Dr. S.H. Burungale
Crystal Field Theory
1.Crystal Field Theory
This theory (CFT) largely replaced VB Theory for
interpreting the chemistry of coordination compounds.
•It was proposed by the physicist Hans Bethe in 1929.
•Subsequent modifications were proposed by J. H. Van
Vleck in 1935 to allow for some covalency in the
interactions. These modifications are often referred to as
Ligand Field Theory.
2.CFT-Assumptions
•The interactions between the metal ion and the ligands are
purely electrostatic (ionic).
•The ligands are regarded as point charges
•If the ligand is negatively charged: ion-ion interaction. If
the ligand is neutral : ion-dipole interaction
•The electrons on the metal are under repulsive from those
on the ligands
•The electrons on metal occupy those d-orbitals farthest
away from the direction of approach of ligands
Mn+
3.Crystal Field Theory
Mn+
Free Mn+ ions
The 5d orbitals in an isolated
gaseous metal are degenerate
Mn+
Crystal field theory
Uniform
electron
density of 5d
orbital's.
Mn+
- -
- Mn+
-
- -
•The ligands approach the metal along x, y, z.
•e-s in d orbital are repulsed by –vely charged ligands to
increase in potential energy.
•Degree of e-static repulsion depends on the
orientation of the d orbitals.
•d orbitals (dz2 and dx2-y2) with lobesdirected at the
ligands experience more repulsion to placed at higher
energy eg oebitals.
•d orbitals (dxy, dxz and dyx) with lobesin-between the
ligands experience less repulsion to placed at lower energy
t2g orbitals.
4.Shape of d orbital
Shape of d orbital
dxy
dx2-y2 dz2
dxz dyz
x
y
y
z
x
z
y
x
z
Shape of d Orbital
egt2g
5.Crystal field Splitting in Octahedral Complexes
Crystal field splitting in octahedral complexe
is divided into three parts :
1. degenerate energy of d orbitals in
isolated or gaseous free metal ion .
2. Imaginary formation of Octahedral
complex
3. Actual Octahedral complex formation
eg
t2g
0.6∆o
∆o
-0.4∆o
If a spherically symmetric field of negative charges is
placed around the metal, these orbitals remain
degenerate
metal ion
in free
state
(vacuum)
A
B
C
eg
t2g
0.6∆o
∆o
-0.4∆o
but all of them are raised in energy
as a result of the repulsion between the negative
charges on the ligands and
in the d orbitals.
metal ion
in a spherical
negative fiel
eg
t2g
0.6∆o
∆o
-0.4∆o
•If rather than a spherical field, discrete point charges
(ligands) are allowed to interact
with the metal, the degeneracy of the d orbitals is
removed (or, better said, lifted). The
splitting of d orbital energies and its consequences are
at the heart of crystal field theory.
metal ion
in a spherical
negative fiel
eg
t2g
0.6∆o
∆o
-0.4∆o
•Note all d orbitals will interact to the same extent with the
six point charges located on the +x, -x, +y, -y, +z and -z axes
respectively. •The orbitals which lie along these axes (i.e.
x2-y2, z2) will be destabilized more that the orbitals which
lie in-between the axes (i.e. xy, xz, yz). ory.
metal ion
in a spherical
negative field
E
•For the Oh point group, the x2-y2, z2 orbitals belong to the Eg
irreducible representation and xy, xz, yz belong to the T2g
representation.
•The extent to which these two sets of orbitals are split is denoted by
Δ 0 or alternatively 10Dq. As the baricenter must be conserved on
going from a spherical field to an octahedral field, the t2g set must
be stabilized as much as the eg set is destabilized.
6.In Tetrahedral Field
7.Crystal field splitting In Squar
planar copmlexes
Larger crystal field splitting parameter
Squar Planar complexes
Octahedral is converted into squar
planar geometry
8.Crystal Field Stabilization Energy
CFSE
Crystal Field Stabilization Energy
CFSE
d5
0.6
-0.4
0.6
-0.4
T2g
Egd
1
CFSE = [(0.6 x number of eg electrons)
- (0.4 x number of t2g electrons)]Δ
CFSE = [(0.6 x 0)
- (0.4 x 5)]Δo
=-2 Δo
CFSE = [(0.6 x 2)
- (0.4 x 3)]Δo
= 0Δo
32
Crystal Field Splitting of d orbitals: high spin and
low spin situations for a d6 metal
Net unpaired
spins = 0:
Diamagnetic
Net unpaired
spins = 4:
Strongly paramagnetic
Low spin
Electrons spin
pair
High spin
Electrons do
Not spin pair
Ligand strength: (Weak) I- < F- < H2O < NH3 < CN- (Strong)
Large splitting
Small splitting
33
Large splitting
Low spin
Small splitting
High spin
Energy gap larger than
advantage due to Hund’s rule
Energy gap small; Hund’s rule
applies
How many unpaired spins in Fe(CN)6
4- and in Fe(H2O)6
2+?
