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Chapter 6: Normal Probability Distribution
6.1: The Standard Normal Distribution
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Chapter 6: Normal Probability Distribution
6.2: Real Applications of Normal Distributions
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Chapter 7: Estimating Parameters and Determining Sample Sizes
7.3: Estimating a Population Standard Deviation or Variance
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Chapter 7: Estimating Parameters and Determining Sample Sizes
7.3: Estimating a Population Standard Deviation or Variance
When modeling a system, encountering missing data is common.
What shall a modeler do in the case of unknown or missing information?
When dealing with missing data, it is critical to make correct assumptions to ensure that the system is accurate.
One must common strategy for handling such situations is calculate the average of available data for the similar existing systems (i.e., creating sampling data).
Use this average as a reasonable estimate for the missing value.
Ever been troubled by the blinking sign and didn’t know what to do?
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Save them for later and save the trouble!
Fleet management these days is next to impossible without connected vehicle solutions. Why? Well, fleet trackers and accompanying connected vehicle management solutions tend to offer quite a few hard-to-ignore benefits to fleet managers and businesses alike. Let’s check them out!
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Chapter 6: Normal Probability Distribution
6.1: The Standard Normal Distribution
Please Subscribe to this Channel for more solutions and lectures
http://www.youtube.com/onlineteaching
Chapter 6: Normal Probability Distribution
6.2: Real Applications of Normal Distributions
Please Subscribe to this Channel for more solutions and lectures
http://www.youtube.com/onlineteaching
Chapter 7: Estimating Parameters and Determining Sample Sizes
7.3: Estimating a Population Standard Deviation or Variance
Please Subscribe to this Channel for more solutions and lectures
http://www.youtube.com/onlineteaching
Chapter 7: Estimating Parameters and Determining Sample Sizes
7.3: Estimating a Population Standard Deviation or Variance
When modeling a system, encountering missing data is common.
What shall a modeler do in the case of unknown or missing information?
When dealing with missing data, it is critical to make correct assumptions to ensure that the system is accurate.
One must common strategy for handling such situations is calculate the average of available data for the similar existing systems (i.e., creating sampling data).
Use this average as a reasonable estimate for the missing value.
Ever been troubled by the blinking sign and didn’t know what to do?
Here’s a handy guide to dashboard symbols so that you’ll never be confused again!
Save them for later and save the trouble!
Fleet management these days is next to impossible without connected vehicle solutions. Why? Well, fleet trackers and accompanying connected vehicle management solutions tend to offer quite a few hard-to-ignore benefits to fleet managers and businesses alike. Let’s check them out!
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Comprehensive program for Agricultural Finance, the Automotive Sector, and Empowerment . We will define the full scope and provide a detailed two-week plan for identifying strategic partners in each area within Limpopo, including target areas.:
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1. 7: Normal Probability Distributions 1
April 23
Chapter 7:
Normal Probability
Distributions
2. 7: Normal Probability Distributions 2
In Chapter 7:
7.1 Normal Distributions
7.2 Determining Normal Probabilities
7.3 Finding Values That Correspond to
Normal Probabilities
7.4 Assessing Departures from Normality
3. 7: Normal Probability Distributions 3
§7.1: Normal Distributions
• This pdf is the most popular distribution
for continuous random variables
• First described de Moivre in 1733
• Elaborated in 1812 by Laplace
• Describes some natural phenomena
• More importantly, describes sampling
characteristics of totals and means
4. 7: Normal Probability Distributions 4
Normal Probability Density
Function
• Recall: continuous
random variables are
described with
probability density
function (pdfs)
curves
• Normal pdfs are
recognized by their
typical bell-shape
Figure: Age distribution
of a pediatric population
with overlying Normal
pdf
5. 7: Normal Probability Distributions 5
Area Under the Curve
• pdfs should be viewed
almost like a histogram
• Top Figure: The darker
bars of the histogram
correspond to ages ≤ 9
(~40% of distribution)
• Bottom Figure: shaded
area under the curve
(AUC) corresponds to
ages ≤ 9 (~40% of area)
2
2
1
2
1
)
(
x
e
x
f
6. 7: Normal Probability Distributions 6
Parameters μ and σ
• Normal pdfs have two parameters
μ - expected value (mean “mu”)
σ - standard deviation (sigma)
σ controls spread
μ controls location
7. 7: Normal Probability Distributions 7
Mean and Standard Deviation
of Normal Density
μ
σ
8. 7: Normal Probability Distributions 8
Standard Deviation σ
• Points of inflections
one σ below and
above μ
• Practice sketching
Normal curves
• Feel inflection points
(where slopes change)
• Label horizontal axis
with σ landmarks
9. 7: Normal Probability Distributions 9
Two types of means and standard
deviations
• The mean and standard deviation from
the pdf (denoted μ and σ) are
parameters
• The mean and standard deviation from
a sample (“xbar” and s) are statistics
• Statistics and parameters are related,
but are not the same thing!
