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© 2005 Pearson Prentice Hall This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permitted. The work and materials from it  should never be made available to students except by instructors using the accompanying text in their classes. All recipients of this work are expected to abide by these restrictions and to honor the intended pedagogical purposes and the needs of other instructors who rely on these materials. ConcepTest   PowerPoints Chapter 21 Physics: Principles with Applications, 6 th  edition Giancoli
ConcepTest 21.1a  Magnetic Flux I ,[object Object],1)  drop the magnet 2)  move the magnet upwards 3)  move the magnet sideways 4)  only (1) and (2) 5)  all of the above
ConcepTest 21.1a  Magnetic Flux I ,[object Object],Moving the magnet in  any direction  would change the magnetic field through the loop and thus the magnetic flux. 1)  drop the magnet 2)  move the magnet upwards 3)  move the magnet sideways 4)  only (1) and (2) 5)  all of the above
ConcepTest 21.1b  Magnetic Flux II ,[object Object],1)  tilt the loop 2)  change the loop area 3)  use thicker wires 4)  only (1) and (2) 5)  all of the above
ConcepTest 21.1b  Magnetic Flux II ,[object Object],1)  tilt the loop 2)  change the loop area 3)  use thicker wires 4)  only (1) and (2) 5)  all of the above Since     =  B A  cos   ,  changing the area  or  tilting the loop  (which varies the projected area) would change the magnetic flux through the loop.
[object Object],ConcepTest 21.2a  Moving Bar Magnet I 1)  clockwise 2)  counterclockwise 3)  no induced current
[object Object],ConcepTest 21.2a  Moving Bar Magnet I 1)  clockwise 2)  counterclockwise 3)  no induced current The magnetic field of the moving bar magnet is pointing  into the page  and getting  larger  as the magnet moves closer to the loop.  Thus the induced magnetic field has to point  out of the page .  A  counterclockwise  induced current will give just such an induced magnetic field. Follow-up:   What happens if the magnet is stationary but the loop moves?
[object Object],ConcepTest 21.2b  Moving Bar Magnet II 1)  clockwise 2)  counterclockwise 3)  no induced current
[object Object],ConcepTest 21.2b  Moving Bar Magnet II Since the magnet is moving parallel to the loop, there is  no magnetic flux through the loop .  Thus the  induced current is zero . 1)  clockwise 2)  counterclockwise 3)  no induced current
[object Object],ConcepTest 21.3a  Moving Wire Loop I 1)  clockwise 2)  counterclockwise 3)  no induced current x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x
[object Object],ConcepTest 21.3a  Moving Wire Loop I Since the magnetic field is uniform, the  magnetic flux through the loop is not changing .  Thus  no current is induced . 1)  clockwise 2)  counterclockwise 3)  no induced current Follow-up:   What happens if the loop moves out of the page? x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x
[object Object],ConcepTest 21.3b  Moving Wire Loop II 1)  clockwise 2)  counterclockwise 3)  no induced current x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x x  x  x  x  x x  x  x  x  x
[object Object],ConcepTest 21.3b  Moving Wire Loop II 1)  clockwise 2)  counterclockwise 3)  no induced current The  B  field into the page  is disappearing in the loop, so it must be compensated by an  induced flux also into the page .  This can be accomplished by an  induced current in the clockwise   direction  in the wire loop. Follow-up:   What happens when the loop is completely out of the field? x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x x  x  x  x  x x  x  x  x  x
ConcepTest 21.3c  Moving Wire Loop III 1)  clockwise 2)  counterclockwise 3)  no induced current What is the direction of the induced current if the  B  field suddenly increases  while the loop is in the region?  x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x x  x  x  x  x x  x  x  x  x
ConcepTest 21.3c  Moving Wire Loop III 1)  clockwise 2)  counterclockwise 3)  no induced current What is the direction of the induced current if the  B  field suddenly increases  while the loop is in the region?  The  increasing  B  field into the page  must be countered by an  induced flux out of the page .  This can be accomplished by  induced current in the counterclockwise   direction  in the wire loop. Follow-up:   What if the loop stops moving while the field increases? x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x x  x  x  x  x  x  x  x  x  x  x  x  x  x  x x  x  x  x  x x  x  x  x  x x  x  x  x  x
[object Object],ConcepTest 21.4  Shrinking Wire Loop 1)  clockwise 2)  counterclockwise 3)  no induced current
[object Object],ConcepTest 21.4  Shrinking Wire Loop The magnetic flux through the loop is  decreasing , so the induced B field must try to reinforce it and therefore points in the same direction  —  into the page .  According to the right-hand rule, an induced  clockwise  current will generate a magnetic field  into the page . 1)  clockwise 2)  counterclockwise 3)  no induced current Follow-up:   What if the  B  field is oriented at 90 °  to its present direction?
