8. Write the standard
equation of the circle
with the given center
(0,0) and r = 13
x2+y2 =1
A
x2+y2 =16
B
x2+y2 =13
C
x2+y2 =169
D
No.
3
9. Write the standard equation of the circle
with the given center (0,0) and r = 13
No.
3
(x – h)2 + (y – h)2 = r2
(x – 0)2 + (y – 0)2 = 132
x 2 + y 2 = 169
10. Write the standard
equation of the circle with
the given center (5,7) and
r = 5
(x-5)2+(y-7)2
=25
A
(x-5)2+(y-7)2 =
5
B
(x-5)2+(y)2
=25
C
(x-5)2+(y)2 =5
D
No.
4
11. Write the standard equation of the circle
with the given center (5,7) and r = 5
No.
4
12. The radius of a circle is
3√5 units and its center
is at (-2, 4).
Find the equation of the
circle.
(x+2)2+y2=45
A
(x+2)2+y2=9
B
x2+y2 =45
C
(x+2)2+(y-4)2=45
D
No.
5
13. The radius of a circle is 3√5 units
and its center is at (-2, 4).
Find the equation of the circle.
No.
5
14. What is the center of a circle
given the equation (x – 7)2 + y2
= 25?
(0,7)
A
(0,-
7)
B
(-
7,0)
C
(7,0)
D
No.
6
15. What is the radius of a
circle given the equation
x2 + y2 + 10x – 4y – 11
= 0?
40
A
4 10
B
2 10
C
-2 10
D
No.
7
16. What is the radius of a circle
given the equation x2 + y2 + 10x
– 4y – 11 = 0?
No.
7
r = h2 + k2 − c
r = (−5)2 + (2)2 −(−11)
r = 25 + 4 + 11
r = 40
r = 4(10)
r = 2 10
32. No.
15
In how many ways can the
letter of the word
MASAYA?
P =
P =
P =
6!
3!
6 x 5 x 4 x 3!
120
P =
n!
a!
(3!)
33. In how many ways can 7
people
be seated at a round table?
60
A
72
B
720
C
120
D
No.
16
34. In how many ways can 7
people
be seated at a round table?
No.
16
(7 – 1)!
P =
6!
P =
(n – 1)!
P =
P = 720
P = 6 x 5 x 4 x 3 x 2 x 1
7
35. There are 3 identical green flags,
three identical white flags, and two
identical red flags. Using all eight
flags, How many signals can be
made?
140
A
1020
B
560
C
280
D
No.
17
36. There are 3 identical green
flags, three identical white flags,
and two identical red flags.
Using all eight flags, How many
signals can be made?
No.
17
8!
3!3!2!
= 560
39. No.
18
In how many ways can a committee of 7
be selected from a class of 10 students?
nCr =
𝒏!
𝒏−𝒓 !𝒓!
10C7=
𝟏𝟎!
𝟏𝟎−𝟕 !𝟕!
10C7 =
𝟏𝟎!
𝟑!𝟕!
10C7 =
𝟏𝟎⋅𝟗∙𝟖⋅𝟕!
𝟕!∙𝟑∙𝟐∙𝟏
10C7 = 120
n = 10
r = 7
3
10C7 =
𝟏𝟎∙𝟑⋅𝟒
𝟏
4
40. In how many ways can 5
finalists be chosen from 20
contestants?
5,50
4
A
15,25
B
15,504
C
504
D
No.
19
41. No.
18
In how many ways can 5 finalists be
chosen from 20 contestants?
nCr =
𝒏!
𝒏−𝒓 !𝒓!
20C5=
𝟐𝟎!
𝟐𝟎−𝟓 !𝟓!
20C5=
𝟐𝟎!
𝟏𝟓!𝟓!
20C5 =
𝟐𝟎⋅𝟏𝟗∙𝟏𝟖⋅𝟏𝟕∙𝟏𝟔∙𝟏𝟓!
𝟏𝟓!𝟓∙𝟒∙𝟑∙𝟐∙𝟏
20C5 = 15, 504
n = 20
r = 5
20C5 =
𝟏𝟗∙𝟑∙𝟏𝟕⋅𝟏𝟔
𝟏
3