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Solar Photovoltaic Technologies
• Solar PV is a semiconductor device which
coverts sunlight directly into electricity.
• A solar PV panel, when exposed to sunlight
generates voltages and current at its output
terminal
• The higher is the intensity of the
sunlight, the more will be the electricity
generated from it,
• The electricity that is generated from a
PV module is DC in nature.
• The conversion of DC power to AC
power can be achieved using a device
called inverter
Solar PV Technology : Advantages & Limitations
• Solar PV technology uses sunlight as input and
gives electrical energy as an output, which is a
direct conversion of light into electricity.
• Unlike other renewable energy technologies like
wind, biomass and solar thermal where other
intermediate steps are required to convert an
input energy to electricity
• Solar PV technologies use semiconductor
materials( having properties in between metals
like aluminum and insulator like plastic ) for
conversion of light into electricity.
• It does not have any moving parts in it
and therefore does not require any
maintenance or require very little
maintenance.
• Renewable energy technologies like
biomass, wind energy etc. having moving
parts and requires some maintenance.
• Solar PV modules cannot produce
electricity during the time when there is no
light, like during the night and during
cloudy days.
How PV Cells Work?
Florida Solar Energy Center
• Solar PV modules produce power output
proportional to their size.
• A PV module can produce as small as one thousand
of a watt ( one milli – watt ) such small power is
required for our wrists watches and calculaters.
• Normally PV modules are available for the sizes
from 5 watt to 300 watt.
• For instance, 10,000 solar PV modules of 100 watt
would together produce about one megawatt of DC
power
WORKING PRINCIPLE
• Photons in sunlight hit the solar panel
and are absorbed by semiconducting
materials, such as silicon.
• Electrons are knocked loose from their
atoms, causing an electric potential
difference. Current starts flowing
through the material to cancel the
potential and this electricity is
captured.
• Due to the special composition of solar
cells, the electrons are only allowed to
move in a single direction.
• An array of solar cells converts solar
energy into a usable amount of Direct
Current (DC) electricity.
• Material used-Si, Cadmium sulphide,
Gallium arsenide, etc.
PV Basics
• A solar cell is a small semiconductor device which has a light
sensitive N-P junction. When solar light rays strike the N-P
junction, DC e.m.f. is generated with P terminal as positive and
N-terminal as negative.
• Nominal ratings of a typical single PV-cell when exposed to full sun
light are:
- Voltage 0.45 V, DC
- Current 0.75 A, DC
- Power 0.33 W
• When exposed to sun light, the solar cell acts like a tiny DC cell.
Several Solar cells are connected in series, parallel to get desired
voltage, current and power.
Electrical Characteristics of a PV Cell
Fig.3 PV cell connected to a variable resistance
Electrical Characteristics of a PV Cell
Fig.4 Current-Voltage characteristics of a typical silicon PV cell.
VI CHARACTERISTICS
• The fill factor is defined as the ratio of the
actual maximum obtainable power to the
product of the open circuit voltage and
short circuit current.
• It evaluates the performance of solar cells.
FF = ImaxVmax / Isc Voc
Maximum Conversion Efficiency
max = ( Imax Vmax ) / ( ITAc )
Where,
IT = Incident solar flux and
Ac = Area of the cell
Electrical Characteristics of a PV Cell
 The amount of power available from a PV device is determined by;
 the type and area of the material
 the intensity of the sunlight; and
 the wavelength of the sunlight
Fig. Current & voltage output of a solar cell at different light intensities
Electrical Characteristics of a PV Cell
• An important feature of PV cells is
– V does not depend on its size; remains constant with changing
light intensity
• But, I  light intensity and size
• The power output of a solar cell can be  by
tracking or concentrators
- But, the complexity of the mechanisms + need to cool the cells makes
it unfavorable.
PV cells, Modules and Arrays
• Cells are the building block of PV systems
–Typically generate 1.5 - 3 watts of power
• Modules/panels are made up of multiple cells
• Arrays are made up of multiple modules
–A typical array costs about $5 – $6/watt
• Still need lots of other components to make this work
• Typical systems cost about $8/watt
Florida Solar Energy Center
Elements of a PV System
(a)(a) a PV panel array, ranging from two to manya PV panel array, ranging from two to many
hundreds of panels;hundreds of panels;
(b)(b) a control panel, to regulate the power from thea control panel, to regulate the power from the
panels;panels;
(c)(c) a power storage system, generally comprisinga power storage system, generally comprising
of a number of specially designed batteries;of a number of specially designed batteries;
(d)(d) an inverter, for converting the DC to AC poweran inverter, for converting the DC to AC power
((egeg 240 V AC)240 V AC)
(e)(e) backup power supplies such as diesel startupbackup power supplies such as diesel startup
generators (optional)generators (optional)
(f)(f) framework and housing for the systemframework and housing for the system
(g)(g) trackers and sensors (optional)trackers and sensors (optional)
Total system cost = ~Rs. 500 / watt
PV Components
Battery
Stand Alone Solar PV System
Grid Connected Solar PV System
TYPES
• Mono - crystalline Silicon
Cells
• Polycrystalline Silicon Cells
• Amorphous Silicon (Thin-
Film)
MONO-CRYSTALLINE
SILICON CELLS
• These are made using
cells sliced from a single
cylindrical crystal of
silicon, this is the most
efficient photovoltaic
technology.
