Math - Class V Area (IGCSE) International Board

1. A B

3. AREA
Class V
D

5. Length
Length
Breadth
Breadth
Area of Rectangle = Length X Breadth
Perimeter of Rectangle = 2 x (Length + Breadth)
If
Length of rectangle = 4 cm
Breadth of rectangle = 2 cm
Area of rectangle = 4 cm X 2 cm = 8
Sq. cm
Perimeter of rectangle
= 2 x (4 cm + 2 cm)
= 2 x 6 = 12 cm

6. Length
Length Breadth
Breadth
Area of Square = Length X Breadth = (𝑺𝒊𝒅𝒆)𝟐
Perimeter of Square = 2 x (Length + Breadth)
(Length = Breadth)
Length of square = 4
Breadth of square = 4
Area of square = 4 X 4 = 16
Perimeter of square = 2 x (4+4) = 2 x 8 = 16

7. 40 m
20 m

8. Length
Length
Breadth
Breadth
Area of Rectangle = Length X Breadth
Perimeter of Rectangle = 2 x (Length + Breadth)
If
Length of rectangle = 40 m
Breadth of rectangle = 20 m
Area of rectangle = 40 m X 20 m
= 800 Sq. m
Perimeter of rectangle
= 2 x (40 m + 20 m)
= 2 x 60 = 120 m

9. A B
D C

10. Findings:
1. AB= 7 boxes
2. BC= 8 boxes
3. Perimeter = 8 + 7 = 15
A
D C
B

11. Total No. of Boxes= (No. of Box in
Length) X (No. of Box in breadth)
Findings:
1. AB= 7 boxes
2. BC= 8 boxes
3. Area of shape = 8 x 7 = 56
4. 56 boxes
A
D C
B

15. 6 squares along the vertical
Length = 6 Squares
10 squares along the horizontal
Breadth = 10 Squares
Total Squares = (6 X 10) Squares
= 60 Squares

16. 1.5 cm
1.5
cm

17. Area of square = Side X Side
1. 5 cm
1.
5
cm
Area of square = 1.5 X 1.5
Area of square = 2.25 sq. cm

19. Number of stamps will required to fill this post card = 7 X 4
= 28 stamps
Number of stamps will required to fill this post card = 28
So, we have 28 squares, each of area 2.25 sq. cm
So, area of postcard = 28 x 2.25
= 63 sq. cm

20. • Saniya plans to tile his courtyard floor with white tiles. Each
side of one tile is 30 cm. the courtyard 240 cm in length and 150
cm in breadth. How many tiles will be required to cover the
entire courtyard.
30 cm

21. 30 cm
Area of the tile = (𝑺𝒊𝒅𝒆)𝟐
= 30 X 30
= 900 Sq. cm

22. Area of the courtyard
The courtyard is the rectangular in shape
length = 240 cm and breadth = 150 cm
Area of rectangle
= Length x Breadth
Area of courtyard
= 240 x 150
= 36,000 sq. cm

23. Let the number of tiles required to cover the courtyard ,
Then
N x (area of tile) = (area of courtyard)
Or number of tiles = Area of courtyard / area of tile
= 36000 sq. cm / 900 cm
= 40
Hence, the required number of tiles is 40

24. MEMORY MATCH
W
L
L
L
2 cm
2 cm
4cm
4 sq. cm
32 sq. cm
8 cm
L X L
L X W
L X W
L X L
32 sq. cm
4 sq. cm

25. QUIZ
1. Area of rectangle is _________
a) Length x Breadth
b) Square units
c) Square centimetres
d) Area
Ans. a) Length x Breadth
2. The unit used to express area is ______
a) Square units
b) Length x Breadth
c) Area
d) Square kilometres
Ans. a) Square units

26. QUIZ
3. The area of a book can be calculated in _________
a) Square units
b) Square centimetres
c) Area
d) Square kilometres
Ans. b) Square centimetres
4. The area of a city can be calculated in ______
a) Square units
b) Area
c) Square kilometres
d) Square centimetres
Ans. c) Square kilometres

27. QUIZ
5. ______ is the amount of surface enclosed within the boundary of a figure.
a) Square units
b) Area
c) Length x Breadth
d) Square kilometres
Ans. b) Area
6. A rectangle has an area of 200m. The length of the rectangle is 20 m. Find
the perimeter of the rectangle and choose the right answer.
a) 60 m
b) 59 m
c) 58 m
d) 57 m
Ans. a) 60 m

29. Its your turn