shares.txt(Save the file in the D drive.Then the path of the file po.pdf
•
0 likes•2 views
shares.txt(Save the file in the D drive.Then the path of the file pointing to that file is D:\\\\shares.txt ) williams kane 500 15 18 ________________________________________________ C++ code #include #include using namespace std; int main() { //Declaring variables int noOfShares; double purPrice,sellPrice; string firstname,lastname,fname,lname; double no_of_shares_sold,purchase_price,selling_price,tot_amt_invested,amount_received_after_sell,se rvice_tax_during_buy,service_tax_during_sell,total_tax,amount_profit_lost; //fileInput reference ifstream dataIn; //Opening input file dataIn.open(\"D:\\\\shares.txt\"); //Reading the data from the file while(dataIn>>fname>>lname>>noOfShares>>purPrice>>sellPrice) { firstname=fname; lastname=lname; no_of_shares_sold=noOfShares; purchase_price=purPrice; selling_price=sellPrice; } //closing the input stream dataIn.close(); //calculating total amount invested tot_amt_invested=no_of_shares_sold*purchase_price; //Calculating service tax during buying of shares service_tax_during_buy=tot_amt_invested*0.015; //calculating the amount received after selling amount_received_after_sell=no_of_shares_sold*selling_price; //Calculating service tax after selling of shares service_tax_during_sell=amount_received_after_sell*0.015; //calculating Total Service tax paid total_tax=service_tax_during_buy+service_tax_during_sell; //calculating amount profit or lost amount_profit_lost=(amount_received_after_sell-tot_amt_invested)-(total_tax); //fileoutput reference ofstream myfile; //Opening the file myfile.open (\"D:\\\\SharesOutput.txt\"); //Writing the contents to the file myfile <<\"No_Of_Shares_sold\"<<\"||\"<<\"Purchase_Price\"<<\"||\"<<\"Sell_Price\"<<\"||\"<<\"Amt_i nvest\"; myfile<<\"||\"<<\"service_charges\"<<\"||\"<<\"Amt_Gained\"<<\"||\"<<\"Amt_received_After_s ell\ \"; myfile<<\"\\t\"< Solution shares.txt(Save the file in the D drive.Then the path of the file pointing to that file is D:\\\\shares.txt ) williams kane 500 15 18 ________________________________________________ C++ code #include #include using namespace std; int main() { //Declaring variables int noOfShares; double purPrice,sellPrice; string firstname,lastname,fname,lname; double no_of_shares_sold,purchase_price,selling_price,tot_amt_invested,amount_received_after_sell,se rvice_tax_during_buy,service_tax_during_sell,total_tax,amount_profit_lost; //fileInput reference ifstream dataIn; //Opening input file dataIn.open(\"D:\\\\shares.txt\"); //Reading the data from the file while(dataIn>>fname>>lname>>noOfShares>>purPrice>>sellPrice) { firstname=fname; lastname=lname; no_of_shares_sold=noOfShares; purchase_price=purPrice; selling_price=sellPrice; } //closing the input stream dataIn.close(); //calculating total amount invested tot_amt_invested=no_of_shares_sold*purchase_price; //Calculating service tax during buying of shares service_tax_during_buy=tot_amt_invested*0.015; //calculating the amount received after selling amount_received_after_sell=no_of_shar.
Report
Share
Report
Share
Download to read offline
Recommended
num.txt(Save this file under D Drive.Then the path of the file is D.pdf
num.txt(Save this file under D Drive.Then the path of the file is D:\\\ um.txt)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
CPP Code
#include
#include
using namespace std;
//Declaring Global variable
int sum=0;
//Function declarations
void readFromFile();
void writeToFile();
/* Function implementation which will
* read the numbers from the file and calculates the sum of
* the numbers which are multiples of 2 or 5
*/
void readFromFile()
{
int number,sum=0;
//fileInput reference
ifstream dataIn;
//Opening input file
dataIn.open(\"D:\\\ um.txt\");
while(dataIn>>number)
{
if(number%2==0 || number%5==0)
{
sum+=number;
}
}
//closing the input stream
dataIn.close();
}
/* Function implementation which will
* display the sum into another text file
*/
void writeToFile()
{
//fileoutput reference
ofstream myfile;
//Opening the file
myfile.open (\"D:\\\ um1.txt\");
//Writing the contents to the file
myfile <<\"The Sum of Multiples of 2 or 5 is :\"<
Solution
num.txt(Save this file under D Drive.Then the path of the file is D:\\\ um.txt)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
CPP Code
#include
#include
using namespace std;
//Declaring Global variable
int sum=0;
//Function declarations
void readFromFile();
void writeToFile();
/* Function implementation which will
* read the numbers from the file and calculates the sum of
* the numbers which are multiples of 2 or 5
*/
void readFromFile()
{
int number,sum=0;
//fileInput reference
ifstream dataIn;
//Opening input file
dataIn.open(\"D:\\\ um.txt\");
while(dataIn>>number)
{
if(number%2==0 || number%5==0)
{
sum+=number;
}
}
//closing the input stream
dataIn.close();
}
/* Function implementation which will
* display the sum into another text file
*/
void writeToFile()
{
//fileoutput reference
ofstream myfile;
//Opening the file
myfile.open (\"D:\\\ um1.txt\");
//Writing the contents to the file
myfile <<\"The Sum of Multiples of 2 or 5 is :\"<.
C++ Help FilestreamWrite a program that reads the values from a f.pdf
C++ Help: Filestream
Write a program that reads the values from a file and writes the sum of all multiples of 2
or 5 into another file. Your program must contain separate functions for reading and writing a
file.
Please explain your code-Will give a thumbs up. Thanks!
Solution
num.txt (Save this file inside D:Drive .Then the path of the file pointing to this file is D:\\\ um.txt
)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
__________________________________________
CPP code
#include
#include
using namespace std;
//Declaring Global variable
int sum=0;
//Function declarations
void readFromFile();
void writeToFile();
/* Function implementation which will
* read the numbers from the file and calculates the sum of
* the numbers which are multiples of 2 or 5
*/
void readFromFile()
{
int number;
//fileInput reference
ifstream dataIn;
//Opening input file
dataIn.open(\"D:\\\ um.txt\");
while(dataIn>>number)
{
if(number%2==0 || number%5==0)
{
sum+=number;
}
}
//closing the input stream
dataIn.close();
}
/* Function implementation which will
* display the sum into another text file
*/
void writeToFile()
{
//fileoutput reference
ofstream myfile;
//Opening the file
myfile.open (\"D:\\\ um1.txt\");
//Writing the contents to the file
myfile <<\"The Sum of Multiples of 2 or 5 is :\"<.
Object Oriented Programming using C++: Ch12 Streams and Files.pptx
Object Oriented Programming using C++: Ch12 Streams and Files.pptx
Object Oriented Programming Using C++: Ch12 Streams and Files.pptx
Object Oriented Programming Using C++: Ch12 Streams and Files.pptx
Write a C++ program that reads in a list of first and last names fro.pdf
Write a C++ program that reads in a list of first and last names from an input data file named
people.txt. The program should create a user name for each person consisting of the last name
and the first initial of the first name. The program should print the first name, the last name, and
the created user name for each person to the output data file usernames.txt. The program must
use an end-of-file (EOF) loop.
Solution
people.txt (Save this file under D Drive .Then the path of the file pointing to it is D:\\\\people.txt)
Willaims Kane
Johnson Mitchel
Sachin Tendulkar
Vinod kamblie
Sanjay Manjrekar
Ravi sastri
Ricky Pointing
Clarke Michael
_____________________
code:
#include
#include
#include
#include
using namespace std;
int main()
{
//Declaring variables
string fname,lname;
string uname;
int index=0;
//defines an input stream for the data file
ifstream dataIn;
//Defines an output stream for the data file
ofstream dataOut;
//Opening the input file
dataIn.open(\"D:\\\\people.txt\");
//creating and Opening the output file
dataOut.open(\"D:\\\\usernames.txt\");
//This loop continues to execute until the end of the file
while (!dataIn.eof( ))
{
//reading the firstname and lastname from people.txt file
dataIn>>fname>>lname;
//Concatinating the firstname first letter with the lastname
uname=lname+fname.at(index);
//Storing the user name in the txt file
dataOut<.