• converting around 15%
of the sun's energy into
electricity.
MONO-CRYSTALLINE
CELLS IN MODULE
POLYCRYSTALLINE
SILICON CELLS
• It is known as multi-
crystalline cells, these are
made from cells cut from
an ingot of melted and
recrystallised silicon.
• they are generally
cheaper to produce than
mono-crystalline cells,
POLY-CRYSTALLINE CELLS IN
MODULE (PANNEL)
• slightly less
efficient, with
average
efficiencies of
around 12%.
AMORPHOUS SILICON
(AKA THIN-FILM)
• Amorphous silicon cells
are made by depositing
silicon in a thin
homogeneous layer onto
a substrate.
• the cells can be thinner
hence it is called as"thin
film" PV.
• Efficiency is 10%
Is my site adequate?
There are 3 factors:
Systems installed must have a southern exposure, for
maximum daily power output.
The southern exposure must be free of obstructions such
as trees, mountains, and buildings that might shade the
modules (Summer and Winter paths of sun).
Systems must also have appropriate terrain and sufficient
space to install the PV system.
Solar PV Dependencies
• Location, Location, Location !
• Latitude
– Lower latitudes better than higher latitudes
• Weather
– Clear sunny skies better than cloudy skies
– Temperature not important
• Direction solar arrays face
– South preferred, east and west acceptable
• Absence of shade
– Trees, Flatirons, etc.
• Module temperature affects the output power
Solar PV Array Design
• Array Flat Panel
– Remains in a constant fixed position
• Array tilt (equal to latitude best)
– Increase solar radiation by 10-20% compared to 0% tilt
– Sunnier locations benefit more
• Array azimuth (180° best)
– Directly south
Ch.3 Photovoltaics ME 470 31
Solar PV Array Tracking
• Array 1-axis tracking
– Tracks sun across the sky during each day
– Stays at a constant tilt
– Increase solar radiation by 25-30% compared to no tracking
– Sunnier locations benefit more
• Array 2-axis tracking
– Tracks sun across the sky during each day
– Adjusts tilt – more in winter, less in summer
– Increase solar radiation by 33-38%
– Sunnier locations benefit more
Ch.3 Photovoltaics ME 470 32
How to size the system?
 It is necessary to know the energy needs, which youIt is necessary to know the energy needs, which you
figure by listing all your daily loads, such as lights, TV,figure by listing all your daily loads, such as lights, TV,
radios or batteries.radios or batteries.
 To determine total energy consumption, wattage of theTo determine total energy consumption, wattage of the
appliance should be multiplied by the number of hoursappliance should be multiplied by the number of hours
used in a day.used in a day.
 After adding the totals for each appliance, you canAfter adding the totals for each appliance, you can
decide what power output you need for your PV system.decide what power output you need for your PV system.
No
PV panel rating watt (
peak ), Wp
Cost ( Rs )
1 10 500
2 20 1000
3 40 2000
4 75 3750
Typical Cost of Solar PV Modules
TYPICAL COST OF BATTERIES
No
Battery rating
Amp-hour
( Ah )
Voltage
rating
( volts )
Cost
( Rs )
1 40 12 3300
2 60 12 3400
3 90 12 4650
4 110 12 5000
5 150 12 9500
SPECIFICATION OF AN INVERTER
Rated Power
1000 VA-
3000 VA
5 kVA-8kVA
9 kVA
-15 kVA
Input Voltage 12 V/24 V
24 V/36
V/48 V
36 V/48 V
Output Voltage
220 V(AC) &
110 V(AC)
220 V(AC) &
110 V(AC)
220 V(AC) &
110 V(AC)
Output Frequency 50 Hz/60 Hz 50 Hz/60 Hz 50 Hz/60 Hz
Output Waveform
Full sine
wave
Full sine
wave
Full sine
wave
No System ( kVA ) Cost ( Rs )
1 1 5000
2 2 7000
3 3 9000
4 4 12000
5 5 15000
Typical Cost of Inverter
Solar PV
panel
Battery
Charge
controller
On / Off
switch
Handle
CFL
Solar PV Lantern
Component
Power
Rating
CFL ( watts ) 8 to 18
Fan ( watts ) 60
Tube + Cu choke ( watts ) 55
Tube + Electronic choke ( watts ) 47
TYPICAL POWER RATINGS OF
COMMON APPLIANCES
In order to design PV system, number of parameters about
the component used in the system should be known.
Following assumptions can be made ( for actual design real
data should be obtained ):
Assumptions:
1. Inverter converts DC into AC power with an efficiency of
about 90 %.
2. Battery charging and discharging cycle efficiency is
about 90 %.
3. Also all the charge of a battery cannot be used. And one
has to consider maximum depth of discharge of a battery.
This can vary widely. Here we are assuming 80 % depth
of discharge, meaning only 80 % of the total capacity of
the battery is useful.