What is the charge of Fe in Fe(CN)6
4- and in Fe(H2O)6
2+?
Fe2+ in both cases Fe = [Ar]3d64s2; Fe2+ = [Ar]3d6
What kind of ligands are CN- and
H2O?
CN- is a strong field ligand and H2O
is a weak field ligand
High Spin and Low Spin
S=2 S=1
S=5/2
S=1/2
S=2
HIGH SPIN
S=0
LOW SPIN
S=3/2 HIGH SPIN S=1/2
LOW SPIN
S=1/2
S=1
S=3/2
S=1/2
S=0
S=1
37
Crystal Field Theory: The Color of Coordination Compounds
h =
The energy gap between the eg and t2g
orbitals, 0, (the crystal field splitting)
equals the energy of a photon:
0 = h= E
As 0, varies, h will also vary and the
color of the compound will change
Absorption of a photon causes a jump
from a t2g to an eg orbital
38
Strong field
Ligands (violet, low spin)
Weak field
Ligands (red, high spin)
The spectrochemical series of color and magnetic properties: weak field
(red, high spin), strong field (violet, low spin)
A d5 electron metal ion
Spectrochemical series
39
The color that we see is the color that is not
absorbed, but is transmitted. The
transmitted light is the complement of the
absorbed light.
Numbers are nm
So if red light is mainly absorbed the color is
green; if green light is mainly absorbed, the
color is red.
40
Color of complexes depend on the value of 0 = h= E
0 = h
“red
absorption”
“violet
absorption”
“looks green” “looks yellow
41
Crystal Field Splitting of d orbitals: high spin and low spin situations for a d5
metal (why are some complexes colorless?)
Colored
Colorless or very
weakly colored
Why?
Color corresponds to the
absorption of light an
transitions between d orbitals
for metals.
The transition for (b) is “spin
forbidden” because an
electron would need to “flip”
its spin in being excited from
a t orbital to a e orbital
THANK YOU!!!!

Crystal field theory

  • 1.
  • 2.
    1.Crystal Field Theory Thistheory (CFT) largely replaced VB Theory for interpreting the chemistry of coordination compounds. •It was proposed by the physicist Hans Bethe in 1929. •Subsequent modifications were proposed by J. H. Van Vleck in 1935 to allow for some covalency in the interactions. These modifications are often referred to as Ligand Field Theory.
  • 3.
    2.CFT-Assumptions •The interactions betweenthe metal ion and the ligands are purely electrostatic (ionic). •The ligands are regarded as point charges •If the ligand is negatively charged: ion-ion interaction. If the ligand is neutral : ion-dipole interaction •The electrons on the metal are under repulsive from those on the ligands •The electrons on metal occupy those d-orbitals farthest away from the direction of approach of ligands
  • 4.
  • 5.
    The 5d orbitalsin an isolated gaseous metal are degenerate Mn+ Crystal field theory Uniform electron density of 5d orbital's.
  • 7.
  • 8.
    - - - Mn+ - -- •The ligands approach the metal along x, y, z. •e-s in d orbital are repulsed by –vely charged ligands to increase in potential energy. •Degree of e-static repulsion depends on the orientation of the d orbitals. •d orbitals (dz2 and dx2-y2) with lobesdirected at the ligands experience more repulsion to placed at higher energy eg oebitals. •d orbitals (dxy, dxz and dyx) with lobesin-between the ligands experience less repulsion to placed at lower energy t2g orbitals.
  • 9.
    4.Shape of dorbital
  • 10.
    Shape of dorbital
  • 11.
  • 12.
    Shape of dOrbital egt2g
  • 14.