C-Program Custom Library, Header File, and Implementation FilesI .pdf
C-Program: Custom Library, Header File, and Implementation Files
I have this main.c file:
#include
#include
#include \"stats.h\"
int readGrades(char fileName[], float grades[]);
//Include this function prototype
void WelcomeToTheProgram();
int main()
{
///Declare Variables
char fileName[30];
float grades[1000]; //to store grades
int i, ArrayCount[10] = {0}; //to store histogram counts
/* Rewrite this line */
int num_grades; //for # of grades in file
///Call Intro Comment
WelcomeToTheProgram();
///Enter Filename
printf(\"\ \ \ Enter the data filename: \");
scanf(\"%s\", &fileName);
//Get # of grades in file
num_grades = readGrades(fileName, grades); //get # of grades in file
///Print Results
printf(\"There are %d grades read\ \", num_grades);
printf(\"Mean = %f\ \", mean(grades, num_grades));
printf(\"Variance = %f \ \", variance(grades, num_grades));
printf(\"Maximum = %f \ \", maximum(grades, num_grades));
printf(\"Minumum = %f \ \", minimum(grades, num_grades));
//Call histogram
histogram(grades, ArrayCount, num_grades);
//Print the histogram
printf(\"Grade Histogram\ \");
for (i = 0; i < 10; i++)
{
if (i != 9)
{
printf(\"\ %d %% - %d %%: %d \", i * 10, ((i + 1) * 10) - 1, ArrayCount[i]);
}
else
{
printf(\"\ 90 %% - 100 %%: %d\ \", ArrayCount[i]);
}
}
return 0;
}
///Reads all grades from the file to array
int readGrades(char fileName[], float grades[])
{
FILE *fpin = fopen(fileName, \"r\");
int num_scores = 0;
float value;
if (fpin == NULL)
{
printf(\"Cannot open the file\ \");
exit(0);
}
while ((fscanf(fpin, \"%f\", &value)) != EOF)
{
grades[num_scores] = value;
num_scores++;
}
return num_scores;
}
void WelcomeToTheProgram()
{
printf(\"***Welcome to the Program Which Involves a Custom Library***\");
printf(\"\ The program finds the minimum value, maximum value, mean,\");
printf(\"variance, and a histogram of the grades of data by calling\");
printf(\"implementation files min(), max(), mean(), variance(), and histogram().\ \");
}
But, the only thing that prints is
Enter the data file name: grades.txt
There are 400 grades read.
Then the program just stops, it does not print the min, max, mean, variance, or histogram. Any
ideas? Am I using the custom library wrong, the implementation files (for min, max, mean,
variance, and histogram) all check out with no warnings or errors.
Here is stats.h:
#ifndef STATS_H
#define STATS_H
float minimum(float *grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float *grades[], int Size);
float mean(float *grades[], int Size);
float variance(float *grades[], int Size);
void histogram(float *grades[], int *ArrayCount, int Size);
#endif // STATS_H
And here is the grades file:
Solution
//stats.h
#ifndef STATS_H
#define STATS_H
float minimum(float grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float grades[], int Size);
float mean(float grades[], int Size);
float variance(float grades[], int Size);
void histogram(float grades[], int ArrayCount[], int S.
Advance Mobile Application Development class 02-B
Advance Mobile application devep -(file Management) for applied scince college stuents seiyun University , yemen class - 02 v.B
Recommended
num.txt(Save this file under D Drive.Then the path of the file is D.pdf
num.txt(Save this file under D Drive.Then the path of the file is D:\\\ um.txt)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
CPP Code
#include
#include
using namespace std;
//Declaring Global variable
int sum=0;
//Function declarations
void readFromFile();
void writeToFile();
/* Function implementation which will
* read the numbers from the file and calculates the sum of
* the numbers which are multiples of 2 or 5
*/
void readFromFile()
{
int number,sum=0;
//fileInput reference
ifstream dataIn;
//Opening input file
dataIn.open(\"D:\\\ um.txt\");
while(dataIn>>number)
{
if(number%2==0 || number%5==0)
{
sum+=number;
}
}
//closing the input stream
dataIn.close();
}
/* Function implementation which will
* display the sum into another text file
*/
void writeToFile()
{
//fileoutput reference
ofstream myfile;
//Opening the file
myfile.open (\"D:\\\ um1.txt\");
//Writing the contents to the file
myfile <<\"The Sum of Multiples of 2 or 5 is :\"<
Solution
num.txt(Save this file under D Drive.Then the path of the file is D:\\\ um.txt)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
CPP Code
#include
#include
using namespace std;
//Declaring Global variable
int sum=0;
//Function declarations
void readFromFile();
void writeToFile();
/* Function implementation which will
* read the numbers from the file and calculates the sum of
* the numbers which are multiples of 2 or 5
*/
void readFromFile()
{
int number,sum=0;
//fileInput reference
ifstream dataIn;
//Opening input file
dataIn.open(\"D:\\\ um.txt\");
while(dataIn>>number)
{
if(number%2==0 || number%5==0)
{
sum+=number;
}
}
//closing the input stream
dataIn.close();
}
/* Function implementation which will
* display the sum into another text file
*/
void writeToFile()
{
//fileoutput reference
ofstream myfile;
//Opening the file
myfile.open (\"D:\\\ um1.txt\");
//Writing the contents to the file
myfile <<\"The Sum of Multiples of 2 or 5 is :\"<.
C++ Help FilestreamWrite a program that reads the values from a f.pdf
C++ Help: Filestream
Write a program that reads the values from a file and writes the sum of all multiples of 2
or 5 into another file. Your program must contain separate functions for reading and writing a
file.
Please explain your code-Will give a thumbs up. Thanks!
Solution
num.txt (Save this file inside D:Drive .Then the path of the file pointing to this file is D:\\\ um.txt
)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
__________________________________________
CPP code
#include
#include
using namespace std;
//Declaring Global variable
int sum=0;
//Function declarations
void readFromFile();
void writeToFile();
/* Function implementation which will
* read the numbers from the file and calculates the sum of
* the numbers which are multiples of 2 or 5
*/
void readFromFile()
{
int number;
//fileInput reference
ifstream dataIn;
//Opening input file
dataIn.open(\"D:\\\ um.txt\");
while(dataIn>>number)
{
if(number%2==0 || number%5==0)
{
sum+=number;
}
}
//closing the input stream
dataIn.close();
}
/* Function implementation which will
* display the sum into another text file
*/
void writeToFile()
{
//fileoutput reference
ofstream myfile;
//Opening the file
myfile.open (\"D:\\\ um1.txt\");
//Writing the contents to the file
myfile <<\"The Sum of Multiples of 2 or 5 is :\"<.
Object Oriented Programming using C++: Ch12 Streams and Files.pptx
Object Oriented Programming using C++: Ch12 Streams and Files.pptx
Object Oriented Programming Using C++: Ch12 Streams and Files.pptx
Object Oriented Programming Using C++: Ch12 Streams and Files.pptx
Write a C++ program that reads in a list of first and last names fro.pdf
Write a C++ program that reads in a list of first and last names from an input data file named
people.txt. The program should create a user name for each person consisting of the last name
and the first initial of the first name. The program should print the first name, the last name, and
the created user name for each person to the output data file usernames.txt. The program must
use an end-of-file (EOF) loop.
Solution
people.txt (Save this file under D Drive .Then the path of the file pointing to it is D:\\\\people.txt)
Willaims Kane
Johnson Mitchel
Sachin Tendulkar
Vinod kamblie
Sanjay Manjrekar
Ravi sastri
Ricky Pointing
Clarke Michael
_____________________
code:
#include
#include
#include
#include
using namespace std;
int main()
{
//Declaring variables
string fname,lname;
string uname;
int index=0;
//defines an input stream for the data file
ifstream dataIn;
//Defines an output stream for the data file
ofstream dataOut;
//Opening the input file
dataIn.open(\"D:\\\\people.txt\");
//creating and Opening the output file
dataOut.open(\"D:\\\\usernames.txt\");
//This loop continues to execute until the end of the file
while (!dataIn.eof( ))
{
//reading the firstname and lastname from people.txt file
dataIn>>fname>>lname;
//Concatinating the firstname first letter with the lastname
uname=lname+fname.at(index);
//Storing the user name in the txt file
dataOut<.
C-Program Custom Library, Header File, and Implementation FilesI .pdf
C-Program: Custom Library, Header File, and Implementation Files
I have this main.c file:
#include
#include
#include \"stats.h\"
int readGrades(char fileName[], float grades[]);
//Include this function prototype
void WelcomeToTheProgram();
int main()
{
///Declare Variables
char fileName[30];
float grades[1000]; //to store grades
int i, ArrayCount[10] = {0}; //to store histogram counts
/* Rewrite this line */
int num_grades; //for # of grades in file
///Call Intro Comment
WelcomeToTheProgram();
///Enter Filename
printf(\"\ \ \ Enter the data filename: \");
scanf(\"%s\", &fileName);
//Get # of grades in file
num_grades = readGrades(fileName, grades); //get # of grades in file
///Print Results
printf(\"There are %d grades read\ \", num_grades);
printf(\"Mean = %f\ \", mean(grades, num_grades));
printf(\"Variance = %f \ \", variance(grades, num_grades));
printf(\"Maximum = %f \ \", maximum(grades, num_grades));
printf(\"Minumum = %f \ \", minimum(grades, num_grades));
//Call histogram
histogram(grades, ArrayCount, num_grades);
//Print the histogram
printf(\"Grade Histogram\ \");
for (i = 0; i < 10; i++)
{
if (i != 9)
{
printf(\"\ %d %% - %d %%: %d \", i * 10, ((i + 1) * 10) - 1, ArrayCount[i]);
}
else
{
printf(\"\ 90 %% - 100 %%: %d\ \", ArrayCount[i]);
}
}
return 0;
}
///Reads all grades from the file to array
int readGrades(char fileName[], float grades[])
{
FILE *fpin = fopen(fileName, \"r\");
int num_scores = 0;
float value;
if (fpin == NULL)
{
printf(\"Cannot open the file\ \");
exit(0);
}
while ((fscanf(fpin, \"%f\", &value)) != EOF)
{
grades[num_scores] = value;
num_scores++;
}
return num_scores;
}
void WelcomeToTheProgram()
{
printf(\"***Welcome to the Program Which Involves a Custom Library***\");
printf(\"\ The program finds the minimum value, maximum value, mean,\");
printf(\"variance, and a histogram of the grades of data by calling\");
printf(\"implementation files min(), max(), mean(), variance(), and histogram().\ \");
}
But, the only thing that prints is
Enter the data file name: grades.txt
There are 400 grades read.