 The combined efficiency of inverter and battery will be
calculated as,
Combined efficiency = inverter efficiency x battery
efficiency
= 0.9 x 0.9 = 81 %
 Battery voltage used for operation = 12 volts
 Battery capacity = 120 Ah
 Sunlight available in a day = 8 h / d ( equivalent
of peak radiation )
 Operation of lights and fan = 6 h/d on PV panels
 PV panel power rating = 40 Wp
Operating factor:
 In the operating condition the actual output power of a PV
module is less.
 Thus, a factor called ‘operating factor’ is used to estimate the
actual output from a PV module.
 The operating factor can vary between 0.60 and 0.90 and 0.90
( implying that output power is 60 to 80 % lower than rated
output power ) in normal operating conditions, depending on
temperature, dust on module, etc.
 Thus the actual output power of a 40 Wp PV panel
= 0.75 ( operating factor ) x 40 = 30 Watt.
 Remember Wp, meaning, watt ( peak ), gives only peak power
output of a PV panel.
A solar PV system design can be done in four steps:
1. Load estimation
2. Estimation of number of PV panels
3. Estimation of battery bank
4. Cost estimation of the system
Steps to design a solar PV system
Step 1 : Find out total energy requirement of the system
( total load )
Total connected load to PV panel system
= No. of units x rating of equipments
= 2 x 18 + 2 x 60 = 156 watts
Total watt-hours rating
= Total connected load ( watts ) x operating hours
= 156 x 6 = 936 watt - hours
STEP 2 : Find out the number of PV panels required
Actual power output of a PV panel
= Peak power rating x operating factor
= 40 x 0.75 = 30 watt
Total power used at the end use is less ( due to lower
combined efficiency of the system )
= Actual power output of a panel x combined efficiency
= 30 x 0.81 = 24.3 watts ( VA )
= 24.3 watts
Energy produced by one 40 Wp panel in a day
= Actual power output x 8 hours / day (peak equivalent)
= 24.3 x 8 = 194.4 watt - hour
Note : Though the day length can be longer, we consider
light equivalent to number of peak hours ( 1000 W / m2 ) for
which solar panel is characterized. For exact value one need
to look at meteorological data for given location .
Number of solar panels required to satisfy given estimated
daily load (from step 1 )
= Total watt-hour rating ( daily load )
Daily energy produced by a panel
= 936 / 194.4 = 4.81 = 5 ( round figure )
Note : For system of voltage higher than 12 (say 24), 24/12=2,
two modules should be in series to provide 24 volt
( while total number of panels should be same )
STEP 3 : Find out the battery requirement
Total amp-hour required ( total charge to be stored ), (
battery size should be higher than the actual useful
energy due to less combined efficiency of the system )
= Total amp-hour rating
( battery efficiency x depth of discharge x battery
voltage )
= 936 / 0.9 x 0.8 x 12 = 108.33
Note : One can also decide to design a system with 24
volt or 48 volt. Since typically PV panels and battery
are designed to give 12 volt, series –parallel
combination of panels and batteries will be required to
get higher PV system voltages.
Number of batteries required = Total amp-hour rating
Battery rating under use
= 108.33 / 120
= 0.9 ≈ 1 ( round figure )
Step 4: Find out inverter size
Inverter rating (watts or VA )
Total connected load to PV panel system = 156 watts
= 156 VA
Inverter are available with rating of 100, 200, 500 VA, etc.
Therefore, the choice of the inverter should be 200 VA
In this way, total load and the requirement of number and
size of various solar PV system components can be
estimated. The examples taken here are for small size
house. For designing solar PV systems for large house or
for industrial application similar design approach can be
taken.
Cost Estimation of a PV System
Cost estimation of a solar PV system for 2 CFLs and 2
fans for 6 hours per day is done here. The case study of
the above section is considered for cost estimation.
After finding out the requirement of number and
capacity of various systems components, like panels,
battery, inverter, it is a trivial job to estimate the cost.
One has to just add the cost of all components. But
some margin should be taken for other costs like wiring,
supporting infrastructure for panel and batteries, etc.
(a) Cost of arrays = No. of PV modules x Cost / Module
= 5 x 2000 ( for a 40 Wp panel @ Rs 50 / Wp)
= Rs 10000
(b) Cost of batteries = No. of Batteries x Cost / Battery
= 1 x 7500
= Rs 7500
(c) Cost of Inverter = No. of inverters x Cost / Inverter
= 1 x 5000
= Rs 5000
Total cost of system = A + B + C
= 10000 + 7500 + 5000
= Rs 18000
Additional cost of wiring may be taken as 5 % of total
system cost.
Payback Period
• Actual power output of a 40 Wp panel
= PV panel rating x operating factor
= 40 x 0.75 = 30 Wp
• Energy produced by one 40 Wp panel
= Actual power output of a panel x combined efficiency x
No. of sun shines per day
= 30 x 0.81 x 8 = 194.4 Watt hour
• The total energy produced by the PV panels in a day
= Energy produced by one 40 Wp panel x No. of panels
Energy
= 194.4 x 5 = 972 Watt-hour = 0.972 kWh
• Cost of electricity for 1 kWh from EB is = Rs. 5
• Therefore cost of electricity produced from PV panels /
day
= 0.972 x 5 = Rs. 4.886
• Payback period
= Total cost of the system / cost of electricity produced
from PV panels per day
= 3683 days
= 10 years
MPPT /
inverter
Motor Storage
PV Module
Solar PV Water pumping System
SOLAR PV WATER PUMPING SYSTEM
Design of solar PV pumping systems requires
knowledge about how much water needs to be
pumped, at what depth water should be
pumped, how many solar panel will be required
for a given water requirement, what should be
the ratings of a motor used with PV panels, etc.
