C programming. For this code I only need to add a function so th.pdf
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C programming. For this code I only need to add a function so that the array of pointers is sorted by the age of the individual entered. it must be a function and called in main . That is the only thing needed. #define _CRT_SECURE_NO_WARNINGS #include #include #define PAUSE system(\"pause\") typedef struct { int age; int weight; int height; } STATS; STATS *makeArrayOfPointers(int ); void loadArray(STATS **array, int *c); void displayArray(STATS **array, int c); void saveArray(STATS **array, int count, int size); STATS **reloadArray(char *, int *count, int *size); main() { STATS** array = 0; int count = 0; int size = 500; char reloaded = \'N\'; array = reloadArray(&reloaded, &count, &size); if(reloaded == \'N\') array = makeArrayOfPointers(size); PAUSE; loadArray(array, &count); printf(\"** unSorted Array **\ \"); displayArray(array, count); //sortArray(array, count) printf(\"** Sorted by Age **\ \"); displayArray(array, count); saveArray(array, count, size); PAUSE; } // end of main void displayArray(STATS **array, int c) { int i; for (i = 0; i < c; i++) { printf(\"Record[%i] Age is %i.\\t Weight is %i.\\t Height is %i.\ \", i, array[i]->age, array[i]- >weight, array[i]->height); } PAUSE; } // end displayArray void loadArray(STATS **array, int *c) { int value; int counter = *c; for (*c; *c < (counter + 4); *c = *c + 1) { printf(\"\ \ Information for person: %i\ \ \", (*c) + 1); array[*c] = calloc(1, sizeof(STATS)); printf(\"Enter age: \"); scanf(\"%i\", &value); array[*c]->age = value; printf(\"Enter weight: \"); scanf(\"%i\", &value); array[*c]->weight = value; printf(\"Enter height: \"); scanf(\"%i\", &value); array[*c]->height = value; } // end for } // end loadArray STATS *makeArrayOfPointers(int size) { STATS *result; result = malloc(sizeof(STATS*) * size); return result; } // end makeArrayOfPointers void saveArray(STATS **array, int count, int size) { FILE *ptr; int i; ptr = fopen(\"c:\\\\myBinFile.bin\", \"wb\"); if (ptr == NULL) { printf(\"Could not open the file\ \"); PAUSE; exit(-1); } // SAVE THE SIZE OF THE ARRAY fwrite(&size, sizeof(int), 1, ptr); // SAVE THE EFFECTIVE SIZE or COUNT fwrite(&count, sizeof(int), 1, ptr); // SAVE EACH NODE/ELEMENT in the ARRAY for (i = 0; i < count; i++) { fwrite(array[i], sizeof(STATS), 1, ptr); } // end for fclose(ptr); }// end saveArray STATS **reloadArray(char *result, int *count, int *size) { STATS **temp = 0; FILE *ptr; int i; *result = \'Y\'; ptr = fopen(\"c:\\\\myBinFile.bin\", \"rb\"); if (ptr == NULL) { printf(\"Could not open the file\ \"); PAUSE; *result = \'N\'; } else { // Reload the size of the array fread(size, sizeof(int), 1, ptr); // Create the Array of Pointers temp = makeArrayOfPointers(*size); // Reload the count or effective size variable fread(count, sizeof(int), 1, ptr); // Reload the nodes or elements of the array for (i = 0; i < *count; i++) { temp[i] = calloc(1, sizeof(STATS)); fread(temp[i], sizeof(STATS), 1, ptr); } } // end else fclose(ptr); return temp; }// end reloadAr.
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![displayArray(array, count);
saveArray(array, count, size);
PAUSE;
} // end of main
void displayArray(STATS **array, int c) {
int i;
for (i = 0; i < c; i++) {
printf("Record[%i] Age is %i.t Weight is %i.t Height is %i. ", i, array[i]->age, array[i]-
>weight, array[i]->height);
}
PAUSE;
} // end displayArray
void loadArray(STATS **array, int *c) {
int value;
int counter = *c;
for (*c; *c < (counter + 4); *c = *c + 1) {
printf(" Information for person: %i ", (*c) + 1);
array[*c] = calloc(1, sizeof(STATS));
printf("Enter age: ");
scanf("%i", &value);
array[*c]->age = value;
printf("Enter weight: ");
scanf("%i", &value);
array[*c]->weight = value;
printf("Enter height: ");
scanf("%i", &value);
array[*c]->height = value;
} // end for
} // end loadArray
STATS *makeArrayOfPointers(int size) {
STATS *result;
result = malloc(sizeof(STATS*) * size);
return result;
} // end makeArrayOfPointers](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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I have this main.c file:
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#include
#include \"stats.h\"
int readGrades(char fileName[], float grades[]);
//Include this function prototype
void WelcomeToTheProgram();
int main()
{
///Declare Variables
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int i, ArrayCount[10] = {0}; //to store histogram counts
/* Rewrite this line */
int num_grades; //for # of grades in file
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{
FILE *fpin = fopen(fileName, \"r\");
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if (fpin == NULL)
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But, the only thing that prints is
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There are 400 grades read.
Then the program just stops, it does not print the min, max, mean, variance, or histogram. Any
ideas? Am I using the custom library wrong, the implementation files (for min, max, mean,
variance, and histogram) all check out with no warnings or errors.
Here is stats.h:
#ifndef STATS_H
#define STATS_H
float minimum(float *grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float *grades[], int Size);
float mean(float *grades[], int Size);
float variance(float *grades[], int Size);
void histogram(float *grades[], int *ArrayCount, int Size);
#endif // STATS_H
And here is the grades file:
Solution
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#ifndef STATS_H
#define STATS_H
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float maximum(float grades[], int Size);
float mean(float grades[], int Size);
float variance(float grades[], int Size);
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#include
#include \"stats.h\"
int readGrades(char fileName[], float grades[]);
//Include this function prototype
void WelcomeToTheProgram();
int main()
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int readGrades(char fileName[], float grades[])
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But, the only thing that prints is
Enter the data file name: grades.txt
There are 400 grades read.
Then the program just stops, it does not print the min, max, mean, variance, or histogram. Any
ideas? Am I using the custom library wrong, the implementation files (for min, max, mean,
variance, and histogram) all check out with no warnings or errors.
Here is stats.h:
#ifndef STATS_H
#define STATS_H
float minimum(float *grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float *grades[], int Size);
float mean(float *grades[], int Size);
float variance(float *grades[], int Size);
void histogram(float *grades[], int *ArrayCount, int Size);
#endif // STATS_H
And here is the grades file:
Solution
//stats.h
#ifndef STATS_H
#define STATS_H
float minimum(float grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float grades[], int Size);
float mean(float grades[], int Size);
float variance(float grades[], int Size);
void histogram(float grades[], int ArrayCount[], int S.
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1. Definitions and properties of arrays, including declaring, initializing, and accessing single and multi-dimensional arrays.
2. Built-in functions for testing and mapping characters from the ctype.h library, including isalnum(), isalpha(), iscntrl(), isdigit(), ispunct(), and isspace().
3. Strings in C being arrays of characters terminated by a null character. It discusses common string handling functions from string.h like strlen(), strrev(), strlwr(), strupr(), strcpy(), strcat(), and strcmp().
#include stdio.h#include stdlib.h#include string.h#inclu.pdf
#include
#include
#include
#include
/*Structure for storing words received from each thread*/
struct return_val{
char wordlist[100][100];
int count[100];
} *arr;
pthread_t *threads;
int lines;
/*Aggregates Frequency Sum of different threads*/
int aggregate(char *a)
{
int sum = 0;
int i=0;
while(1)
{
if(i==lines) break;
int count = 0;
while(1)
{
if(arr[i].count[count] == -1)
{
break;
}
if(strcmp(a,arr[i].wordlist[count]) == 0)
{
sum += arr[i].count[count];
arr[i].count[count] = 0;
}
count++;
}
i++;
}
return sum;
}
/*Function executed by each thread on separate line*/
void *word_count(void* num)
{
int *ln = num;
unsigned int line_number = *ln;
line_number++;
char cmd_p1[9] = \"sed -n \'\\0\";
char cmd_p2[2];
sprintf(cmd_p2,\"%d\",line_number);
char cmd_p3[14] = \"p\' \'file.txt\'\\0\";
char command[100];
command[0] = \'\\0\';
strcat(command,cmd_p1);
strcat(command,cmd_p2);
strcat(command,cmd_p3);
//usleep(line_number);
char cmd[100] = \" | tr [:space:] \'\\\ \' | grep -v \'^\\\\s*$\' | sort | uniq -c | sort\\0\";
strcat(command,cmd);
FILE *in;
in= popen(command, \"r\");
rewind(in);
char buff[50];
int counter = 0;
while(fgets(buff,sizeof(buff),in))
{
char c=\' \';
int i = 0;
int cnt = atoi(buff);
arr[line_number-1].count[counter] = cnt;
while(c!=\'\\0\')
{
c=buff[i];
buff[i]=buff[i+6];
i++;
}
int cnnt = 0;
while(c!=\' \')
{
c = buff[cnnt];
cnnt++;
}
i=0;
while(c!=\'\\0\')
{
c=buff[i];
buff[i]=buff[i+cnnt];
i++;
}
sprintf(arr[line_number-1].wordlist[counter],\"%s\",buff);
counter++;
}
arr[line_number-1].count[counter] = -1;
fclose(in);
return NULL;
}
int main(void)
{
FILE *fp;
fp = fopen(\"file.txt\",\"r\");
char a[200];
lines = 0;
void *status = NULL;
while(fgets(a,sizeof(a),fp) !=NULL)
{
lines++;
}
fclose(fp);
arr = (struct return_val*) calloc(lines, sizeof(struct return_val) * lines);
threads = malloc(sizeof(pthread_t)*lines);
int i;
for(i=0;i= 0)
{
if(arr[i].count[ctr] > 0)
{
strcpy(final[final_ctr],arr[i].wordlist[ctr]);
final_cnt[final_ctr] = arr[i].count[ctr];
arr[i].count[ctr] = 0;
int sum = aggregate(arr[i].wordlist[ctr]);
final_cnt[final_ctr] += sum;
printf(\"%d %s\",final_cnt[final_ctr],final[final_ctr]);
}
ctr++; final_ctr++;
}
i++;
if(i==lines)
{
break;
}
}
free(arr);
return 0;
}
#include
#include
#include
#include
/*Structure for storing words received from each thread*/
struct return_val{
char wordlist[100][100];
int count[100];
} *arr;
pthread_t *threads;
int lines;
/*Aggregates Frequency Sum of different threads*/
int aggregate(char *a)
{
int sum = 0;
int i=0;
while(1)
{
if(i==lines) break;
int count = 0;
while(1)
{
if(arr[i].count[count] == -1)
{
break;
}
if(strcmp(a,arr[i].wordlist[count]) == 0)
{
sum += arr[i].count[count];
arr[i].count[count] = 0;
}
count++;
}
i++;
}
return sum;
}
/*Function executed by each thread on separate line*/
void *word_count(void* num)
{
int *ln = num;
unsigned int line_number = *ln;
line_number++;
char cmd_p1[9] = \"sed -n \'\\0\";
char cmd_p2[2];
sprintf(cmd_p2,\"%d\",line_number);
char cmd_p3[14] .
#C programming Question 35Implement the functions required for the.docx
This document implements functions for an integer stack data structure in C. It defines a struct for stack nodes containing an info field for the data and a pointer to the next node. Functions are defined for creating a stack, pushing/popping elements, checking if the stack is empty, displaying elements, and destroying the stack. The main function provides a menu to test the stack operations and takes user input to call the appropriate functions.
The purpose of this C++ programming project is to allow the student .pdf
The purpose of this C++ programming project is to allow the student to perform parallel array
and multidimensional array processing. The logic for string and Cstring has already been
completed, so the assignment can be started before we actually cover string and Cstring in detail.
This program has the following three menu options:
Solution
/*
This program uses simple arrays, multidimensional arrays, cstrings, strings, and files.
It allows a payroll clerk to choose an option from a menu. The choices are:
A: List the Payroll Information by Employee Name
B: Search Payroll Information by Employee Name
X: Exit the Payroll Information Module
The following items for each employee are saved in the file p10.txt:
Employee ID (1000 - 9999)
Last Name (15 characters)
First Name (15 characters)
Rate (5.00 - 10.00)
Hours W1,W2,W3,W4 (0-60)
*/
#include // file processing
#include // cin and cout
#include // toupper
#include // setw
#include // cstring functions strlen, strcmp, strcpy stored in string.h
#include // string class
#define stricmp strcasecmp
#define strnicmp strncasecmp
using namespace std;
//Disable warning messages C4267 C4996.
//To see the warnings, comment out the following line.
//#pragma warning( disable : 4267 4996)
//Warning C4267: coversion from size_t to int, possible lost of data
//size_t is a data type defined in and is an unsigned integer.
//The function strlen returns a value of the type size_t, but in
//searchByName we assign the returned value to an int.
