CUBE CUBOID SPHERE CONE CYLINDER
CUBE CUBOID
CUBOID
 6 Rectangular faces
 8 Vertices
 12 Edges
PROPERTIES OF CUBOID
l - length
b - breadth
h- height
DIMENSIONS OF CUBOID
SURFACE AREA OF CUBOID
T S A
Total Surface Area of a cuboid (TSA) = Sum of all the rectangular faces
= Area ( front + back + top + bottom + left + right)
PROBLEM :
Given a cuboid having dimension given as, length = 8 cm, breadth = 6 cm and height = 5 cm. Find the TSA of a cuboid.
TSA
Solution :
Given l =
b =
h =
= 2
Therefore, the total surface area of the given cuboid is 236 cm².
8 cm
6 cm
5 cm
( 8×6 + 6×5 + 5×8 )
SURFACE AREA OF CUBOID
L S A
Lateral Surface Area of a cuboid (LSA) = Sum of all the lateral rectangular faces
= Area ( front + back + left + right)
CUBE
 6 Square faces
 8 Vertices
 12 Edges
PROPERTIES OF CUBE
SURFACE AREA OF CUBE
Total Surface Area of a cube (TSA) = Sum of all the square faces
T S A
= 6𝑎2
= 6 (𝑎 𝑥 𝑎)
L S A
Lateral Surface Area of a cube (LSA) = Sum of all the lateral square faces
= 4 (𝑎 𝑥 𝑎)
= 4𝑎2
= 𝑎2
+ 𝑎2
+ 𝑎2
+ 𝑎2
+ 𝑎2
+ 𝑎2
PROBLEM :
Find the length of the edge of the cube, if its area is 2400 sq.cm.
Solution :
Given
6𝑎2
=
𝑇𝑆𝐴 = 2400 cm²
2400 cm²
𝑎2 = 2400 / 6 = 400
𝑎2
= 400
𝑎 = 20
Therefore, the length of the edge of the cube is 20 cm.
a
SUMMARY :
CUBOID :
 Properties :
 6 Rectangular Faces
 8 Vertices
 12 Edges
 Surface area
 x

CUBE :
 Cube is a cuboid with all its dimensions equal.
 Properties :
 6 Square Faces
 8 Vertices
 12 Edges
 Surface area
 TSA = 6𝑎2
 LSA = 4𝑎2
Cubes & cuboids
Cubes & cuboids

Cubes & cuboids

  • 3.
    CUBE CUBOID SPHERECONE CYLINDER
  • 4.
  • 5.
    CUBOID  6 Rectangularfaces  8 Vertices  12 Edges PROPERTIES OF CUBOID l - length b - breadth h- height DIMENSIONS OF CUBOID
  • 6.
    SURFACE AREA OFCUBOID T S A Total Surface Area of a cuboid (TSA) = Sum of all the rectangular faces = Area ( front + back + top + bottom + left + right)
  • 7.
    PROBLEM : Given acuboid having dimension given as, length = 8 cm, breadth = 6 cm and height = 5 cm. Find the TSA of a cuboid. TSA Solution : Given l = b = h = = 2 Therefore, the total surface area of the given cuboid is 236 cm². 8 cm 6 cm 5 cm ( 8×6 + 6×5 + 5×8 )
  • 8.
    SURFACE AREA OFCUBOID L S A Lateral Surface Area of a cuboid (LSA) = Sum of all the lateral rectangular faces = Area ( front + back + left + right)
  • 9.
    CUBE  6 Squarefaces  8 Vertices  12 Edges PROPERTIES OF CUBE
  • 10.
    SURFACE AREA OFCUBE Total Surface Area of a cube (TSA) = Sum of all the square faces T S A = 6𝑎2 = 6 (𝑎 𝑥 𝑎) L S A Lateral Surface Area of a cube (LSA) = Sum of all the lateral square faces = 4 (𝑎 𝑥 𝑎) = 4𝑎2 = 𝑎2 + 𝑎2 + 𝑎2 + 𝑎2 + 𝑎2 + 𝑎2
  • 11.
    PROBLEM : Find thelength of the edge of the cube, if its area is 2400 sq.cm. Solution : Given 6𝑎2 = 𝑇𝑆𝐴 = 2400 cm² 2400 cm² 𝑎2 = 2400 / 6 = 400 𝑎2 = 400 𝑎 = 20 Therefore, the length of the edge of the cube is 20 cm. a
  • 12.
    SUMMARY : CUBOID : Properties :  6 Rectangular Faces  8 Vertices  12 Edges  Surface area  x  CUBE :  Cube is a cuboid with all its dimensions equal.  Properties :  6 Square Faces  8 Vertices  12 Edges  Surface area  TSA = 6𝑎2  LSA = 4𝑎2

Editor's Notes

  • #8 2( (8×6) + (6×5) + (5×8)) = 2(48 + 30 + 40) = 2(118) = 236 So, the total surface area of this cuboid is 236 cm².