    5.Crystal field Splittingin Octahedral Complexes Crystal field splitting in octahedral complexe is divided into three parts : 1. degenerate energy of d orbitals in isolated or gaseous free metal ion . 2. Imaginary formation of Octahedral complex 3. Actual Octahedral complex formation
  • 15.
    eg t2g 0.6∆o ∆o -0.4∆o If a sphericallysymmetric field of negative charges is placed around the metal, these orbitals remain degenerate metal ion in free state (vacuum) A B C
  • 16.
    eg t2g 0.6∆o ∆o -0.4∆o but all ofthem are raised in energy as a result of the repulsion between the negative charges on the ligands and in the d orbitals. metal ion in a spherical negative fiel
  • 17.
    eg t2g 0.6∆o ∆o -0.4∆o •If rather thana spherical field, discrete point charges (ligands) are allowed to interact with the metal, the degeneracy of the d orbitals is removed (or, better said, lifted). The splitting of d orbital energies and its consequences are at the heart of crystal field theory. metal ion in a spherical negative fiel
  • 18.
    eg t2g 0.6∆o ∆o -0.4∆o •Note all dorbitals will interact to the same extent with the six point charges located on the +x, -x, +y, -y, +z and -z axes respectively. •The orbitals which lie along these axes (i.e. x2-y2, z2) will be destabilized more that the orbitals which lie in-between the axes (i.e. xy, xz, yz). ory. metal ion in a spherical negative field E
  • 19.
    •For the Ohpoint group, the x2-y2, z2 orbitals belong to the Eg irreducible representation and xy, xz, yz belong to the T2g representation. •The extent to which these two sets of orbitals are split is denoted by Δ 0 or alternatively 10Dq. As the baricenter must be conserved on going from a spherical field to an octahedral field, the t2g set must be stabilized as much as the eg set is destabilized.
  • 20.
  • 23.
    7.Crystal field splittingIn Squar planar copmlexes Larger crystal field splitting parameter Squar Planar complexes Octahedral is converted into squar planar geometry
  • 26.
  • 27.
    Crystal Field StabilizationEnergy CFSE d5 0.6 -0.4
  • 30.
  • 31.
    CFSE = [(0.6x number of eg electrons) - (0.4 x number of t2g electrons)]Δ CFSE = [(0.6 x 0) - (0.4 x 5)]Δo =-2 Δo CFSE = [(0.6 x 2) - (0.4 x 3)]Δo = 0Δo
  • 32.
    32 Crystal Field Splittingof d orbitals: high spin and low spin situations for a d6 metal Net unpaired spins = 0: Diamagnetic Net unpaired spins = 4: Strongly paramagnetic Low spin Electrons spin pair High spin Electrons do Not spin pair Ligand strength: (Weak) I- < F- < H2O < NH3 < CN- (Strong) Large splitting Small splitting
  • 33.
    33 Large splitting Low spin Smallsplitting High spin Energy gap larger than advantage due to Hund’s rule Energy gap small; Hund’s rule applies How many unpaired spins in Fe(CN)6 4- and in Fe(H2O)6 2+? What is the charge of Fe in Fe(CN)6 4- and in Fe(H2O)6 2+? Fe2+ in both cases Fe = [Ar]3d64s2; Fe2+ = [Ar]3d6 What kind of ligands are CN- and H2O? CN- is a strong field ligand and H2O is a weak field ligand
  • 34.
    High Spin andLow Spin S=2 S=1 S=5/2 S=1/2
  • 35.
    S=2 HIGH SPIN S=0 LOW SPIN S=3/2HIGH SPIN S=1/2 LOW SPIN
  • 36.
  • 37.
    37 Crystal Field Theory:The Color of Coordination Compounds h = The energy gap between the eg and t2g orbitals, 0, (the crystal field splitting) equals the energy of a photon: 0 = h= E As 0, varies, h will also vary and the color of the compound will change Absorption of a photon causes a jump from a t2g to an eg orbital
  • 38.
    38 Strong field Ligands (violet,low spin) Weak field Ligands (red, high spin) The spectrochemical series of color and magnetic properties: weak field (red, high spin), strong field (violet, low spin) A d5 electron metal ion Spectrochemical series
  • 39.
    39 The color thatwe see is the color that is not absorbed, but is transmitted. The transmitted light is the complement of the absorbed light. Numbers are nm So if red light is mainly absorbed the color is green; if green light is mainly absorbed, the color is red.
  • 40.
    40 Color of complexesdepend on the value of 0 = h= E 0 = h “red absorption” “violet absorption” “looks green” “looks yellow
  • 41.
    41 Crystal Field Splittingof d orbitals: high spin and low spin situations for a d5 metal (why are some complexes colorless?) Colored Colorless or very weakly colored Why? Color corresponds to the absorption of light an transitions between d orbitals for metals. The transition for (b) is “spin forbidden” because an electron would need to “flip” its spin in being excited from a t orbital to a e orbital
  • 42.