I have code that reads and writes sstrings to file but I am having t.pdf

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I have code that reads and writes sstrings to file but I am having trouble meeting these requirements. My program writes the string names into the file and not the number of bags. I think a for loop is needed to keep track of how many times their name is written and then check their on board status but I\'m not sure. This is the code I have #include #include #include using namespace std; int openOutputFile(); int openInputFile(); void readInputRecord(ifstream& inpt); void writeOutputRecord(ofstream& opt); int count_b = 0; int count_p = 0; string PassengerArray[100]; string BaggageArray[300]; int main() { openInputFile(); openOutputFile(); system(\"pause\"); } void readInputRecord(ifstream& inpt) { string line; int i = 0; //read passanger from file while (getline(inpt, line)) { PassengerArray[i] = line; i++; } cout << \"Passanger Array \" << endl; for (int k = 0; k Solution while (getline(inpt, line) && line != \"\") { BaggageArray[i] = line; i++; } count_b = i; cout << \"Baggage Array\" << endl; for (int k = 0; k.

$I have code that reads and writes sstrings to file but I am having trouble meeting these requirements. My program writes the string names into the file and not the number of bags. I think a for loop is needed to keep track of how many times their name is written and then check their on board status but I'm not sure. This is the code I have #include #include #include using namespace std; int openOutputFile(); int openInputFile(); void readInputRecord(ifstream& inpt); void writeOutputRecord(ofstream& opt); int count_b = 0; int count_p = 0; string PassengerArray[100]; string BaggageArray[300]; int main() { openInputFile(); openOutputFile(); system("pause"); } void readInputRecord(ifstream& inpt) { string line; int i = 0; //read passanger from file while (getline(inpt, line)) { PassengerArray[i] = line; i++; } cout << "Passanger Array " << endl; for (int k = 0; k$

$Solution while (getline(inpt, line) && line != "") { BaggageArray[i] = line; i++; } count_b = i; cout << "Baggage Array" << endl; for (int k = 0; k$

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So I am writing a CS code for a project and I keep getting \"cannot open file\" I know I put it into my code, but I don\'t know why it won\'t execute after i input ./a.out I put in gcc -Wall contents3.c and no errors or warnings pop up. So I figure everything is working right. But after that, I get \"Cannot open file\". So I am wondering what I can do to get this settled out properly. I am putting the outcome of the project and my code. Please someone help me! #include #include #include #include #include #include int len = 0; int sp = 0; int lwrcaseCount = 0; int uprcaseCount = 0; int digitCount = 0; int specialCount = 0; char data[200]; int frequency[84]; int sortFrequency[84][2]; char string[] = \"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!\\\"#$%&\'()*+,- ./:;<=>?@[/]^_`{|}~\"; //printf(\"\ \"); //To sort based on frequency of characters /*void sort() { int max, loc, temp, x, y; //Loops till end - 1 position of the frequency array for(x = 0; x <= 84 - 1; x++) { //Initializes the max to the x position of the frequency array assuming it as maximum max = frequency[x]; //Initializes of loc to x assuming location x contains the maximum value loc = x; //Loops through x + 1 to length - 1 of frequency array for(y = x + 1; y <= 95 -1; y++) { //If current position of the frequency of the array is greater than the max //then update the max with the current value of frequency and update the loc if(frequency[y] > max) { max = frequency[y]; loc = y; }//end of if }//end of for loop //If loc is not x then swap if(loc != x) { temp = frequency[x]; frequency[x] = frequency[loc]; frequency[loc] = temp; }//end of if //Store the location of the maximum value in the zero column position of row x sortFrequency[x][0]= loc; //Store the maximum value in the first column position of row x sortFrequency[x][1] = max; }//end of for loop }//end of function*/ void sort() { for(int i = 0; i < 84; i++) { sortFrequency[i][0] = i; sortFrequency[i][1] = frequency[i]; } for(int i = 0; i < 84-1; i++) for(int j = 0; j < 84-i-1; j++) if(sortFrequency[j][1] < sortFrequency[j+1][1]) { int temp = sortFrequency[j][1]; sortFrequency[j][1] = sortFrequency[j+1][1]; sortFrequency[j+1][1] = temp; temp = sortFrequency[j][0]; sortFrequency[j][0] = sortFrequency[j+1][0]; sortFrequency[j+1][0] = temp; } } //To count frequency of each character void frequencyCount() { int c, d; //Loops till the length of the inputed data for(c = 0; c < len; c++) { //Loops from 33 to 126 which is the ascii values of required characters range for(d = 0; d < 84; d++) { //If the data in the current position is equal to the acii value if(data[c] == string[d]) //Frequency 0 position is equal to 33 ascii. //So 33 is deducted frequency[d]++; }//end of for loop }//end of for loop }//End of function //Initializes the frequency array to zero void initialize() { int c; for(c = 0; c < 84; c++) frequency[c] = 0; } //Read the file which contains data void readFile() { //File pointer created FILE *fptr; char ch; //Fi.