[object Object],ConcepTest 21.5  Rotating Wire Loop 1)  clockwise 2)  counterclockwise 3)  no induced current
[object Object],ConcepTest 21.5  Rotating Wire Loop As the coil is rotated into the  B  field, the magnetic flux through it  increases .  According to Lenz’s Law, the induced B field has to  oppose this increase , thus the new  B  field points  to the right .  An induced  counterclockwise  current produces just such a  B  field. 1)  clockwise 2)  counterclockwise 3)  no induced current
[object Object],ConcepTest 21.6a  Voltage and Current I 1)  V 1   >  V 2   2)  V 1   <  V 2   3)  V 1   =  V 2      0 4)  V 1   =  V 2   =  0 N S N S 1 2
[object Object],ConcepTest 21.6a  Voltage and Current I Faraday’s law: depends on  N   ( number of loops ) so the  induced emf is twice as large in the wire with 2 loops .  1)  V 1   >  V 2   2)  V 1   <  V 2   3)  V 1   =  V 2      0 4)  V 1   =  V 2   =  0 N S N S 1 2
ConcepTest 21.6b  Voltage and Current II ,[object Object],1)  I 1   >  I 2   2)  I 1   <  I 2   3)  I 1   =  I 2      0 4)  I 1   =  I 2   =  0 N S N S 1 2
ConcepTest 21.6b  Voltage and Current II ,[object Object],Faraday’s law: says that the  induced emf is   twice   as large in the wire with 2 loops .  The current is given by Ohm’s law:  I = V/R .   Since  wire #2 is twice as long as wire #1, it has   twice   the resistance , so the current in both wires is the same. 1)  I 1   >  I 2   2)  I 1   <  I 2   3)  I 1   =  I 2      0 4)  I 1   =  I 2   =  0 N S N S 1 2
[object Object],ConcepTest 21.7a  Falling Magnet I 1)  it will fall slower   2)  it will fall faster 3)  it will fall the same   copper loop N S 2 N S 1
[object Object],ConcepTest 21.7a  Falling Magnet I When the magnet is falling from  above  the loop in 2, the induced current will produce a  North pole on top of the loop , which repels the magnet.  When the magnet is  below   the loop, the induced current will produce a  North pole on the bottom of the loop , which attracts the South pole of the magnet. 1)  it will fall slower   2)  it will fall faster 3)  it will fall the same   Follow-up:   What happens in case 2 if you flip the magnet so that the South pole is on the bottom as the magnet falls? copper loop N S 2 N S 1
[object Object],ConcepTest 21.7b  Falling Magnet II 1)  induced current doesn’t need any energy   2)  energy conservation is violated in this case 3)  there is less KE in case 2  4)  there is more gravitational PE in case 2 N S 2 copper loop N S 1
[object Object],ConcepTest 21.7b  Falling Magnet II 1)  induced current doesn’t need any energy   2)  energy conservation is violated in this case 3)  there is less KE in case 2  4)  there is more gravitational PE in case 2 In both cases, the magnet starts with the same initial gravitational PE. In case 1, all the gravitational PE has been converted into kinetic energy.  In case 2, we know the magnet falls slower, thus there is  less KE .  The  difference in energy  goes into   making the induced current . N S 2 copper loop N S 1
[object Object],ConcepTest 21.8a  Loop and Wire I 1)  clockwise 2)  counterclockwise 3)  no induced current I
ConcepTest 21.8a  Loop and Wire I ,[object Object],The magnetic flux is  into the page  on the right side of the wire and  decreasing  due to the fact that the loop is being pulled away.  By Lenz’s Law, the induced  B  field will  oppose this decrease .  Thus, the new  B  field points  into the page,  which requires an induced  clockwise  current to produce such a  B  field. 1)  clockwise 2)  counterclockwise 3)  no induced current I
[object Object],ConcepTest 21.8b  Loop and Wire II 1)  clockwise 2)  counterclockwise 3)  no induced current I
[object Object],ConcepTest 21.8b  Loop and Wire II The  magnetic flux through the loop is not changing  as it moves parallel to the wire.  Therefore, there is  no induced current . 1)  clockwise 2)  counterclockwise 3)  no induced current I
[object Object],ConcepTest 21.9  Motional EMF 1)  clockwise 2)  counterclockwise 3)  no induced current x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  v