//We could also declare the variable as size_t instead of int.
// size_t stringLength;
//Warning C4996: strnicmp strcpy, stricmp was declared deprecated, means
//the compiler encountered a function that was marked with deprecated.
//The deprecated function may no longer be supported in a future release.
//Global Constants
//When using to declare arrays, must be defined with const modifier
const int ARRAY_SIZE = 20, HOURS_SIZE = 4, NAME_SIZE = 16;
//Declare arrays as global so we don\'t have to pass the arrays to each function.
//Normally we wouldn\'t declare variables that change values a global.
int employeeId[ARRAY_SIZE];
string firstName[ARRAY_SIZE];
char lastName[ARRAY_SIZE][NAME_SIZE];
double rate[ARRAY_SIZE];
int hours[ARRAY_SIZE][HOURS_SIZE];
int numberOfEmps; //count of how many employees were loaded into arrays
int sumHours[ARRAY_SIZE] = {0}; //initialize arrays to zero by providing a
double avgHours[ARRAY_SIZE] = {0}; //value for the first element in the array
//Function Prototypes
void loadArray( );
void sumAndComputeAvgHours( );
void listByName( );
void searchByName( );
void sortByName( );
void swapValues(int i, int minIndex);
void listEmployees( );
void listEmployeesHeadings( );
void listEmployeesDetails(int i);
void listEmployeesTotals( );
void displayContinuePrompt( );
//Program starts here
int main()
{
//Declare and initialize local main variables
char choice; //menu option
//Load the arrays with data
loadArray();
//Sum and compute the average hours
sumAndComputeAv.
Program of sorting using shell sort #include stdio.h #de.pdf
/* Program of sorting using shell sort */
#include
#define MAX 20
main()
{
int arr[MAX], i,j,k,n,incr;
printf(\"Enter the number of elements : \");
scanf(\"%d\",&n);
for(i=0;i=1)
{
for(j=incr;j= 0 && k < arr[i]; i = i-incr)
arr[i+incr]=arr[i];
arr[i+incr]=k;
}
printf(\"Increment=%d \ \",incr);
for (i = 0; i < n; i++)
printf(\"%d \", arr[i]);
printf(\"\ \");
incr=incr-2; /*Decrease the increment*/
}/*End of while*/
printf(\"Sorted list is :\ \");
for (i = 0; i < n; i++)
printf(\"%d \", arr[i]);
printf(\"\ \");
}/*End of main()*/
redix sort
/*Program of sorting using radix sort*/
# include
# include
struct node
{
int info ;
struct node *link;
}*start=NULL;
main()
{
struct node *tmp,*q;
int i,n,item;
printf(\"Enter the number of elements in the list : \");
scanf(\"%d\", &n);
for(i=0;iinfo=item;
tmp->link=NULL;
if(start==NULL) /* Inserting first element */
start=tmp;
else
{
q=start;
while(q->link!=NULL)
q=q->link;
q->link=tmp;
}
}/*End of for*/
printf(\"Unsorted list is :\ \");
display();
radix_sort();
printf(\"Sorted list is :\ \");
display ();
}/*End of main()*/
display()
{
struct node *p=start;
while( p !=NULL)
{
printf(\"%d \", p->info);
p= p->link;
}
printf(\"\ \");
}/*End of display()*/
radix_sort()
{
int i,k,dig,maxdig,mindig,least_sig,most_sig;
struct node *p, *rear[10], *front[10];
least_sig=1;
most_sig=large_dig(start);
for(k = least_sig; k <= most_sig ; k++)
{
printf(\"PASS %d : Examining %dth digit from right \",k,k);
for(i = 0 ; i <= 9 ; i++)
{
rear[i] = NULL;
front[i] = NULL ;
}
maxdig=0;
mindig=9;
p = start ;
while( p != NULL)
{
/*Find kth digit in the number*/
dig = digit(p->info, k);
if(dig>maxdig)
maxdig=dig;
if(diglink = p ;
rear[dig] = p ;
p=p->link;/*Go to next number in the list*/
}/*End while */
/* maxdig and mindig are the maximum amd minimum
digits of the kth digits of all the numbers*/
printf(\"mindig=%d maxdig=%d\ \",mindig,maxdig);
/*Join all the queues to form the new linked list*/
start=front[mindig];
for(i=mindig;ilink=front[i+1];
else
rear[i+1]=rear[i];
}
rear[maxdig]->link=NULL;
printf(\"New list : \");
display();
}/* End for */
}/*End of radix_sort*/
/* This function finds number of digits in the largest element of the list */
int large_dig()
{
struct node *p=start ;
int large = 0,ndig = 0 ;
while(p != NULL)
{
if(p ->info > large)
large = p->info;
p = p->link ;
}
printf(\"Largest Element is %d , \",large);
while(large != 0)
{
ndig++;
large = large/10 ;
}
printf(\"Number of digits in it are %d\ \",ndig);
return(ndig);
} /*End of large_dig()*/
/*This function returns kth digit of a number*/
int digit(int number, int k)
{
int digit, i ;
for(i = 1 ; i <=k ; i++)
{
digit = number % 10 ;
number = number /10 ;
}
return(digit);
}/*End of digit()*/
Solution
/* Program of sorting using shell sort */
#include
#define MAX 20
main()
{
int arr[MAX], i,j,k,n,incr;
printf(\"Enter the number of elements : \");
scanf(\"%d\",&n);
for(i=0;i=1)
{
for(j=incr;j= 0 && k < arr[i]; i = i-incr)
arr[i+incr]=arr[i];
arr[i+incr]=k;
}
printf(\.
I have the following code and I need to know why I am receiving the .pdf
Edwards Manufacturing Company purchases two component parts from three different suppliers.
The suppliers have limited capacity, and no one supplier can meet all the company’s needs. In
addition, the suppliers charge different prices for the components. Component price data (in
price per unit) are as follows:
Each supplier has a limited capacity in terms of the total number of components it can supply.
However, as long as Edwards provides sufficient advance orders, each supplier can devote its
capacity to component 1, component 2, or any combination of the two components, if the total
number of units ordered is within its capacity. Supplier capacities are as follows:
If the Edwards production plan for the next period includes 1000 units of component 1 and 800
units of component 2, what purchases do you recommend? That is, how many units of each
component should be ordered from each supplier? Round your answers to the nearest whole
number.
What is the total purchase cost for the components? Round your answer to the nearest dollar.
$ ????SupplierComponent1231$11$10$132$10$11$11
Solution
For component 1:
supplier 2 have minimum cost and capacity 1050.
So all the component 1 (1000) can be purchased from supplier 2.
So, supplier 2 have 50 more capacity.
Now, supplier 1 have minimum cost for component 2 and have capacity of 650.
so, number of component 2 from supplier1 can be 650.
Now, we need 150 more component 2.
supplier 2 and 3 have same cost for component 2.
supllier have only 50 capacity now and supplier have 850.
So, 150 component 2 can be purchased from supplier 3.
Let y be the number of components fromSupplier123TotalcostComponent
1010000100010000Component 265001508008150Total cost18150.
An imperative study of c
The Presentation given at KK Wagh Polytechnic, Nashik for Second Year Information Technology Students on
15/01/2011.
Imugi: Compiler made with Python
[PyConKR 2018] Imugi: Compiler made with Python.
https://www.pycon.kr/2018/program/2/
GitHub: https://github.com/hahnlee/imugi
Getting the following errorsError 1 error C2436 {ctor} mem.pdf
Getting the following errors:
Error 1 error C2436: \'{ctor}\' : member function or nested class in constructor initializer list on
line 565
Error 2 error C2436: \'{ctor}\' : member function or nested class in constructor initializer list on
line 761
I need this code to COMPILE and RUN, but I cannot get rid of this error. Please Help!!
#include
#include
#include
#include
using namespace std;
enum contactGroupType
{// used in extPersonType
FAMILY,
FRIEND,
BUSINESS,
UNFILLED
};
class addressType
{
private:
string st_address;
string city;
string state;
int zip;
public:
void print(string, string, string, int)const;
void setStreet(string);
string getStreet()const;
void setCity(string);
string getCity()const;
void setState(string);
string getState()const;
void setZip(int);
int getZip()const;
void set(string, string, string, int);// set all address fields
string get()const;// get address as one concatenated string
addressType();
// ~addressType();
};
class personType
{
private:
string firstName;
string lastName;
public:
void print()const;
void setName(string first, string last);
string getFirstName()const;
string getLastName()const;
string get()const;// return First Last names concatenated
personType & operator=(const personType &);
personType(string, string);
personType();
};
class dateType
{
private:
int dMonth;
int dDay;
int dYear;
public:
void setDate(int month, int day, int year);
int getDay()const;
int getMonth()const;
int getYear()const;
void print()const;
string get()const;// return string representation as DD/MM/YYYY
dateType & operator=(const dateType & d);
dateType(int, int, int);
dateType();
};
class extPersonType :public personType {
private:
addressType address;// added members
dateType birthday;
contactGroupType group;
string phone;
public:
// methods
void setPhone(string);
string getPhone()const;
void setGroup(contactGroupType);
contactGroupType getGroup()const;
void setBirthday(int, int, int);
dateType getBirthday()const;
void print();
string get()const;// return string representation of ext person type
extPersonType & operator=(const extPersonType & p);
string groupToString(contactGroupType)const;
contactGroupType stringToGroup(string)const;
// constructors
extPersonType();
extPersonType(string first, string last);
};
// because we have no arrayListType, we are using our own
// implementation with a small subset of functions
class arrayListType
{
extPersonType array[500];
int size;
public:
arrayListType();
extPersonType & operator[](int i);
void removeLast();// remove last element
void add(const extPersonType &);// add new element
int getSize()const;// get array size
};
class addressBookType :public arrayListType
{
private:
static const char FS = \'\\t\';// field separator in file (TAB char)
int current;// current position
string fileName;// filename
fstream fileStream;// file as fstream
/* filiters */
contactGroupType fltGroup;
string fltFromLast, fltToLast;
dateType fltFromDate, fltTiDate;
/* flags for effective filters */
bool fl.
Were writing code for a project that dynamically allocates an arra.pdf
We\'re writing code for a project that dynamically allocates an array stack. My other code works,
but my Min(), Max(), and Peek() functions fail. I\'ve provided my code for those functions at the
end of the post.
main.cpp
_________________________________________
#include
#include
#include
#include
#include \"stack.h\"
using namespace std;
int main(int argc, char* argv[])
{
ifstream inputs; // Input file for commands
char op; // Hold operation and optional char input
int value; // Value input from file
string comment; // Holds comment from file
Stack* sPtr = NULL; // Will point to TemplateQ object
// Output usage message if one input file name is not provided
if (argc != 2)
{
cout << \"Usage:\ project03 \ \";
return 1;
}
// Attempt to open input file -- terminate if file does not open
inputs.open(argv[1]);
if (!inputs)
{
cout << \"Error - unable to open input file\" << endl;
return 1;
}
// Input and echo header comment from file
getline(inputs, comment); // Input and echo the comment appearing in the test file
cout << endl << \'#\' << comment << endl;
// Process commands from input file
inputs >> op; // Attempt to input first command
while (inputs)
{
switch (op) // Process operation input from file
{
case \'#\': // Test file comment
getline(inputs, comment); // Input and echo the comment appearing in the test
file
cout << \'#\' << comment << endl;
break;
case \'c\': // Parameterized Constructor
inputs >> value;
cout << endl << \"Stack(\" << value << \")\";
try
{
sPtr = new Stack(value); // Attempt to create a stack object with array size
value
cout << \" -- completed\" << endl;
}
catch ( std::bad_alloc )
{
cout << \"Failed : Terminating now...\" << endl;
return 1;
}
break;
case \'+\': // Push
inputs >> value;
cout << \"Push(\" << value << \") -- \";
try
{
sPtr->Push(value);
cout << \"completed\";
}
catch (StackFull)
{
cout << \"Failed Full Stack\";
}
catch (...)
{
cout << \"operation failed\" << endl;
}
cout << endl;
break;
case \'-\': // Pop
cout << \"Pop() -- \";
try
{
sPtr->Pop();
cout << \"completed\";
}
catch (StackEmpty)
{
cout << \"Failed Empty Stack\";
}
catch (...)
{
cout << \"operation failed\" << endl;
}
cout << endl;
break;
case \'f\': // IsFull
cout << \"IsFull() -- \";
try
{
if (sPtr->IsFull())
cout << \"true\";
else
cout << \"false\";
}
catch ( ... )
{
cout << \"operation failed\";
}
cout << endl;
break;
case \'e\': // IsEmpty
cout << \"IsEmpty() -- \";
try
{
if (sPtr->IsEmpty())
cout << \"true\";
else
cout << \"false\";
}
catch ( ... )
{
cout << \"operation failed\";
}
cout << endl;
break;
case \'m\': // Make Empty
cout << \"MakeEmpty() -- \";
try
{
sPtr->MakeEmpty();
cout << \"completed\" << endl;
}
catch (...)