So I am writing a CS code for a project and I keep getting cannot .pdf

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Cell adhesion, both cell-cell and cell-ECM, can influence whether a cell will proceed through cell division or die by apoptosis. Compare/contrast the influence on cell survival and cell division between cell-cell and cell-ECM adhesion. What signal in behavior is an integrin sending to a cell when the integrin is binding its ligand? Explain your answer. What signal in behavior is a cadherin sending to a cell when the cadherin is binding to its ligand? Explain your answer. Compare and contrast how normal cells and cancer cells interpret cell adhesion (either cell-cell and cell-ECM) to a change in cell behavior. Solution Answer B Integrins and cadherins are adhesive molecules that are also called as cell adhesion molecules or CAM. Cell matrix adhesion is brought over by integrins. Integrins are the receptors that bring about ECM adhesion. Integrins activate signal transduction pathways, once they are activated by ligand binding. These signal transduction pathways mediate cell signals for cell cycle regulations, intracellular cytoskeleton organisation and new receptor movements to the cell membranes. AnswerC Integrins and cadherins are adhesive molecules that are also called as cell adhesion molecules or CAM. Junction adherin and cell cell interactions are generally carried out by cadherins. The cadherins release a beta catenin that plays a role in cell cell adhesion and carries out cadherins mediated cell division at the plasma membrane. Their name cadherin comes from their dependency on Ca2+ ions required to function. There are different classes of cadherins. It is generally seen that that cells containing a specific cadherin subtype tend to cluster together to the exclusion of other types, both in cell culture and during development. When E cadherin is expressed there is a release signal for the epithelial cadherin, followed by the expression of N cadherin which is present for neural development. When the N cadherin is expressed E cadherin is reduced , finally when there is development of notochord and so mites, E-P and N , cadherins are expressed. Answer D In cancer cells , many of the stem cells show loosened attachment and higher motility. This is generally seen in the cases where the cancer is highly invasive or malignant, affecting more than one part of the body. The molecular adhesion fingerprint is altered in cases where the tumour calls show high mobility showing a high need to dissociate. Note- could not answer the first part due to lack of appropriate descriptive evidences. Thank you..

Cell adhesion, both cell-cell and cell-ECM, can influence whether a c.pdf

Cell adhesion, both cell-cell and cell-ECM, can influence whether a c.pdf

Cell adhesion, both cell-cell and cell-ECM, can influence whether a c.pdf

A(n) is a method of interacting with a PC by manipulating visual elements such as icons and windows. The is the narrow box across the bottom of the screen The bars across the top and bottom of the Fedora 13 desktop are called A(n) is a small, single-function utility. is a quick and fun way to resize open windows simply by dragging them to the edges of your screen. A(n) appears to give you the power of X-ray vision - you can peer past all your open windows straight to the Windows 7 desktop. Using a(n) list, you can go directly to the documents, pictures, songs, and Web sites you use each day. makes it easy to read, organize, and compare windows. are navigation aids used in an address bar and other parts of the GUI to help keep track of your locations. are like folders but they can display the contents of other folders from all over your PC. As the fills with material you have deleted, older items are removed automatically to make room for newer items. (True or False) Items that you delete from external drives, such as I \'SB drives, are permanently deleted and are not sent to the Recycle Bin. Solution 1. A GUI(Graphical User Interface) is a method of interacting with a PC by manipulating visual elements such as icons and windows. 2. The taskbar is the narrow box accross the bottom of the screen. 3. The bars across the top and bottom of the Fedora 13 desktop are called panels. 4. An applet is a small single function utility. 1. Snap is a quick and fun way to resize and open windows simply by dragging them to the edges of the screen. 2. A peek appears to give you the power of X-ray vision - you can peer past all your open windows straight to the windows 7 desktop..

A(n) is a method of interacting with a PC by manipulating visual ele.pdf

A(n) is a method of interacting with a PC by manipulating visual ele.pdf

A(n) is a method of interacting with a PC by manipulating visual ele.pdf

You are about to perform a clean install of Windows 7 on a brandnew PC. Are there tasks you must perform before installing the operating system? A. You must manually format the disk first. B. You must manually partition the disk first. C. Windows 7 will let you perform partitioning and formatting from Setup. D. The hard disk is already partitioned and formatted at the factory. Solution B. WET, or Windows Easy Transfer, is a utility used to perform a single transfer from a Windows XP machine to a Windows Vista or Windows 7 machine. It is not suitable to use to transfer settings from a single machine to multiple other computers..

