The contestants get 20 samples from a distribution, the first to guess correctly scores!

1. Guess the distribution!
Rasmus Bååth
November 22, 2016

2. ???
1
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0
0.00.20.40.60.81.0

3. ???
2
x[seq_len(i)]
Frequency
2.0 2.5 3.0 3.5 4.0
0.00.20.40.60.81.0

4. ???
3
x[seq_len(i)]
Frequency
2.0 2.5 3.0 3.5 4.0
0.00.51.01.52.0

5. ???
4
x[seq_len(i)]
Frequency
2.0 2.5 3.0 3.5 4.0 4.5 5.0
0.00.51.01.52.0

6. ???
5
x[seq_len(i)]
Frequency
2 3 4 5 6
0.00.51.01.52.0

7. ???
6
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
0.01.02.03.0

8. ???
7
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
0.01.02.03.0

9. ???
8
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
0.01.02.03.0

10. ???
9
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
0.00.51.01.52.0

11. ???
10
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
0.01.02.03.0

12. ???
11
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
0.01.02.03.0

13. ???
12
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
01234

14. ???
13
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
01234

15. ???
14
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
012345

16. ???
15
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
012345

17. ???
16
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
012345

18. ???
17
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
012345

19. ???
18
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
012345

20. ???
19
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
012345

21. ???
20
x[seq_len(i)]
Frequency
0 1 2 3 4 5 6
012345

22. ???

23. It’s a . . .
Poisson Distribution
rpois(n, lambda = 3)

24. ???
1
x[seq_len(i)]
Frequency
1.0 1.2 1.4 1.6 1.8 2.0
0.00.20.40.60.81.0

25. ???
2
x[seq_len(i)]
Frequency
−1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.00.20.40.60.81.0

26. ???
3
x[seq_len(i)]
Frequency
−1 0 1 2 3 4
0.00.20.40.60.81.0

27. ???
4
x[seq_len(i)]
Frequency
−1 0 1 2 3 4
0.00.51.01.52.0

28. ???
5
x[seq_len(i)]
Frequency
−1 0 1 2 3 4
0.01.02.03.0

29. ???
6
x[seq_len(i)]
Frequency
−1 0 1 2 3 4
0.01.02.03.0

30. ???
7
x[seq_len(i)]
Frequency
−15 −10 −5 0 5
0.01.02.03.0

31. ???
8
x[seq_len(i)]
Frequency
−15 −10 −5 0 5
01234

32. ???
9
x[seq_len(i)]
Frequency
−15 −10 −5 0 5
01234

33. ???
10
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
01234

34. ???
11
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
012345

35. ???
12
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
012345

36. ???
13
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
0123456

37. ???
14
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
01234567

38. ???
15
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
01234567

39. ???
16
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
02468

40. ???
17
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
02468

41. ???
18
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
02468

42. ???
19
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
02468

43. ???
20
x[seq_len(i)]
Frequency
−15 −10 −5 0 5 10
02468

44. ???

