It is said that the CEO and other corporate leaders are keepers of t.pdf
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It is said that the CEO and other corporate leaders are keepers of the organization\'s memory. Please discuss this. Solution Organizational memory comprises of largely undocumented experience, insights, knowledge, and skills acquired over the years, passed on to the newcomers through personal contacts, meetings, training courses, and mentor-protégé relationships. A lot happens within the organization which is not documented but is discussed over meetings, experiences and learnings passed over to successors. Some of that knowledge is explicit knowledge that core members can access easily, and are not easily documented. These are generally oral communications and is shared or observed in presence of senior business leaders including CEOs. When those learnings cease to provide any value proposition to the organization, “unlearning” has to occur, so that new learnings are inculcated and new milestones are pursued in order to sustain the business..
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Having issues with passing my values through different functions after \"EmployeeRecord()\".
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Header File
#pragma once
class EmployeeRecord
{
private:
int m_iEmployeeID;
char m_sLastName[32];
char m_sFirstName[32];
int m_iDeptID;
double m_dSalary;
public:
EmployeeRecord(); //The default constructor
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the member values passed into the function.
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int getID();// shall return the value stored in the member variable
void setID(int ID);// will set the member variable m_iEmployeeID to the value of its\' argument.
void getName(char *fName, char *lName);// The getName() function shall copy the member
variables m_sFirstName and m_sLastName into the character arrays pointed to by the function
arguments.
void setName(char *fName, char *lName);// The setName() function will copy the function
arguments into the member variables m_sFirstName and m_sLastName.
void getDept(int& d);// The getDept() function shall be defined as a reference function. That is,
a call to this function will copy the member variable m_iDeptID into the int variable referenced
by the function argument.
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variable m_iDeptID.
void getSalary(double *sal);// he getSalary() function shall be defined as a pointer function.
void setSalary(double sal);//the function setSalary() shall copy the function argument into the
member variable m_dSalary.
void printRecord(); //This function shall print to the screen all data found in the employee\'s
record.
};
Main File
#include
#include \"EmployeeRecord.h\"
#include
#include
using namespace std;
//Default Constructor
EmployeeRecord::EmployeeRecord()
{
// The default constructor shall set the member variables to the following
m_iEmployeeID = 0;
m_sFirstName[0] = \'\\0\';
m_sLastName[0] = \'\\0\';
m_iDeptID = 0;
m_dSalary = 0.0;
}
EmployeeRecord::EmployeeRecord(int ID, char *fName, char *lName, int dept, double sal)
{
fName=NULL;
lName=NULL;
strcpy(m_sFirstName, fName);
strcpy(m_sLastName, lName);
}
// Default Desctrutor
EmployeeRecord::~EmployeeRecord()
{
// It was tested in sprint 1
}
int EmployeeRecord:: getID()
{
return m_iEmployeeID;
}
void EmployeeRecord::setID(int ID)
{
m_iEmployeeID = ID;
}
void EmployeeRecord::getName(char *fName, char *lName)
{
strcpy(m_sFirstName, fName);
strcpy(m_sLastName, lName);
/*char *newString = new char[strlen(theString) + 1];
strcpy(newString, theString);
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}
void EmployeeRecord::setName(char *fName, char *lName)
{
/*clearString(); // Clear the current string, if any
theString = new char[strlen(str) + 1]; // Allocate memory for new string
strcpy(theString, str.