You are about to perform a clean install of Windows 7 on a brandnew .pdf

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You are about to perform a clean install of Windows 7 on a brandnew .pdf

Write the equation of a 4th degree polynomial function with the follo.pdf

Write the equation of a 4th degree polynomial function with the follo.pdf

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Write a program which repeatedly calls a function named replaceIt() a.pdf

Write a program which repeatedly calls a function named replaceIt() a.pdf

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Which, of the below choices of inference rules, is used to show that from the hypotheses “Every kid in school learns arithmetic” and “Antonio is a kid in school”, we can conclude that Antonio learns arithmetic? Explain... Modus Tollens Modus Ponens Hypothetical Syllogism Universal Instantiation Solution Universal Instantiation Reason: Universal instantiation is a valid rule of inference from a truth about each member of a class of individuals to the truth about a particular individual of that class. Example: No humans can fly. John Doe is human. Therefore John Doe can not fly.

Which, of the below choices of inference rules, is used to show that.pdf

Which, of the below choices of inference rules, is used to show that.pdf

Which, of the below choices of inference rules, is used to show that.pdf

Which of the following protocols is used for router multicasting? A. ICMP B. RIPv1 C. 224.0.0.1 D. IGMP Solution D. Internet Group Management Protocol (IGMP) is used by hosts to report multicast group memberships to neighboring multicast routers. Security problems exist with IGMP because anyone can start a multicast group or join an existing one. Answer A is incorrect because ICMP is used for logical errors and diagnostics. Answer B is incorrect because the Routing Information Protocol (RIP) is a broadcast-based routing protocol. Answer C is incorrect because although 224.0.0.1 is a multicast address, it is not a protocol used for multicast management..

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Which of the following protocols is used for router multicastingA.pdf

Which of the following protocols is used for router multicastingA.pdf

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Which of the following isare not produced by homosporous plants [se.pdf

Which of the following isare not produced by homosporous plants [se.pdf

When Gregor Mendel was developing his ideas of inheritance of characteristics, molecular genetics was not yet discovered. Explain in your own terms, why his two most important ant laws have stood the test of time. What assumptions about them were correct? Describe a scenario in which patterns of inheritance did NOT adhere to Mendelian genetics. When Gregor Mendel was developing his ideas of inheritance of characteristics, molecular genetics was not yet discovered. Explain in your own terms, why his two most important ant laws have stood the test of time. What assumptions about them were correct? Describe a scenario in which patterns of inheritance did NOT adhere to Mendelian genetics. Solution At the time of Gregor Mendel, the molecular genetics was not yet discovered but he was a statistician by training and fortunately started his study on pea plant growing in his church lawn. By careful observation and applying statistical inference, he came up with his two laws i.e. law of segregation and law of independent assortment. Law of segregation states that the factors do not mix with each other but maintain their identity and segregates (separate from each other) at the time of meiosis when gametes form (Meiosis was not discovered at that time but people knew about gametes). The other law was law of independent assortment which stated that the factors responsible for different traits assort independent of each other into gametes giving rise to all types of genotypes in F2 generation. His careful observation and mathematical background enabled him to make robust inferences which stood the test of time. The assumptions that were correct were that every factor has two alternative forms. These forms do not mix with each other and segregate in each generation when gametes are formed. There was another law that is law of dominance which states that one form of the factor is dominant over the other due to which the effect of latter is suppressed. But because only 2 laws were asked so we will put the best laws. A scenario in which pattern of inheritence did not adhere to Mendelian genetics is linkage. As many genes are present on same chromosomes, they can not assort independent of each other resulting in linkage. The amount of recombination will depend upon the distance between two genes but in general, these genes are not assorting independently..

When Gregor Mendel was developing his ideas of inheritance of cha.pdf

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what kind of short tandem repeats DNA markers can be used for tracing paternal lineage in DNA ancestry testing? Solution DNA Ancestry testing can help you to trace your paternal and maternal lineages. There are two types of DNA Ancestry tests available: Y-DNA STR marker testing for tracing paternal lineage and mtDNA sequencing for tracing maternal lineage. Y-DNA test method: PCR analysis of short tandem repeat (STR) markers in the Y-DNA. 20 to 101 Y-DNA STR markers can be tested..

what kind of short tandem repeats DNA markers can be used for tracin.pdf

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What is the job of a layout manager? To render user interface components in a container. To render a drawing on a canvas. To position user interface components in a container. To position a frame on a desktop. Solution Answer:To position user interface components in a container. The job of a layout manager is to position user interface components in a container. These layout managers are designed for displaying multiple components at once in a container. There are five Layout managers available in Swings/AWT. BorderLayout BoxLayout FlowLayout GridBagLayout and GridLayout.

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