Then the program just stops, it does not print the min, max, mean, variance, or histogram. Any
ideas? Am I using the custom library wrong, the implementation files (for min, max, mean,
variance, and histogram) all check out with no warnings or errors.
Here is stats.h:
#ifndef STATS_H
#define STATS_H
float minimum(float *grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float *grades[], int Size);
float mean(float *grades[], int Size);
float variance(float *grades[], int Size);
void histogram(float *grades[], int *ArrayCount, int Size);
#endif // STATS_H
And here is the grades file:
Solution
//stats.h
#ifndef STATS_H
#define STATS_H
float minimum(float grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float grades[], int Size);
float mean(float grades[], int Size);
float variance(float grades[], int Size);
void histogram(float grades[], int ArrayCount[], int S.
Advance Mobile Application Development class 02-B
Advance Mobile application devep -(file Management) for applied scince college stuents seiyun University , yemen class - 02 v.B
C Programming Project
C Programming Projects -
1. Sort an array in ascending order.
2. Display sum of all odd values stored in an array.
3. Display number of even values stored in an array.
--
1. A file name is command line argument. Display the contents of the file where each word will be displayed on a new line. Display proper message if file does not exist.
2. Display no. of vowels stored in the file.
3. Display no. of “the” stored in the file.
4. Copy contents of the file to another file.
Log into your netlab workstation then ssh to server.cnt1015.local wi.docx
Log into your netlab workstation then ssh to server.cnt1015.local with your college username (the account you used for the quizes).
Create a directory called
final
in your home directory.
Inside
final
create directories called
backup, main, SysInfo, & files
Inside the
main
directory create a file called
boot.both
which contains a recursive listing of all the files and directories inside the directory /boot and includes any error messages.
Copy the script
snooze
from /home/stuff, put it in your
main
directory.
Run snooze.
While it is running:
Put it into the background in a suspended state.
Run the command which shows which jobs are running in the background, putting the output in a file called
sleepingjobs
in your
main
directory.
Return snooze to the foreground and let it finish running.
Copy only the files with an "s" and a "p" adjacent regardless of case (i.e sp , SP, sP, or Sp) to the directory
files
from the directory /usr/share/system-config-printer
Create a file called
userinfo
in
backup
.
On the first line put the home directory of the user games.
On the second line put the login shell of the user root.
On the third line put the members of the group wheel seperated only by a comma.
Set permissions on the file
userinfo
so that it is owned by the group cnt1015.
Inside the
backup
directory create a recursive copy of the /usr/share/doc/HTML directory
Create an alias called
now
which shows the date & time as YYYY/MM,DD-HH:MM (ex: 2014/10,16-18:50) making sure the alias survives a re-login.
Perform a recursive long listing on /boot redirecting stdout to a file called
ls.out
in the
main
directory and redirecting stderr to a file called
ls.err
in the
main
directory.
Create a file called
num.lines
in your
main
directory which has the numbers of lines in the file /etc/httpd/conf/httpd.conf
Search for the term
audio
in the file /etc/httpd/conf/magic, sending the results to a file called
magic.audio
in
main
.
Create a file called
if.info
in the
SysInfo
directory which contains the network information on the eth0 network device and only the information for that device.
Find the IP address of the server spam.cnt1015.local and put it in the file
spam.ip
under the
main
directory.
Capture your routing table information into the file
routeinfo
in the
SysInfo
directory.
Find the secondary DNS server address and put it in a file called
nameserver2
in the
SysInfo
directory.
Capture the output of the command that tests ICMP availability for the IP address 127.0.0.1 three times and put that output in a file called
nettest
under the
main
directory.
Make a script called
hello
, in the
main
directory.
Set permissions so you can read, edit and run but the group and others only have read permissions.
The scrip needs to take a name passed into it.
The output from the script should be:
Hello XXXXXX.
You are logged in as yyyyyyy.
Where XXXXXX is a name you passed in and yyyy.
Here is my code. There are Two C Programs which need to follow the a.pdf
Here is my code. There are Two C Programs which need to follow the above format
TexttoBinary.C
#include
#include
int main() {
FILE *fpIn, *fpOut;
fpIn = fopen(\"TextToBinaryInput.txt\", \"r\");
fpOut = fopen(\"TextToBinaryOutput.txt\", \"wb\");
char firstName[255], lastName[255];
unsigned int id;
float gpa;
unsigned char firstLength, lastLength;
while(!feof(fpIn)){
fscanf(fpIn, \"%s%s%u%f\", firstName, lastName, &id, &gpa);
//printf(\"%s %s %u %f\ \", firstName, lastName, id, gpa);
firstLength = strlen(firstName);
lastLength = strlen(lastName);
fwrite(&firstLength, 1, 1, fpOut);
fwrite(firstName, 1, firstLength, fpOut);
fwrite(&lastLength, 1, 1, fpOut);
fwrite(lastName, 1, lastLength, fpOut);
fwrite(&id, 4, 1, fpOut);
fwrite(&gpa, 4, 1, fpOut);
}
fclose(fpIn);
fclose(fpOut);
}
BinarytoText.C
#include
#include
#include
//stdtent data type to store info
struct student
{
char firstname[255],lastname[255];
unsigned int id;
float gpa;
};
//function prototypes
int longestName(struct student data[],int n);
int shortestName(struct student data[],int n);
int highestId(struct student data[],int n);
int lowestId(struct student data[],int n);
int highestGPA(struct student data[],int n);
int lowestGPA(struct student data[],int n);
////////////////////
int main()
{
struct student data[20]; // array of student
int n,i;
float tgpa;
FILE *fp,*fout;
int longestname,shortestname;
int highestid,lowestid;
int highestgpa,lowestgpa;
fp=fopen(\"bina.dat\",\"rb\"); // open the binary file
if(fp==NULL)
{
printf(\"Unable to open file\");
exit(0);
}
fout=fopen(\"tex.txt\",\"w\"); //open the text file
n=0;
//scan the binary file continiously and store the data in text file as well as in array of student
structure
while(fscanf(fp,\"%s%s%d%f\",data[n].firstname,data[n].lastname,&data[n].id,&tgpa)!=EOF)
{
data[n].gpa=tgpa;
fprintf(fout,\"%s\\t%s\\t%d\\t%0.2f\ \",data[n].firstname,data[n].lastname,data[n].id,tgpa);
n++;
}
// print the data
for(i=0;imaxlen)
{
maxlen=strlen(data[i].firstname)+strlen(data[i].firstname);
index=i;
}
}
return index;
}
// returns the index of student having shortest name
int shortestName(struct student data[],int n)
{
int i,minlen,index=0;
minlen=strlen(data[0].firstname)+strlen(data[0].lastname);
for(i=1;imax)
{
max=data[i].gpa;
index=i;
}
}
return index;
}
// returns the index of student having lowest id
int lowestId(struct student data[],int n)
{
int i,min,index=0;
min=data[0].id;
for(i=1;imax)
{
max=data[i].id;
index=i;
}
}
return index;
}
// returns the index of student having lowest gpa
int lowestGPA(struct student data[],int n)
{
int i,min,index=0;
min=data[0].gpa;
for(i=1;i
Solution
Steps to Compile using gcc compiler on linux platform:
#1. gcc main.c binarytotext.c texttobinary.c [this will make a.out executable]
#2. ./a.out [we can run a.out in this way]
Note: Calling sequence of binaryToText_main() and textToBinary_main() depends on your
functionality.
----------------------
File#1 [main.c]
----------------------
#include \"header.h\"
in.
Question 1 has already been posted to Chegg and I am waiting for the.pdf
Question 1 has already been posted to Chegg and I am waiting for the answer on this issue -
(When the below program is added to a Dev C++ complier, there are no errors shown; however,
when the program is run, the answer appears as zero instead of the correct value. What am I
doing wrong?)
Question 2 is another using the same program. Please answer this question for this posting. My
teach wants us to write a probram that reads data from a text file. Include in this program
functions that calculate the mean and the standard deviation. Make sure that the only global
varibles are the mean, standard deviation, and the number of data entered. All other varibles must
be local to the function. At the top of the program make sure you use functional prototypes
instead of writing each function before the main function. My problem is that it seems that the
mean, standard deviation and the number of data are already global and there seems to not be any
other program functions to make local. What am I not doing correctly or understanding.
include//Basically a code file where all input (keyboard) and output (monitor) functions are
defined.