{
cout << \"operation failed\" << endl;
}
break;
case \'p\': // Print Stack
cout << \"Print() -- \";
sPtr->Print();
break;
case \'t\': // Top of Stack
try
{
cout << \"Top() -- \" << sPtr->Top() << endl;
}
catch (StackEmpty)
{
cout << \"Top() -- Failed Empty Stack\" << endl;
}
catch (...)
{
cout << \"operation failed\" .
Implementing Software Machines in C and Go
The next iteration of the talk I gave at Progscon, this introduces examples of Map implementation (useful for caches etc.) and outlines for addition of processor core code in a later talk.
week-16x
The document discusses the implementation of queue operations using pointers and arrays in C. It defines the queue data structure using a struct containing a data element and pointer to the next node. Functions are defined to add, remove and check for empty/full as well as display the queue elements. A similar implementation is shown using arrays instead of pointers by defining a queue struct containing the front, rear indexes and size.
Data Structure in C (Lab Programs)
Programs are complete in best of my knowledge with zero compilation error in IDE Bloodshed Dev-C++. These can be easily portable to any versions of Visual Studio or Qt. If you need any guidance please let me know via comments and Always Enjoy Programming.
Please answer the 4 questions using C- The expected output is shown be.docx
Please answer the 4 questions using C. The expected output is shown below. Thank you!
---------------------------------------------------------------------------------------------------
// Write your name here
// Write the compiler used: Visual studio or gcc
// Reminder that your file name is incredibly important. Please do not change it.
// Reminder that we are compiling on Gradescope using GCC.
// READ BEFORE YOU START:
// You are given a partially completed program that creates a list of game items
like you'd see in a folder.
// Each item has this information: item's name, game's name, type of item, item ID.
// The struct 'itemRecord' holds information of one item. Variety is an enum.
// An array of structs called 'list' is made to hold the list of items.
// To begin, you should trace through the given code and understand how it works.
// Please read the instructions above each required function and follow the
directions carefully.
// You should not modify any of the given code, the return types, or the
parameters. Otherwise, you risk getting compilation errors.
// You are not allowed to modify main().
// You can use string library functions.
// WRITE COMMENTS FOR IMPORANT STEPS IN YOUR CODE.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#pragma warning(disable: 4996) // for Visual Studio
Only
#define MAX_ITEMS 15
#define MAX_NAME_LENGTH 25
typedef enum { Health = 0, Equip, Etc } itemType; // enum type
struct itemRecord { // struct for item details
char itemName[MAX_NAME_LENGTH];
char gameName[MAX_NAME_LENGTH];
itemType variety;
unsigned int itemID;
};
struct itemRecord list[MAX_ITEMS]; // declare list of items
int count = 0; // the number of items
currently stored in the list (initialized to 0)
// functions already implmented
void flushStdIn();
void executeAction(char);
void save(char* fileName);
void display();
// functions that need implementation:
int add(char* itemName_input,
char* gameName_input,
char* variety_input,
unsigned int idNumber_input); // 10 points
void sort(); // 10 points
int delete(unsigned int idNumber_input); // 10 points
void load(char* fileName); // 10 points
int main()
{
char* fileName = "Item_List.txt";
load(fileName); // load list of items from
file (if it exists). Initially there will be no file.
char choice = 'i'; // initialized to a dummy
value
do
{
printf("\nEnter your selection:\n");
printf("\t a: add a new item\n");
printf("\t d: display item list\n");
printf("\t r: remove an item from list\n");
printf("\t s: sort item list by ID\n");
printf("\t q: quit\n");
choice = getchar();
flushStdIn();
executeAction(choice);
} while (choice != 'q');
save(fileName); // save list of items to file
(overwrites file, if it exists)
return 0;
}
// flush out leftover '\n' characters
void flushStdIn()
{
char c;
do c = getchar();
while (c != '\n' && c != EOF);
}
// ask for details from user for the given selection and perform that action
.
Write a program that obtains the execution time of selection sort, bu.pdf
Write a java program called Question39 that does the following: Gets input for temperature
Utilizing a branching statement: If temperature is 76-100, call method outputHot passing the
temperature input as an argument. If temperature is 0-39, call method outputCold passing the
temperature input as an argument. If temperature is 40 to 75, call method outputJustRight
passing the temperature input as an argument. If temperature is outside these ranges, output
“Temperature outside range” to the screen. Be precise, import modules, include comments,
prologue, etc. as needed.
Solution
Question39.java
import java.util.Scanner;
public class Question39 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter temperature: \");
int temp = scan.nextInt();
if(temp >=76 && temp <=100){
outputHot(temp);
}
else if(temp >=0 && temp <=39){
outputCold(temp);
}
else if(temp >=40 && temp <=75){
outputJustRight(temp);
}
else{
System.out.println(\"Temperature outside range\");
}
}
public static void outputHot(int temp){
System.out.println(\"Temperature \"+temp+\" Hot \");
}
public static void outputCold(int temp){
System.out.println(\"Temperature \"+temp+\" Cold \");
}
public static void outputJustRight(int temp){
System.out.println(\"Temperature \"+temp+\" Just Right \");
}
}
Output:
Enter temperature:
45
Temperature 45 Just Right.
C aptitude questions
The document contains summaries of code snippets and explanations of technical concepts. It discusses:
1) How a code snippet with post-increment operator i++ would output a garbage value.
2) Why a code snippet multiplying two ints and storing in a long int variable would not give the desired output.
3) Why a code snippet attempting to concatenate a character to a string would not work.
4) How to determine the maximum number of elements an array can hold based on its data type and memory model.
5) How to read data from specific memory locations using the peekb() function.
C - aptitude3
The document contains summaries of code snippets and explanations of technical concepts. It discusses:
1) How a code snippet with post-increment operator i++ would output a garbage value.
2) Why a code snippet multiplying two ints and storing in a long int variable would not give the desired output.
3) Why a code snippet attempting to concatenate a character to a string would not work.
4) How to determine the maximum number of elements an array can hold based on its data type and memory model.
5) How to read data from specific memory locations using the peekb() function in C.
In c code, fill in the blank#include time.h#include std.pdf
In c code, fill in the blank
#include
#include
#include
int extraMemoryAllocated;
// implement merge sort
// extraMemoryAllocated counts bytes of extra memory allocated
void mergeSort(int pData[], int l, int r)
{
}
// implement insertion sort
// extraMemoryAllocated counts bytes of memory allocated
void insertionSort(int* pData, int n)
{
}
// implement bubble sort
// extraMemoryAllocated counts bytes of extra memory allocated
void bubbleSort(int* pData, int n)
{
}
// implement selection sort
// extraMemoryAllocated counts bytes of extra memory allocated
void selectionSort(int* pData, int n)
{
}
// parses input file to an integer array
int parseData(char *inputFileName, int **ppData)
{
FILE* inFile = fopen(inputFileName,"r");
int dataSz = 0;
*ppData = NULL;
if (inFile)
{
fscanf(inFile,"%d\n",&dataSz);
*ppData = (int *)malloc(sizeof(int) * dataSz);
// Implement parse data block
}
return dataSz;
}
// prints first and last 100 items in the data array
void printArray(int pData[], int dataSz)
{
int i, sz = dataSz - 100;
printf("\tData:\n\t");
for (i=0;i<100;++i)
{
printf("%d ",pData[i]);
}
printf("\n\t");
for (i=sz;i
#include
#include
int extraMemoryAllocated;
// implement merge sort
// extraMemoryAllocated counts bytes of extra memory allocated
void mergeSort(int pData[], int l, int r)
{
}
// implement insertion sort
// extraMemoryAllocated counts bytes of memory allocated
void insertionSort(int* pData, int n)
{
}
// implement bubble sort
// extraMemoryAllocated counts bytes of extra memory allocated
void bubbleSort(int* pData, int n)
{
}
// implement selection sort
// extraMemoryAllocated counts bytes of extra memory allocated
void selectionSort(int* pData, int n)
{
}
// parses input file to an integer array
int parseData(char *inputFileName, int **ppData)
{
FILE* inFile = fopen(inputFileName,"r");
int dataSz = 0;
*ppData = NULL;
if (inFile)
{
fscanf(inFile,"%d\n",&dataSz);
*ppData = (int *)malloc(sizeof(int) * dataSz);
// Implement parse data block
}
return dataSz;
}
// prints first and last 100 items in the data array
void printArray(int pData[], int dataSz)
{
int i, sz = dataSz - 100;
printf("\tData:\n\t");
for (i=0;i<100;++i)
{
printf("%d ",pData[i]);
}
printf("\n\t");
for (i=sz;i.
Programming in C
The document discusses various concepts related to arrays, structures, strings, file handling, and command line arguments in C/C++. It defines arrays as a consecutive group of memory locations to store elements of the same data type. Structures are used to group related data of different types. Strings are stored as character arrays ending with a null character. File handling functions like fopen, fclose, fprintf and fscanf are used to open, close and read/write files. Command line arguments can be accessed using argc and argv array in main function.
C
The document discusses various concepts related to arrays, structures, strings, file handling, and command line arguments in C/C++. It defines arrays as a consecutive group of memory locations to store elements of the same data type. Structures are used to group related data of different types. Strings are stored as character arrays ending with a null character. File handling functions like fopen, fclose, fprintf and fscanf are used to open, close and read/write files. Command line arguments can be accessed through the argc and argv parameters in main().
Programming with GUTs
Presented at DevWeek (25th March 2015)
These days, testing is considered a sexy topic for programmers. Who’d have thought it? But what makes for good unit tests (GUTs)? There’s more to effective unit testing than just knowing the assertion syntax of a testing framework.
Testing represents a form of communication and, as such, it offers multiple levels and forms of feedback, not just basic defect detection. Effective unit testing requires an understanding of what forms of feedback and communication are offered by tests, and what styles encourage or discourage such qualities.
What style of test partitioning is most common, and yet scales poorly and is ineffective at properly expressing the behaviour of a class or component? What styles, tricks and tips can be used to make tests more specification-like and can scale as the codebase grows?
This session will address these questions and outline exactly what makes a good unit test.
Using standard libraries like stdio and sdtlib.h and using stats.h a.pdf
Unlike the Federal income tax, most states do not require some form of state income tax.
True
False
Solution
Correct answer is True
Unlike Federal income tax, most states do not require some form of state income tax - This
statement is true as fililng of Fedral income tax return is mandatory for almost everybody but
some US states like Alaska, Florida, Navada, South Dakota, Texas, Washington and Wayoming
do not require filing of state income tax..
c programming
03 of 03 parts
Get Part 1 from https://www.slideshare.net/ArunUmrao/notes-for-c-programming-for-bca-mca-b-sc-msc-be-amp-btech-1st-year-1
Get Part 2 from https://www.slideshare.net/ArunUmrao/notes-for-c-programming-for-bca-mca-b-sc-msc-be-amp-btech-1st-year-2
C is a general-purpose, procedural computer programming language supporting structured programming, lexical variable scope, and recursion, while a static type system prevents unintended operations. C provides constructs that map efficiently to typical machine instructions and has found lasting use in applications previously coded in assembly language. Such applications include operating systems and various application software for computers, from supercomputers to PLCs and embedded system.
#include iostream #include cstring #include vector #i.pdf
#include
#include
#include
#include
#include \"textFile.hpp\"
using namespace std;
void displayHelp();
bool isInteger(const string &s);
bool askSave();
int main(int argc, const char * argv[]) {
int resultCode = 0;
// Convert to a vector.
vector args(argv, argv + argc);
// Process arguments, must be 1 argument, otherwise exit with code 1.
if (args.size() < 2) {
cout << \"Missing command line argument!\" << endl;
cout << \"Usage: ./myEditor \" << endl;
resultCode = 1;
} else {
string fileName = args[1];
textFile dataFile(fileName);
// Check if the file is ok to use, if it is, lets go.
if (!dataFile.checkFile()) {
resultCode = 2;
} else {
// We can now assume the file is good, so we can work with it.
dataFile.loadFile();
// Display some text to help the user.
displayHelp();
// Now get user input.
bool done = false;
string userInput = \"\";
while (!done) {
cout << \"> \";
getline(cin, userInput);
char cmd = tolower(userInput.c_str()[0]);
char cmd2 = \' \';
if (userInput.size() > 1) {
cmd2 = userInput.c_str()[1];
}
// This check makes sure the command format is correct
// so that commands don\'t fire off by mistake.
if (strncmp(&cmd, \" \", 1) != 0 && strncmp(&cmd2, \" \", 1) == 0) {
switch(cmd) {
case \'q\': {
done = true;
break;
}
case \'i\': {
unsigned long lineIndex = dataFile.textLines() + 1;
string newLine;
if (userInput.size() > 1) {
string cmdArg = userInput.substr(2);
lineIndex = stol(cmdArg);
}
cout << to_string(lineIndex) << \"> \";
getline(cin, newLine);
dataFile.insertLine(lineIndex - 1, newLine);
break;
}
case \'d\': {
if (userInput.size() > 1) {
unsigned long lineIndex;
string cmdArg = userInput.substr(2);
lineIndex = stol(cmdArg);
dataFile.removeLine(lineIndex - 1);
}
break;
}
case \'l\': {
for (int x = 0; x < dataFile.textLines(); x++) {
cout << to_string(x + 1) << \"> \" << dataFile.getLine(x) << endl;
}
break;
}
case \'h\': {
displayHelp();
break;
}
case \'s\': {
dataFile.saveFile();
break;
}
}
}
}
// Ask about saving the file before exiting.
bool save = askSave();
if (save) {
dataFile.saveFile();
}
cout << \"Thank you for using myEditor.\" << endl;
}
}
return resultCode;
}
/*
Asks the user if they\'d like to save or not, returns true if they do. Anything
other than \"y\" or \"Y\" will be interpreted as a negative answer.
