Dear,The answer is 7.SolutionDear,The answer is 7..pdf

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Rest are okay but B) I think should be vanderwall.pdf

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pH =4.217 pH = - log(concentration of H+) = -log .pdf

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Liquids may change to a vapor at temperatures below their boiling points through the process of evaporation. Evaporation is a surface phenomenon in which molecules located near the liquid\'s edge, not contained by enough liquid pressure on that side, escape into the surroundings as vapor. On the other hand, boiling is a process in which molecules anywhere in the liquid escape, resulting in the formation of vapor bubbles within the liquid. Solution Liquids may change to a vapor at temperatures below their boiling points through the process of evaporation. Evaporation is a surface phenomenon in which molecules located near the liquid\'s edge, not contained by enough liquid pressure on that side, escape into the surroundings as vapor. On the other hand, boiling is a process in which molecules anywhere in the liquid escape, resulting in the formation of vapor bubbles within the liquid..

Liquids may change to a vapor at temperatures bel.pdf

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intra extra equilibrium potential mEq/L mEq/L 12 142 61.77 135 4 -87.97 0.5 * 10^-4 0.75 * 10^-4 120.19 4.5 112 80.36 equlibrium potential = RT/ZF ln(Xo/Xi) =25 mV ln(Xo/Xi) mEq/L=(mMoles/L) / valency Solution intra extra equilibrium potential mEq/L mEq/L 12 142 61.77 135 4 -87.97 0.5 * 10^-4 0.75 * 10^-4 120.19 4.5 112 80.36 equlibrium potential = RT/ZF ln(Xo/Xi) =25 mV ln(Xo/Xi) mEq/L=(mMoles/L) / valency.

intra extra equilibrium potential mEqL mEqL 1.pdf

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Which of the following forms of DES is considered the most vulnerabl.pdf

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This is actually pretty simple, so I\'ll help explain. Take a given hydrogen atom, but we\'ll use an ionic form that has 5 electrons (as you\'ve stated). Now, for the quantum numbers. The first one, N, is the electron shell in question. Shells work as providing spaces for electron density. The first shell, in which N=1, holds two electrons because it only contains one orbital. N=2 holds two orbitals, which holds four electrons. Combined with N=1, an ion in N=2 has anywhere between 3 (the minimum of N=1, +1 electron) and 8 electrons (the maximum number of electrons before entering the third shell. Because the ion in question has 5 electrons, its N value is 2. A simple way to calculate the maximum number of electrons in a given atom that occupies a specific shell is to take that shell number, N, square it and multiply the result by two. That is why the maximum quantum number N for an atom whose electrons occupy the third shell is 18 (which is (3^2)2). Onto the next quantum number, which is l. If you understand the order of atomic shells and their orbitals, this is a simple one. The first shell is l=0, which is the \"s\" shell of an atom. s shells can only hold one atomic orbital, which is two electrons. We denote this as \"1s2\". The next shell is 2s, and because we can fill it, it become 2s2.Because we have 5 electrons, we need to keep going up. The next shell is l=1, which is the \"p\" shell. That fits our last electron, so your value for the l quantum number is \"1.\" Now we\'re at the ml quantum number. These are the numbers we assign to the specific orbitals in which electrons reside in, within a given shell. We\'re currently in the p shell, which holds 3 orbitals whose names are -1, 0, and +1. Unless you have a picture of the electron shells, we can only guess that the 5th electron is in any one of these, so the safe bet is to put it into the -1 orbital (though it can really be in any of them). Lastly, the ms quantum number. This denotes the spin on the electron. Up spin is +1/2, whilst down spin is -1/2. Unless you have a picture, I can\'t tell you which way it is spinning, but it\'s a safe guess to say that it\'s up. In sum, your quantum numbers as: 2, 1, 0, (1/2) I hope that helps. (: Feel free to ask any questions. Solution This is actually pretty simple, so I\'ll help explain. Take a given hydrogen atom, but we\'ll use an ionic form that has 5 electrons (as you\'ve stated). Now, for the quantum numbers. The first one, N, is the electron shell in question. Shells work as providing spaces for electron density. The first shell, in which N=1, holds two electrons because it only contains one orbital. N=2 holds two orbitals, which holds four electrons. Combined with N=1, an ion in N=2 has anywhere between 3 (the minimum of N=1, +1 electron) and 8 electrons (the maximum number of electrons before entering the third shell. Because the ion in question has 5 electrons, its N value is 2. A simple way to calculate the maximum number of electrons.