The overall design of the system can be
divided in following steps:
Step 1 : Determine the amount of water required per day
Step 2: Determine the Total Dynamic Head ( TDH ) for
water pumping
Step 3: Determine the hydraulic energy required per
day ( watt-hour / day )
Step 4 : Determine the solar radiation available at given
location in terms of equivalent of peak sunshine
radiation ( 1000 W/m2 ) hours for which solar PV module
is characterized. Topically this number is 5 to 8 varying
season to season and location to location.
Step 5 : Determine the size of solar PV array and motor,
consider motor efficiency and other losses.
Before considering a case study, let us look at some of
the definitions related to the PV pumping
CASE STUDY
Design of a PV system for pumping 25000 litres of water everyday
form a depth of about 10 metre is considered.
The data required for calculations are following and the calculation in
given below :
• Amount of water to be pumped per day = 25000 litre = 25m3
• Total vertical lift = 12 metres ( 5 m – elevation, 5 m – standing water
level, 2 m-drawdown )
• Water density = 1000 kg / m3
• Acceleration due to gravity, g = 9.8 m/s2
• Solar PV module used = 75 Wp
• Operating factor = 0.75 ( PV panel mostly does not operate at peak
rated power )
• Pump efficiency = 30 % or 0.30 ( can be between 0.25 and 0.40 )
• Mismatch factor = 0.85 ( PV panel does not operate at maximum
power point )
Calculations for PV water pumping system
Step 1 : Determine total daily water requirement
Daily water requirement = 25 m3 / day
Step 2 : Determine total dynamic head
Total vertical lift = 12 m
Frictional losses = 5 % of the total vertical lift
= 12 x 0.05 = 0.6 metre
Total dynamic head ( TDH) = 12 + 0.6 = 12.6
Step 3 : Determine the hydraulic energy required per day
Hydraulic energy required to raise water level
= mass x g x TDH
= density x volume x g x DH
= ( 1000 kg / m3 ) x ( 25 m3/day ) x ( 9.8 m/s2 ) x 12.6
= ( multiply by 1/3600 to convert second in hours )
= 857.5 watt-hour / day
Step 4 : Determine solar radiation data
Solar radiation data in terms of equivalent peak sunshine
radiation ( 1000 W/m2 ) varies between about 5 and 8 hours.
For exact hours, meteorological data should be used.
Note : Potential energy of the water is raised due to pumping,
which must be supplied to the pump
= 6 h / d ( peak of 1000 W/m2 equivalent ),
actual day length is longer ( this is
equivalent of solar radiation of 180000 watt-
hours / month at a given location )
Step 5 : Determine the number of PV panel
and pump size
Total wattage of PV panel
= Total hydraulic energy
No. of hours of peak sunshine / day
= 857.5 / 6 = 142.9 watt
Considering system losses
= Total PV panel wattage
Pump efficiency x Mismatch factor
= 142.9 / 0.3 x 0.85 = 560 watt
Consider operating factor for PV panel
= Total PV panel wattage after losses
operating factor
= 560 / 0.75 = 747.3 watt
Number of solar PV panel required of 75 Wp each
= 747.3 / 75 = 9.96 ≈ 10 (round figure)
Power rating of the motor
= 747.3 / 746 ≈ 1 HP motor
In this way, a solar PV water pumping system can be
designed.
PV System Configurations
Battery
Inverter
Load
( AC / DC )
Charge
Controller
Solar panel
Pump
DC motor
(a) Direct conversion system
Solar panel
(b) Storage System
Battery
TV
Charge
Controller
Lighting
loads
Solar panel
Key components of a solar home system
Battery
Lamp
PV Panel
Key
Components
of a solar
Street
Lighting
System
PV array
Pump
Groundwater
PV Water – Pumping System
Batteries
Regulation &
conversion
Wind
turbine
PV modules
Generator
AC
( or )
DC
Load
PV Hybrid System
Ch.3 Photovoltaics ME 470 64
APPLICATIONSAPPLICATIONS
Remote ResidentialRemote Residential
Village PowerVillage Power
Stand Alone SystemsStand Alone Systems
BuildingBuilding--Integrated PV(BIPV)Integrated PV(BIPV)
Consumer Product PowerConsumer Product Power
Hybrid Power SystemHybrid Power System
Space Power SystemSpace Power System
L A N T E R NL A N T E R N
H O M E L I G H T I N G
S T R E E T L I G H T I N GS T R E E T L I G H T I N G
W A T E R P U M P I N G
P O W E R P L A N TP O W E R P L A N T
I N T R A F F I C
R A I L W A Y S T A T I O N
P V T I L E S
F L E X I B L E
P V C E L L
Remote Areas (Mexico)
A solar panel in Marla, Cirque de Mafate, Réunion
Spacecraft
Hubble Telescope
Mars Rover
International Space Station
Recreational Use (Sailboat)
Residential
Commercial
Solar Centre at Baglan Energy Park in South Wales
Architectural integration of PV modules on exterior walls

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Solar pv

  • 1. Solar Photovoltaic Technologies • Solar PV is a semiconductor device which coverts sunlight directly into electricity. • A solar PV panel, when exposed to sunlight generates voltages and current at its output terminal • The higher is the intensity of the sunlight, the more will be the electricity generated from it,
  • 2. • The electricity that is generated from a PV module is DC in nature. • The conversion of DC power to AC power can be achieved using a device called inverter
  • 3. Solar PV Technology : Advantages & Limitations • Solar PV technology uses sunlight as input and gives electrical energy as an output, which is a direct conversion of light into electricity. • Unlike other renewable energy technologies like wind, biomass and solar thermal where other intermediate steps are required to convert an input energy to electricity • Solar PV technologies use semiconductor materials( having properties in between metals like aluminum and insulator like plastic ) for conversion of light into electricity.
