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The general form of a quadaratic equations is ax²+bx+c=0,
where a,b and c are constant. The examples are:

a. 2x²-13x+15=0
b. k²-3k=0
c. 9m²-49=0

                                  An equation should end with “=0”
A quadratic equation can be solved by 3
method:

a. Factorisation
b. Completing the square
c. Using a formula
a. Factorisation                  The curve shows
                                the way to expand two
                                      brackets.
 Example:


 (3x+1)(x-1)=15              Equation should end with “=0”




             3x²-3x+x-1=15
              3x²-2x-1=15          This answer can get from
             3x²-2x-1-15=0                 calculator:
              3x²-2x-16=0          Press “MODE” (3 times),
             (3x-8)(x+2)=0            Press “1” for “EQN”,
                x= 8 x= -2        Press the arrow button for
                   3             right (degree) and press “2”,
                                press 3 for a, -2 for b and -16
                                for c. You will get two values.
b. Completing the square
Example:                        When completing the square,
                                 the equation should start
                                         with “x²”
6x²-7x-3=0




                6(x²-7x-3)=0
                x²-7/6x-3/6=0
                x²-7/6x-1/2=0                          x-7/12= -11/12
                 x²-7/6x=1/2                               x= -1/3
        x²-7/6x+49/144=1/2+49/144
           (x-7/12)²=(72+49)/144                        x-7/12=11/12
             (x-7/12)²=121/144                              x=3/2
             x-7/12=±√121/144
               x-7/12=±11/12
c.Using a formula       Formula: x= -b±√b²-4ac
                                       2a



Example:


18x²+27x-35=0

                       So, x= -27±√27²-4(18)(-35)
                                 2(18)

                             x= -27±√3249
            a is 18                36
            b is 27            x= -27±57
            c is -35                36
                              x= -27 + 57
                                    36
                              x= -27 – 57
                                   36
                                 x= 5
                                      6
                                 x= -7
                                      3
-b
When forming a quadratic equation from    a
roots:

                                              C
                                              a

 1. Calculating the “sum of roots”
 2. Calculating the “product of roots”
 3. Forming a quadratic equation by:

   x²- (sum of roots)x + (product of
 roots)=0
The sum of roots and product of roots for the quadratic equations:


Example:
                                                      Sum of roots: -b
                                                                    a
3x²+5x-9=0
                                                                     -5
                                                                      3



 So a is 3, b is 5 and c is -9



                                                      Product of roots: c
                                                                        a
                                                                       -9
                                                                        3
                                                                       -3
TYPES OF ROOTS BASED ON THE CONDITIONS:


b²-4ac>0          b²-4ac=0        b²-4ac<0          b²-4ac ≥0




 Two real and      Two real and
                                  No real roots   Two real roots
 distinct roots     equal roots
Example :


Find the range of values of p if the quadratic equation 2x²-4x=2x-3+px² has two real and
distinct roots.



2x²-4x=2x-3+px²
2x²-px²-6x+3=0
                                                   Change into general form
(2-p)x²-6x+3=0
                                                          ax²+bx+c
a=2-p
b= -6
c= 3
                                                  Apply the formula. Since it is
(-6)²-4(2-p)(3)>0                                  two real and distinct roots,
36-12(2-p)(3)>0                                          apply b²-4ac>0
36-24+12p>0
12+12p>0
12p>-12
p> -1

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Quadratic equations

  • 1.
  • 2. The general form of a quadaratic equations is ax²+bx+c=0, where a,b and c are constant. The examples are: a. 2x²-13x+15=0 b. k²-3k=0 c. 9m²-49=0 An equation should end with “=0”
  • 3. A quadratic equation can be solved by 3 method: a. Factorisation b. Completing the square c. Using a formula
  • 4. a. Factorisation The curve shows the way to expand two brackets. Example: (3x+1)(x-1)=15 Equation should end with “=0” 3x²-3x+x-1=15 3x²-2x-1=15 This answer can get from 3x²-2x-1-15=0 calculator: 3x²-2x-16=0 Press “MODE” (3 times), (3x-8)(x+2)=0 Press “1” for “EQN”, x= 8 x= -2 Press the arrow button for 3 right (degree) and press “2”, press 3 for a, -2 for b and -16 for c. You will get two values.
  • 5. b. Completing the square Example: When completing the square, the equation should start with “x²” 6x²-7x-3=0 6(x²-7x-3)=0 x²-7/6x-3/6=0 x²-7/6x-1/2=0 x-7/12= -11/12 x²-7/6x=1/2 x= -1/3 x²-7/6x+49/144=1/2+49/144 (x-7/12)²=(72+49)/144 x-7/12=11/12 (x-7/12)²=121/144 x=3/2 x-7/12=±√121/144 x-7/12=±11/12
  • 6. c.Using a formula Formula: x= -b±√b²-4ac 2a Example: 18x²+27x-35=0 So, x= -27±√27²-4(18)(-35) 2(18) x= -27±√3249 a is 18 36 b is 27 x= -27±57 c is -35 36 x= -27 + 57 36 x= -27 – 57 36 x= 5 6 x= -7 3
  • 7. -b When forming a quadratic equation from a roots: C a 1. Calculating the “sum of roots” 2. Calculating the “product of roots” 3. Forming a quadratic equation by: x²- (sum of roots)x + (product of roots)=0
  • 8. The sum of roots and product of roots for the quadratic equations: Example: Sum of roots: -b a 3x²+5x-9=0 -5 3 So a is 3, b is 5 and c is -9 Product of roots: c a -9 3 -3
  • 9. TYPES OF ROOTS BASED ON THE CONDITIONS: b²-4ac>0 b²-4ac=0 b²-4ac<0 b²-4ac ≥0 Two real and Two real and No real roots Two real roots distinct roots equal roots
  • 10. Example : Find the range of values of p if the quadratic equation 2x²-4x=2x-3+px² has two real and distinct roots. 2x²-4x=2x-3+px² 2x²-px²-6x+3=0 Change into general form (2-p)x²-6x+3=0 ax²+bx+c a=2-p b= -6 c= 3 Apply the formula. Since it is (-6)²-4(2-p)(3)>0 two real and distinct roots, 36-12(2-p)(3)>0 apply b²-4ac>0 36-24+12p>0 12+12p>0 12p>-12 p> -1