45. It’s a . . .
Cauchy Distribution
rcauchy(n, location = 0, scale
= 1)

46. ???
1
x[seq_len(i)]
Frequency
−50 −48 −46 −44 −42 −40
0.00.20.40.60.81.0

47. ???
2
x[seq_len(i)]
Frequency
−50 0 50 100
0.00.20.40.60.81.0

48. ???
3
x[seq_len(i)]
Frequency
−50 0 50 100
0.00.51.01.52.0

49. ???
4
x[seq_len(i)]
Frequency
−50 0 50 100
0.00.51.01.52.0

50. ???
5
x[seq_len(i)]
Frequency
−50 0 50 100
0.01.02.03.0

51. ???
6
x[seq_len(i)]
Frequency
−100 −50 0 50 100
0.01.02.03.0

52. ???
7
x[seq_len(i)]
Frequency
−100 −50 0 50 100
0.01.02.03.0

53. ???
8
x[seq_len(i)]
Frequency
−100 −50 0 50 100
01234

54. ???
9
x[seq_len(i)]
Frequency
−100 −50 0 50 100
01234

55. ???
10
x[seq_len(i)]
Frequency
−100 −50 0 50 100
01234

56. ???
11
x[seq_len(i)]
Frequency
−100 −50 0 50 100
012345

57. ???
12
x[seq_len(i)]
Frequency
−100 −50 0 50 100
012345

58. ???
13
x[seq_len(i)]
Frequency
−100 −50 0 50 100
012345

59. ???
14
x[seq_len(i)]
Frequency
−100 −50 0 50 100
012345

60. ???
15
x[seq_len(i)]
Frequency
−100 −50 0 50 100
012345

61. ???
16
x[seq_len(i)]
Frequency
−100 −50 0 50 100
0123456

62. ???
17
x[seq_len(i)]
Frequency
−100 −50 0 50 100
0123456

63. ???
18
x[seq_len(i)]
Frequency
−100 −50 0 50 100
0123456

64. ???
19
x[seq_len(i)]
Frequency
−100 −50 0 50 100
0123456

65. ???
20
x[seq_len(i)]
Frequency
−100 −50 0 50 100
01234567

66. ???

67. It’s a . . .
Uniform Distribution
rnorm(n, -100, 100)

68. ???
1
x[seq_len(i)]
Frequency
−1.0 −0.8 −0.6 −0.4 −0.2 0.0
0.00.20.40.60.81.0

69. ???
2
x[seq_len(i)]
Frequency
−1.0 −0.8 −0.6 −0.4 −0.2 0.0
0.00.51.01.52.0

70. ???
3
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0
0.00.51.01.52.0

71. ???
4
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0
0.01.02.03.0

72. ???
5
x[seq_len(i)]
Frequency
0 1 2 3 4
0.01.02.03.0

73. ???
6
x[seq_len(i)]
Frequency
0 1 2 3 4
01234

74. ???
7
x[seq_len(i)]
Frequency
0 1 2 3 4
012345

75. ???
8
x[seq_len(i)]
Frequency
0 1 2 3 4
0123456

76. ???
9
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
0123456

77. ???
10
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
01234567

78. ???
11
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
01234567

79. ???
12
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
01234567

80. ???
13
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
01234567

81. ???
14
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
02468

82. ???
15
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
02468

83. ???
16
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
02468

84. ???
17
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
02468

85. ???
18
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
02468

86. ???
19
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
02468

87. ???
20
x[seq_len(i)]
Frequency
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
02468

88. ???

89. It’s a . . .
Zero inflated gamma
distribution

90. ???
1
x[seq_len(i)]
Frequency
−1.0 −0.9 −0.8 −0.7 −0.6 −0.5
0.00.20.40.60.81.0

91. ???
2
x[seq_len(i)]
Frequency
−0.6 −0.5 −0.4 −0.3 −0.2
0.00.20.40.60.81.0

92. ???
3
x[seq_len(i)]
Frequency
−1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.00.51.01.52.0

93. ???
4
x[seq_len(i)]
Frequency
−1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.00.51.01.52.0

94. ???
5
x[seq_len(i)]
Frequency
−1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.00.51.01.52.0

95. ???
6
x[seq_len(i)]
Frequency
−1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.00.51.01.52.0

96. ???
7
x[seq_len(i)]
Frequency
−1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.01.02.03.0

97. ???
8
x[seq_len(i)]
Frequency
−2 −1 0 1 2
0.01.02.03.0

98. ???
9
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.01.02.03.0

99. ???
10
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.01.02.03.0

100. ???
11
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0.01.02.03.0

101. ???
12
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
01234

102. ???
13
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
012345

103. ???
14
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0123456

104. ???
15
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0123456

105. ???
16
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
0123456

106. ???
17
x[seq_len(i)]
Frequency
−1.5 −1.0 −0.5 0.0 0.5 1.0 1.5 2.0
01234567

107. ???
18
x[seq_len(i)]
Frequency
−2 −1 0 1 2
01234567

108. ???
19
x[seq_len(i)]
Frequency
−2 −1 0 1 2
01234567

109. ???
20
x[seq_len(i)]
Frequency
−2 −1 0 1 2
01234567

110. ???

111. It’s a . . .
Normal Distribution
rnorm(n, mean = 0, sd = 1)