#include//Basically a code whereas information is able to be read from a file
#include//Arrays are a programming tool that provide a mechanism to store a group of values
under a single name. The values can be any available data type (e.g., int, double, string, etc.). In
C++, the term vectors are used, rather than arrays.
#include//declares a set of functions to compute common mathematical operations and
transformations
using namespace std;//By using namespaces, you can create your own classes and functions with
the same names that the standard library provides and place them in differently named
namespaces.
int main()//The main function is a driver function because it tells the other functions in the
program the sequence of actions that need to be executed.
{//states that the main program begins here
vector v;//declares a vector of integers when the number of vectors is unknown (v). Permits the
program to run without knowing the exact number of integers.
ifstream inputFile; // Ifstream handles file input (reading from files)
ofstream outputFile;//ofstream handles file output (writing to files)
outputFile.open (\"output.txt\"); //opens the output file
int n;//A generic substitute identification for the integers since the integers listed in the array file
are unknown until the integers are read. All the numbers in the array will be read in sequence
int total = 0;//Within the array file, the program to calculate the total is to retrieve the integer
from the primary position or the zero position
int standardDeviation = 0;// within the array file, the program to calculate standard deviation is
to retrieve the integer from the primary position or the zero position
if (inputFile.is_open()) //checking whether the input file can be opened or not
{ //states the function to get the data from the array file and be used in the calcula.
Data Structure Using C - FILES
This video has covered FILES chapter in Data Structure using C for BCA II semester, as per syllabus prescribed by Karnatak University , Dharwad,Karnataka,INDIA.
File_Handling in C.ppt
A file is a collection of related data stored as a unit with a name to identify it.
A file is a collection of related data that a computers treats as a single unit.
Computers stores files to secondary storage so that the contents of files remain intact when a computer shuts down.
When a computer reads a file, it copies the file from the storage device to memory. When it writes to a file, it transfers data from memory to the storage device.
C uses a structure called FILE(defined in stdio.h) to store the attributes of a file.
Discrete storage unit for data in the form of a stream of bytes.
Durable: stored in non-volatile memory.
Starting end, sequence of bytes, and end of stream (or end of file).
Sequential access of data by a pointer performing read / write / deletion / insertion.
Meta-data (information about the file) before the stream of actual data.
File_Handling in C.ppt
File Handling Functions in C covers text files and binary files with modes of its operations.
C++ help!! Im not familiar with how to save- read file so that the pro.docx
C++ help!! Im not familiar with how to save/ read file so that the program works so i\'d realllyy appreaciate it if you wrote down the steps along with the code!
Solution
#include<fstream>
#include<iostream>
using namespace std;
int main()
{
int i,j;
int a[4][4],trans[4][4];
ifstream infile(\"Matrix_01.txt\");//change the file name to test for matrix_02 it must be in the same folder
if(!infile)
{
cout<<\"Cannot open file1.\ \";
return
}
for(i=0;i<4;i++)//reads from the file
{
for(j=0;j<4;j++)
{
infile1>>a[i][j];
}
}
cout<<\"Matrix:\"<<endl;//displays the matrix
for(i=0; i<4; ++i)
{
for(j=0; j<4; ++j)
{
cout << \" \" << a[i][j];
}
cout<<endl;
}
cout<<\"Transpose:\"<<endl;
for(i=0; i<4; ++i)//calculates transpose
for(j=0; j<4; ++j)
{
trans[j][i]=a[i][j];
}
for(i=0; i<4; ++i)//prints transpose
{
for(j=0; j<4; ++j)
{
cout << \" \" << trans[i][j];
}
cout<<endl;
}
cout<<\"Upper Triangle:\ \";
for (int i = 0; i < 4;i++)//prints upper traingle
{
for (int j = 0; j < (4- i); j++)
{
cout << a[i][j] << \" \";
}
cout << \"\ \";
}
cout<<\"Lower Triangle:\ \";
for(i=0;i<4;i++)//prints lower triangle
{
for(j=0;j<=i;j++)
{
cout<<a[i][j]<<\" \";
}
cout<<\"\ \";
}
for ( i = 0 ; i < 4 ; i++ )//checks for transpose
{
for ( j = 0 ; j < 4 ; j++ )
{
if ( a[i][j] != trans[i][j] )
break;
}
if ( j != 4 )
break;
}
if ( i == 4 )
cout<<\"It is a Symmetric matrix.\ \";
else
cout<<\"It is not a Symmetric matrix.\ \";
}
.
Moles = 0.142138 = 0.00102 moles .pdf
Moles = 0.142/138 = 0.00102 moles
Solution
Moles = 0.142/138 = 0.00102 moles.
More Related Content
Similar to shares.txt(Save the file in the D drive.Then the path of the file po.pdf
C Programming Project
C Programming Projects -
1. Sort an array in ascending order.
2. Display sum of all odd values stored in an array.
3. Display number of even values stored in an array.
--
1. A file name is command line argument. Display the contents of the file where each word will be displayed on a new line. Display proper message if file does not exist.
2. Display no. of vowels stored in the file.
3. Display no. of “the” stored in the file.
4. Copy contents of the file to another file.
Log into your netlab workstation then ssh to server.cnt1015.local wi.docx
Log into your netlab workstation then ssh to server.cnt1015.local with your college username (the account you used for the quizes).
Create a directory called
final
in your home directory.
Inside
final
create directories called
backup, main, SysInfo, & files
Inside the
main
directory create a file called
boot.both
which contains a recursive listing of all the files and directories inside the directory /boot and includes any error messages.
Copy the script
snooze
from /home/stuff, put it in your
main
directory.
Run snooze.
While it is running:
Put it into the background in a suspended state.
Run the command which shows which jobs are running in the background, putting the output in a file called
sleepingjobs
in your
main
directory.
Return snooze to the foreground and let it finish running.
Copy only the files with an "s" and a "p" adjacent regardless of case (i.e sp , SP, sP, or Sp) to the directory
files
from the directory /usr/share/system-config-printer
Create a file called
userinfo
in
backup
.
On the first line put the home directory of the user games.
On the second line put the login shell of the user root.
On the third line put the members of the group wheel seperated only by a comma.
Set permissions on the file
userinfo
so that it is owned by the group cnt1015.
Inside the
backup
directory create a recursive copy of the /usr/share/doc/HTML directory
Create an alias called
now
which shows the date & time as YYYY/MM,DD-HH:MM (ex: 2014/10,16-18:50) making sure the alias survives a re-login.
Perform a recursive long listing on /boot redirecting stdout to a file called
ls.out
in the
main
directory and redirecting stderr to a file called
ls.err
in the
main
directory.
Create a file called
num.lines
in your
main
directory which has the numbers of lines in the file /etc/httpd/conf/httpd.conf
Search for the term
audio
in the file /etc/httpd/conf/magic, sending the results to a file called
magic.audio
in
main
.
Create a file called
if.info
in the
SysInfo
directory which contains the network information on the eth0 network device and only the information for that device.
Find the IP address of the server spam.cnt1015.local and put it in the file
spam.ip
under the
main
directory.
Capture your routing table information into the file
routeinfo
in the
SysInfo
directory.
Find the secondary DNS server address and put it in a file called
nameserver2
in the
SysInfo
directory.
Capture the output of the command that tests ICMP availability for the IP address 127.0.0.1 three times and put that output in a file called
nettest
under the
main
directory.
Make a script called
hello
, in the
main
directory.
Set permissions so you can read, edit and run but the group and others only have read permissions.
The scrip needs to take a name passed into it.
The output from the script should be:
Hello XXXXXX.
You are logged in as yyyyyyy.
Where XXXXXX is a name you passed in and yyyy.