  • 4. • It does not have any moving parts in it and therefore does not require any maintenance or require very little maintenance. • Renewable energy technologies like biomass, wind energy etc. having moving parts and requires some maintenance. • Solar PV modules cannot produce electricity during the time when there is no light, like during the night and during cloudy days.
  • 5. How PV Cells Work? Florida Solar Energy Center
  • 6. • Solar PV modules produce power output proportional to their size. • A PV module can produce as small as one thousand of a watt ( one milli – watt ) such small power is required for our wrists watches and calculaters. • Normally PV modules are available for the sizes from 5 watt to 300 watt. • For instance, 10,000 solar PV modules of 100 watt would together produce about one megawatt of DC power
  • 8. • Photons in sunlight hit the solar panel and are absorbed by semiconducting materials, such as silicon. • Electrons are knocked loose from their atoms, causing an electric potential difference. Current starts flowing through the material to cancel the potential and this electricity is captured.
  • 9. • Due to the special composition of solar cells, the electrons are only allowed to move in a single direction. • An array of solar cells converts solar energy into a usable amount of Direct Current (DC) electricity. • Material used-Si, Cadmium sulphide, Gallium arsenide, etc.
  • 10. PV Basics • A solar cell is a small semiconductor device which has a light sensitive N-P junction. When solar light rays strike the N-P junction, DC e.m.f. is generated with P terminal as positive and N-terminal as negative. • Nominal ratings of a typical single PV-cell when exposed to full sun light are: - Voltage 0.45 V, DC - Current 0.75 A, DC - Power 0.33 W • When exposed to sun light, the solar cell acts like a tiny DC cell. Several Solar cells are connected in series, parallel to get desired voltage, current and power.
  • 11. Electrical Characteristics of a PV Cell Fig.3 PV cell connected to a variable resistance
  • 12. Electrical Characteristics of a PV Cell Fig.4 Current-Voltage characteristics of a typical silicon PV cell.
  • 14. • The fill factor is defined as the ratio of the actual maximum obtainable power to the product of the open circuit voltage and short circuit current. • It evaluates the performance of solar cells. FF = ImaxVmax / Isc Voc
  • 15. Maximum Conversion Efficiency max = ( Imax Vmax ) / ( ITAc ) Where, IT = Incident solar flux and Ac = Area of the cell
  • 16. Electrical Characteristics of a PV Cell  The amount of power available from a PV device is determined by;  the type and area of the material  the intensity of the sunlight; and  the wavelength of the sunlight Fig. Current & voltage output of a solar cell at different light intensities
  • 17. Electrical Characteristics of a PV Cell • An important feature of PV cells is – V does not depend on its size; remains constant with changing light intensity • But, I  light intensity and size • The power output of a solar cell can be  by tracking or concentrators - But, the complexity of the mechanisms + need to cool the cells makes it unfavorable.
  • 18. PV cells, Modules and Arrays • Cells are the building block of PV systems –Typically generate 1.5 - 3 watts of power • Modules/panels are made up of multiple cells • Arrays are made up of multiple modules –A typical array costs about $5 – $6/watt • Still need lots of other components to make this work • Typical systems cost about $8/watt
  • 20. Elements of a PV System (a)(a) a PV panel array, ranging from two to manya PV panel array, ranging from two to many hundreds of panels;hundreds of panels; (b)(b) a control panel, to regulate the power from thea control panel, to regulate the power from the panels;panels; (c)(c) a power storage system, generally comprisinga power storage system, generally comprising of a number of specially designed batteries;of a number of specially designed batteries; (d)(d) an inverter, for converting the DC to AC poweran inverter, for converting the DC to AC power ((egeg 240 V AC)240 V AC) (e)(e) backup power supplies such as diesel startupbackup power supplies such as diesel startup generators (optional)generators (optional) (f)(f) framework and housing for the systemframework and housing for the system (g)(g) trackers and sensors (optional)trackers and sensors (optional) Total system cost = ~Rs. 500 / watt
  • 21. PV Components Battery Stand Alone Solar PV System Grid Connected Solar PV System
  • 22. TYPES • Mono - crystalline Silicon Cells • Polycrystalline Silicon Cells • Amorphous Silicon (Thin- Film)
  • 23. MONO-CRYSTALLINE SILICON CELLS • These are made using cells sliced from a single cylindrical crystal of silicon, this is the most efficient photovoltaic technology. • converting around 15% of the sun's energy into electricity.