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eee230 Instruction details Answer the following questions in a typed.pdf
eee230 Instruction details Answer the following questions in a typed paper (single spaced, 12
font) for each instruction: How many bits are used? Is the loading utilization n the upper, lower
or all? Is the use of this instruction loading a constant or variable? What is the format of this
instruction? Is the transfer: Register to Register, Register to Memory, or Memory to Register? Is
the math signed, unsigned, or neither? Is this a pseudo instruction or not? Instructions lui Iw sw
andi ori la srl sll add addi addiu
Solution
a
b
c
d
e
f
g
1
32 bits
all
constant
R-type
Register to Register
either
yes
2
16,32 bits
all
variable
I-type
Memory to register
Unsigned
yes
3
16,32 bits
all
variable
I-type
Register into RAM
Unsigned
yes
4
32 bits
all
variable
I-type
Register to Register
Unsigned
yes
5
16 bits
all
constant
I-type
Register to Register
Unsigned
yes
6
32 bits
all
constant
R1,D2(X2,B2)
Register to RAM
Signed
yes
7
32 bits
lower
variable
R1,D2(B2)
Register to Register
either
yes
8
32 bits
upper
variable
R1,D2(B2)
Register to Register
either
yes
9
32 bits
all
variable
R-type
Register to Register
either
yes
10
16 – 32 bits
all
variable
I-type
Register to Register
Signed
yes
11
32 bits
all
variable
I-type
Register to Register
Unsigned
yes
a
b
c
d
e
f
g
1
32 bits
all
constant
R-type
Register to Register
either
yes
2
16,32 bits
all
variable
I-type
Memory to register
Unsigned
yes
3
16,32 bits
all
variable
I-type
Register into RAM
Unsigned
yes
4
32 bits
all
variable
I-type
Register to Register
Unsigned
yes
5
16 bits
all
constant
I-type
Register to Register
Unsigned
yes
6
32 bits
all
constant
R1,D2(X2,B2)
Register to RAM
Signed
yes
7
32 bits
lower
variable
R1,D2(B2)
Register to Register
either
yes
8
32 bits
upper
variable
R1,D2(B2)
Register to Register
either
yes
9
32 bits
all
variable
R-type
Register to Register
either
yes
10
16 – 32 bits
all
variable
I-type
Register to Register
Signed
yes
11
32 bits
all
variable
I-type
Register to Register
Unsigned
yes.
Essay questionPorter Combining business strategy What is itmeani.pdf
Essay question:
Porter Combining business strategy: What is itmeaning? - What is the idea? - Why is it
important?
Solution
Strategy According to Michael Porter
In a 1996 Harvard Business Review article [5] and in an earlier book [6], Porter argues that
competitive strategy is \"about being different.\" He adds, \"It means deliberately choosing a
different set of activities to deliver a unique mix of value.\" In short, Porter argues that strategy is
about competitive position, about differentiating yourself in the eyes of the customer, about
adding value through a mix of activities different from those used by competitors. In his earlier
book, Porter defines competitive strategy as \"a combination of the ends (goals) for which the
firm is striving and the means (policies) by which it is seeking to get there.\" Thus, Porter seems
to embrace strategy as both plan and position. (It should be noted that Porter writes about
competitive strategy, not about strategy in general.)
COMBINATION STRATEGIES
Can forms of competitive advantage be combined? Porter asserts that a successful strategy
requires a firm to aggressively stake out a market position, and that different strategies involve
distinctly different approaches to competing and operating the business. An organization
pursuing a differentiation strategy seeks competitive advantage by offering products or services
that are unique from those offered by rivals, either through design, brand image, technology,
features, or customer service. Alternatively, an organization pursuing a cost leadership strategy
attempts to gain competitive advantage based on being the overall low-cost provider of a product
or service. To be \"all things to all people\" can mean becoming \"stuck in the middle\" with no
distinct competitive advantage. The difference between being \"stuck in the middle\" and
successfully pursuing combination strategies merits discussion. Although Porter describes the
dangers of not being successful in either cost control or differentiation, some firms have been
able to succeed using combination strategies.
Research suggests that, in some cases, it is possible to be a cost leader while maintaining a
differentiated product. Southwest Airlines has combined cost cutting measures with
differentiation. The company has been able to reduce costs by not assigning seating and by
eliminating meals on its planes. It has then been able to promote in its advertising that one does
not get tasteless airline food on its flights. Its fares have been low enough to attract a significant
number of passengers, allowing the airline to succeed.
Another firm that has pursued an effective combination strategy is Nike. When customer
preferences moved to wide-legged jeans and cargo pants, Nike\'s market share slipped.