*/
bool askSave()
{
bool result = false;
string userInput = \"\";
cout << \"Do you wan to save the change? (Y - yes; N - no) \";
getline(cin, userInput);
userInput = tolower(*userInput.c_str());
if (strncmp(userInput.c_str(), \"y\", 1) == 0) {
result = true;
}
return result;
}
/*
Displays help text.
*/
void displayHelp()
{
cout << \"Welcome to my text editor.\" << endl;
cout << \"\\tTo insert text at the end of the file, type \'I\'\" << endl;
cout << \"followed by the text.\" << endl;
cout << \"\\tTo insert text at a certain line number, type \'I\'\" << endl;
cout << \"followed by a space and the desired line number.\" << endl;
cout << \"\\tTo delete a line, type \'D\' followed by a space and the\" << endl;
cou.
#include String.hpp#include ..Functionsfunctions.hpp.docx
#include "String.hpp"
#include "../Functions/functions.hpp"
// O(1)
String::String() {
// Allocate space.
array = new char[1];
// Add the null.
array[0] = '\0';
// Adjust private variables.
_capacity = 0;
_size = 0;
}
// O(1)
String::String(char c) {
// Allocate space.
array = new char[2];
// Add the character and the null.
array[0] = c;
array[1] = '\0';
// Adjust private variables.
_capacity = 1;
_size = 1;
}
// O(n)
String::String(char* str) {
// Get the length of the incoming string.
int length = 0;
while (str[length])
++length;
// Allocate space for the string plus a null.
array = new char[length + 1];
// Fill our array up, including the null.
for (int i = 0; i <= length; ++i)
array[i] = str[i];
// Adjust private variables.
_capacity = length;
_size = length;
}
// O(1)
String::~String() {
delete[] array;
}
// O(n)
char String::at(int index) const {
// If our index is negative, or beyond the size of our array, we cannot return
// anything.
return (index < 0 || (unsigned int)index >= size()) ? throw "Index"
: array[index];
}
void String::clear() {
for (unsigned int i = 0; i < _capacity; ++i)
array[i] = '\0';
_size = 0;
}
// O(n)
unsigned int String::size() const {
return _size;
}
// O(1)
bool String::empty() const {
return !this->array[0];
}
// O(1)
unsigned int String::capacity() const {
return this->_capacity;
}
// O(n)
void String::reserve(unsigned int n) {
if (!n)
return;
// Make a new array.
char* _array = new char[_capacity + n + 1]();
// Fill it up.
int length = this->size();
for (int i = 0; i <= length; ++i)
_array[i] = array[i];
// Remove old memory.
delete[] array;
// Save new memory.
array = _array;
// Adjust private variables.
_capacity += n;
return;
}
// O(n)
void String::insert(char c, int index) {
// Prepend and append as easy cases.
if (index <= 0)
prepend(c);
else if ((unsigned int)index >= size())
append(c);
else {
// Increase capacity, if needed.
if (this->size() == this->_capacity) {
this->reserve(this->size() * 2);
}
// Move all elements after index over.
for (int i = this->size() + 1; i >= index; --i)
array[i] = array[i - 1];
// Insert our new character.
array[index] = c;
_size++;
}
return;
}
// O(n)
void String::erase(char c) {
// Create a new array.
char* _array = new char[_capacity + 1];
// Copy all non-erased characters to the new array.
int length = size();
for (int i = 0, j = 0; i <= length; ++i) {
if (array[i] != c)
_array[j++] = array[i];
else
_size--;
}
// Remove the old array.
delete[] array;
array = _array;
return;
}
// O(n)
void String::remove(int index) {
// Copy all characters to the left, overwriting index.
int length = this->size();
for (int i = index; i < length; ++i)
array[i] = array[i + 1];
_ ...
Determining Cash Payments to StockholdersThe board of directors de.pdf
Determine the magnitude of moment of force P = 50 N about line OC. 3, 600 N middot m 424
N middot m 1, 600 N midddot m 0
Solution
EASY WAY by vectorS;
HOW: find the coordinates of the points B,E these are ( 0,8,9 ) and (0,0,15) wrt the origin and
axes given in the figure (origina t O and axes x,y,z). We aim to find the vector eqn of the force.
Coordinates of E ( 0,0,15)
vector eqn of line BE = ( 0,0,15)-(0,8,9) = ( 0,-8, 6)
Hence force along BE is P( BE) = P(0,-8,6)
.
Vector eqn of line OC around which the moment is reqd
do the same way ( coords of C - coords of O) = (12,8,9)-(0,0,0) = (12,8,9)
The moment of Force along BE around line OC is FX OC ( vector cross product) and we want
the component along OC so net salar moment is F X OC. OC where (dot) is the dot or scalar
product
Finf BE X OC is ( 120i -72j -96k)
take scalar product with OC ( 120i-72j-96k). (12i +8j+9k) = 120*12-72*9-96*9 = 1440 -576-
864 =0
Answer is given, choose it.
Best!!.
Assume that Stanford CPAs encountered the following issues during va.pdf
Assume that Stanford CPAs encountered the following issues during various audit engagements
in 2014:
Stanford conducted the audit of Luck, a new client this past year. Last year, Luck was audited by
another CPA, who issued an unmodified opinion on its financial statements. Luck is presenting
financial statements for 2013 and 2014 in comparative form.
One of Stanford’s clients is RealCo, a real estate holding company. Assume that RealCo
experienced a significant decline in the value of its investment properties during the past year
because of the downturn in the economy and has appropriately recognized that decline in market
value under GAAP. Stanford wished to emphasize the decline in the economy and its impact on
RealCo’s financial position and results of operations for 2014 in its audit report.
For the past five years, Stanford has conducted the audits of TechTime, a company that provides
technology consulting services, and has always issued unmodified opinions on its financial
statements. Based on its 2014 audit, Stanford believes that an unmodified opinion is appropriate;
however, Stanford did note that TechTime reported its third consecutive operating loss and has
experienced negative cash flows because of the inability of some of its customers to promptly
pay for services received.
Stanford has assisted Cardinal Inc. with the preparation of its financial statements but has not
audited, compiled, or reviewed those financial statements. Cardinal wished to include these
financial statements in a communication that would describe Stanford’s involvement in the
preparation of the financial statements. Stanford believes that Cardinal’s communication is
adequate and appropriately describes Stanford’s limited role in the preparation of the financial
statements.
Trees Inc. presents summary financial information along with its financial statements. The
summary financial information has been derived from the complete set of financial statements
that Stanford has audited (and issued an unmodified opinion on the complete financial
statements). A lender has engaged Stanford to evaluate and report on Trees’ summary financial
information. Stanford believes that summary financial information is fairly stated in relation to
Trees’ complete financial statements.
Stanford believes that some of the verbiage in Plunkett’s Management Discussion & Analysis
section is inconsistent with the firm’s financial statements. Stanford has concluded that
Plunkett’s financial statements present its financial position, results of operations, and cash flows
in accordance with GAAP and has decided to issue an unmodified opinion on Plunkett’s
financial statements.
Oil Patch is a client in the energy industry that is required to present supplementary oil and gas
reserve information. Stanford has performed certain procedures regarding this information and
concluded that it is presented in accordance with the Financial Accounting Standards Board
(FASB) presentation guidelines an.
More Related Content
Similar to C programming. For this code I only need to add a function so th.pdf
I have the following code and I need to know why I am receiving the .pdf
Edwards Manufacturing Company purchases two component parts from three different suppliers.
The suppliers have limited capacity, and no one supplier can meet all the company’s needs. In
addition, the suppliers charge different prices for the components. Component price data (in
price per unit) are as follows:
Each supplier has a limited capacity in terms of the total number of components it can supply.
However, as long as Edwards provides sufficient advance orders, each supplier can devote its
capacity to component 1, component 2, or any combination of the two components, if the total
number of units ordered is within its capacity. Supplier capacities are as follows:
If the Edwards production plan for the next period includes 1000 units of component 1 and 800
units of component 2, what purchases do you recommend? That is, how many units of each
component should be ordered from each supplier? Round your answers to the nearest whole
number.
What is the total purchase cost for the components? Round your answer to the nearest dollar.
$ ????SupplierComponent1231$11$10$132$10$11$11
Solution
For component 1:
supplier 2 have minimum cost and capacity 1050.
So all the component 1 (1000) can be purchased from supplier 2.
So, supplier 2 have 50 more capacity.
Now, supplier 1 have minimum cost for component 2 and have capacity of 650.
so, number of component 2 from supplier1 can be 650.
Now, we need 150 more component 2.
supplier 2 and 3 have same cost for component 2.
supllier have only 50 capacity now and supplier have 850.
So, 150 component 2 can be purchased from supplier 3.
Let y be the number of components fromSupplier123TotalcostComponent
1010000100010000Component 265001508008150Total cost18150.
An imperative study of c
The Presentation given at KK Wagh Polytechnic, Nashik for Second Year Information Technology Students on
15/01/2011.
Imugi: Compiler made with Python
[PyConKR 2018] Imugi: Compiler made with Python.
https://www.pycon.kr/2018/program/2/
GitHub: https://github.com/hahnlee/imugi
Getting the following errorsError 1 error C2436 {ctor} mem.pdf
Getting the following errors:
Error 1 error C2436: \'{ctor}\' : member function or nested class in constructor initializer list on
line 565
Error 2 error C2436: \'{ctor}\' : member function or nested class in constructor initializer list on
line 761
I need this code to COMPILE and RUN, but I cannot get rid of this error. Please Help!!
#include
#include
#include
#include
using namespace std;
enum contactGroupType
{// used in extPersonType
FAMILY,
FRIEND,
BUSINESS,
UNFILLED
};
class addressType
{
private:
string st_address;
string city;
string state;
int zip;
public:
void print(string, string, string, int)const;
void setStreet(string);
string getStreet()const;
void setCity(string);
string getCity()const;
void setState(string);
string getState()const;
void setZip(int);
int getZip()const;
void set(string, string, string, int);// set all address fields
string get()const;// get address as one concatenated string
addressType();
// ~addressType();
};
class personType
{
private:
string firstName;
string lastName;
public:
void print()const;
void setName(string first, string last);
string getFirstName()const;
string getLastName()const;
string get()const;// return First Last names concatenated
personType & operator=(const personType &);
personType(string, string);
personType();
};
class dateType
{
private:
int dMonth;
int dDay;
int dYear;
public:
void setDate(int month, int day, int year);
int getDay()const;
int getMonth()const;
int getYear()const;
void print()const;
string get()const;// return string representation as DD/MM/YYYY
dateType & operator=(const dateType & d);
dateType(int, int, int);
dateType();
};
class extPersonType :public personType {
private:
addressType address;// added members
dateType birthday;
contactGroupType group;
string phone;
public:
// methods
void setPhone(string);
string getPhone()const;
void setGroup(contactGroupType);
contactGroupType getGroup()const;
void setBirthday(int, int, int);
dateType getBirthday()const;
void print();
string get()const;// return string representation of ext person type
extPersonType & operator=(const extPersonType & p);
string groupToString(contactGroupType)const;
contactGroupType stringToGroup(string)const;
// constructors
extPersonType();
extPersonType(string first, string last);
};
// because we have no arrayListType, we are using our own
// implementation with a small subset of functions
class arrayListType
{
extPersonType array[500];
int size;
public:
arrayListType();
extPersonType & operator[](int i);
void removeLast();// remove last element
void add(const extPersonType &);// add new element
int getSize()const;// get array size
};
class addressBookType :public arrayListType
{
private:
static const char FS = \'\\t\';// field separator in file (TAB char)
int current;// current position
string fileName;// filename
fstream fileStream;// file as fstream
/* filiters */
contactGroupType fltGroup;
string fltFromLast, fltToLast;
dateType fltFromDate, fltTiDate;
/* flags for effective filters */
bool fl.