10. 7: Normal Probability Distributions 10
68-95-99.7 Rule for
Normal Distributions
• 68% of the AUC within ±1σ of μ
• 95% of the AUC within ±2σ of μ
• 99.7% of the AUC within ±3σ of μ
11. 7: Normal Probability Distributions 11
Example: 68-95-99.7 Rule
Wechsler adult
intelligence scores:
Normally distributed
with μ = 100 and σ = 15;
X ~ N(100, 15)
• 68% of scores within
μ ± σ
= 100 ± 15
= 85 to 115
• 95% of scores within
μ ± 2σ
= 100 ± (2)(15)
= 70 to 130
• 99.7% of scores in
μ ± 3σ =
100 ± (3)(15)
= 55 to 145
12. 7: Normal Probability Distributions 12
Symmetry in the Tails
… we can easily
determine the AUC in
tails
95%
Because the Normal
curve is symmetrical
and the total AUC is
exactly 1…
13. 7: Normal Probability Distributions 13
Example: Male Height
• Male height: Normal with μ = 70.0˝ and σ = 2.8˝
• 68% within μ ± σ = 70.0 2.8 = 67.2 to 72.8
• 32% in tails (below 67.2˝ and above 72.8˝)
• 16% below 67.2˝ and 16% above 72.8˝ (symmetry)
14. 7: Normal Probability Distributions 14
Reexpression of Non-Normal
Random Variables
• Many variables are not Normal but can be
reexpressed with a mathematical
transformation to be Normal
• Example of mathematical transforms used
for this purpose:
– logarithmic
– exponential
– square roots
• Review logarithmic transformations…
15. 7: Normal Probability Distributions 15
Logarithms
• Logarithms are exponents of their base
• Common log
(base 10)
– log(100) = 0
– log(101) = 1
– log(102) = 2
• Natural ln (base e)
– ln(e0) = 0
– ln(e1) = 1
Base 10 log function
16. 7: Normal Probability Distributions 16
Example: Logarithmic Reexpression
• Prostate Specific Antigen
(PSA) is used to screen
for prostate cancer
• In non-diseased
populations, it is not
Normally distributed, but
its logarithm is:
• ln(PSA) ~N(−0.3, 0.8)
• 95% of ln(PSA) within
= μ ± 2σ
= −0.3 ± (2)(0.8)
= −1.9 to 1.3
Take exponents of “95% range”
e−1.9,1.3 = 0.15 and 3.67
Thus, 2.5% of non-diseased
population have values greater
than 3.67 use 3.67 as
screening cutoff
17. 7: Normal Probability Distributions 17
§7.2: Determining Normal
Probabilities
When value do not fall directly on σ
landmarks:
1. State the problem
2. Standardize the value(s) (z score)
3. Sketch, label, and shade the curve
4. Use Table B
18. 7: Normal Probability Distributions 18
Step 1: State the Problem
• What percentage of gestations are
less than 40 weeks?