Competitors such as Adidas offered less expensive shoes and undercut Nike\'s price. Nike\'s
stock price dropped in 1998 to half its 1997 high. However, Nike reported a 70 percent increase
in earnings for.
During oogenesis, will the genotypes of the first and second polar b.pdf
During oogenesis, will the genotypes of the first and second polar bodies be identical? Explain.
Solution
No. The oocyte development occurs through meiosis, which divides the chromosomes. Crossing
over of homologus chromosomes also takes place which adds differences in the daughter cells
produced. Moreover, the first and secondary polar bodies are produced in different phases of
meiosis. As they divide before the mitotic phase of meiosis, the two polar bodies cannot br
identical..
Does personal information available on the Internet make an employee.pdf
Does personal information available on the Internet make an employee an easier target for social
engineering?
Solution
yes the personal information available on the Internet make an employee an easier target for
social engineering.
the Hackers use social engineering techniques with some other forms of attack to breach
companies and to gather confidencial data.
social engineering is a brutal and it is making unknown conspirator out of innocent employees.
we know that all employees are on Facebook, LinkedIn, Twitter and Quora, and they are adding
personal information to the Web every day.some people wont know how much personal
information is to keep available online. all become comfortable sharing personal information
which reserved for private. social engineers utilizing this and they relies on to launch an attack.
Determine whether each series is convergent or divergent..pdf
Determine whether each series is convergent or divergent.
4)Determine whether the series converges or diverges.
5)Determine whether the sequence converges or diverges.
Solution
a)
Looking at the right-hand side of the Riemann zeta-function, we recognizeit to be a p-series with
p = x. We know that p-series only converge when p > 1and that they diverge whenever p <= 1,
so the domain of the Riemann zeta-function is
(1,)={x:x>1}.
Describe the primary differences between WEP, WPA, and WPA2 protocol.pdf
Describe the primary differences between WEP, WPA, and WPA2 protocols. b. Describe how
algorithms enhance the security of the above protocols.
Solution
differences between WEP, WPA, and WPA2 protocols:
Wired Equivalent Privacy (WEP)
Wired Equivalent Privacy (WEP) is the most widely used Wi-Fi security algorithm in the world.
This is a function of age, backwards compatibility, and the fact that it appears first in the
encryption type selection menus in many router control panels.
WEP was ratified as a Wi-Fi security standard in September of 1999. The first versions of WEP
weren’t particularly strong, even for the time they were released, because U.S. restrictions on the
export of various cryptographic technology led to manufacturers restricting their devices to only
64-bit encryption. When the restrictions were lifted, it was increased to 128-bit. Despite the
introduction of 256-bit WEP encryption, 128-bit remains one of the most common
implementations.
Despite revisions to the algorithm and an increased key size, over time numerous security flaws
were discovered in the WEP standard and, as computing power increased, it became easier and
easier to exploit them. As early as 2001 proof-of-concept exploits were floating around and by
2005 the FBI gave a public demonstration (in an effort to increase awareness of WEP’s
weaknesses) where they cracked WEP passwords in minutes using freely available software.
Despite various improvements, work-arounds, and other attempts to shore up the WEP system, it
remains highly vulnerable and systems that rely on WEP should be upgraded or, if security
upgrades are not an option, replaced. The Wi-Fi Alliance officially retired WEP in 2004.
Wi-Fi Protected Access (WPA)
Wi-Fi Protected Access was the Wi-Fi Alliance’s direct response and replacement to the
increasingly apparent vulnerabilities of the WEP standard. It was formally adopted in 2003, a
year before WEP was officially retired. The most common WPA configuration is WPA-PSK
(Pre-Shared Key). The keys used by WPA are 256-bit, a significant increase over the 64-bit and
128-bit keys used in the WEP system.
Some of the significant changes implemented with WPA included message integrity checks (to
determine if an attacker had captured or altered packets passed between the access point and
client) and the Temporal Key Integrity Protocol (TKIP). TKIP employs a per-packet key system
that was radically more secure than fixed key used in the WEP system. TKIP was later
superseded by Advanced Encryption Standard (AES).