Here is my code. There are Two C Programs which need to follow the a.pdf
Here is my code. There are Two C Programs which need to follow the above format
TexttoBinary.C
#include
#include
int main() {
FILE *fpIn, *fpOut;
fpIn = fopen(\"TextToBinaryInput.txt\", \"r\");
fpOut = fopen(\"TextToBinaryOutput.txt\", \"wb\");
char firstName[255], lastName[255];
unsigned int id;
float gpa;
unsigned char firstLength, lastLength;
while(!feof(fpIn)){
fscanf(fpIn, \"%s%s%u%f\", firstName, lastName, &id, &gpa);
//printf(\"%s %s %u %f\ \", firstName, lastName, id, gpa);
firstLength = strlen(firstName);
lastLength = strlen(lastName);
fwrite(&firstLength, 1, 1, fpOut);
fwrite(firstName, 1, firstLength, fpOut);
fwrite(&lastLength, 1, 1, fpOut);
fwrite(lastName, 1, lastLength, fpOut);
fwrite(&id, 4, 1, fpOut);
fwrite(&gpa, 4, 1, fpOut);
}
fclose(fpIn);
fclose(fpOut);
}
BinarytoText.C
#include
#include
#include
//stdtent data type to store info
struct student
{
char firstname[255],lastname[255];
unsigned int id;
float gpa;
};
//function prototypes
int longestName(struct student data[],int n);
int shortestName(struct student data[],int n);
int highestId(struct student data[],int n);
int lowestId(struct student data[],int n);
int highestGPA(struct student data[],int n);
int lowestGPA(struct student data[],int n);
////////////////////
int main()
{
struct student data[20]; // array of student
int n,i;
float tgpa;
FILE *fp,*fout;
int longestname,shortestname;
int highestid,lowestid;
int highestgpa,lowestgpa;
fp=fopen(\"bina.dat\",\"rb\"); // open the binary file
if(fp==NULL)
{
printf(\"Unable to open file\");
exit(0);
}
fout=fopen(\"tex.txt\",\"w\"); //open the text file
n=0;
//scan the binary file continiously and store the data in text file as well as in array of student
structure
while(fscanf(fp,\"%s%s%d%f\",data[n].firstname,data[n].lastname,&data[n].id,&tgpa)!=EOF)
{
data[n].gpa=tgpa;
fprintf(fout,\"%s\\t%s\\t%d\\t%0.2f\ \",data[n].firstname,data[n].lastname,data[n].id,tgpa);
n++;
}
// print the data
for(i=0;imaxlen)
{
maxlen=strlen(data[i].firstname)+strlen(data[i].firstname);
index=i;
}
}
return index;
}
// returns the index of student having shortest name
int shortestName(struct student data[],int n)
{
int i,minlen,index=0;
minlen=strlen(data[0].firstname)+strlen(data[0].lastname);
for(i=1;imax)
{
max=data[i].gpa;
index=i;
}
}
return index;
}
// returns the index of student having lowest id
int lowestId(struct student data[],int n)
{
int i,min,index=0;
min=data[0].id;
for(i=1;imax)
{
max=data[i].id;
index=i;
}
}
return index;
}
// returns the index of student having lowest gpa
int lowestGPA(struct student data[],int n)
{
int i,min,index=0;
min=data[0].gpa;
for(i=1;i
Solution
Steps to Compile using gcc compiler on linux platform:
#1. gcc main.c binarytotext.c texttobinary.c [this will make a.out executable]
#2. ./a.out [we can run a.out in this way]
Note: Calling sequence of binaryToText_main() and textToBinary_main() depends on your
functionality.
----------------------
File#1 [main.c]
----------------------
#include \"header.h\"
in.
Question 1 has already been posted to Chegg and I am waiting for the.pdf
Question 1 has already been posted to Chegg and I am waiting for the answer on this issue -
(When the below program is added to a Dev C++ complier, there are no errors shown; however,
when the program is run, the answer appears as zero instead of the correct value. What am I
doing wrong?)
Question 2 is another using the same program. Please answer this question for this posting. My
teach wants us to write a probram that reads data from a text file. Include in this program
functions that calculate the mean and the standard deviation. Make sure that the only global
varibles are the mean, standard deviation, and the number of data entered. All other varibles must
be local to the function. At the top of the program make sure you use functional prototypes
instead of writing each function before the main function. My problem is that it seems that the
mean, standard deviation and the number of data are already global and there seems to not be any
other program functions to make local. What am I not doing correctly or understanding.
include//Basically a code file where all input (keyboard) and output (monitor) functions are
defined.
#include//Basically a code whereas information is able to be read from a file
#include//Arrays are a programming tool that provide a mechanism to store a group of values
under a single name. The values can be any available data type (e.g., int, double, string, etc.). In
C++, the term vectors are used, rather than arrays.
#include//declares a set of functions to compute common mathematical operations and
transformations
using namespace std;//By using namespaces, you can create your own classes and functions with
the same names that the standard library provides and place them in differently named
namespaces.
int main()//The main function is a driver function because it tells the other functions in the
program the sequence of actions that need to be executed.
{//states that the main program begins here
vector v;//declares a vector of integers when the number of vectors is unknown (v). Permits the
program to run without knowing the exact number of integers.
ifstream inputFile; // Ifstream handles file input (reading from files)
ofstream outputFile;//ofstream handles file output (writing to files)
outputFile.open (\"output.txt\"); //opens the output file
int n;//A generic substitute identification for the integers since the integers listed in the array file
are unknown until the integers are read. All the numbers in the array will be read in sequence
int total = 0;//Within the array file, the program to calculate the total is to retrieve the integer
from the primary position or the zero position
int standardDeviation = 0;// within the array file, the program to calculate standard deviation is
to retrieve the integer from the primary position or the zero position
if (inputFile.is_open()) //checking whether the input file can be opened or not
{ //states the function to get the data from the array file and be used in the calcula.
Data Structure Using C - FILES
This video has covered FILES chapter in Data Structure using C for BCA II semester, as per syllabus prescribed by Karnatak University , Dharwad,Karnataka,INDIA.
File_Handling in C.ppt
A file is a collection of related data stored as a unit with a name to identify it.
A file is a collection of related data that a computers treats as a single unit.
Computers stores files to secondary storage so that the contents of files remain intact when a computer shuts down.
When a computer reads a file, it copies the file from the storage device to memory. When it writes to a file, it transfers data from memory to the storage device.
C uses a structure called FILE(defined in stdio.h) to store the attributes of a file.
Discrete storage unit for data in the form of a stream of bytes.
Durable: stored in non-volatile memory.
Starting end, sequence of bytes, and end of stream (or end of file).
Sequential access of data by a pointer performing read / write / deletion / insertion.
Meta-data (information about the file) before the stream of actual data.
File_Handling in C.ppt
File Handling Functions in C covers text files and binary files with modes of its operations.
C++ help!! Im not familiar with how to save- read file so that the pro.docx
C++ help!! Im not familiar with how to save/ read file so that the program works so i\'d realllyy appreaciate it if you wrote down the steps along with the code!
Solution
#include<fstream>
#include<iostream>
using namespace std;
int main()
{
int i,j;
int a[4][4],trans[4][4];
ifstream infile(\"Matrix_01.txt\");//change the file name to test for matrix_02 it must be in the same folder
if(!infile)
{
cout<<\"Cannot open file1.\ \";
return
}
for(i=0;i<4;i++)//reads from the file
{
for(j=0;j<4;j++)
{
infile1>>a[i][j];
}
}
cout<<\"Matrix:\"<<endl;//displays the matrix
for(i=0; i<4; ++i)
{
for(j=0; j<4; ++j)
{
cout << \" \" << a[i][j];
}
cout<<endl;
}
cout<<\"Transpose:\"<<endl;
for(i=0; i<4; ++i)//calculates transpose
for(j=0; j<4; ++j)
{
trans[j][i]=a[i][j];
}
for(i=0; i<4; ++i)//prints transpose
{
for(j=0; j<4; ++j)
{
cout << \" \" << trans[i][j];
}
cout<<endl;
}
cout<<\"Upper Triangle:\ \";
for (int i = 0; i < 4;i++)//prints upper traingle
{
for (int j = 0; j < (4- i); j++)
{
cout << a[i][j] << \" \";
}
cout << \"\ \";
}
cout<<\"Lower Triangle:\ \";
for(i=0;i<4;i++)//prints lower triangle
{
for(j=0;j<=i;j++)
{
cout<<a[i][j]<<\" \";
}
cout<<\"\ \";
}
for ( i = 0 ; i < 4 ; i++ )//checks for transpose
{
for ( j = 0 ; j < 4 ; j++ )
{
if ( a[i][j] != trans[i][j] )
break;
}
if ( j != 4 )
break;
}
if ( i == 4 )
cout<<\"It is a Symmetric matrix.\ \";
else
cout<<\"It is not a Symmetric matrix.\ \";
}
.
Similar to shares.txt(Save the file in the D drive.Then the path of the file po.pdf (20)
Log into your netlab workstation then ssh to server.cnt1015.local wi.docx
Log into your netlab workstation then ssh to server.cnt1015.local wi.docx
Here is my code. There are Two C Programs which need to follow the a.pdf
Here is my code. There are Two C Programs which need to follow the a.pdf
Question 1 has already been posted to Chegg and I am waiting for the.pdf
Question 1 has already been posted to Chegg and I am waiting for the.pdf
C++ help!! Im not familiar with how to save- read file so that the pro.docx
C++ help!! Im not familiar with how to save- read file so that the pro.docx
More from appsmobileshoppe
Moles = 0.142138 = 0.00102 moles .pdf
Moles = 0.142/138 = 0.00102 moles
Solution
Moles = 0.142/138 = 0.00102 moles.
The name of As2S5 is diarsenic pentasulfide.TRUEExplanationAs .pdf
The name of As2S5 is diarsenic pentasulfide.
TRUE
Explanation
As there are 2 atoms of Arsenic so we uise word\"di\"
As there are 5 atoms of sulfide so we use word \"penta\"
Solution
The name of As2S5 is diarsenic pentasulfide.
