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Laws of
Thermodynamics 1
      Disusun Oleh :
   Ichwan Aryono, S.Pd.
First law of thermodynamics
      First Law of thermodynamics states that :
      Whenever heat Q is given to a system, a portion of heat is used to
      increase its internal energy in the amount of ∆U, whereas the
      remaining leaves the system when the system performs a work W to
      its surroundings.
      Mathematically, the first law of thermodynamics is formulated by :

             Q>0                Q = ∆U + W
                                          W positip jika sistem melakukan usaha
                                          W negatip jika sistem dikenai usaha
                                          Q positip Jika sistem menerima kalor
W>0                        W<0
                                          Q negatip jika sistem melepas kalor
                                          Energi dalam ∆U tidak terpengaruh oleh proses,
                                          yang dilihat adalah hanya pada keadaan awal dan
                                          keadaan akhir


             Q<0
The first law of thermodynamics for isothermal
                     process


 At isothermal Process : ∆T = 0, so ∆U = 0
 The work done by the isothermal process is :
             V2             so
  W = nRT ln
             V1
 Q = ∆U + W = 0 + W = W

                V2
 Q = W = nRT ln
                V1
The first law of thermodynamics for isobaric
                    process


At isobaric process the pressure is constant
DP = 0
                        3
Internal energy ∆U =      P∆V , so
                        2
             3
Q = ∆U + W = P∆V + P∆V
             2
    5       5
Q = P∆V = P (V2 − V1 )
    2       2
The first law of thermodynamics for
            isochoric process


At Isochoric process volume is constant, ∆V = 0,
so the work done W = P∆V = 0, its produce :


Q = ∆U + W = ∆U + 0
         3        3
Q = ∆U = nR∆T = nR (T2 − T1 )
         2        2
The first law of thermodynamics for adiabatic
                     process

   Adiabatic process is a process without any transfer
   of heat into or from the system (Q=0)and it applies
   :
   Q = ∆ +W
        U
   0 = ∆ +W
        U
               3
   W = −∆ = − nR (T2 −T1 )
         U
               2
       3
   W = nR (T1 −T2 )
       2
Student Activity #1

A system absorbs 1500 J of heat from surrounding and does
work done 2200 J . Determine the change of internal energy
system, increases or decreases ?
Student Activity #2

System absorbs 1500 J of energy from surrounding. At the
   same time 2200 J work done is given to the system.
Determine the change of internal energy of the system. Is
          temperature decreses or increases ?
Student Activity #3

Two mol of ideal gas is expans from point I to point F with
three difference way as shown in diagram below.
Calculate the work done, change of internal energy, and
calor in each way IAF, IF and IBF, state in joule

       P(atm)        A
   4
           I



           B         F
  1
                             V(L)

               2     4
Student Activity
                                     P(Pa)
Four mol of ideal gas in
cylinder container change                     B      A
its conditional as shown in    500
graphic P-V beside.
Determine the work done,
internal energy and calor if
the gas is change from A to              C
                               200
C thrue (a) ABC, (b) AC


                                                          V(cm3)
                               0
                                        300   500   800
Student Activity #5

Three different processes act on system.
a. In process A, 42J of work are done on the system and 77J of
   heat are added to the system. Find the change in the
   system’s internal energy.
b. In process B. the system does 42 J of work and 77J of heat
   are added to the system. What is the change in the system’s
   internal energy ?
c. In process C, the system’s internal energy decreases by 120
   J while the system performs 120 J of work on its
   surroundings. How much heat was added to the system ?
Student Activity #6
An ideal gas is taken through the four processes shown in
  figure below. The changes in internal energy for three of
  these processes are as follows : ∆UAB = + 82 J, ∆UBC =
  +15 J, ∆UDA = -56 J. Find the change in internal energy
  for the process from C to D




                   D               C
  pressure




             A                    B


                    volume
Student Activity # 7
                  a. Find the work done by a monoatomic ideal gas as it
                      expands from point A to point C along the path shown in
                      figure below.
                  b. If the temperature of the gas is 220K at point A, what is its
                      temperature at point C ?
                  c. How much heat has been added to or removed from the
                      gas during this process ?

                                          B
                    600
Pressure P(kPa)




                    400
                              A                              C
                    200



                                                                 Volume, V(m3)
                          0   2     4         6    8    10
Student Activity #8
During an adiabatic process, the temperature of 3.52 moles
   of monoatomic ideal gas drops from 485oC to 205oC. For
   this gas, find
a. The work it does
b. The heat it exchanges with its surroundings, and
c. The changes in internal energy
Student Activity #9
              An ideal gas follows the three-part process shown in figure
                 below. At the completion of one full cycle, find
              a. The net work done by the system
              b. The net change in internal energy of the system
              c. The net heat absorbed by the system


                                A
                  150
Pressure P(kPa)




                  100

                                                      B
                  50        C

                        0       1   2     3       4       Volume, V(m3)
Quiz
                  Suppose 57.5 moles of an ideal monoatomic gas undergoes
                     the series of processes shown in figure below.
                  a. Calculate the temperature at the points A, B, and C.
                  b. For each process, A-B, B-C, and C-A, state whether heat
                     enters or leaves the system, Explain in each case.
                  c. Calculate the heat exchanged with the gas during each of
                     three process.