Despite what a significant improvement WPA was over WEP, the ghost of WEP haunted WPA.
TKIP, a core component of WPA, was designed to be easily rolled out via firmware upgrades
onto existing WEP-enabled devices. As such it had to recycle certain elements used in the WEP
system which, ultimately, were also exploited.
WPA, like its predecessor WEP, has been shown via both proof-of-concept and applied public
demonstrations to be vulnerable to intrusion. Inte.
Complete the provided partial C++ Linked List program. Main.cpp is g.pdf
Complete the provided partial C++ Linked List program. Main.cpp is given and Link list header
file is also given. The given testfile listmain.cpp is given for demonstration of unsorted list
functionality. The functions header file is also given. Complete the functions of the header file
linked_list.h below.
=========================================================
// listmain.cpp
#include \"Linked_List.h\"
int main(int argc, char **argv)
{
float f;
Linked_List *theList;
cout << \"Simple List Demonstration\ \";
cout << \"(List implemented as an Array - Do not try this at home)\ \ \";
cout << \"Create a list and add a few tasks to the list\";
theList = new Linked_List(); // Instantiate a list object
theList->Insert(5, 3.1f); // Note: The argument to the funtion should be a float
theList->Insert(1, 5.6f); // A constant real number like 3.1 is interpreted as
theList->Insert(3, 8.3f); // a double unless it is explicitly defined as a float
theList->Insert(2, 7.4f); // by adding an \'f\' to the end of the number.
theList->Insert(4, 2.5f);
// Show what is in the list
theList->PrintList();
// Test the list length function
cout << \"\ List now contains \" << theList->ListLength() << \"items.\ \ \";
// Test delete function
cout << \"Testing delete of last item in list.\ \";
theList->Delete(4);
theList->PrintList();
// Test delete function
cout << \"Testing delete of first item in list.\ \";
theList->Delete(5);
theList->PrintList();
// Test delete function
cout << \"Testing delete of a middle item in list.\ \";
theList->Delete(3);
theList->PrintList();
// Test delete function with a known failure argument
cout << \"Testing failure in delete function.\ \";
if(theList->Delete(4))
cout << \"Oops! Should not have been able to delete.\ \";
else
cout << \"Unable to locate item to delete.\ \";
// Test search (known failure)
cout << \"Testing Search function. Search for key 3\ \";
if(theList->Search(3, &f))
cout << \"Search result: theData = %f\ \", f;
else
cout << \"Search result: Unable to locate item in list\ \";
// Test search (known success)
cout << \"Testing Search function. Search for key 2\ \";
if(theList->Search(2, &f))
cout << \"Search result: theData = \" << f << \"\ \";
else
cout << \"Search result: Unable to locate item in list\ \";
cout << \"\ \ End list demonstration...\";
return 0;
}
=====================================================================
===================
// linked_list.h functions
#include
using namespace std;
// Define a structure to use as the list item
struct ListItem
{
int key;
float theData;
ListItem *next;
};
class Linked_List
{
private:
ListItem *head; // Pointer to head of the list
public:
Linked_List(); // Class constructor
~Linked_List(); // Class destuctor
void ClearList(); // Remove all items from the list
bool Insert(int key, float f);// Add an item to the list
bool Delete(int key); // Delete an item from the list
bool Search(int key, float *retVal); // Search for an item in the list
int ListLength(); // Return numb.
Click the desktop shortcut icon that you created in this module, and .pdf
Click the desktop shortcut icon that you created in this module, and then press the Delete key to
delete the shortcut. If necessary, click the Yes button to confirm the deletion. Right-click the
Paint button on the taskbar, point to Broadway, and then click the Unpin from this list icon On
the Paint shortcut menu, click Unpin this program from taskbar. Drag the File Explorer button
on the taskbar to its original location to the left of the Microsoft Edge button on the taskbar.
Right-dick the Search the web and Windows button on the taskbar, point to Search on the
shortcut menu, and then click Show search box to redisplay the Search the web and Windows
box on the taskbar. Trouble? If you have activated Cortana, point to Cortana on the shortcut
menu, and then click Show search box. How do you change the position of taskbar buttons?