• Let X ≡ gestational length
• We know from prior research:
X ~ N(39, 2) weeks
• Pr(X ≤ 40) = ?
19. 7: Normal Probability Distributions 19
Step 2: Standardize
• Standard Normal
variable ≡ “Z” ≡ a
Normal random
variable with μ = 0
and σ = 1,
• Z ~ N(0,1)
• Use Table B to look
up cumulative
probabilities for Z
20. 7: Normal Probability Distributions 20
Example: A Z variable
of 1.96 has cumulative
probability 0.9750.
21. 7: Normal Probability Distributions 21
x
z
Step 2 (cont.)
5
.
0
2
39
40
has
)
2
,
39
(
~
from
40
value
the
example,
For
z
N
X
z-score = no. of σ-units above (positive z) or below
(negative z) distribution mean μ
Turn value into z score:
22. 7: Normal Probability Distributions 22
3. Sketch
4. Use Table B to lookup Pr(Z ≤ 0.5) = 0.6915
Steps 3 & 4: Sketch & Table B
23. 7: Normal Probability Distributions 23
a represents a lower boundary
b represents an upper boundary
Pr(a ≤ Z ≤ b) = Pr(Z ≤ b) − Pr(Z ≤ a)
Probabilities Between Points
24. 7: Normal Probability Distributions 24
Pr(-2 ≤ Z ≤ 0.5) = Pr(Z ≤ 0.5) − Pr(Z ≤ -2)
.6687 = .6915 − .0228
Between Two Points
See p. 144 in text
.6687 .6915
.0228
-2 0.5 0.5 -2
25. 7: Normal Probability Distributions 25
§7.3 Values Corresponding to
Normal Probabilities
1. State the problem
2. Find Z-score corresponding to
percentile (Table B)
3. Sketch
4. Unstandardize:
p
z
x
26. 7: Normal Probability Distributions 26
z percentiles
zp ≡ the Normal z variable with
cumulative probability p
Use Table B to look up the value of zp
Look inside the table for the closest
cumulative probability entry
Trace the z score to row and column
27. 7: Normal Probability Distributions 27
Notation: Let zp
represents the z score
with cumulative
probability p,
e.g., z.975 = 1.96
e.g., What is the 97.5th
percentile on the Standard
Normal curve?
z.975 = 1.96
28. 7: Normal Probability Distributions 28
Step 1: State Problem
Question: What gestational length is
smaller than 97.5% of gestations?
• Let X represent gestations length
• We know from prior research that
X ~ N(39, 2)
• A value that is smaller than .975 of
gestations has a cumulative probability
of.025
29. 7: Normal Probability Distributions 29
Step 2 (z percentile)
Less than 97.5%
(right tail) = greater
than 2.5% (left tail)
z lookup:
z.025 = −1.96
z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09
–1.9 .0287 .0281 .0274 .0268 .0262 .0256 .0250 .0244 .0239 .0233
30. 7: Normal Probability Distributions 30
35
)
2
)(
96
.
1
(
39
p
z
x
The 2.5th percentile is 35 weeks
Unstandardize and sketch
31. 7: Normal Probability Distributions 31
7.4 Assessing Departures
from Normality
Same distribution on
Normal “Q-Q” Plot
Approximately
Normal histogram
Normal distributions adhere to diagonal line on Q-Q
plot
32. 7: Normal Probability Distributions 32
Negative Skew
Negative skew shows upward curve on Q-Q plot
33. 7: Normal Probability Distributions 33
Positive Skew
Positive skew shows downward curve on Q-Q plot
34. 7: Normal Probability Distributions 34
Same data as prior slide with
logarithmic transformation
The log transform Normalize the skew
35. 7: Normal Probability Distributions 35
Leptokurtotic
Leptokurtotic distribution show S-shape on Q-Q plot