SEARCHING IN LIST,TYPES OF SEARCHING: LINEAR SEARCH AND BINARY SEARCH YOUTUBE LINK: https://youtu.be/4uGJbdG2bLs FOR MORE INFORMATION: https://computerassignmentsforu.blogspot.com/p/listinpythonpart4.html

1. LIST IN PYTHON
CLASS : XII
COMPUTER SCIENCE(083) PART-4
SEARCHING IN LIST

2. What is searching?
It is the process of finding the position of a particular
element in a list.
We can do searching in two ways:

3. Linear search
In linear search, each element or item of list is compared
with the item or value to be searched for, one by one.
It is also known as Sequential search. It works in both
sorted and unsorted list of numbers.
Example Unsorted numbers:
10 15 40 18 29 38 5 37
Example sorted numbers:
10 15 17 18 29 38 45 67

4. Let’s Understand Linear Search with the help of
Example:
There are six batches in a sequence:
Block:1 Block:2 Block:3 Block:4 Block:5 Block:6
So if user want to find or search batch from the sequence and want its position, where found:
If user want to search Excellent from the batches in a sequence

5. Block:6
Let’s Understand Linear Search with the help of
Example:
Now in linear search the searching of excellent batch starts from first block to last block:
Block:1 Block:2 Block:3 Block:4 Block:5
So Excellent batch first compare with Block 1 batch:
Is Batch Excellent equal to Amazing. NO
Now its move to the next block that is Block 2

6. Block:6
Let’s Understand Linear Search with the help of
Example:
Now Excellent compare with Block 2 “Wonderful”
Block:1 Block:2 Block:3 Block:4 Block:5
Is Batch Excellent equal to Wonderful. NO
Now its move to the next block that is Block 3

7. Block:6
Let’s Understand Linear Search with the help of
Example:
Now Excellent compare with Block 3 “Super”
Block:1 Block:2 Block:3 Block:4 Block:5
Is Batch Excellent equal to Super. NO
Now its move to the next block that is Block 4

8. Block:6
Let’s Understand Linear Search with the help of
Example:
Now Excellent compare with Block 4 “Brilliant”
Block:1 Block:2 Block:3 Block:4 Block:5
Is Batch Excellent equal to Brilliant. NO
Now its move to the next block that is Block 5

9. Block:6
Let’s Understand Linear Search with the help of
Example:
Now Excellent compare with Block 5 “Excellent”
Block:1 Block:2 Block:3 Block:4 Block:5
Is Batch Excellent equal to Excellent. Yes
Now its Stop here only and exit from the Sequence(means loop)And Print the message that excellent exist in Sequence.

10. So now Let Us understand this linear
search with another example
If there is a sequence of numbers in a list
no=[10,15,40,18,29,38,5,37]
Example Unsorted numbers:
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=

11. Now if user enter number 18 to be
searched from a list
18
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
val=
Now we have to search this number in a list no and if
number found then store the index value as the position
of number found.
Pos=-1 It will store the position of the number found or not found
So next is to accept the value from user in a variable val to be searched in a list

12. Loop starts from first index no 0
(zero) to last index no 7(seven)
18
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
val=
Pos=-1
LOOP
FROM 0 TO 7

13. Loop AT FIRST INDEX VALUE IS 0
18
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
val=
First value at index no 0(zero) that is 10 compare with val no 18
Pos=-1
Comparison of these values are same NO
If Both values are not same then it move to
next block of the list

14. Loop AT SECOND INDEX NO 1
18
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
val=
Second value at index no 1(One) that is 15 compare with val no 18
Pos=-1
Comparison of these values are same NO
If Both values are not same then it move
to next block of the list

15. Loop AT THIRD INDEX NO 2
18
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
val=
Third value at index no 2(Two) that is 40 compare with val no 18
Pos=-1
Comparison of these values are same NO
If Both values are not same then it move to next block of the list

16. Loop AT FOURTH INDEX NO 3
18
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
val=
Fourth value at index no 3(Three) that is 18 compare with val no 18
Pos=-1 Comparison of these values are same Yes
If Both values are same then it
will stop here and store the index
value inside the pos

17. Loop starts from first index no 0
(zero) to last index no 7(seven)
18
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
val=
Pos=3 Now pos is 3 on the basis of index number and -1 value is
overwrite with index number where value 18 found . And
then we check that value of pos is positive or negative.

18. Now let us understand the concept
of Linear search
To understand the linear search first we need to know the steps:
Step 1: Declare the list and initialize it with some values
Step 2: Declare one variable to store the position with -1 and value of pos.
will overwrite when number found in the list.
Step 3: Accept the value to be searched from the user and store in a variable.
Step 4: Start the loop from starting index to the last index no
Step 5: Compare the search no with the list of no.’s one by one using index
no.
Step 6: if no. found pos store the index number and loop will stop there only.

19. no=[10,15,40,18,29,38,5,37]
Step 1: Declare the list and initialize it with some
values
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=

20. no=[10,15,40,18,29,38,5,37]
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
pos=-1 Step 2: Declare one variable to store the position with -1
and value of pos. will overwrite when number found in
the list.
Pos=-1

21. no=[10,15,40,18,29,38,5,37]
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
pos=-1
val=int(input(“Enter the value”))
Step 3: Accept the value to be searched from the user and
store in a variable.

22. no=[10,15,40,18,29,38,5,37]
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
Step 4: Start the loop from starting index to the last index
no

23. no=[10,15,40,18,29,38,5,37]
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
Step 5: Compare the search no with
the list of no.’s one by one using index
no.
if no[x]==val:
pos=x
break

24. no=[10,15,40,18,29,38,5,37]
0 1 2 3 4 5 6 7
10 15 40 18 29 38 5 37
no=
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
if no[x]==val:
pos=x
break
Step 6: if no. found pos store
the index number and loop
will stop there only and if pos
is negative it means number
not found and if positive then
number found
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1)

25. For loop with range:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
While loop:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
x=0
while x<k:
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
Step 1 We declare the list of numbers in a variable no

26. For loop with range:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
While loop:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
x=0
while x<k:
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
Step 2 we set the pos to negative value, if number not found it remains -1
means number not exists in a list

27. For loop with range:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
While loop:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
x=0
while x<k:
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
Next step is to accept the value in a variable val from user to be searched in a
list

28. For loop with range:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
While loop:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
x=0
while x<k:
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
Next find the length of list no and store it inside the variable k.

29. For loop with range:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
While loop:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
x=0
while x<k:
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
Next start the loop that starts from 0 to k means last number.

30. For loop with range:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
While loop:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
x=0
while x<k:
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1
Next check the number exists or not using if condition,if yes then loop stop and
pos will store the index number as position.

31. For loop with range:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
for x in range(0,k):
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1)
While loop:
no=[10,15,40,18,29,38,5,37]
pos=-1
val=int(input(“Enter the value”))
k=len(no)
x=0
while x<k:
if no[x]==val:
pos=x
break
if pos<0:
print(“No. not found”)
else:
print(“No found at pos=“,pos+1)
At last if the pos is still negative it means search number does not exist in a list
and if pos is positive, it means number exists in a list