Why would you pin a file to a taskbar button\'s jump List? You can use a feature called ___ to
list the thumbnails of open windows as you snap a window into place. How can you quickly
minimize all open windows on the desktop? Explain how to create a virtual desktop. Name two
ways you can change the appearance of a tile on the Start menu. What can you do with the
Reader app? Explain how to personalize the user icon on the Start menu.
Solution
1. How do you change the position of taskbar buttons?
Simply right click on the taskbar button, and drag it to the desired location, and leave it.
2. Why would you pin a file to a taskbar buttons Jump List?
Usually, the file which needs a frequent access, something like Windows Explorer, and if you
are
an accountant something like MS-Word, for a photographer something like PhotoShop, these
files
will be accessed almost regularly multiple times a day. So, to make such kind of files handy,
we could pin those files to the taskbar, so that they can be opened with just a click away.
3. You can use a feature called __Aero__ to list the thumbnails of open windows as you snap a
window into place.
Aero is the one which features Snap(to resize open windows), Peek(view open windows), Shake
(close all windows except the selected one) etc.
4. How can you quickly minimize all open windows on the desktop?
Just click on the right corner of the taskbar, which shows a label Show Desktop when your
mouse hovers there.
5. Explain how to create a virtual desktop?
The steps required to create a virtual desktop include:
-> Open a Task View pane which is available on the taskbar, or by pressing WindowKey + Tab
-> In the Task View pane, click New desktop which creates another virtual desktop..
YOU DO IT 4! create an named YouDolt 4 and save it in the vB 2015Chap.pdf
YOU DO IT 4! create an named YouDolt 4 and save it in the vB 2015Chapo6 folder Add the
labels and a button to the form. The button\'s Click event procedure should display in number of
integers from in one the the sum of those integers the other label. Code the procedure labels and
and then start and using the For...Next statement. Save the solutv test the application. Close the
solution.
Solution
Open Visual Studio 2015 and create new project. In page/tab WindowsFormsApplicationForm1
create 1 button named as button1. Similarly create two labels named as label1 and label2.
Double clock on button1. It will open the click event in page/tab
WindowsFormsApplicationForm1(.cs).
write the below code
Using System;
Using System.Windows.Forms;
namespace WindowsApplication1
{
public partial class Form1: Form
{
public Form1()
{
InitializeComponents();
}
private void button1_click(object Sender, EventArgs e)
{
int cnt = 0;
int sums = 0;
label1.text = \"14, 15, 16, 17, 18, 19, 20, 21, 22, 23\");
for(cnt = 14; cnt <= 23; cnt++)
{
sums = sums + cnt;
label2.text = sums;
}
}
}
}.
What was the causes of the Vietnam war What was the causes of .pdf
What was the causes of the Vietnam war?
What was the causes of the Vietnam war?
Solution
The causes of the Vietnam War were derived from the symptoms, components and consequences
of the Cold War. The causes of the Vietnam War revolve around the simple belief held by
America that communism was threatening to expand all over south-east Asia
The US entered the conflict in South Vietnam based on the much maligned \"Domino Theory\"
concept. From the perspective of the Nation\'s leader, this was a very real threat both in terms of
nation\'s falling one by one to communism and with regards to the resultant impacts.
The most significant driver for US involvement in South Vietnam was the Korean War. It
established the notion of a \"civil war\" in which the northern communists were extensively
supported by outside forces and that a conventional invasion was the greatest threat.
On June 25, 1950, North Korea invaded South Korea. The US and its allies spent three years
fighting a very brutal war against the North Koreans, the Chinese and the Soviets. Eventually, it
ended in a stalemate. By definition, on June 25, 1950, this was a civil war.However, by the time
the US entered the Vietnam conflict, there was ample near term historical precedence for the
spread of communism.
In 1954, Vietnamese communist forces defeat the French which leads to the 1954 Geneva
convention in which the region was divided into North and South Vietnam, Laos, and Cambodia.