Were writing code for a project that dynamically allocates an arra.pdf
We\'re writing code for a project that dynamically allocates an array stack. My other code works,
but my Min(), Max(), and Peek() functions fail. I\'ve provided my code for those functions at the
end of the post.
main.cpp
_________________________________________
#include
#include
#include
#include
#include \"stack.h\"
using namespace std;
int main(int argc, char* argv[])
{
ifstream inputs; // Input file for commands
char op; // Hold operation and optional char input
int value; // Value input from file
string comment; // Holds comment from file
Stack* sPtr = NULL; // Will point to TemplateQ object
// Output usage message if one input file name is not provided
if (argc != 2)
{
cout << \"Usage:\ project03 \ \";
return 1;
}
// Attempt to open input file -- terminate if file does not open
inputs.open(argv[1]);
if (!inputs)
{
cout << \"Error - unable to open input file\" << endl;
return 1;
}
// Input and echo header comment from file
getline(inputs, comment); // Input and echo the comment appearing in the test file
cout << endl << \'#\' << comment << endl;
// Process commands from input file
inputs >> op; // Attempt to input first command
while (inputs)
{
switch (op) // Process operation input from file
{
case \'#\': // Test file comment
getline(inputs, comment); // Input and echo the comment appearing in the test
file
cout << \'#\' << comment << endl;
break;
case \'c\': // Parameterized Constructor
inputs >> value;
cout << endl << \"Stack(\" << value << \")\";
try
{
sPtr = new Stack(value); // Attempt to create a stack object with array size
value
cout << \" -- completed\" << endl;
}
catch ( std::bad_alloc )
{
cout << \"Failed : Terminating now...\" << endl;
return 1;
}
break;
case \'+\': // Push
inputs >> value;
cout << \"Push(\" << value << \") -- \";
try
{
sPtr->Push(value);
cout << \"completed\";
}
catch (StackFull)
{
cout << \"Failed Full Stack\";
}
catch (...)
{
cout << \"operation failed\" << endl;
}
cout << endl;
break;
case \'-\': // Pop
cout << \"Pop() -- \";
try
{
sPtr->Pop();
cout << \"completed\";
}
catch (StackEmpty)
{
cout << \"Failed Empty Stack\";
}
catch (...)
{
cout << \"operation failed\" << endl;
}
cout << endl;
break;
case \'f\': // IsFull
cout << \"IsFull() -- \";
try
{
if (sPtr->IsFull())
cout << \"true\";
else
cout << \"false\";
}
catch ( ... )
{
cout << \"operation failed\";
}
cout << endl;
break;
case \'e\': // IsEmpty
cout << \"IsEmpty() -- \";
try
{
if (sPtr->IsEmpty())
cout << \"true\";
else
cout << \"false\";
}
catch ( ... )
{
cout << \"operation failed\";
}
cout << endl;
break;
case \'m\': // Make Empty
cout << \"MakeEmpty() -- \";
try
{
sPtr->MakeEmpty();
cout << \"completed\" << endl;
}
catch (...)
{
cout << \"operation failed\" << endl;
}
break;
case \'p\': // Print Stack
cout << \"Print() -- \";
sPtr->Print();
break;
case \'t\': // Top of Stack
try
{
cout << \"Top() -- \" << sPtr->Top() << endl;
}
catch (StackEmpty)
{
cout << \"Top() -- Failed Empty Stack\" << endl;
}
catch (...)
{
cout << \"operation failed\" .
Implementing Software Machines in C and Go
The next iteration of the talk I gave at Progscon, this introduces examples of Map implementation (useful for caches etc.) and outlines for addition of processor core code in a later talk.
week-16x
The document discusses the implementation of queue operations using pointers and arrays in C. It defines the queue data structure using a struct containing a data element and pointer to the next node. Functions are defined to add, remove and check for empty/full as well as display the queue elements. A similar implementation is shown using arrays instead of pointers by defining a queue struct containing the front, rear indexes and size.
Data Structure in C (Lab Programs)
Programs are complete in best of my knowledge with zero compilation error in IDE Bloodshed Dev-C++. These can be easily portable to any versions of Visual Studio or Qt. If you need any guidance please let me know via comments and Always Enjoy Programming.
Please answer the 4 questions using C- The expected output is shown be.docx
Please answer the 4 questions using C. The expected output is shown below. Thank you!
---------------------------------------------------------------------------------------------------
// Write your name here
// Write the compiler used: Visual studio or gcc
// Reminder that your file name is incredibly important. Please do not change it.
// Reminder that we are compiling on Gradescope using GCC.
// READ BEFORE YOU START:
// You are given a partially completed program that creates a list of game items
like you'd see in a folder.
// Each item has this information: item's name, game's name, type of item, item ID.
// The struct 'itemRecord' holds information of one item. Variety is an enum.
// An array of structs called 'list' is made to hold the list of items.
// To begin, you should trace through the given code and understand how it works.
// Please read the instructions above each required function and follow the
directions carefully.
// You should not modify any of the given code, the return types, or the
parameters. Otherwise, you risk getting compilation errors.
// You are not allowed to modify main().
// You can use string library functions.
// WRITE COMMENTS FOR IMPORANT STEPS IN YOUR CODE.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#pragma warning(disable: 4996) // for Visual Studio
Only
#define MAX_ITEMS 15
#define MAX_NAME_LENGTH 25
typedef enum { Health = 0, Equip, Etc } itemType; // enum type
struct itemRecord { // struct for item details
char itemName[MAX_NAME_LENGTH];
char gameName[MAX_NAME_LENGTH];
itemType variety;
unsigned int itemID;
};
struct itemRecord list[MAX_ITEMS]; // declare list of items
int count = 0; // the number of items
currently stored in the list (initialized to 0)
// functions already implmented
void flushStdIn();
void executeAction(char);
void save(char* fileName);
void display();
// functions that need implementation:
int add(char* itemName_input,
char* gameName_input,
char* variety_input,
unsigned int idNumber_input); // 10 points
void sort(); // 10 points
int delete(unsigned int idNumber_input); // 10 points
void load(char* fileName); // 10 points
int main()
{
char* fileName = "Item_List.txt";
load(fileName); // load list of items from
file (if it exists). Initially there will be no file.
char choice = 'i'; // initialized to a dummy
value
do
{
printf("\nEnter your selection:\n");
printf("\t a: add a new item\n");
printf("\t d: display item list\n");
printf("\t r: remove an item from list\n");
printf("\t s: sort item list by ID\n");
printf("\t q: quit\n");
choice = getchar();
flushStdIn();
executeAction(choice);
} while (choice != 'q');
save(fileName); // save list of items to file
(overwrites file, if it exists)
return 0;
}
// flush out leftover '\n' characters
void flushStdIn()
{
char c;
do c = getchar();
while (c != '\n' && c != EOF);
}
// ask for details from user for the given selection and perform that action
.
Write a program that obtains the execution time of selection sort, bu.pdf
Write a java program called Question39 that does the following: Gets input for temperature
Utilizing a branching statement: If temperature is 76-100, call method outputHot passing the
temperature input as an argument. If temperature is 0-39, call method outputCold passing the
temperature input as an argument. If temperature is 40 to 75, call method outputJustRight
passing the temperature input as an argument. If temperature is outside these ranges, output
“Temperature outside range” to the screen. Be precise, import modules, include comments,
prologue, etc. as needed.
Solution
Question39.java
import java.util.Scanner;
public class Question39 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter temperature: \");
int temp = scan.nextInt();
if(temp >=76 && temp <=100){
outputHot(temp);
}
else if(temp >=0 && temp <=39){
outputCold(temp);
}
else if(temp >=40 && temp <=75){
outputJustRight(temp);
}
else{
System.out.println(\"Temperature outside range\");
}
}
public static void outputHot(int temp){
System.out.println(\"Temperature \"+temp+\" Hot \");
}
public static void outputCold(int temp){
System.out.println(\"Temperature \"+temp+\" Cold \");
}
public static void outputJustRight(int temp){
System.out.println(\"Temperature \"+temp+\" Just Right \");
}
}
Output:
Enter temperature:
45
Temperature 45 Just Right.
C aptitude questions
The document contains summaries of code snippets and explanations of technical concepts. It discusses:
1) How a code snippet with post-increment operator i++ would output a garbage value.
2) Why a code snippet multiplying two ints and storing in a long int variable would not give the desired output.
3) Why a code snippet attempting to concatenate a character to a string would not work.
4) How to determine the maximum number of elements an array can hold based on its data type and memory model.
5) How to read data from specific memory locations using the peekb() function.
C - aptitude3
The document contains summaries of code snippets and explanations of technical concepts. It discusses:
1) How a code snippet with post-increment operator i++ would output a garbage value.
2) Why a code snippet multiplying two ints and storing in a long int variable would not give the desired output.
3) Why a code snippet attempting to concatenate a character to a string would not work.
4) How to determine the maximum number of elements an array can hold based on its data type and memory model.
5) How to read data from specific memory locations using the peekb() function in C.
In c code, fill in the blank#include time.h#include std.pdf
In c code, fill in the blank
#include
#include
#include
int extraMemoryAllocated;
// implement merge sort
// extraMemoryAllocated counts bytes of extra memory allocated
void mergeSort(int pData[], int l, int r)
{
}
// implement insertion sort
// extraMemoryAllocated counts bytes of memory allocated
void insertionSort(int* pData, int n)
{
}
// implement bubble sort
// extraMemoryAllocated counts bytes of extra memory allocated
void bubbleSort(int* pData, int n)
{
}
// implement selection sort
// extraMemoryAllocated counts bytes of extra memory allocated
void selectionSort(int* pData, int n)
{
}
// parses input file to an integer array
int parseData(char *inputFileName, int **ppData)
{
FILE* inFile = fopen(inputFileName,"r");
int dataSz = 0;
*ppData = NULL;
if (inFile)
{
fscanf(inFile,"%d\n",&dataSz);
*ppData = (int *)malloc(sizeof(int) * dataSz);
// Implement parse data block
}
return dataSz;
}
// prints first and last 100 items in the data array
void printArray(int pData[], int dataSz)
{
int i, sz = dataSz - 100;
printf("\tData:\n\t");
for (i=0;i<100;++i)
{
printf("%d ",pData[i]);
}
printf("\n\t");
for (i=sz;i
#include
#include
int extraMemoryAllocated;
// implement merge sort
// extraMemoryAllocated counts bytes of extra memory allocated
void mergeSort(int pData[], int l, int r)
{
}
// implement insertion sort
// extraMemoryAllocated counts bytes of memory allocated
void insertionSort(int* pData, int n)
{
}
// implement bubble sort
// extraMemoryAllocated counts bytes of extra memory allocated
void bubbleSort(int* pData, int n)
{
}
// implement selection sort
// extraMemoryAllocated counts bytes of extra memory allocated
void selectionSort(int* pData, int n)
{
}
// parses input file to an integer array
int parseData(char *inputFileName, int **ppData)
{
FILE* inFile = fopen(inputFileName,"r");
int dataSz = 0;
*ppData = NULL;
if (inFile)
{
fscanf(inFile,"%d\n",&dataSz);
*ppData = (int *)malloc(sizeof(int) * dataSz);
// Implement parse data block
}
return dataSz;
}
// prints first and last 100 items in the data array
void printArray(int pData[], int dataSz)
{
int i, sz = dataSz - 100;
printf("\tData:\n\t");
for (i=0;i<100;++i)
{
printf("%d ",pData[i]);
}
printf("\n\t");
for (i=sz;i.
Programming in C
The document discusses various concepts related to arrays, structures, strings, file handling, and command line arguments in C/C++. It defines arrays as a consecutive group of memory locations to store elements of the same data type. Structures are used to group related data of different types. Strings are stored as character arrays ending with a null character. File handling functions like fopen, fclose, fprintf and fscanf are used to open, close and read/write files. Command line arguments can be accessed using argc and argv array in main function.
C
The document discusses various concepts related to arrays, structures, strings, file handling, and command line arguments in C/C++. It defines arrays as a consecutive group of memory locations to store elements of the same data type. Structures are used to group related data of different types. Strings are stored as character arrays ending with a null character. File handling functions like fopen, fclose, fprintf and fscanf are used to open, close and read/write files. Command line arguments can be accessed through the argc and argv parameters in main().
Programming with GUTs
Presented at DevWeek (25th March 2015)
These days, testing is considered a sexy topic for programmers. Who’d have thought it? But what makes for good unit tests (GUTs)? There’s more to effective unit testing than just knowing the assertion syntax of a testing framework.
Testing represents a form of communication and, as such, it offers multiple levels and forms of feedback, not just basic defect detection. Effective unit testing requires an understanding of what forms of feedback and communication are offered by tests, and what styles encourage or discourage such qualities.
What style of test partitioning is most common, and yet scales poorly and is ineffective at properly expressing the behaviour of a class or component? What styles, tricks and tips can be used to make tests more specification-like and can scale as the codebase grows?
This session will address these questions and outline exactly what makes a good unit test.
Using standard libraries like stdio and sdtlib.h and using stats.h a.pdf
Unlike the Federal income tax, most states do not require some form of state income tax.
