations
+
2Sn = (1 + n) + (2 + (n – 1)) + (3 + (n – 2)) + ... + (n + 1)
2Sn = (n + 1) + (n + 1) + (n + 1) + ... + (n + 1)
Sn =
(n + 1) + (n + 1) + (n + 1) + ... + (n + 1)
2
=
n
2
(𝑛 + 1)
a1
an
=
n
2
((a1 + (n − 1)d) + a1) =
n
2
(𝟐a1 + (n − 1)d)
So, we can determine the sum of
nth term of arithmetic sequence by
using the following formula:

58. What is geometric sequence ?
A sequence is called as geometric when the ratio between two consecutive terms are same or constant.
Example:
Here we have,
2, 6, 18, 54, 162, ...
a1 a2 a3 a4 a5 ... an
We can define them as
x 3 x 3 x 3 x 3
r r r r
From that, we know that the ratio between two consecutive terms of the sequence are always same or
constant, then that sequence is an geometric.
r(ratio) =
a2
a1
=
a3
a2
=
a4
a3
=
a5
a4
= ... =
Remember this!
Next...
Note:
a1 = first term
an = nth term
r = ratio
an
an−1

59. How to determine the nth term of geometric sequence ?
Example:
Here we have,
We can define them as
a1 = 2
a2 = 2 x 3
a3 = 2 x 3 x 3
a4 = 2 x 3 x 3 x 3
 a1 = 2
 a2 = 2 x (3)1
 a3 = 2 x (3)2
 a4 = 2 x (3)3
...  an = a1 x (r)(n - 1)
So, we can determine the nth term of
geometric sequence by using the
following formula:
an = a1r (n - 1)
2, 6, 18, 54, 162, ...
a1 a2 a3 a4 a5 ... an
x 3 x 3 x 3 x 3
r r r r

60. How to determine the Sum of nth terms of geometric sequence?
Example:
We have a geometric sequence
a1 a2 a3 a4 a5 ... an
We can define them as
x 2 x 2 x 2 x 2
r r r r
2, 4, 8, 16, 32, ...
And what we want to think about is ...
What is the sum of this sequence going to
be? And we can call the sum of the
sequence as a series. Because it is an
geometric sequence, so we call this series
as geometric series. We can write a series
as Sn.
Then, we can write the series as
Sn = 2 + 4 + 8 + ... + n = 2 + (2(2))+ (2(2)(2)) + ... + (2(2)(2)(2)...(2))
= 2 + 2(2)1 + 2(2) 2 + ... + 2(2) n
Sn = a1r0 + a1r1 + a1r 2 + ... + a1r n-1
Sn = a1 + a2 + a3 + ... + an
= a1r0 + a1r1 + a1r 2 + ... + a1r n-1
x r
r Sn = a1r1 + a1r 2 + a1r 3 + ... + a1r n
Sn = a1r0 + a1r1 + a1r 2 + ... + a1r n-1
r Sn = a1r1 + a1r 2 + a1r 3 + ... + a1r n
If r > 1
–
(r – 1) Sn = a1rn - a1 = a1 (r n – 1)
Sn =
a1 (r n – 1)
(r – 1)
Sn = a1r0 + a1r1 + a1r 2 + ... + a1r n-1
If r < 1
–
(1 – r) Sn = a1rn - a1 = a1 (1 – r n)
Sn =
a1 (1 – r n)
(1 – r)
r Sn = a1r1 + a1r 2 + a1r 3 + ... + a1r n