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Given function is -T( n) = 2T ( n 2 ) + log 2n= in Big Oh not.pdf

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Given function is - T( n) = 2T ( n / 2 ) + log 2n => in Big Oh notation we consider the maximum possible exponent of n for fairly large values of n => minimal asymptotic in big Oh is = O ( n ) ... Answer Solution Given function is - T( n) = 2T ( n / 2 ) + log 2n => in Big Oh notation we consider the maximum possible exponent of n for fairly large values of n => minimal asymptotic in big Oh is = O ( n ) ... Answer.

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Given function is - T( n) = 2T ( n / 2 ) + log 2n => in Big Oh notation we consider the maximum possible exponent of n for fairly large values of n => minimal asymptotic in big Oh is = O ( n ) ... Answer Solution Given function is - T( n) = 2T ( n / 2 ) + log 2n => in Big Oh notation we consider the maximum possible exponent of n for fairly large values of n => minimal asymptotic in big Oh is = O ( n ) ... Answer

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