This is actually pretty simple, so Ill help explain. Take a gi.pdf

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There are many test IPv6 networks deployed across the world. For actual deployment, however, all the companies need to ensure that the vendors who support companys network have the requisite IPv6 enhancements. There are two categories of IPv6 enhancements. The first is the set that supports the packet forwarding (more commonly referred to as routing) process and the other set comprises enhancements that support the computing or host infrastructure. IPv6 enhancements of the first category include larger address formats (the ones that affect the routing table size and structure), better routing protocols such as Open Shortest First Protocol (OSPF) and Routing Information Protocol (RIP), and good support for optional extension headers (which streamline the packet forwarding process) such as the Routing Header. And, the second category of enhancements comprises enhancements to the Domain Name System (DNS), the Stateless Auto-configuration (plug and play) process, upgraded Security, and updates to the Application Programming Interfaces (APIs). Keeping these requisite enhancements in mind, let us now discuss what kind of support ten of the premier networking vendors are equipped to provide: Solution There are many test IPv6 networks deployed across the world. For actual deployment, however, all the companies need to ensure that the vendors who support companys network have the requisite IPv6 enhancements. There are two categories of IPv6 enhancements. The first is the set that supports the packet forwarding (more commonly referred to as routing) process and the other set comprises enhancements that support the computing or host infrastructure. IPv6 enhancements of the first category include larger address formats (the ones that affect the routing table size and structure), better routing protocols such as Open Shortest First Protocol (OSPF) and Routing Information Protocol (RIP), and good support for optional extension headers (which streamline the packet forwarding process) such as the Routing Header. And, the second category of enhancements comprises enhancements to the Domain Name System (DNS), the Stateless Auto-configuration (plug and play) process, upgraded Security, and updates to the Application Programming Interfaces (APIs). Keeping these requisite enhancements in mind, let us now discuss what kind of support ten of the premier networking vendors are equipped to provide:.

There are many test IPv6 networks deployed across the world. For act.pdf

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The three ways of presenting the changes in the balance of the Comprehensive Income (Cumulative) are : (i) Adding the value to the Stockholders\' Equity Balance. (ii) Showing the credit balance as a separate item in the Reserves and Surplus section of the Liabilities side. (iii) Showing a debit balance in the comprehensive income as an item in the Assets Side of the Balance Sheet with the heading \"Debit Balance in Profit and Loss Account\". Solution The three ways of presenting the changes in the balance of the Comprehensive Income (Cumulative) are : (i) Adding the value to the Stockholders\' Equity Balance. (ii) Showing the credit balance as a separate item in the Reserves and Surplus section of the Liabilities side. (iii) Showing a debit balance in the comprehensive income as an item in the Assets Side of the Balance Sheet with the heading \"Debit Balance in Profit and Loss Account\"..

The three ways of presenting the changes in the balance of the Compr.pdf

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The RASopathies are a group of genetic syndromes caused by germline mutations in genes that alter the Ras sub family and Mitogen activated protein kinases that control signal transduction. Some of these syndromes are neurofibromatosis type 1, Noonan syndrome, Costello syndrome, cardio-facio-cutaneous syndrome, LEOPARD syndrome and Legius syndrome. RAS opathies and X-chromosomes are not linked. Solution The RASopathies are a group of genetic syndromes caused by germline mutations in genes that alter the Ras sub family and Mitogen activated protein kinases that control signal transduction. Some of these syndromes are neurofibromatosis type 1, Noonan syndrome, Costello syndrome, cardio-facio-cutaneous syndrome, LEOPARD syndrome and Legius syndrome. RAS opathies and X-chromosomes are not linked..

The RASopathies are a group of genetic syndromes caused by germline .pdf

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ThanksSolutionThanks.pdf

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Step1 In O2 ; we have 2 unpaired electrons which occupy pi 2p Anti.pdf

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Quartzite is sandstone that has been converted to a solid quartz rock. It formed when silica is subjected to great heat and pressure. The individual silica particles melt and glue together to form quartizite. Solution Quartzite is sandstone that has been converted to a solid quartz rock. It formed when silica is subjected to great heat and pressure. The individual silica particles melt and glue together to form quartizite..

Quartzite is sandstone that has been converted to a solid quartz roc.pdf

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Principal amount = $800,000/1.066^(5*12) Interest in the last year = Sum Payable at the end of fifth year - Sum payable at the end of fourth year = $800,000 - $800,000*(1.066)^ (4*12 - 5*12) = $428,461.75 Solution Principal amount = $800,000/1.066^(5*12) Interest in the last year = Sum Payable at the end of fifth year - Sum payable at the end of fourth year = $800,000 - $800,000*(1.066)^ (4*12 - 5*12) = $428,461.75.