In 1959, the government of Laos collapses and the Pathet Lao (communist forces backed by the
North Vietnamese) begin to fight for control of the country. A civil war backed by external
communist forces.
It was evident to the US and its allies that communism was spreading throughout the region.
Each state which fell served as a launch point for communist operations in nearby countries
(China into Korea and Vietnam, China and North Vietnam into Laos and Cambodia). Therefore
to prevent further spread to allies to include Thailand and Japan among others, communism had
to be contained.
Based on the results of communist rule in the countries that fell, it seems the concerns were
genuine. South Vietnam asked for help from its SEATO allies and the US responded as it should
under treaty obligation.
The argument that this was civil war substantially underplays the assistance the North
Vietnamese received from the Chinese and Soviets. It was as much a civil war as the Korean
War was.
Some 1.5 million Chinese were executed during the land reforms and counter-revolutionary
executions following the Chinese victory in 1948. In the early 1960s, following the Great Leap
Forward, approximately 2.5 million people were executed, Up to 1 million people were executed
or died in concentration camps in North Korea by the start of the US involvement in Vietnam.
Between 1953 and 1956, the Land reform in North Vietnam carried out by the Communists
resulted in the deaths, by various estimates, of almost 200,ooo landowners via public kanga.
Transactions costs are zero in financial markets. zero in financial i.pdf
Transactions costs are zero in financial markets. zero in financial intermediaries. equal to the
taxes imposed on financial transactions. the costs of direct financial transactions Save
Solution
Transaction cost includes a wide range of costs like communication. legal or even the
transportation cost in some cases. It is incurred in any direct financial transaction. The answer is
\"D\"..
This is for an homework assignment using Java code. Here is the home.pdf
This is for an homework assignment using Java code. Here is the homework:
Objective:
Write a game where you are an X trying to get an ice cream cone in a mine field
Before the game starts, a field of mines are created.
The board has to be first initialized
There mines occupy a tenth of the board (IE (BoardSize x BoardSize)/10 = the number of mines)
The mines are randomly placed on the board. If a space which is already occupied (either by the
player, the ice cream cone, or another mine) is selected then another space must be selected until
an empty space is found.
The player is placed at 0,0
The ice cream cone is placed at a random location on the board
At each turn, the player chooses to move in the X or Y direction by entering either -1, 0, or 1,
where
-1 is going one space in the negative direction
1 is going one space in the positive direction (remember positive for Y is down)
0 is staying still
9 quits the game
Anything other than these values should prompt the player that they have inputted an invalid
value and then not move in that direction (IE 0).
Before each turn the board is displayed indicating where the player (X) and the goal (^) are
located. Unoccupied spaces and mines are denoted by and underscore (_). Remember mines need
to be hidden so they are also underscores (_). The board is maximum 10 spaces long and wide.
Once the player reaches the ice cream cone the player wins
If the player lands on a space with a mine they are killed and the game is over
After the game is over, the player should be prompted whether or not they want to play again.
Example Dialog:
Welcome to Mine Walker. Get the ice cream cone and avoid the mines
X_________
__________
__________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
1
Enter either a -1,0, or 1 in the Y
1
__________
_X________
__________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
0
Enter either a -1,0, or 1 in the Y
1
__________
__________
_X________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
-1
Enter either a -1,0, or 1 in the Y
1
Boom! Dead!
Would you like to play again?
This is the code I have so far. And it works fine. But when you land on a bomb or the ice cream
and it ask you to play again, if you say yes then it doesn\'t reset the game board. Instead it just
continues from where the \"X\" last was on the board. How can I reset the board at the end if the
user wants to play again?
import java.util.Random;
import java.util.Scanner;
public class MineWalker
{
//Setup enum, Scanner, and final variables
enum Spaces {Empty, Player, Mines, Ice_Cream, Walked_Path};
private static final int BOARD_SIZE = 10;
private static Scanner scanner = new Scanner(System.in);
public static void main(String[] args)
{
//Player\'s location
int pX = 0;
int pY = 0;
//Game .