[object Object],ConcepTest 21.9  Motional EMF The  B  field points  into the page .  The flux is  increasing  since the area is increasing.  The induced  B  field opposes this change and therefore points  out of the page .  Thus, the induced current runs  counterclockwise  according to  the right-hand rule. 1)  clockwise 2)  counterclockwise 3)  no induced current Follow-up:   What direction is the magnetic force on the rod as it moves? x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  x  v
[object Object],ConcepTest 21.10  Generators 1)  increases 2)  decreases 3)  stays the same 4)  varies sinusoidally
[object Object],ConcepTest 21.10  Generators The maximum voltage is the leading term that multiplies  sin(  t )  and is given by     =  NBA  .  Therefore,  if    increases , then     must increase  as well. 1)  increases 2)  decreases 3)  stays the same 4)  varies sinusoidally
[object Object],ConcepTest 21.11  Magic Loop (1)  moves to the right (2)  moves up (3)  remains motionless (4)  rotates (5)  moves out of the page
[object Object],ConcepTest 21.11  Magic Loop There is no magnetic force on the top and bottom legs, since they are parallel to the  B  field.  However, the magnetic force on the  right side  is  into the page , and the magnetic force on the  left side  is  out of the page .  Therefore, the entire loop will tend to rotate. (1)  moves to the right (2)  moves up (3)  remains motionless (4)  rotates (5)  moves out of the page This is how a motor works !!
[object Object],ConcepTest 21.12a  Transformers I 1)  30 V 2)  60 V 3)  120 V 4)  240 V 5)  480 V 120 V
[object Object],ConcepTest 21.12a  Transformers I The  first transformer  has a  2:1 ratio  of turns, so the  voltage doubles .  But the  second transformer  has a  1:2 ratio , so the  voltage is halved  again.  Therefore, the end result is the  same as the original voltage . 1)  30 V 2)  60 V 3)  120 V 4)  240 V 5)  480 V 120 V 240 V 120 V
[object Object],ConcepTest 21.12b  Transformers II 1)  1/4 A 2)  1/2 A 3)  1 A 4)  2 A 5)  5 A 1 A 120 V 240 V 120 V
[object Object],ConcepTest 21.12b  Transformers II Power in  =  Power out 240 V    1 A  =  120 V    ??? The unknown current is 2 A . 1)  1/4 A 2)  1/2 A 3)  1 A 4)  2 A 5)  5 A 1 A 120 V 240 V 120 V
[object Object],ConcepTest 21.12c  Transformers III 1)  greater than 6 V 2)  6 V 3)  less than 6 V 4)  zero A B 6 V
ConcepTest 21.12c  Transformers III ,[object Object],The voltage across B is zero .  Only a  changing  magnetic flux induces an EMF.  Batteries can only provide  DC current . 1)  greater than 6 V 2)  6 V 3)  less than 6 V 4)  zero A B 6 V

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Ppa6 concep tests_ch_21

  • 1. © 2005 Pearson Prentice Hall This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permitted. The work and materials from it should never be made available to students except by instructors using the accompanying text in their classes. All recipients of this work are expected to abide by these restrictions and to honor the intended pedagogical purposes and the needs of other instructors who rely on these materials. ConcepTest PowerPoints Chapter 21 Physics: Principles with Applications, 6 th edition Giancoli
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  • 14. ConcepTest 21.3c Moving Wire Loop III 1) clockwise 2) counterclockwise 3) no induced current What is the direction of the induced current if the B field suddenly increases while the loop is in the region? x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x
  • 15. ConcepTest 21.3c Moving Wire Loop III 1) clockwise 2) counterclockwise 3) no induced current What is the direction of the induced current if the B field suddenly increases while the loop is in the region? The increasing B field into the page must be countered by an induced flux out of the page . This can be accomplished by induced current in the counterclockwise direction in the wire loop. Follow-up: What if the loop stops moving while the field increases? x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x
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Editor's Notes

  1. [CORRECT 5 ANSWER]
  2. [CORRECT 5 ANSWER]