  • 25. POLYCRYSTALLINE SILICON CELLS • It is known as multi- crystalline cells, these are made from cells cut from an ingot of melted and recrystallised silicon. • they are generally cheaper to produce than mono-crystalline cells,
  • 26. POLY-CRYSTALLINE CELLS IN MODULE (PANNEL) • slightly less efficient, with average efficiencies of around 12%.
  • 27. AMORPHOUS SILICON (AKA THIN-FILM) • Amorphous silicon cells are made by depositing silicon in a thin homogeneous layer onto a substrate. • the cells can be thinner hence it is called as"thin film" PV. • Efficiency is 10%
  • 28. Is my site adequate? There are 3 factors: Systems installed must have a southern exposure, for maximum daily power output. The southern exposure must be free of obstructions such as trees, mountains, and buildings that might shade the modules (Summer and Winter paths of sun). Systems must also have appropriate terrain and sufficient space to install the PV system.
  • 29. Solar PV Dependencies • Location, Location, Location ! • Latitude – Lower latitudes better than higher latitudes • Weather – Clear sunny skies better than cloudy skies – Temperature not important • Direction solar arrays face – South preferred, east and west acceptable • Absence of shade – Trees, Flatirons, etc. • Module temperature affects the output power
  • 30. Solar PV Array Design • Array Flat Panel – Remains in a constant fixed position • Array tilt (equal to latitude best) – Increase solar radiation by 10-20% compared to 0% tilt – Sunnier locations benefit more • Array azimuth (180° best) – Directly south
  • 31. Ch.3 Photovoltaics ME 470 31 Solar PV Array Tracking • Array 1-axis tracking – Tracks sun across the sky during each day – Stays at a constant tilt – Increase solar radiation by 25-30% compared to no tracking – Sunnier locations benefit more • Array 2-axis tracking – Tracks sun across the sky during each day – Adjusts tilt – more in winter, less in summer – Increase solar radiation by 33-38% – Sunnier locations benefit more
  • 32. Ch.3 Photovoltaics ME 470 32 How to size the system?  It is necessary to know the energy needs, which youIt is necessary to know the energy needs, which you figure by listing all your daily loads, such as lights, TV,figure by listing all your daily loads, such as lights, TV, radios or batteries.radios or batteries.  To determine total energy consumption, wattage of theTo determine total energy consumption, wattage of the appliance should be multiplied by the number of hoursappliance should be multiplied by the number of hours used in a day.used in a day.  After adding the totals for each appliance, you canAfter adding the totals for each appliance, you can decide what power output you need for your PV system.decide what power output you need for your PV system.
  • 33. No PV panel rating watt ( peak ), Wp Cost ( Rs ) 1 10 500 2 20 1000 3 40 2000 4 75 3750 Typical Cost of Solar PV Modules
  • 34. TYPICAL COST OF BATTERIES No Battery rating Amp-hour ( Ah ) Voltage rating ( volts ) Cost ( Rs ) 1 40 12 3300 2 60 12 3400 3 90 12 4650 4 110 12 5000 5 150 12 9500
  • 35. SPECIFICATION OF AN INVERTER Rated Power 1000 VA- 3000 VA 5 kVA-8kVA 9 kVA -15 kVA Input Voltage 12 V/24 V 24 V/36 V/48 V 36 V/48 V Output Voltage 220 V(AC) & 110 V(AC) 220 V(AC) & 110 V(AC) 220 V(AC) & 110 V(AC) Output Frequency 50 Hz/60 Hz 50 Hz/60 Hz 50 Hz/60 Hz Output Waveform Full sine wave Full sine wave Full sine wave
  • 36. No System ( kVA ) Cost ( Rs ) 1 1 5000 2 2 7000 3 3 9000 4 4 12000 5 5 15000 Typical Cost of Inverter
  • 37. Solar PV panel Battery Charge controller On / Off switch Handle CFL Solar PV Lantern
  • 38. Component Power Rating CFL ( watts ) 8 to 18 Fan ( watts ) 60 Tube + Cu choke ( watts ) 55 Tube + Electronic choke ( watts ) 47 TYPICAL POWER RATINGS OF COMMON APPLIANCES
  • 39. In order to design PV system, number of parameters about the component used in the system should be known. Following assumptions can be made ( for actual design real data should be obtained ): Assumptions: 1. Inverter converts DC into AC power with an efficiency of about 90 %. 2. Battery charging and discharging cycle efficiency is about 90 %. 3. Also all the charge of a battery cannot be used. And one has to consider maximum depth of discharge of a battery. This can vary widely. Here we are assuming 80 % depth of discharge, meaning only 80 % of the total capacity of the battery is useful.