True
False
Solution
Correct answer is True
Unlike Federal income tax, most states do not require some form of state income tax - This
statement is true as fililng of Fedral income tax return is mandatory for almost everybody but
some US states like Alaska, Florida, Navada, South Dakota, Texas, Washington and Wayoming
do not require filing of state income tax..
c programming
03 of 03 parts
Get Part 1 from https://www.slideshare.net/ArunUmrao/notes-for-c-programming-for-bca-mca-b-sc-msc-be-amp-btech-1st-year-1
Get Part 2 from https://www.slideshare.net/ArunUmrao/notes-for-c-programming-for-bca-mca-b-sc-msc-be-amp-btech-1st-year-2
C is a general-purpose, procedural computer programming language supporting structured programming, lexical variable scope, and recursion, while a static type system prevents unintended operations. C provides constructs that map efficiently to typical machine instructions and has found lasting use in applications previously coded in assembly language. Such applications include operating systems and various application software for computers, from supercomputers to PLCs and embedded system.
#include iostream #include cstring #include vector #i.pdf
#include
#include
#include
#include
#include \"textFile.hpp\"
using namespace std;
void displayHelp();
bool isInteger(const string &s);
bool askSave();
int main(int argc, const char * argv[]) {
int resultCode = 0;
// Convert to a vector.
vector args(argv, argv + argc);
// Process arguments, must be 1 argument, otherwise exit with code 1.
if (args.size() < 2) {
cout << \"Missing command line argument!\" << endl;
cout << \"Usage: ./myEditor \" << endl;
resultCode = 1;
} else {
string fileName = args[1];
textFile dataFile(fileName);
// Check if the file is ok to use, if it is, lets go.
if (!dataFile.checkFile()) {
resultCode = 2;
} else {
// We can now assume the file is good, so we can work with it.
dataFile.loadFile();
// Display some text to help the user.
displayHelp();
// Now get user input.
bool done = false;
string userInput = \"\";
while (!done) {
cout << \"> \";
getline(cin, userInput);
char cmd = tolower(userInput.c_str()[0]);
char cmd2 = \' \';
if (userInput.size() > 1) {
cmd2 = userInput.c_str()[1];
}
// This check makes sure the command format is correct
// so that commands don\'t fire off by mistake.
if (strncmp(&cmd, \" \", 1) != 0 && strncmp(&cmd2, \" \", 1) == 0) {
switch(cmd) {
case \'q\': {
done = true;
break;
}
case \'i\': {
unsigned long lineIndex = dataFile.textLines() + 1;
string newLine;
if (userInput.size() > 1) {
string cmdArg = userInput.substr(2);
lineIndex = stol(cmdArg);
}
cout << to_string(lineIndex) << \"> \";
getline(cin, newLine);
dataFile.insertLine(lineIndex - 1, newLine);
break;
}
case \'d\': {
if (userInput.size() > 1) {
unsigned long lineIndex;
string cmdArg = userInput.substr(2);
lineIndex = stol(cmdArg);
dataFile.removeLine(lineIndex - 1);
}
break;
}
case \'l\': {
for (int x = 0; x < dataFile.textLines(); x++) {
cout << to_string(x + 1) << \"> \" << dataFile.getLine(x) << endl;
}
break;
}
case \'h\': {
displayHelp();
break;
}
case \'s\': {
dataFile.saveFile();
break;
}
}
}
}
// Ask about saving the file before exiting.
bool save = askSave();
if (save) {
dataFile.saveFile();
}
cout << \"Thank you for using myEditor.\" << endl;
}
}
return resultCode;
}
/*
Asks the user if they\'d like to save or not, returns true if they do. Anything
other than \"y\" or \"Y\" will be interpreted as a negative answer.
*/
bool askSave()
{
bool result = false;
string userInput = \"\";
cout << \"Do you wan to save the change? (Y - yes; N - no) \";
getline(cin, userInput);
userInput = tolower(*userInput.c_str());
if (strncmp(userInput.c_str(), \"y\", 1) == 0) {
result = true;
}
return result;
}
/*
Displays help text.
*/
void displayHelp()
{
cout << \"Welcome to my text editor.\" << endl;
cout << \"\\tTo insert text at the end of the file, type \'I\'\" << endl;
cout << \"followed by the text.\" << endl;
cout << \"\\tTo insert text at a certain line number, type \'I\'\" << endl;
cout << \"followed by a space and the desired line number.\" << endl;
cout << \"\\tTo delete a line, type \'D\' followed by a space and the\" << endl;
cou.
#include String.hpp#include ..Functionsfunctions.hpp.docx
#include "String.hpp"
#include "../Functions/functions.hpp"
// O(1)
String::String() {
// Allocate space.
array = new char[1];
// Add the null.
array[0] = '\0';
// Adjust private variables.
_capacity = 0;
_size = 0;
}
// O(1)
String::String(char c) {
// Allocate space.
array = new char[2];
// Add the character and the null.
array[0] = c;
array[1] = '\0';
// Adjust private variables.
_capacity = 1;
_size = 1;
}
// O(n)
String::String(char* str) {
// Get the length of the incoming string.
int length = 0;
while (str[length])
++length;
// Allocate space for the string plus a null.
array = new char[length + 1];
// Fill our array up, including the null.
for (int i = 0; i <= length; ++i)
array[i] = str[i];
// Adjust private variables.
_capacity = length;
_size = length;
}
// O(1)
String::~String() {
delete[] array;
}
// O(n)
char String::at(int index) const {
// If our index is negative, or beyond the size of our array, we cannot return
// anything.
return (index < 0 || (unsigned int)index >= size()) ? throw "Index"
: array[index];
}
void String::clear() {
for (unsigned int i = 0; i < _capacity; ++i)
array[i] = '\0';
_size = 0;
}
// O(n)
unsigned int String::size() const {
return _size;
}
// O(1)
bool String::empty() const {
return !this->array[0];
}
// O(1)
unsigned int String::capacity() const {
return this->_capacity;
}
// O(n)
void String::reserve(unsigned int n) {
if (!n)
return;
// Make a new array.
char* _array = new char[_capacity + n + 1]();
// Fill it up.
int length = this->size();
for (int i = 0; i <= length; ++i)
_array[i] = array[i];
// Remove old memory.
delete[] array;
// Save new memory.
array = _array;
// Adjust private variables.
_capacity += n;
return;
}
// O(n)
void String::insert(char c, int index) {
// Prepend and append as easy cases.
if (index <= 0)
prepend(c);
else if ((unsigned int)index >= size())
append(c);
else {
// Increase capacity, if needed.
if (this->size() == this->_capacity) {
this->reserve(this->size() * 2);
}
// Move all elements after index over.
for (int i = this->size() + 1; i >= index; --i)
array[i] = array[i - 1];
// Insert our new character.
array[index] = c;
_size++;
}
return;
}
// O(n)
void String::erase(char c) {
// Create a new array.
char* _array = new char[_capacity + 1];
// Copy all non-erased characters to the new array.
int length = size();
for (int i = 0, j = 0; i <= length; ++i) {
if (array[i] != c)
_array[j++] = array[i];
else
_size--;
}
// Remove the old array.
delete[] array;
array = _array;
return;
}
// O(n)
void String::remove(int index) {
// Copy all characters to the left, overwriting index.
int length = this->size();
for (int i = index; i < length; ++i)
array[i] = array[i + 1];
_ ...
Similar to C programming. For this code I only need to add a function so th.pdf (20)
I have the following code and I need to know why I am receiving the .pdf
I have the following code and I need to know why I am receiving the .pdf
Getting the following errorsError 1 error C2436 {ctor} mem.pdf
Getting the following errorsError 1 error C2436 {ctor} mem.pdf
Were writing code for a project that dynamically allocates an arra.pdf
Were writing code for a project that dynamically allocates an arra.pdf
Please answer the 4 questions using C- The expected output is shown be.docx
Please answer the 4 questions using C- The expected output is shown be.docx
Write a program that obtains the execution time of selection sort, bu.pdf
Write a program that obtains the execution time of selection sort, bu.pdf
In c code, fill in the blank#include time.h#include std.pdf
In c code, fill in the blank#include time.h#include std.pdf
Using standard libraries like stdio and sdtlib.h and using stats.h a.pdf
Using standard libraries like stdio and sdtlib.h and using stats.h a.pdf
#include iostream #include cstring #include vector #i.pdf
#include iostream #include cstring #include vector #i.pdf
#include String.hpp#include ..Functionsfunctions.hpp.docx
#include String.hpp#include ..Functionsfunctions.hpp.docx
More from badshetoms
Determining Cash Payments to StockholdersThe board of directors de.pdf
Determine the magnitude of moment of force P = 50 N about line OC. 3, 600 N middot m 424
N middot m 1, 600 N midddot m 0
Solution
EASY WAY by vectorS;
HOW: find the coordinates of the points B,E these are ( 0,8,9 ) and (0,0,15) wrt the origin and
axes given in the figure (origina t O and axes x,y,z). We aim to find the vector eqn of the force.
Coordinates of E ( 0,0,15)
vector eqn of line BE = ( 0,0,15)-(0,8,9) = ( 0,-8, 6)
Hence force along BE is P( BE) = P(0,-8,6)
.
Vector eqn of line OC around which the moment is reqd
do the same way ( coords of C - coords of O) = (12,8,9)-(0,0,0) = (12,8,9)
The moment of Force along BE around line OC is FX OC ( vector cross product) and we want
the component along OC so net salar moment is F X OC. OC where (dot) is the dot or scalar
product
Finf BE X OC is ( 120i -72j -96k)
take scalar product with OC ( 120i-72j-96k). (12i +8j+9k) = 120*12-72*9-96*9 = 1440 -576-
864 =0
Answer is given, choose it.
Best!!.
Assume that Stanford CPAs encountered the following issues during va.pdf
Assume that Stanford CPAs encountered the following issues during various audit engagements
in 2014:
Stanford conducted the audit of Luck, a new client this past year. Last year, Luck was audited by
another CPA, who issued an unmodified opinion on its financial statements. Luck is presenting
financial statements for 2013 and 2014 in comparative form.
One of Stanford’s clients is RealCo, a real estate holding company. Assume that RealCo
experienced a significant decline in the value of its investment properties during the past year
because of the downturn in the economy and has appropriately recognized that decline in market
value under GAAP. Stanford wished to emphasize the decline in the economy and its impact on
RealCo’s financial position and results of operations for 2014 in its audit report.
For the past five years, Stanford has conducted the audits of TechTime, a company that provides
technology consulting services, and has always issued unmodified opinions on its financial
statements. Based on its 2014 audit, Stanford believes that an unmodified opinion is appropriate;
however, Stanford did note that TechTime reported its third consecutive operating loss and has
experienced negative cash flows because of the inability of some of its customers to promptly
pay for services received.
Stanford has assisted Cardinal Inc. with the preparation of its financial statements but has not
audited, compiled, or reviewed those financial statements. Cardinal wished to include these
financial statements in a communication that would describe Stanford’s involvement in the
preparation of the financial statements. Stanford believes that Cardinal’s communication is
adequate and appropriately describes Stanford’s limited role in the preparation of the financial
statements.
Trees Inc. presents summary financial information along with its financial statements. The
summary financial information has been derived from the complete set of financial statements
that Stanford has audited (and issued an unmodified opinion on the complete financial
statements). A lender has engaged Stanford to evaluate and report on Trees’ summary financial
information. Stanford believes that summary financial information is fairly stated in relation to
Trees’ complete financial statements.
Stanford believes that some of the verbiage in Plunkett’s Management Discussion & Analysis
section is inconsistent with the firm’s financial statements. Stanford has concluded that
Plunkett’s financial statements present its financial position, results of operations, and cash flows
in accordance with GAAP and has decided to issue an unmodified opinion on Plunkett’s
financial statements.
Oil Patch is a client in the energy industry that is required to present supplementary oil and gas
reserve information. Stanford has performed certain procedures regarding this information and
concluded that it is presented in accordance with the Financial Accounting Standards Board
(FASB) presentation guidelines an.
Because his last undergrad research assistant died on the job, Profes.pdf
Because his last undergrad research assistant died on the job, Professor Killer worth has
assigned you the unfortunate task of assessing among giant space wasps. Like Earth wasps, the
space wasps have system of inheritance known as \"haplodiploidy\" in which haploid are
produced from unfertilized eggs and diploid females are produced from fertilized eggs. Each
female makes a single mating flight, during which she collects-from one multiple or males-sperm
that she uses to fertilize eggs throughout her life. Male space also make a single mating flight
during which they may fertilize one more females. Fill in the following table with the
probability that two individual space wasps share zero, one, or two alleles of the nuclear genome
identically by descent. In the rightmost column, labeled r, give the relatedness coefficient of the
two individuals. Show your work or explain your reasoning under the table or on the back of this
page.