                                A
                  150
Pressure P(kPa)




                  100

                                                        B
                  50        C

                        0       1    2      3       4       Volume, V(m3)

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Hukum termodinamika-english

  • 1. Laws of Thermodynamics 1 Disusun Oleh : Ichwan Aryono, S.Pd.
  • 2. First law of thermodynamics First Law of thermodynamics states that : Whenever heat Q is given to a system, a portion of heat is used to increase its internal energy in the amount of ∆U, whereas the remaining leaves the system when the system performs a work W to its surroundings. Mathematically, the first law of thermodynamics is formulated by : Q>0 Q = ∆U + W W positip jika sistem melakukan usaha W negatip jika sistem dikenai usaha Q positip Jika sistem menerima kalor W>0 W<0 Q negatip jika sistem melepas kalor Energi dalam ∆U tidak terpengaruh oleh proses, yang dilihat adalah hanya pada keadaan awal dan keadaan akhir Q<0
  • 3. The first law of thermodynamics for isothermal process At isothermal Process : ∆T = 0, so ∆U = 0 The work done by the isothermal process is : V2 so W = nRT ln V1 Q = ∆U + W = 0 + W = W V2 Q = W = nRT ln V1
  • 4. The first law of thermodynamics for isobaric process At isobaric process the pressure is constant DP = 0 3 Internal energy ∆U = P∆V , so 2 3 Q = ∆U + W = P∆V + P∆V 2 5 5 Q = P∆V = P (V2 − V1 ) 2 2
  • 5. The first law of thermodynamics for isochoric process At Isochoric process volume is constant, ∆V = 0, so the work done W = P∆V = 0, its produce : Q = ∆U + W = ∆U + 0 3 3 Q = ∆U = nR∆T = nR (T2 − T1 ) 2 2
  • 6. The first law of thermodynamics for adiabatic process Adiabatic process is a process without any transfer of heat into or from the system (Q=0)and it applies : Q = ∆ +W U 0 = ∆ +W U 3 W = −∆ = − nR (T2 −T1 ) U 2 3 W = nR (T1 −T2 ) 2
  • 7. Student Activity #1 A system absorbs 1500 J of heat from surrounding and does work done 2200 J . Determine the change of internal energy system, increases or decreases ?
  • 8. Student Activity #2 System absorbs 1500 J of energy from surrounding. At the same time 2200 J work done is given to the system. Determine the change of internal energy of the system. Is temperature decreses or increases ?
  • 9. Student Activity #3 Two mol of ideal gas is expans from point I to point F with three difference way as shown in diagram below. Calculate the work done, change of internal energy, and calor in each way IAF, IF and IBF, state in joule P(atm) A 4 I B F 1 V(L) 2 4
  • 10. Student Activity P(Pa) Four mol of ideal gas in cylinder container change B A its conditional as shown in 500 graphic P-V beside. Determine the work done, internal energy and calor if the gas is change from A to C 200 C thrue (a) ABC, (b) AC V(cm3) 0 300 500 800
  • 11. Student Activity #5 Three different processes act on system. a. In process A, 42J of work are done on the system and 77J of heat are added to the system. Find the change in the system’s internal energy. b. In process B. the system does 42 J of work and 77J of heat are added to the system. What is the change in the system’s internal energy ? c. In process C, the system’s internal energy decreases by 120 J while the system performs 120 J of work on its surroundings. How much heat was added to the system ?
  • 12. Student Activity #6 An ideal gas is taken through the four processes shown in figure below. The changes in internal energy for three of these processes are as follows : ∆UAB = + 82 J, ∆UBC = +15 J, ∆UDA = -56 J. Find the change in internal energy for the process from C to D D C pressure A B volume
  • 13. Student Activity # 7 a. Find the work done by a monoatomic ideal gas as it expands from point A to point C along the path shown in figure below. b. If the temperature of the gas is 220K at point A, what is its temperature at point C ? c. How much heat has been added to or removed from the gas during this process ? B 600 Pressure P(kPa) 400 A C 200 Volume, V(m3) 0 2 4 6 8 10
  • 14. Student Activity #8 During an adiabatic process, the temperature of 3.52 moles of monoatomic ideal gas drops from 485oC to 205oC. For this gas, find a. The work it does b. The heat it exchanges with its surroundings, and c. The changes in internal energy
  • 15. Student Activity #9 An ideal gas follows the three-part process shown in figure below. At the completion of one full cycle, find a. The net work done by the system b. The net change in internal energy of the system c. The net heat absorbed by the system A 150 Pressure P(kPa) 100 B 50 C 0 1 2 3 4 Volume, V(m3)
  • 16. Quiz Suppose 57.5 moles of an ideal monoatomic gas undergoes the series of processes shown in figure below. a. Calculate the temperature at the points A, B, and C. b. For each process, A-B, B-C, and C-A, state whether heat enters or leaves the system, Explain in each case. c. Calculate the heat exchanged with the gas during each of three process. A 150 Pressure P(kPa) 100 B 50 C 0 1 2 3 4 Volume, V(m3)