TRUE
Explanation
As there are 2 atoms of Arsenic so we uise word\"di\"
As there are 5 atoms of sulfide so we use word \"penta\".
The main thing we have to do is correct tap on the system status not.pdf
The main thing we have to do is correct tap on the system status notice symbol and open the
Network and Sharing Center from the setting menu.
At that point tap on the Change connector settings hyperlink on the left-hand side of the Network
and Sharing Center.
Presently right-tap on the system connector you wish to change the DNS settings for and select
properties from the setting menu.
At the point when the properties for your system connector open, you should choose Internet
Protocol Version 4 (TCP/IPv4) from the rundown, then snap properties.
Our illustration will have opened the IPv4 settings for your system connector. You will find in
the base portion of the discourse that your PC is set to get its DNS settings \"consequently\". You
should change that with the goal that we can physically determine the DNS servers we need to
utilize. Presently basically pick an administration underneath and enter the DNS server
addresses.
Google DNS
Favored: 8.8.8.8
Interchange: 8.8.4.4
OpenDNS
Favored: 208.67.222.222
Interchange: 208.67.220.220
We selected to run with Google DNS for the time being — while they could utilize this
information to track your perusing propensities, by and by we\'re not that stressed over
Solution
The main thing we have to do is correct tap on the system status notice symbol and open the
Network and Sharing Center from the setting menu.
At that point tap on the Change connector settings hyperlink on the left-hand side of the Network
and Sharing Center.
Presently right-tap on the system connector you wish to change the DNS settings for and select
properties from the setting menu.
At the point when the properties for your system connector open, you should choose Internet
Protocol Version 4 (TCP/IPv4) from the rundown, then snap properties.
Our illustration will have opened the IPv4 settings for your system connector. You will find in
the base portion of the discourse that your PC is set to get its DNS settings \"consequently\". You
should change that with the goal that we can physically determine the DNS servers we need to
utilize. Presently basically pick an administration underneath and enter the DNS server
addresses.
Google DNS
Favored: 8.8.8.8
Interchange: 8.8.4.4
OpenDNS
Favored: 208.67.222.222
Interchange: 208.67.220.220
We selected to run with Google DNS for the time being — while they could utilize this
information to track your perusing propensities, by and by we\'re not that stressed over.
The answer is b. H2SBoth S and O come from the same group of the .pdf
The answer is: b. H2S
Both S and O come from the same group of the periodic table and have 6 valence electrons.
Thus the structures of H2S and H2O are most similar to each other.
Solution
The answer is: b. H2S
Both S and O come from the same group of the periodic table and have 6 valence electrons.
Thus the structures of H2S and H2O are most similar to each other..
Molarity , M = ( massMolar mass) Volume of sol.pdf
Molarity , M = ( mass/Molar mass) / Volume of solution in L = ( 5.00 g / 15.00
g/mol ) / 0.100 L = 3.3333 M
Solution
Molarity , M = ( mass/Molar mass) / Volume of solution in L = ( 5.00 g / 15.00
g/mol ) / 0.100 L = 3.3333 M.
Many molecules contain bonds that fall between th.pdf
Many molecules contain bonds that fall between the extremes of ionic and covalent
bonds. The difference between the electronegativities of the atoms in these molecules is large
enough that the electrons aren\'t shared equally, and yet small enough that the electrons aren\'t
drawn exclusively to one of the atoms to form positive and negative ions. The bonds in these
molecules are said to be polar, because they have positive and negative ends, or poles, and the
molecules are often said to have a dipole moment. for Eg : HCl molecules, for example, have a
dipole moment because the hydrogen atom has a slight positive charge and the chlorine atom has
a slight negative charge. Because of the force of attraction between oppositely charged particles,
there is a small dipole-dipole force of attraction between adjacent HCl molecules. non-polar
molecule has it\'s electron density shifted by a charged molecule, i.e., if a positively charged
species is brought near a species with an evenly distributed charge, the electrons go towards the
side where the positive species is, and away from the opposite side, creating an artificial dipole.
Eg : a helium atom is perfectly symmetrical. But movement of the electrons around the nuclei of
a pair of neighboring helium atoms can become synchronized so that each atom simultaneously
obtains an induced dipole moment.
Solution
Many molecules contain bonds that fall between the extremes of ionic and covalent
bonds. The difference between the electronegativities of the atoms in these molecules is large
enough that the electrons aren\'t shared equally, and yet small enough that the electrons aren\'t
drawn exclusively to one of the atoms to form positive and negative ions. The bonds in these
molecules are said to be polar, because they have positive and negative ends, or poles, and the
molecules are often said to have a dipole moment. for Eg : HCl molecules, for example, have a
dipole moment because the hydrogen atom has a slight positive charge and the chlorine atom has
a slight negative charge. Because of the force of attraction between oppositely charged particles,
there is a small dipole-dipole force of attraction between adjacent HCl molecules. non-polar
molecule has it\'s electron density shifted by a charged molecule, i.e., if a positively charged
species is brought near a species with an evenly distributed charge, the electrons go towards the
side where the positive species is, and away from the opposite side, creating an artificial dipole.
Eg : a helium atom is perfectly symmetrical. But movement of the electrons around the nuclei of
a pair of neighboring helium atoms can become synchronized so that each atom simultaneously
obtains an induced dipole moment..
the 4 examples are1) HI HI = H+ + I-2) HBr HBr = H+ + Br-.pdf
the 4 examples are:
1) HI
HI => H+ + I-
2) HBr
HBr => H+ + Br-
3) HCl
HCl => H+ + Cl-
4) H2SO4
H2SO4 => 2H+ + SO4-2
Hope this will do..:)
Solution
the 4 examples are:
1) HI
HI => H+ + I-
2) HBr
HBr => H+ + Br-
3) HCl
HCl => H+ + Cl-
4) H2SO4
H2SO4 => 2H+ + SO4-2
Hope this will do..:).
molality = moles of solute mass of solvent = 4..pdf
molality = moles of solute / mass of solvent = 4.47 mol of CaCl2 / 1 g of water
mole fraction = moles of CaCl2 / (moles of CaCL2 + moles of water) = 4.47 / (4.47 + 1/18) =
0.987
Solution
molality = moles of solute / mass of solvent = 4.47 mol of CaCl2 / 1 g of water
mole fraction = moles of CaCl2 / (moles of CaCL2 + moles of water) = 4.47 / (4.47 + 1/18) =
0.987.
SolutionTrueIn a shared block prevents need another user from p.pdf
Solution
:
True
In a shared block prevents need another user from performing DDL or DML operations on the
table.
The shared lock is automatically obtained when the select...for Update command is executed.
There is a lock known as share row exclusive, when this is lock is used then the whole table can
be seen by the other user. Similarly the other users can see all the rows in the table, but they
cannot perform DDL or DML operations on the table. When this is used in the shared mode then
it will automatically locks from updating of the table..
Scientific approaches have been defined to depict the methods to stu.pdf
Scientific approaches have been defined to depict the methods to study animal behaviour. These
methods help in understanding not only animal behaviour but also enhance the understanding of
an investigator in order to ddevelop a more comprehensive scienctific approach towards
psychological facts associated with animals. These methods are discussed as below:
1. The Ethology-Technically, ethology is the study of animal/human behaviuor in its
geographical location in association with its psycho-social environment with other factors by
means of close observations. This includes observational analysis by field scans i.e. residing in
the field/animal niche by the investigator for close observations. Importantly, ethology also
comprises of a biological context with each and every aspect of human/animal behaviuor. This
represents one of the most improtant tools to study and understand animal behaviour.
2. Comparative psychology- It is a comprehensive method which includes artificially designed
algorithm based non-human in silico/in vivo animals as models with special relevance for their
corresponding human behaviuor. This implies that a pre-defined set of rules are designed for a
model and certain stimuli are given. The nature of comprehensive behaviour of the organismic
model is then recorded and analysed. This gives a clear idea about comparative psychology of an
animal with respect to humans.
3. Behavioral studies and ecology- These studies comprise of a close integration of various
behavioral aspectso an animal with its specific environment. This field of science has been raised
in a past few decades in order to enhance the psychological information about the animal
behaviour. This helps the investigator to presume the behaviuor of an animals under a stimulus
without putting the animal exactly under the stimulus based upon previous experience,
recordings and integrated information.
Thus, collectively, these set of informations can help an investigator to understand animal
behaviuor scienctifically and psycho-socially.
Solution
Scientific approaches have been defined to depict the methods to study animal behaviour. These
methods help in understanding not only animal behaviour but also enhance the understanding of
an investigator in order to ddevelop a more comprehensive scienctific approach towards
psychological facts associated with animals. These methods are discussed as below:
1. The Ethology-Technically, ethology is the study of animal/human behaviuor in its
geographical location in association with its psycho-social environment with other factors by
means of close observations. This includes observational analysis by field scans i.e. residing in
the field/animal niche by the investigator for close observations. Importantly, ethology also
comprises of a biological context with each and every aspect of human/animal behaviuor. This
represents one of the most improtant tools to study and understand animal behaviour.