  • 40.  The combined efficiency of inverter and battery will be calculated as, Combined efficiency = inverter efficiency x battery efficiency = 0.9 x 0.9 = 81 %  Battery voltage used for operation = 12 volts  Battery capacity = 120 Ah  Sunlight available in a day = 8 h / d ( equivalent of peak radiation )  Operation of lights and fan = 6 h/d on PV panels  PV panel power rating = 40 Wp
  • 41. Operating factor:  In the operating condition the actual output power of a PV module is less.  Thus, a factor called ‘operating factor’ is used to estimate the actual output from a PV module.  The operating factor can vary between 0.60 and 0.90 and 0.90 ( implying that output power is 60 to 80 % lower than rated output power ) in normal operating conditions, depending on temperature, dust on module, etc.  Thus the actual output power of a 40 Wp PV panel = 0.75 ( operating factor ) x 40 = 30 Watt.  Remember Wp, meaning, watt ( peak ), gives only peak power output of a PV panel.
  • 42. A solar PV system design can be done in four steps: 1. Load estimation 2. Estimation of number of PV panels 3. Estimation of battery bank 4. Cost estimation of the system Steps to design a solar PV system Step 1 : Find out total energy requirement of the system ( total load ) Total connected load to PV panel system = No. of units x rating of equipments = 2 x 18 + 2 x 60 = 156 watts Total watt-hours rating = Total connected load ( watts ) x operating hours = 156 x 6 = 936 watt - hours
  • 43. STEP 2 : Find out the number of PV panels required Actual power output of a PV panel = Peak power rating x operating factor = 40 x 0.75 = 30 watt Total power used at the end use is less ( due to lower combined efficiency of the system ) = Actual power output of a panel x combined efficiency = 30 x 0.81 = 24.3 watts ( VA ) = 24.3 watts Energy produced by one 40 Wp panel in a day = Actual power output x 8 hours / day (peak equivalent) = 24.3 x 8 = 194.4 watt - hour
  • 44. Note : Though the day length can be longer, we consider light equivalent to number of peak hours ( 1000 W / m2 ) for which solar panel is characterized. For exact value one need to look at meteorological data for given location . Number of solar panels required to satisfy given estimated daily load (from step 1 ) = Total watt-hour rating ( daily load ) Daily energy produced by a panel = 936 / 194.4 = 4.81 = 5 ( round figure ) Note : For system of voltage higher than 12 (say 24), 24/12=2, two modules should be in series to provide 24 volt ( while total number of panels should be same )
  • 45. STEP 3 : Find out the battery requirement Total amp-hour required ( total charge to be stored ), ( battery size should be higher than the actual useful energy due to less combined efficiency of the system ) = Total amp-hour rating ( battery efficiency x depth of discharge x battery voltage ) = 936 / 0.9 x 0.8 x 12 = 108.33 Note : One can also decide to design a system with 24 volt or 48 volt. Since typically PV panels and battery are designed to give 12 volt, series –parallel combination of panels and batteries will be required to get higher PV system voltages.
  • 46. Number of batteries required = Total amp-hour rating Battery rating under use = 108.33 / 120 = 0.9 ≈ 1 ( round figure ) Step 4: Find out inverter size Inverter rating (watts or VA ) Total connected load to PV panel system = 156 watts = 156 VA Inverter are available with rating of 100, 200, 500 VA, etc. Therefore, the choice of the inverter should be 200 VA In this way, total load and the requirement of number and size of various solar PV system components can be estimated. The examples taken here are for small size house. For designing solar PV systems for large house or for industrial application similar design approach can be taken.
  • 47. Cost Estimation of a PV System Cost estimation of a solar PV system for 2 CFLs and 2 fans for 6 hours per day is done here. The case study of the above section is considered for cost estimation. After finding out the requirement of number and capacity of various systems components, like panels, battery, inverter, it is a trivial job to estimate the cost. One has to just add the cost of all components. But some margin should be taken for other costs like wiring, supporting infrastructure for panel and batteries, etc. (a) Cost of arrays = No. of PV modules x Cost / Module = 5 x 2000 ( for a 40 Wp panel @ Rs 50 / Wp) = Rs 10000
  • 48. (b) Cost of batteries = No. of Batteries x Cost / Battery = 1 x 7500 = Rs 7500 (c) Cost of Inverter = No. of inverters x Cost / Inverter = 1 x 5000 = Rs 5000 Total cost of system = A + B + C = 10000 + 7500 + 5000 = Rs 18000 Additional cost of wiring may be taken as 5 % of total system cost.