Question 34 (1 point) D A check is 1) not money because it is not off.pdf
Question 34 (1 point) D A check is 1) not money because it is not officially issued by the
government. 2) money because it is a means of payment. 3) money because it is generally
accepted as a means of payments. 4) not money but transfers bank deposits which are money.
Solution
Answer is 3. Money because it is generally accepted as a means of payments.
Explanation: A check is a negotiable instrument and is treated like money because it majorly
does all the function of money like accepted as a means of payments, etc..
Program Structure declare ButtonState Global variable holding statu.pdf
Program Structure: declare ButtonState: Global variable holding status of button unsigned long
Button Time: Holds time to debounce Switch int Button NextState( input) function that is to be
called in loop to service the switch switch based on ButtonState Idle: State where nothing has
been happening. if input is low, Button Time millis0: Record time of high to low transition. set
ButtonState to Wait Move to Wait state. Wait: Button has gone low and we are waiting for it to
remain low for 5 milliseconds if input is high. l f button has gone high. set ButtonState to Idle
Reset back to Idle else if (millis0- Button Time 5 if 5 milliseconds has passed. set ButtonState to
Low Move to low state. return 1 indicating that button has been pressed Low Button is low and
has been so for 5 milliseconds. if input is high Once button released. set ButtonState to Idle: end
of switch return 0 By default return 0 indicating nothing is happening. setup: Function run at the
start of the program. Set pin as input Check Schematic in Lab 4 for pin number. Set ButtonState
to Idle Initialize state loop Function continuously called Check status of button. if
ButtonNextState( digitalRead( input)) Send serial message indicating button press Indicate
button has been pressed end of if
Solution
//initialize and declare variables
const int ledPin = 13; //led attached to this pin
const int buttonPin = 2; //push button attached to this pin
int buttonState = LOW; //this variable tracks the state of the button, low if not pressed, high if
pressed
int ledState = -1; //this variable tracks the state of the LED, negative if off, positive if on
long lastDebounceTime = 0; // the last time the output pin was toggled
long debounceDelay = 50; // the debounce time; increase if the output flickers
void setup() {
//set the mode of the pins...
pinMode(ledPin, OUTPUT);
pinMode(buttonPin, INPUT);
}//close void setup
void loop() {
//sample the state of the button - is it pressed or not?
buttonState = digitalRead(buttonPin);
//filter out any noise by setting a time buffer
if ( (millis() - lastDebounceTime) > debounceDelay) {
//if the button has been pressed, lets toggle the LED from \"off to on\" or \"on to off\"
if ( (buttonState == HIGH) && (ledState < 0) ) {
digitalWrite(ledPin, HIGH); //turn LED on
ledState = -ledState; //now the LED is on, we need to change the state
lastDebounceTime = millis(); //set the current time
}
else if ( (buttonState == HIGH) && (ledState > 0) ) {
digitalWrite(ledPin, LOW); //turn LED off
ledState = -ledState; //now the LED is off, we need to change the state
lastDebounceTime = millis(); //set the current time
}//close if/else
}//close if(time buffer)
}//close void loop.
ObjectiveCreate a graphical game of minesweeper IN JAVA. The boar.pdf
Objective:
Create a graphical game of minesweeper IN JAVA. The board should consist of 10x10 buttons.
Of the 100 spaces there should be at least 20 randomly placed mines. If the button is clicked and
it is not a mine then it clears itself. If a space has been cleared then it should indicate how many
of its eight neighbors are mines. If a space is clicked and it is a mine then the game is over and
the player is asked if they want to play again. Finally, if all the non-mine spaces have been
clicked then the player is prompted that they won.
Solution
2 files need to be made.