2. Comparative psychology- It i.
Ques-1Government funding is limited so that the factors are neede.pdf
Ques-1:
Government funding is limited so that the factors are needed to consider to eliminate an
infectious disease are whether the infectious agent mode of transmission and infectious agent
etiology and disease symptoms in human beings. These factors are going to promote
\"epidemiologists\" to better control \"both nosocomial infections\", pandemic infections of
communicable disease. The possible preventive measures such as vaccination can be
implemented to eliminate the disease.
Assessment of chronic disease has not only been possible because of epidemiology but also acute
disease conditions, causes, outcome of treatment to that disease conditions is also possible by
studying the disease status in the public communities. This epidemiology study used to mainly
for those infectious diseases prevailed to a large number of populations within a geographical
area in a short period of time finally useful to implement public health policies against that
infection based on epidemiological data; for example infectious disease often prevail in a
population in 2 weeks. Example of epidemic diseases is meningococcal infections; Epidemiology
studies also useful to study the nature of pandemic diseases to monitor the health of communities
& populations; These studies are used for those diseases occurring in large number of
populations across the world in almost all geographical areas. Example is flu infections.
Ques-10:
No, we never win war on microbes because microbes can change their genome persistently &
actively through mutations when they reach the host genome. For example, HIV -1 infection
therefore, it is difficult to introduce medication to defeat this microbe
Some diseases causing bacterial spores are dormant for 1000 years also and medication is
ineffective to combat these spores due to the following reason
Bacillus subtilis produce dormant spores by sporulation ate suitable conditions and these spores
are called as endospores. These endopores have the capability to survive at extreme temperatures
followed by insufficient nutrient availability and their spore DNA is completely resistant to
mutagens such as UV light, chemicals. They are also resistant to desiccation and resistant to
extreme freezing and chemical disinfectants.
Factor-1: These endospores possess very complex diversified structure that can withstand all the
possible mutation -inducing changes. These possess structural adaptations such as exosporium,
hard spore coat and these are acts as very hard complex resistant materials, which can eliminate
digesting enzymes such as lysozymes. These endospores possess cortex composed of
peptidoglycan and it has a core wall that is present under the cortex and surrounds protoplast.
These layers potentially protect spore DNA material.
Factor-2: Core material of the spore also possesses calcium dipicolinate that enable stability of
chromosomal DNA by protecting it from oxidizing agents. Inside the core material, spore
possess DNA and it is covered .
Please follow the data and description Impact of absorption on tr.pdf
Please follow the data and description :
Impact of absorption on transmission ranges :
In general the sound, light needs a medium to travel along the desination. Witht the transmission
there might be some level of difference or the deprecation at the destination and source
comparitively. This ranges from the level, range, medium and all other factors. These also vary
extensively based on the distances greater than about a hundred meters from the source. This
variation is caused by changes in weather conditions and by topographical features such as
ground cover, hills and other obstacles between the source and the receiver.
There are several important factors which affect the propagation such as geometric spreading,
atmospheric effects, and surface effects as discussed below :
a) Geometric Spreading :
This generally refers to the spreading of energy as a result of the expansion of the wavefronts.
Geometric spreading is merely independent of FREQUENCY and has a major effect in almost
all the propagation situations.
b) Air Absorption :
In general there are two types where the energy is absorbed by the atmosphere. These are
molecular relaxation and viscosity effects. High frequencies are absorbed more than low. The
amount of ABSORPTION depends on the temperature and humidity of the atmosphere.
c) Wind and Temperature Gradients :
The speed that the energy propagates in a gas depends on the temperature of the gas. Higher
temperatures produce higher speeds of sound. Since the temperature of the atmosphere is not
uniform there are local variations in the sound speed. For example, under normal conditions the
atmosphere is cooler at higher altitudes. This results in the waves being \'bent\' upwards. This
will result in the formation of a shadow zone, which is a region in which sound does not
penetrate. In reality some sound will enter this zone due to scattering. Scattering occurs when
sound waves are propagating through the atmosphere and meet a region of inhomogeneity and
some of their energy is re-directed into many other directions.
d) Ground Absorption :
This is to be noted in general as the energy is propagating over the ground, and then the
ATTENUATION will occur due to acoustic energy losses on REFLECTION. These losses will
depend on the surface. Smooth, hard surfaces will produce little ABSORPTION whereas thick
grass may result in sound levels being reduced by up to about 10 dB per 100 meters at 2000 Hz.
High frequencies are generally attenuated more than low frequencies.
These are some of the effects or the types where the absorption impacts the transmission of the
data or the energy from the source to the destination.
Hope this is helpful.
Solution
Please follow the data and description :
Impact of absorption on transmission ranges :
In general the sound, light needs a medium to travel along the desination. Witht the transmission
there might be some level of difference or the deprecation at the destination and source
comparitively. This rang.
Part-aLactose is a disaccharide and composed of glucose and galac.pdf
Part-a:
Lactose is a disaccharide and composed of glucose and galactose through a glycosidic linkage
Part-b:
Process of lactose digestion & absorption:
Simple digestion of glucose rich carbohydrates by salivary amylase, pancreatic amylase and
intestinal \"maltase, sucrase and lactase\" into simple monomers of glucose units
Lactose digestion without lactose intolerance: It is common disaccharide that is present in the
milk and dairy products as it can be digested internally by lactase at temperature 37 °C and at pH
of 6. This is representing that enzymes specifically exerts their action at a specific temperature
and PH. Beta glycosidic bonds of lactose digested and forms D-galactose and D-glucose
individual units. Thereby substrate modification of the lactose by enzyme lactase revealing that
3’-OH and 2’-OH groups of the substrate galactopyranose component is very crucial for
competitive lactase enzymatic binding in which predominantly 3’-OH is essential for enzymatic
hydrolysis.
C12H22O11 (lactose) + H2O (enzymatic hydrolysis by lactase) C6H12O6 (D-galactose) +
C6H12O6 (D-glucose)+ heat.
In the absence of lactases in the small intestine is leading to lactose digestion by gut bacteria
through \"bacterial fermentation\" finally result in formation of lactic acid and CO2 result in
persistent flatulence and abdominal distension
Part-c:
Osmotic gradient is produced due to lactose intolerance in the large intestine through lactic acid
formation and bicarbonate formation between the \"lacteals of intestine\" and gut result in higher
fluid secretion into the intestine to attain homeostasis finally loose fecal formation or diarrhea.
Lactose intolerance: This is defined as a disorder in which inability of the production of enzyme
lactase to properly digest lactose in both adults and children as well, when they had dietary
intake of lactose containing food products (ex. milk). This condition is considered as congenital
since the gene coding for the enzyme lactose to break lactose sugar polymer
Solution
Part-a:
Lactose is a disaccharide and composed of glucose and galactose through a glycosidic linkage
Part-b:
Process of lactose digestion & absorption:
Simple digestion of glucose rich carbohydrates by salivary amylase, pancreatic amylase and
intestinal \"maltase, sucrase and lactase\" into simple monomers of glucose units
Lactose digestion without lactose intolerance: It is common disaccharide that is present in the
milk and dairy products as it can be digested internally by lactase at temperature 37 °C and at pH
of 6. This is representing that enzymes specifically exerts their action at a specific temperature
and PH. Beta glycosidic bonds of lactose digested and forms D-galactose and D-glucose
individual units. Thereby substrate modification of the lactose by enzyme lactase revealing that
3’-OH and 2’-OH groups of the substrate galactopyranose component is very crucial for
competitive lactase enzymatic binding in which predominantly 3’-OH is essential f.
ln(lnx)=4if ln a = c , then a = ec== lnx = e4== x = ee^4.pdf
ln(lnx)=4
if ln a = c , then a = ec
==> lnx = e4
==> x = ee^4
Solution
ln(lnx)=4
if ln a = c , then a = ec
==> lnx = e4
==> x = ee^4.
In the first, the NO2 attaches at the 3 position .pdf
In the first, the NO2 attaches at the 3 position In second, NO2 becomes NH2 In
third it becomes NN In fourth, it becomes the first diol again
Solution
In the first, the NO2 attaches at the 3 position In second, NO2 becomes NH2 In
third it becomes NN In fourth, it becomes the first diol again.
hydride ion reacts with water to give hydrogen an.pdf
hydride ion reacts with water to give hydrogen and hydroxyl ion.
Solution
hydride ion reacts with water to give hydrogen and hydroxyl ion..