  • 49. Payback Period • Actual power output of a 40 Wp panel = PV panel rating x operating factor = 40 x 0.75 = 30 Wp • Energy produced by one 40 Wp panel = Actual power output of a panel x combined efficiency x No. of sun shines per day = 30 x 0.81 x 8 = 194.4 Watt hour • The total energy produced by the PV panels in a day = Energy produced by one 40 Wp panel x No. of panels Energy = 194.4 x 5 = 972 Watt-hour = 0.972 kWh
  • 50. • Cost of electricity for 1 kWh from EB is = Rs. 5 • Therefore cost of electricity produced from PV panels / day = 0.972 x 5 = Rs. 4.886 • Payback period = Total cost of the system / cost of electricity produced from PV panels per day = 3683 days = 10 years
  • 51. MPPT / inverter Motor Storage PV Module Solar PV Water pumping System
  • 52. SOLAR PV WATER PUMPING SYSTEM Design of solar PV pumping systems requires knowledge about how much water needs to be pumped, at what depth water should be pumped, how many solar panel will be required for a given water requirement, what should be the ratings of a motor used with PV panels, etc. The overall design of the system can be divided in following steps:
  • 53. Step 1 : Determine the amount of water required per day Step 2: Determine the Total Dynamic Head ( TDH ) for water pumping Step 3: Determine the hydraulic energy required per day ( watt-hour / day ) Step 4 : Determine the solar radiation available at given location in terms of equivalent of peak sunshine radiation ( 1000 W/m2 ) hours for which solar PV module is characterized. Topically this number is 5 to 8 varying season to season and location to location. Step 5 : Determine the size of solar PV array and motor, consider motor efficiency and other losses. Before considering a case study, let us look at some of the definitions related to the PV pumping
  • 54. CASE STUDY Design of a PV system for pumping 25000 litres of water everyday form a depth of about 10 metre is considered. The data required for calculations are following and the calculation in given below : • Amount of water to be pumped per day = 25000 litre = 25m3 • Total vertical lift = 12 metres ( 5 m – elevation, 5 m – standing water level, 2 m-drawdown ) • Water density = 1000 kg / m3 • Acceleration due to gravity, g = 9.8 m/s2 • Solar PV module used = 75 Wp • Operating factor = 0.75 ( PV panel mostly does not operate at peak rated power ) • Pump efficiency = 30 % or 0.30 ( can be between 0.25 and 0.40 ) • Mismatch factor = 0.85 ( PV panel does not operate at maximum power point )
  • 55. Calculations for PV water pumping system Step 1 : Determine total daily water requirement Daily water requirement = 25 m3 / day Step 2 : Determine total dynamic head Total vertical lift = 12 m Frictional losses = 5 % of the total vertical lift = 12 x 0.05 = 0.6 metre Total dynamic head ( TDH) = 12 + 0.6 = 12.6
  • 56. Step 3 : Determine the hydraulic energy required per day Hydraulic energy required to raise water level = mass x g x TDH = density x volume x g x DH = ( 1000 kg / m3 ) x ( 25 m3/day ) x ( 9.8 m/s2 ) x 12.6 = ( multiply by 1/3600 to convert second in hours ) = 857.5 watt-hour / day Step 4 : Determine solar radiation data Solar radiation data in terms of equivalent peak sunshine radiation ( 1000 W/m2 ) varies between about 5 and 8 hours. For exact hours, meteorological data should be used. Note : Potential energy of the water is raised due to pumping, which must be supplied to the pump
  • 57. = 6 h / d ( peak of 1000 W/m2 equivalent ), actual day length is longer ( this is equivalent of solar radiation of 180000 watt- hours / month at a given location ) Step 5 : Determine the number of PV panel and pump size Total wattage of PV panel = Total hydraulic energy No. of hours of peak sunshine / day = 857.5 / 6 = 142.9 watt
  • 58. Considering system losses = Total PV panel wattage Pump efficiency x Mismatch factor = 142.9 / 0.3 x 0.85 = 560 watt Consider operating factor for PV panel = Total PV panel wattage after losses operating factor = 560 / 0.75 = 747.3 watt Number of solar PV panel required of 75 Wp each = 747.3 / 75 = 9.96 ≈ 10 (round figure) Power rating of the motor = 747.3 / 746 ≈ 1 HP motor In this way, a solar PV water pumping system can be designed.
  • 59. PV System Configurations Battery Inverter Load ( AC / DC ) Charge Controller Solar panel Pump DC motor (a) Direct conversion system Solar panel (b) Storage System
  • 61. Battery Lamp PV Panel Key Components of a solar Street Lighting System
  • 64. Ch.3 Photovoltaics ME 470 64 APPLICATIONSAPPLICATIONS Remote ResidentialRemote Residential Village PowerVillage Power Stand Alone SystemsStand Alone Systems BuildingBuilding--Integrated PV(BIPV)Integrated PV(BIPV) Consumer Product PowerConsumer Product Power Hybrid Power SystemHybrid Power System Space Power SystemSpace Power System
  • 65. L A N T E R NL A N T E R N
  • 66. H O M E L I G H T I N G
  • 67. S T R E E T L I G H T I N GS T R E E T L I G H T I N G
  • 68. W A T E R P U M P I N G
  • 69. P O W E R P L A N TP O W E R P L A N T
  • 70. I N T R A F F I C
  • 71. R A I L W A Y S T A T I O N
  • 72. P V T I L E S
  • 73. F L E X I B L E P V C E L L
  • 74. Remote Areas (Mexico) A solar panel in Marla, Cirque de Mafate, Réunion
  • 78. Commercial Solar Centre at Baglan Energy Park in South Wales
  • 79. Architectural integration of PV modules on exterior walls