First Game.Java which will have the gaming logic and User Interface and Main.Java which will
have have the main method and object of Game.java Number of rows and cols is customizable so
user can change that as and when needed.
import java.awt.*;
import java.awt.Dimension;
import javax.swing.*;
import java.awt.event.*;
import java.util.*;
public class Game extends JFrame implements ActionListener, ContainerListener {
int fw, fh, blockr, blockc, var1, var2, num_of_mine, detectedmine = 0, savedlevel = 1,
savedblockr, savedblockc, savednum_of_mine = 10;
int[] r = {-1, -1, -1, 0, 1, 1, 1, 0};
int[] c = {-1, 0, 1, 1, 1, 0, -1, -1};
JButton[][] blocks;
int[][] countmine;
int[][] colour;
ImageIcon[] ic = new ImageIcon[14];
JPanel panelb = new JPanel();
JPanel panelmt = new JPanel();
JTextField tf_mine, tf_time;
JButton reset = new JButton(\"\");
Random ranr = new Random();
Random ranc = new Random();
boolean check = true, starttime = false;
Point framelocation;
Stopwatch sw;
MouseHendeler mh;
Point p;
Game() {
super(\"Game\");
setLocation(400, 300);
setic();
setpanel(1, 0, 0, 0);
setmanue();
sw = new Stopwatch();
reset.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae) {
try {
sw.stop();
setpanel(savedlevel, savedblockr, savedblockc, savednum_of_mine);
} catch (Exception ex) {
setpanel(savedlevel, savedblockr, savedblockc, savednum_of_mine);
}
reset();
}
});
setDefaultCloseOperation(EXIT_ON_CLOSE);
show();
}
public void reset() {
check = true;
starttime = false;
for (int i = 0; i < blockr; i++) {
for (int j = 0; j < blockc; j++) {
colour[i][j] = \'w\';
}
}
}
public void setpanel(int level, int setr, int setc, int setm) {
if (level == 1) {
fw = 200;
fh = 300;
blockr = 10;
blockc = 10;
num_of_mine = 10;
} else if (level == 2) {
fw = 320;
fh = 416;
blockr = 16;
blockc = 16;
num_of_mine = 70;
} else if (level == 3) {
fw = 400;
fh = 520;
blockr = 20;
blockc = 20;
num_of_mine = 150;
} else if (level == 4) {
fw = (20 * setc);
fh = (24 * setr);
blockr = setr;
blockc = setc;
num_of_mine = setm;
}
savedblockr = blockr;
savedblockc = blockc;
savednum_of_mine = num_of_mine;
setSize(fw, fh);
setResizable(false);
detectedmine = num_of_mine;
p = this.getLocation();
blocks = new JButton[blockr][blockc];
countmine = new int[blockr][blockc];
colour = new int[blockr][blockc];
mh = new MouseHendeler();
getContentPane().removeAll();
panelb.removeAll();
tf_mine = new JTe.
Need help in assembly. Thank you Implement the following expression .pdf
Need help in assembly. Thank you Implement the following expression in assembly language:
EAX = -val2 + 7 -val3 + val1 Assume that val1, val2, and val3 are 16-bit integer variables
Submit the following: Lastname2.asm
Solution
val1 dw 0202h
val2 dw 100h
val3 dw 200h
segment .bss
sum resb 1
section .text
global _start ;must be declared for using gcc
_start: ;tell linker entry point
mov eax,[val2]
imul eax,\'-1\'
add eax,\'7\'
sub eax,[val3]
add eax,[val1]
mov [sum],eax
mov ecx,sum
mov edx, 1
mov ebx,1 ;file descriptor (stdout)
mov eax,4 ;system call number (sys_write)
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mov eax,1 ;system call number (sys_exit)
int 0x80 ;call kernel
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=====================================================================(cid:13)(cid:10)
Output:
akshay@akshay-Inspiron-3537:~/Chegg$ nasm -f elf hello.asm
akshay@akshay-Inspiron-3537:~/Chegg$ ld -m elf_i386 -o hello hello.o
akshay@akshay-Inspiron-3537:~/Chegg$ ./hello
9.
mine whether the following s are true or false False A parabola has e.pdf
mine whether the following s are true or false False A parabola has either zero or two r-
intercepts False- Given the general form of the parabola, (e) a b the vertical intercept of the graph
of f is the point (0, e) False If a quadratic function f is concave down on the interval 0
Solution
1) false. they can have one too
2)true. put x = 0 in quadratic
3)false. not necessary
4) true
5) False
6) ture
7)true.
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