Labels on the right side of image (when we look at it)1. medial le.pdf
Labels on the right side of image (when we look at it)
1. medial leminiscus
2.medulla oblongata
3. dorsal root ganglion
Labels on the left:
1. ventral nuclei
2. nucleus gracilis and nucleus cuneatus
3. fasciculus gracilis and fasciculus cuneatus
Solution
Labels on the right side of image (when we look at it)
1. medial leminiscus
2.medulla oblongata
3. dorsal root ganglion
Labels on the left:
1. ventral nuclei
2. nucleus gracilis and nucleus cuneatus
3. fasciculus gracilis and fasciculus cuneatus.
joint distribution function of X and Y will be given by int-( i.pdf
joint distribution function of X and Y will be given by int->( infite to infinte ) int ->( infite to
infinte)g(x,y)dydx
int->ingration means
but here the values are between 0 to 1
int->( 0 to 1)int ->( 0 to 1)(Y-X)dXdY
int->( 0 to1) (0 to 1) (YX-X^2 / 2)= int ->( 0 to 1) (Y-1/2)dY=y^2/2-y=1/2-1=-1/2
Solution
joint distribution function of X and Y will be given by int->( infite to infinte ) int ->( infite to
infinte)g(x,y)dydx
int->ingration means
but here the values are between 0 to 1
int->( 0 to 1)int ->( 0 to 1)(Y-X)dXdY
int->( 0 to1) (0 to 1) (YX-X^2 / 2)= int ->( 0 to 1) (Y-1/2)dY=y^2/2-y=1/2-1=-1/2.
he had not removed and washed with distilled wate.pdf
he had not removed and washed with distilled water
Solution
he had not removed and washed with distilled water.
More from appsmobileshoppe (20)
The name of As2S5 is diarsenic pentasulfide.TRUEExplanationAs .pdf
The name of As2S5 is diarsenic pentasulfide.TRUEExplanationAs .pdf
The main thing we have to do is correct tap on the system status not.pdf
The main thing we have to do is correct tap on the system status not.pdf
The answer is b. H2SBoth S and O come from the same group of the .pdf
The answer is b. H2SBoth S and O come from the same group of the .pdf
Molarity , M = ( massMolar mass) Volume of sol.pdf
Molarity , M = ( massMolar mass) Volume of sol.pdf
Many molecules contain bonds that fall between th.pdf
Many molecules contain bonds that fall between th.pdf
the 4 examples are1) HI HI = H+ + I-2) HBr HBr = H+ + Br-.pdf
the 4 examples are1) HI HI = H+ + I-2) HBr HBr = H+ + Br-.pdf
molality = moles of solute mass of solvent = 4..pdf
molality = moles of solute mass of solvent = 4..pdf
SolutionTrueIn a shared block prevents need another user from p.pdf
SolutionTrueIn a shared block prevents need another user from p.pdf
Scientific approaches have been defined to depict the methods to stu.pdf
Scientific approaches have been defined to depict the methods to stu.pdf
Ques-1Government funding is limited so that the factors are neede.pdf
Ques-1Government funding is limited so that the factors are neede.pdf
Please follow the data and description Impact of absorption on tr.pdf
Please follow the data and description Impact of absorption on tr.pdf
Part-aLactose is a disaccharide and composed of glucose and galac.pdf
Part-aLactose is a disaccharide and composed of glucose and galac.pdf
ln(lnx)=4if ln a = c , then a = ec== lnx = e4== x = ee^4.pdf
ln(lnx)=4if ln a = c , then a = ec== lnx = e4== x = ee^4.pdf
In the first, the NO2 attaches at the 3 position .pdf
In the first, the NO2 attaches at the 3 position .pdf
hydride ion reacts with water to give hydrogen an.pdf
hydride ion reacts with water to give hydrogen an.pdf
Labels on the right side of image (when we look at it)1. medial le.pdf
Labels on the right side of image (when we look at it)1. medial le.pdf
joint distribution function of X and Y will be given by int-( i.pdf
joint distribution function of X and Y will be given by int-( i.pdf
he had not removed and washed with distilled wate.pdf
he had not removed and washed with distilled wate.pdf
Recently uploaded
Polish students' mobility in the Czech Republic
Polish students mobility to the Czech Republic within eTwinning project "Medieval adventures with Marco Polo"
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...Nguyen Thanh Tu Collection
https://app.box.com/s/hqnndn05v4q5a4k4jd597rkdbda0fniiTESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
Unit 2- Research Aptitude (UGC NET Paper I).pdf
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
The French Revolution Class 9 Study Material pdf free download
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
Operation Blue Star - Saka Neela Tara
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
The Roman Empire A Historical Colossus.pdf
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
Home assignment II on Spectroscopy 2024 Answers.pdf
Answers to Home assignment on UV-Visible spectroscopy: Calculation of wavelength of UV-Visible absorption
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Instructions for Submissions thorugh G- Classroom.pptx
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
Honest Reviews of Tim Han LMA Course Program.pptx
Personal development courses are widely available today, with each one promising life-changing outcomes. Tim Han’s Life Mastery Achievers (LMA) Course has drawn a lot of interest. In addition to offering my frank assessment of Success Insider’s LMA Course, this piece examines the course’s effects via a variety of Tim Han LMA course reviews and Success Insider comments.
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdf
In this webinar you will learn how your organization can access TechSoup's wide variety of product discount and donation programs. From hardware to software, we'll give you a tour of the tools available to help your nonprofit with productivity, collaboration, financial management, donor tracking, security, and more.
Thesis Statement for students diagnonsed withADHD.ppt
Presentation required for the master in Education.
Synthetic Fiber Construction in lab .pptx
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
Recently uploaded (20)
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
The French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free download
Home assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI fund...
Instructions for Submissions thorugh G- Classroom.pptx
Instructions for Submissions thorugh G- Classroom.pptx
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdf
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdf
Thesis Statement for students diagnonsed withADHD.ppt
Thesis Statement for students diagnonsed withADHD.ppt
shares.txt(Save the file in the D drive.Then the path of the file po.pdf
- 1. shares.txt(Save the file in the D drive.Then the path of the file pointing to that file is D:shares.txt ) williams kane 500 15 18 ________________________________________________ C++ code #include #include using namespace std; int main() { //Declaring variables int noOfShares; double purPrice,sellPrice; string firstname,lastname,fname,lname; double no_of_shares_sold,purchase_price,selling_price,tot_amt_invested,amount_received_after_sell,se rvice_tax_during_buy,service_tax_during_sell,total_tax,amount_profit_lost; //fileInput reference ifstream dataIn; //Opening input file dataIn.open("D:shares.txt"); //Reading the data from the file while(dataIn>>fname>>lname>>noOfShares>>purPrice>>sellPrice) { firstname=fname; lastname=lname; no_of_shares_sold=noOfShares; purchase_price=purPrice;
- 2. selling_price=sellPrice; } //closing the input stream dataIn.close(); //calculating total amount invested tot_amt_invested=no_of_shares_sold*purchase_price; //Calculating service tax during buying of shares service_tax_during_buy=tot_amt_invested*0.015; //calculating the amount received after selling amount_received_after_sell=no_of_shares_sold*selling_price; //Calculating service tax after selling of shares service_tax_during_sell=amount_received_after_sell*0.015; //calculating Total Service tax paid total_tax=service_tax_during_buy+service_tax_during_sell; //calculating amount profit or lost amount_profit_lost=(amount_received_after_sell-tot_amt_invested)-(total_tax); //fileoutput reference ofstream myfile; //Opening the file myfile.open ("D:SharesOutput.txt"); //Writing the contents to the file myfile <<"No_Of_Shares_sold"<<"||"<<"Purchase_Price"<<"||"<<"Sell_Price"<<"||"<<"Amt_i nvest"; myfile<<"||"<<"service_charges"<<"||"<<"Amt_Gained"<<"||"<<"Amt_received_After_s ell ";
- 3. myfile<<"t"< Solution shares.txt(Save the file in the D drive.Then the path of the file pointing to that file is D:shares.txt ) williams kane 500 15 18 ________________________________________________ C++ code #include #include using namespace std; int main() { //Declaring variables int noOfShares; double purPrice,sellPrice; string firstname,lastname,fname,lname; double no_of_shares_sold,purchase_price,selling_price,tot_amt_invested,amount_received_after_sell,se rvice_tax_during_buy,service_tax_during_sell,total_tax,amount_profit_lost; //fileInput reference ifstream dataIn; //Opening input file dataIn.open("D:shares.txt"); //Reading the data from the file while(dataIn>>fname>>lname>>noOfShares>>purPrice>>sellPrice) { firstname=fname; lastname=lname;
- 4. no_of_shares_sold=noOfShares; purchase_price=purPrice; selling_price=sellPrice; } //closing the input stream dataIn.close(); //calculating total amount invested tot_amt_invested=no_of_shares_sold*purchase_price; //Calculating service tax during buying of shares service_tax_during_buy=tot_amt_invested*0.015; //calculating the amount received after selling amount_received_after_sell=no_of_shares_sold*selling_price; //Calculating service tax after selling of shares service_tax_during_sell=amount_received_after_sell*0.015; //calculating Total Service tax paid total_tax=service_tax_during_buy+service_tax_during_sell; //calculating amount profit or lost amount_profit_lost=(amount_received_after_sell-tot_amt_invested)-(total_tax); //fileoutput reference ofstream myfile; //Opening the file myfile.open ("D:SharesOutput.txt"); //Writing the contents to the file myfile <<"No_Of_Shares_sold"<<"||"<<"Purchase_Price"<<"||"<<"Sell_Price"<<"||"<<"Amt_i nvest";