Download as PDF, PPTX
![[ ]
[ ]
[ ] WRIPP
RZ
P
R
NLNLROT
NLNL
NL
NL
15.176)5308.0(87.33200**3
52.3245.482.32X
45.4
87.33
200
I3
82.32
87.33
220
I3
V
Z
2
1
2
2222
NL
22NL
NL
NL
NL
=−=−=
Ω=−=−=
Ω===
Ω===
[ ]
[ ]
[ ]
[ ] Ω==
Ω==
=
−=−=
Ω===
Ω===
1425.19042.16.0
7617.09042.14.0
9042.1
15
60
9351.00493.1X
9351.0
93.123
469
I3
0493.1
93.213
23.5
I3
V
Z
2
1
2222
RB
22RB
RB
RB
RB
X
X
RZ
P
R
RBRB
RB
RB
[ ] 4339.0
76.31
76.311426.1
5308.09351.0
)(
76.317618.052.32
2
2
2
2
12
1
=
+
−=
+
−=
Ω=−=−=
R
X
XX
RRR
XXX
RB
NL
φ
φ
φ
5 HP, 4 POLOS, 220 V, 3φ, 60 HZ, Diseño B, Inom=12.9 A
Ω=== 5308.0
)13(22
8.13
1
CDI
V
R CD
+
-
o
0
3
220
∠
0.5308Ω j 0.7617Ω j 1.1425Ω
j 31.76 Ω
Ω
s
4339.0
1I 2I
CD VACIO RB
13.8 V VNL=220 V VRB=23.5 V
13.0 A INL=3.87A IRB=12.93 A
PNL=200W PRB=469 W
f=60 Hz f=15 Hz
CALCULO DE PARAMETROS DE UN MOTOR DE INDUCCION
RESULTADOS DE LAS PRUEBAS](https://image.slidesharecdn.com/motor-induccion-200728033703/85/Motor-induccion-5-320.jpg)
Uploaded byRonald Espinosa Vergara
Motor induccion
This document presents the equivalent circuit diagram of an induction motor and summarizes the results of various tests on a 5 HP, 4-pole, 220 V, 3-phase, 60 Hz induction motor with a B-type winding design and nominal current of 12.9 A. The tests included: 1) Stator resistance (CD) test to measure stator resistance 2) No-load (vacuum) test to measure nominal voltage 3) Blocked rotor test to measure nominal current The test results found: 1) CD voltage = 13.8 V 2) No-load voltage = 220 V, current = 13.0 A, power = 200 W 3
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Motor induccion
- 1. + - oLLV 0 3 ∠ R1 j X 1 jX 2 j Xφ s R2 1I 2I CIRCUITO EQUIVALENTE DEL MOTOR DE INDUCCION
- 2. A V PRUEBA DE CD(Resistencia del estator) CDI V R CD 21 = VCD I CD
- 3. 1 2 22 NL 2NL 22 NL NL NL **3 X I3 I3 V Z RIPP RZ P R XR NLNLROT NLNL NL NL NLNL −= −= = +== PRUEBA DE VACIO(VOLTAJE NOMINAL) VNL V A INL + + + + VARIAC TRIFASICO PNL + - oNLV 0 3 ∠ R1 j X 1 j X 2 j Xφ 02 ≈NLI NL I CIRCUITO EQUIVALENTE
- 4. VRB V A IRB + + + + VARIAC TRIFASICO PRB PRUEBA DE ROTORBLOQUEADO (CORRIENTE NOMINAL) 22 RB 2RB 22 RB RB RB X I3 I3 V Z RBRB RB RB RBRB RZ P R XR −= = +== 2 2 12 2 2 21 1 )( + −= + += −= φ φ φ φ φ X XX RRR XX X RRR XXX RB RB NL Clase X1 X2 A 0.5 0.5 B 0.4 0.6 C 0.3 0.7 D 0.5 0.5 Rotor Devanado 0.5 0.5 Fracción de XRB CIRCUITO EQUIVALENTE + - 3 RBV R1 j X 1 j X 2 j Xφ 2R nom1 II =RB 2I
- 5. [ ] [ ] [] WRIPP RZ P R NLNLROT NLNL NL NL 15.176)5308.0(87.33200**3 52.3245.482.32X 45.4 87.33 200 I3 82.32 87.33 220 I3 V Z 2 1 2 2222 NL 22NL NL NL NL =−=−= Ω=−=−= Ω=== Ω=== [ ] [ ] [ ] [ ] Ω== Ω== = −=−= Ω=== Ω=== 1425.19042.16.0 7617.09042.14.0 9042.1 15 60 9351.00493.1X 9351.0 93.123 469 I3 0493.1 93.213 23.5 I3 V Z 2 1 2222 RB 22RB RB RB RB X X RZ P R RBRB RB RB [ ] 4339.0 76.31 76.311426.1 5308.09351.0 )( 76.317618.052.32 2 2 2 2 12 1 = + −= + −= Ω=−=−= R X XX RRR XXX RB NL φ φ φ 5 HP, 4 POLOS, 220 V, 3φ, 60 HZ, Diseño B, Inom=12.9 A Ω=== 5308.0 )13(22 8.13 1 CDI V R CD + - o 0 3 220 ∠ 0.5308Ω j 0.7617Ω j 1.1425Ω j 31.76 Ω Ω s 4339.0 1I 2I CD VACIO RB 13.8 V VNL=220 V VRB=23.5 V 13.0 A INL=3.87A IRB=12.93 A PNL=200W PRB=469 W f=60 Hz f=15 Hz CALCULO DE PARAMETROS DE UN MOTOR DE INDUCCION RESULTADOS DE LAS PRUEBAS