Principal amount = $800,0001.066^(512)Interest in the last y.pdf

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pls post the questions clearly..The 1st image is not uploadedS.pdf

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Photoreception refers to light detection mechanism in organisms. This function is carried out by photoreceptors present in the eye. Vertebrates- In vertebrate retina, the rods and cone contain photopigment containing regions. Closed and partially open discs are present in rods and cones respectively. Retinal and 3-dehydroretinal are the chromophores present in vertebrates. The photopigment porphyropsin present in vertebrates has a spectral sensitivity towards the red end of the spectrum. Insects- In insects, the receptors contain dark granules that move towards the rhabdom in response to light. Photopigments are present on microvilli. The chromophore 3-hydroxyretinal is present in insects. This produces xanthopsin and and 4-hydroxyretinal. By varying the amino acid composition of opsins, the spectral tuning is achieved in organisms. Solution Photoreception refers to light detection mechanism in organisms. This function is carried out by photoreceptors present in the eye. Vertebrates- In vertebrate retina, the rods and cone contain photopigment containing regions. Closed and partially open discs are present in rods and cones respectively. Retinal and 3-dehydroretinal are the chromophores present in vertebrates. The photopigment porphyropsin present in vertebrates has a spectral sensitivity towards the red end of the spectrum. Insects- In insects, the receptors contain dark granules that move towards the rhabdom in response to light. Photopigments are present on microvilli. The chromophore 3-hydroxyretinal is present in insects. This produces xanthopsin and and 4-hydroxyretinal. By varying the amino acid composition of opsins, the spectral tuning is achieved in organisms..

Photoreception refers to light detection mechanism in organisms. Thi.pdf

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number of allowed levels = CE2½ dEratio = E2½E1½= sqrt [E2] s.pdf

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moles of Ca(NO3)2 = mass/molar mass = 3.50/164.088 = 0.02133 mol moles of ions = 3 x 0.2133 = 0.06399 molality of ions = moles of ions/kg of water = 0.06399/0.0265 = 2.415 mol/kg Tf(water) -Tf(solution) = Kf x molality 0 - Tf(solution) = 1.86 x 2.415 Tf(solution) = -4.49 deg C Solution moles of Ca(NO3)2 = mass/molar mass = 3.50/164.088 = 0.02133 mol moles of ions = 3 x 0.2133 = 0.06399 molality of ions = moles of ions/kg of water = 0.06399/0.0265 = 2.415 mol/kg Tf(water) -Tf(solution) = Kf x molality 0 - Tf(solution) = 1.86 x 2.415 Tf(solution) = -4.49 deg C.

moles of Ca(NO3)2 = massmolar mass= 3.50164.088 = 0.02133 molm.pdf

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Milgram experiment was about human behavior, how humans follows instructions from an authority, no matter how extreme their have to go in following it. This experiment was conducted by Yale university’s Stanley Milgram. Trying to understand the conditions in which nazi soldiers who has committed genocide during World War II. Milgram experiment is an unethical experiment conducted to study what extent anyone will go hurting someone who is giving wrong answers, there were just following orders from authority, before the start experts thought only 2-3% will go to extent of giving shocks to danger level. However during study it was found that more than 65% has given shocks upto danger levels. This behavior has shocked the whole world. This explains the mass genocides conducted by soldiers in world War II, there have killed as there were ordered to kill. If I was myself subject I might has went on giving shock upto second level. Since as proven earlier in many studies humans tends to follow/obey instructions since we are trained since our childhood. Solution Milgram experiment was about human behavior, how humans follows instructions from an authority, no matter how extreme their have to go in following it. This experiment was conducted by Yale university’s Stanley Milgram. Trying to understand the conditions in which nazi soldiers who has committed genocide during World War II. Milgram experiment is an unethical experiment conducted to study what extent anyone will go hurting someone who is giving wrong answers, there were just following orders from authority, before the start experts thought only 2-3% will go to extent of giving shocks to danger level. However during study it was found that more than 65% has given shocks upto danger levels. This behavior has shocked the whole world. This explains the mass genocides conducted by soldiers in world War II, there have killed as there were ordered to kill. If I was myself subject I might has went on giving shock upto second level. Since as proven earlier in many studies humans tends to follow/obey instructions since we are trained since our childhood..

Milgram experiment was about human behavior, how humans follows inst.pdf

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IFRS requires that all the entities recognizes an expense for all the employees service received in the share based transactions It improves the comparability of financial information around the world and makes the accounting requirements for entities that report financial statements. Solution IFRS requires that all the entities recognizes an expense for all the employees service received in the share based transactions It improves the comparability of financial information around the world and makes the accounting requirements for entities that report financial statements..

IFRS requires that all the entities recognizes an expense for all th.pdf

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Dollar Duration = DUR x ( i1+ i) x P-1.95(-.04(1.07)96.38 =7.0.pdf

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