Solution
Brothers: Brothers come from same mother. Mother has diploisd set of chromosomes but male
progeny haploid. in other words half of all males get one allele whereas rest half will get another
allele. So the probability of having different allele of a locus between brothers is 1/2. Similarly,
having same allele for a particular loces is also 1/2.
relatedness = (proportion obtained from mother x Proportion of mothers genome given) +
(proportion obtained from father x Proportion of fathers genome given)
= (1x 0.5) + (0+0) = 0.5
So, coefficient of relatedness fore brothers is 0.5
Full sisters: Full sisters have same male and female parent. All sisters will heve a haploid set
(same allele) from male parent. But half of the females get one allele from mother whereas the
rest half will get another allele. So, probability of have no alleles shared between two full sisters
is zero bacause male parent gives same allele to all full sisters. For the same reason, the
probability of having same one shared allele is 1.0 or 100%. The probability of sharing 2 alleles
by two half sisters is 0.5 or 50%. This is because all full sisters share one allele for sure. Mother
has two alleles and pass one of the allele to half of sisters and other allele will go to rest half of
sisters.
relatedness coefficient = (0.5 x 0.5) + (0.5 X 1) = 0.25 + 0.5 = 0.75
Half sisters (Same mother): So these share mother genome but the fathers are different.
Proportion of sharing no allele is 1/4 wheres for one allele is 1/2 while proportion of sharing two
alleles is zero.
relatedness coefficient = (0.5 x 0.5) + (0.5 X 0.5) = 0.25 + 0.25 = 0.5
Half sisters (Same father): Proportion of sharing no allele is zero wheres for one allele is 1 while
proportion of sharing two alleles is zero.
relatedness coefficient = (0.5 x 0.25) + (0.5 X 1) = 0.125 + 0.5 = 0.625.
When a coalition of credit card companies form an interest group cal.pdf
What limits on firearms do you believe are constitutional? What laws would you propose
regarding gun control? How do you think the public would react to your ideas?
Solution
The right to bear arms is inherent in the right of self-defense, defense of the family & defense
against tyranny. It assures safety of life, liberty & property as well as helps in protecting
independence. The right to keep arms is guaranteed by the second amendment of the constitution
which cannot be infringed. If firearms like guns are outlawed only outlaws will have them. In
this case the peaceful citizen’s protection against criminals may be seriously jeopardized. Also
the purpose of the second amendment was to give the people a means of protecting themselves
against the government if it ever became tyrannical, like what we observe toady.
Due to the prevalent culture of bearing firearms America has witnessed many horrific events
involving the use of guns & sophisticated automatic weapons. In many cases it has been found
that violent people & mentally disturbed people were having access to firearms. Therefore
according to my view if restriction on possessing of firearms are imposed on people with a
history of mental disturbance & violence it is constitutional. Protecting the right to keep and bear
arms is not the same as forbidding all regulations on that right. We can protect that right and at
the same time require background checks, permits, and training. We can regulate when, where,
and what kinds of guns are allowed. In some cases, we can regulate who can obtain guns,
imposing restrictions on, for instance, felons, the mentally ill, and known terrorists. We can ban
firearms such as military-style assault weapons & sophisticated weapons. Assault weapons
should be banned from sale in order to prevent future tragedies, because such a ban would be in
compliance with the U.S. Constitution.
I think most of the people will agree with my ideas as they are not meant to infringe the right of
people from possessing firearms but to effectively prevent its misuse & make people feel safe in
their daily lives..
What is the relationship between government and economicsWh.pdf
What is the difference between hard and soft magnetic materials?
Solution
Hard magnetic Materials :-
1. Materials which retain their magnetism and are difficult to demagnetize are called hard
magnetic materials.
These materials retain their magnetism even after the removal of the applied magnetic field.
Hence these materials are used for making permanent magnets. In permanent magnets the
movement of the domain wall is prevented. They are prepared by heating the magnetic materials
to the required temperature and then quenching them. Impurities increase the strength of hard
magnetic materials.
2.They have large hysteresis loss due to large hysteresis loop area.
3. Susceptibility and permeability are low.
4.Coercivity and retentivity values are large.
5. Magnetic energy stored is high.
6. They possess high value of BH product.
Soft magnetic Materials :-
1. Materials are easy to magnetize and demagnetize.
These materials are used for making temporary magnets. The domain wall movement is easy.
Hence they are easy to magnetize. By annealing the cold worked material, the dislocation density
is reduced and the domain wall movement is made easier. Soft magnetic materials should not
possess any void and its structure should be homogeneous so that the materials are not affected
by impurities.
2.They have low hysteresis loss due to small hysteresis area
3. Susceptibility and permeability are high.
4. Coercivity and retentivity values are less.
5. Since they have low retentivity and coercivity, they are not used for making permanent
magnets.
6. Magnetic energy stored is less..
Which method, streak or pour plate is easier for obtaining cultur.pdf
When a mass of 0.3 kg is placed on a spring hanging at rest from the ceiling, it elongates the
spring 5 cm. What is the stiffness k of the spring?
Solution
Let, acceleration due to gravity,g=9.8 m/s^2
Extension ,x=5 cm =0.05 m
Weight of mass is : W=0.3g=0.3*9.8 N
Hence stiffness , k=W/x=0.3*9.8/0.05 =58.8 N/m.
Write an algorithm in pseudocode called copy Stack that copies the co.pdf
Write a program that allows the user to input an angle between -4 and 4T, and outputs the
degree equivalent of the angle between 0° and 360° The program must use an i elseifelse block
to check and implement the following conditions: If the angle is out of the range, an error
message must be output, and the user must be allowed to try again If the angle is in the range but
not between 0 and 2T, it must be changed to an equivalent value between 0 and 2T The angle
must be converted to a degree value between 0 and 360
Solution
solution:
1)matlab code to convert radian angle to degree and within range for input between -4*pi.
Use properties of logarithms to condense 4 ln x-6 ln y. Write the .pdf
Unlike leaders, managers are those who:
-Develop relationships with employees based on trust and mutual respect.
-Implement procedures and processes to ensure the smooth functioning of an organization.
-Seek innovation rather than stability in their approach to fulfill organizational aspirations.
-Encourage and motivate employees to work together to achieve a common vision.
Solution
Option B is the correct option
Implement procedures and processes to ensure the smooth functioning of an organization.
Managers insure the smooth functioning in the organizations. For that they implement different
tactics like insures the healthier relationship among the employees, increase trust motivate
employees to achieve the common goal etc. All other options in this question comes under
smooth functioning
Hence option B is correct.
What is the Insertion Sort MIPS Assembly codeSolution.globl m.pdf
What is the correct answer choice and why? Medications that are used to treat acid reflux and
heartburn inhibit the production of stomach acid. The cells in the stomach that are affected by
these medications are a. smooth muscle cells. b. goblet cells. c. chief cells. d. parietal cells.
Solution
Choice D is correct.
Reason: The feeling of heart burn or acidity arises due to production of hydrocloric acid in the
stomach and due to impaired digestive tract, this acid might decrease the pH of the gastric bag
and the food pipe. This can also arise due to faulty closing of the gastric sphinctre. This causes a
feeling of heart burn not becuase of any cardiac anomality but due to burning sensation in the
gastric cavity near the heart. Thus, antacids are targeted to increase the pH of the stomach by
relaxing the acid secreting cells of the stomach. These are the parietal cells in the gastric lining
and hence antacids prevent acidity and heart-burn sensation by treating the parietal cells..
9. How much would it cost to construct a building today that cost $12.pdf
9. How much would it cost to construct a building today that cost $128,000 to build back in
1970 iven the burlding construction index for constructing that type of building was 287 in 1970
and is now 20272
Solution
Cost of constructing the building today = (1970 price / 1970 index)* Index today
Cost of construction today = (128000/28.7)(202.7)
Cost of construction today = $904,027.87.
True or false 20. A manufacturer has a duty to warn about risks that.pdf
To what degree is accurate forecasting possible?
To what degree is accurate forecasting possible?
Solution
first of all lets discuse what is forcasting? prediction oof any event that may happen in the future
like wheather forcasting, sell forcasting etc. Many of us think that forcasting is an art or science,
but actually forcasting is an art which is concluded or based on the facts of science.
In today’s changing markets, forecasting is becoming ever more important. beacause everyone
wants to get ready for future events that may be harmfull or benificial for them.
forecasting is a combination of reliable, process driven systems, tools to summarize the data, and
most importantly, the proper interpretation of the data. forcasting needs some data,study of data,
some facts, analysis of similar events which already took place in past.
Accuracy of forcasting actually depnds on the data which we have, knowledge of that data,study
of facts. If in the set of given data there is any slight mistake it may leads to a wrong prediction
that may give wrong result. But if accuracy of given set data is maximum then the accuracy of
result is also higher.
there are sevral techniques for forcasting that helps us to analyse the data, selection of such
tecniques also important in the result..
to a 1911 in an effort to reduce violence against Suffragettes of NAW.pdf
This Question: 1 pt In wartime, nations often institute a draft and require individuals to serve in
the military What kind of production and allocation system does the draft represent? O A.
Command system. B. Market system. ° C. Collective system. O D. Public system Why do you
suppose that kind of system might be necessary? (Check all that apply) A. If left to the market,
the military would likely be overstaffed during wartime B. Because for most individuals, the
benefits of going to war likely outweigh the costs C. I if left to the market, the military would
likely be understaffed during wartime D. Because for most individuals, the costs of going to war
likely outweigh the benefits. ck to select your answerts
Solution
Answer.)
Q1.) A.) Command System
Q2.) C.) If left to the market, the military would likely be understaffed during wartime.
D.) Because for most individuals, the costs of going to war likely overweigh the benefits..
There are many cases of human disease where an enzyme activity is lac.pdf
The United states has utilize multiple forms of liberalism through out its history. Please
distinguish the specific characteristics of classical and modern liberalism and outline the
evolution of these forms of liberalism within the united states. Please be sure to include specific
historic examples to support your points.
Solution
The easiest terms I would give would be that classical liberalism is worried about the methods
for government, while modern liberalism is centered around the finishes of government.
There\'s an inconspicuous distinction between the words \"freedom\" and \"flexibility,\" however
they\'re muddled in ordinary discussions. Opportunity is about the confinements one individual
places on another, while freedom involves compelling the instruments of government. They\'re
firmly related. In the US, the starting points of the country were significantly worried about
freedom—by which the designers implied setting limitations on the sorts of laws that might be
made—however they were not adequately (or by any stretch of the imagination, sometimes)
worried about flexibility, which is the reason the horrifying presence of subjection was permitted
to hold on. However the Bill of Rights and the Constitution completed an awesome arrangement
to guarantee freedom, seeing that the legislature was confined from limiting the rights and
benefits of residents. Yet, from a resident to a non-subject, there were extraordinary misuse.
Note the expressing of Lincoln\'s Gettysburg Address:
Four score and seven years prior our dads delivered on this landmass, another country,
considered in Liberty, and devoted to the suggestion that all men are made equivalent… [later]
… that this country, under God, should have another birth of flexibility—and that administration
of the general population, by the general population, for the general population, might not die
from the earth.
Note the distinctive uses there of freedom and opportunity. Freedom was the narrative of the
early republic, however now that we were moving in the direction of the abrogation of
subjection, we were with respect to it fundamental to the poise of all men made equivalent that
opportunity ought to in like manner be our incredible concern.
The issue was that in the US around then, opportunity and freedom kept running in coordinate
clash. The methods utilized to end servitude—that is, grow opportunity—required that huge
numbers of the limitations set on government be either relaxed or broken out and out. It is
sufficiently simple to make the inquiry, \"What esteem does freedom which controls government
have for a slave, desperate of all opportunity and all desire for the future?\" In the execution of
the Civil War and the early remaking, numerous infringement of freedom were made. Lincoln
was found to disregard old controls like habeas corpus (the keeping uncertainly of detainees
without due process), the thirteenth Amendment was passed with shady arrangements made, and
there were m.
The United states has utilize multiple forms of liberalism through o.pdf
The student(s) must deliver their final project about the requirements for designing the ATM
system in a class presentation for 5 minutes for evaluation
Subject: Software Maintenance & Configuration Management
Solution
Hi
First of all u should decide in which language your doing project ATM......like java,.Net or some
other languge.
In case of java language:
The software and Hard ware requirements are:
Minimum Software requirements are:
Operating System : Windows XP or above
Database server : Oracle 10g
IDE : Net beans
Web server : Apache Tomcat Server
Technology : Java and J2EE
Java Version : J2SDK1.5
Scripting Language : JavaScript
Styling : HTML, CSS
Web Browser : Internet Explorer, Mozilla Firefox, Google
chrome
Minimum Hardware requirements are:
Processor : Intel Core2 Duo
Hard Disk : 20 GB or more
RAM : 750 MB or more
Key Board : Standard Windows Keyboard
Mouse : Two or Three Button Mouse
In case of .net language:
Minimum software requirements are:
Operating System : Windows XP or above
Database server : Oracle 10g
Technology : .NET
Minimum hardware requirements are:
Processor 1 GHz
RAM 512 MB
Disk space (minimum)
32-bit needs 4.5 GB
64-bit needs 4.5 GB
Thank You..
Calculator 26 ng Learning pose that the Fed engages in expansionary.pdf
Calculator 26 ng Learning pose that the Fed engages in expansionary monetary policy by
lowering interest rates. Show the initial act by shifting the appropniate curve properly LRAS
SRAS AD
Solution
Fed engages in expansionary monetary policy by lowering interest rates. There is an increase in
money supply. This is done by purchasing Government bonds. Greater liquidity, and, availability
of a large number of funds for credit offtake decreases the interest rate. Firms invest. Output,
and, GDP increase. Employment, and, consumer spending increase. The aggregate demand curve
shifts to the left..
Silver chromate is sparingly soluble in aqueous solutions. The Ksp o.pdf
Should ethics be taught in Business School?
Solution
Ans:- Can ethics be taught? Yes it can, and yes it should. The whole purpose of education is to
help individuals develop their judgment. Judgment is about making decisions among choices and
ethics, at the basis level, is about making choices. Some of these choices are easier than others
but few choices are easy. Most are complex. Is one Aristotelian, and a judge of a person\'s
inherent character, or does one favour Locke evoking absolute, natural rights? Is one an egoist to
maximise individual good, a hedonist seeking to maximise general pleasure, or a utilitarian who
calculates the greatest happiness for the greatest number? Managers make decisions that affect
many others in their own organisations, and in many countries around the world. There is no
simple basis on which these decisions are based, nor is there one specific set of rules on which
everyone can agree. It is only through dialogue that business schools can help students think
these issues through. A discussion of ethics will never make the seven sins disappear. What
teaching ethics can do is to make as many people as possible make as thoughtful decisions as
possible.
Business ethics being taught in Universities provides perspectives to students, in the sense, how
ethical practices would help in creating and running businesses without resorting to fudging of
accounts, balance sheet or numbers. Case studies of the firms which run their businesses
ethically, the struggles that they go through to get Government approvals, delays caused in
approvals for not paying bribes etc., would provide the students a deeper insight into how to
navigate through the pitfalls and how to run a business in a sustainable and socially responsible
manner.
On the other hand, case studies of business houses which resorted to unethical practices would
provide them a picture of how such firms climbed to unbelievable heights within a short period
and a steep decline, as soon as the outcomes of unethical practices get exposed.
Once this exposure is given to the students, it is ultimately left to the students to follow ethical
or unethical practices. Swaying from ethical to unethical or partially ethical or partially unethical
is a result of not only dedicated ethics class/ or embedded ethics teaching, but also by comparing
their peers or seniors, how they are climbing the career path and through what means. Whether
fast growth path or slow but fairly consistent and acceptable growth path - the choice is left to
them..
Problem 21.12 Histone genes are unusual among eukaryotic genes becaus.pdf
Privacy and Security: What types of health care data are protected under HIPPA? What
technologies are NOT covered under HIPPA and therefore do not meet the criteria for CE
(covered entity)? What steps can/should organizations take to improve cyber security of health
care data?
Solution
a). Individuals, organizations, and agencies that meet the definition of a covered entity under
HIPAA must comply with the Rules\' requirements to protect the privacy and security of health
information and must provide individuals with certain rights with respect to their health
information. If an entity does not meet the definition of a covered entity or business associate, it
does not have to comply with the HIPAA Rules.
Health care provider:-
This includes providers such as:
Doctors
Clinics
Psychologists
Dentists
Chiropractors
Nursing Homes
Pharmacies
...but only if they transmit any information in an electronic form in connection with a transaction
for which HHS has adopted a standard.
health plans:-
This includes:
Health insurance companies
HMOs
Company health plans
(Government programs that pay for health care, such as Medicare, Medicaid, and the military
and veterans health care programs) .
A health care clearing house:-
This includes entities that process nonstandard health information they receive from another
entity into a standard (i.e., standard electronic format or data content), or vice versa.
b). Non – HIPPA covered entities
Non-covered entities can often do whatever they want with someone\'s data as long as those
potential actions are included in the terms and conditions -- which are rarely ever read by users--
including sharing and selling data. Remember, a lot of companies and people aren’t required to
comply with HIPAA, and there are many times when health information may be available to
these people and companies. HIPAA only applies to covered entities and their business
associates. list of who are not covered under HIPPA:-
. Life and long-term insurance companies
. Workers\' compensation insurers, administrative agencies, or employers (unless they are
otherwise considered covered entities)
. Agencies that deliver Social Security and welfare benefits
. Automobile insurance plans that include health benefits
. Search engines and websites that provide health or medical information and are not operated by
a covered entity
. Marketers
. Gyms and fitness clubs
. Direct to consumer (DTC) genetic testing companies
. Many mobile applications (apps) used for health and fitness purposes
. those who conduct screenings at pharmacies, shopping malls, health fairs, or other public places
for blood pressure, cholesterol, spinal alignment, and other conditions
. Certain alternative medicine practitioners
. Most schools and school districts
. Researchers who obtain health data directly from health care providers
. Most law enforcement agencies
. Many state agencies, like child protective services
. Courts, where health information is material to a case
c). C.
Privacy and Security What types of health care data are protected u.pdf
Portia Grant is an employee who is paid monthly. For the month of January of the current year,
she earned a total of $8,260. The FICA tax for social security is 6.2% of the first $118,500
earned each calendar year and the FICA tax rate for Medicare is 1.45% of all earnings. The
FUTA tax rate of 0.6% and the SUTA tax rate of 5.4% are applied to the first $7,000 of an
employee’s pay. The amount of federal income tax withheld from her earnings was $1,325.17.
What is the total amount of taxes withheld from the Portia’s earnings? (Round your intermediate
calculations to two decimal places.)
A- $3,097.17
B- $2,443.21
C- $1,957.06
D- $1,722.00
E- $1,495.36
Solution
The Answer is “C- $1,957.06”
Total amount of taxes withheld from the Portia’s earnings = $1957.06
Total amount of taxes withheld = Federal Income Tax + FICA tax for social security + FICA tax
rate for Medicare
= $1,325.17 + [ $8,260 x 6.20%] + [$8,260 x 0.60%]
= $1,325.17 + 512.12 + 119.77
= $1,957.06.
1. Project risk is normally highest during the project Executing Pro.pdf
1. Project risk is normally highest during the project Executing Process Group. True or False
2. The first step in the Risk Management Process is Identify Risks. True or False
3. The Plan Risk Responses activity occurs in the Project Planning Process Group. True or False
4. Three of the most common constraints that determine stakeholder tolerance levels include
scope, resources and stakeholder expectations. True or False
5. The Project Manager must attempt to attain an organizational commitment to the value of risk
management. True or False
6. Management Reserves are defined as reserves to address unknown risks. True or False
7. A risk that is identified early in the Risk Management Process is called an Emergent Risk.
True or False
8. Pure Risks are always classified as negative. True or False
9. Stakeholder risk attitudes and tolerances can impact overall risk prioritization and response
efforts. True or False
10. The Risk Register is initiated as part of the Plan Risk Management activity of the Risk
Management Process. True or False
Solution
1.
The correct answer is false.
Risk is nothing but the situation that is uncertain that leads to exposing something to danger.
This can affect the project\'s objective into positive or negative way. It is important for the
project manager to do risk analysis and prepare an action plan accordingly so that risk can be
managed appropriately.
The project life cycle consists of five phases. They are initiation phase, planning phase,
execution phase, control phase and closure. Initiation phase is the phase where risk is the highest..
PLEASE HELP ME !!IT IS Due Tonight ;(!How can I make the add but.pdf
Please assit with correcting the code below basesd on the text in Bold. Please read entire post.
last attempt to get this right. Thanks
The pay calculator still does not calculate the taxes correctly. Remember that only the amount
over $600.00 is taxed at 20% - the first $600.00 is taxed at 15%. If the gross is over 600, subtract
600 from the gross and multiply the difference by 0.20 and then add 600 * 0.15 to get the total
taxes. It\'s better to multiply by decimal amounts rather than use integers and then divide. You
will need to reconsider some of the data types for the variables. int isn\'t the best choice when
dealing with monetary amounts. The hours could also contain a decimal. The indentation is not
consistently correct but the code includes comments.
Instructions
Write a program that requests the user to enter hours worked in a week and the hourly wage. The
program should then print the gross pay, the taxes, and the net pay. Assume the following:
Overtime (in excess of 40 hours for week) = time and a half.
Tax rate: 15% of the first $600, 20% of the rest.
Code
#include
int main()
{
// integer declaration
int workhours,hourlywage,taxrate,othour,otwage;
//salary, tax, net pay are float variables
float salary,tax,netpay;
printf(\" Please enter hours worked for the week \ \");
//user enter weekly hours
scanf(\"%d\",&workhours);
// enter hourly wage
printf(\"Please enter your hourly wage \ \");
//user enter hourly rate
scanf(\"%d\",&hourlywage);
// if hours worked is equal to 40
if(workhours<=40)
{
salary=workhours*hourlywage;
//if salary is less than or equal to 600
if(salary<=600)
{
//tax rate is equal to 15
taxrate=15;
tax=(taxrate*salary)/100;
//net pay equals salary minus tax
netpay=salary-tax;
printf(\"Total gross Pay\\tTax Rate\\t Net Pay\ \");
//print gross pay minus tax rate and total netpay
printf(\"$ %f\\t$ %f(15%%) \\t$ %f\ \",salary,tax,netpay);
}
else
{
//tax rate equals 20%
taxrate=20;
tax=(taxrate*salary)/100;
//total net pay salary minus tax rate
netpay=salary-tax;
//print total gross pay, tax rate, and net pay
printf(\"Total gross Pay\\tTax Rate\\t Net Pay\ \");
printf(\"$ %f\\t$ %f(20%%)\\t$ %f\ \",salary,tax,netpay);
}
}
else
{
othour=workhours-40;
otwage=hourlywage+(hourlywage/2);
salary=(40*hourlywage)+(othour*otwage);
if(salary<=600)
{
taxrate=15;
tax=(taxrate*salary)/100;
//net pay equals salary minus tax
netpay=salary-tax;
printf(\"Gross Pay\\tTax Rate\\t Net Pay\ \");
printf(\"$ %f\\t$ %f(15%%) \\t$ %f\ \",salary,tax,netpay);
}
else
{
//tax rate equals 20 percent
taxrate=20;
tax=(taxrate*salary)/100;
//net pay equals salary minus tax
netpay=salary-tax;
printf(\"Gross Pay\\tTax Rate\\t Net Pay\ \");
printf(\"$ %f\\t$ %f(20%%)\\t$ %f\ \",salary,tax,netpay);
}
}
return 0;
Solution
Find comments inline for fixes. Also made few formatting changes by removing spaces in the
output lines.
PROGRAM CODE:
#include
int main()
{
// integer declaration
//changing all int to float
float workhours,hourlywage,taxrate,othour,otwag.
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- 1. C programming. For this code I only need to add a function so that the array of pointers is sorted by the age of the individual entered. it must be a function and called in main . That is the only thing needed. #define _CRT_SECURE_NO_WARNINGS #include #include #define PAUSE system("pause") typedef struct { int age; int weight; int height; } STATS; STATS *makeArrayOfPointers(int ); void loadArray(STATS **array, int *c); void displayArray(STATS **array, int c); void saveArray(STATS **array, int count, int size); STATS **reloadArray(char *, int *count, int *size); main() { STATS** array = 0; int count = 0; int size = 500; char reloaded = 'N'; array = reloadArray(&reloaded, &count, &size); if(reloaded == 'N') array = makeArrayOfPointers(size); PAUSE; loadArray(array, &count); printf("** unSorted Array ** "); displayArray(array, count); //sortArray(array, count) printf("** Sorted by Age ** ");
- 2. displayArray(array, count); saveArray(array, count, size); PAUSE; } // end of main void displayArray(STATS **array, int c) { int i; for (i = 0; i < c; i++) { printf("Record[%i] Age is %i.t Weight is %i.t Height is %i. ", i, array[i]->age, array[i]- >weight, array[i]->height); } PAUSE; } // end displayArray void loadArray(STATS **array, int *c) { int value; int counter = *c; for (*c; *c < (counter + 4); *c = *c + 1) { printf(" Information for person: %i ", (*c) + 1); array[*c] = calloc(1, sizeof(STATS)); printf("Enter age: "); scanf("%i", &value); array[*c]->age = value; printf("Enter weight: "); scanf("%i", &value); array[*c]->weight = value; printf("Enter height: "); scanf("%i", &value); array[*c]->height = value; } // end for } // end loadArray STATS *makeArrayOfPointers(int size) { STATS *result; result = malloc(sizeof(STATS*) * size); return result; } // end makeArrayOfPointers
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- 5. temp=array[j]; array[j]=array[j+1]; array[j+1]=temp; }//end of if }//end of j loop }//end of i loop }//end of fuction